Here i just want to discus about the following:
My HTML From like the fllowing code:
<html>
<head>
<title>My Form</title>
</head>
<body>
<form id="sample" method="post" action="saveData.php">
Courses:
<input type="checkbox" name="check[]" Value="C++" />C++
<input type="checkbox" name="check[]" Value="PHP"/>PHP
<input type="checkbox" name="check[]" Value="MYSQL" />MYSQL
<input type="checkbox" name="check[]" Value=".Net"/>.Net
Gender:
<input type="radio" name="gen[]" Value="male"/>male
<input type="radio" name="gen[]" Value="female"/>Female
</form>
</body>
</html>
And I Want the OutPut Like The Following:
foreach ($_POST as $key => $val) {
$actVal .= "'".strtolower($key)."|".strtolower($val)."',";
$sqlin .= " ".strtolower($key)." VARCHAR(255) , ";
}
But I got The Output like which one clicked in that options:
Like the following:
-----------------------------------------
male
C++
but I need it like the following:
male,female
C++,PHP,MYSQL,.Net
POST will send all values if you mark them as selected using javascript right before submitting. $_POST["check"] is an array. use a foreach and get all values from that array.
As you're loop through post data which is going to be an array I believe that is why only one of their elements are being returned.
You might want to try something like this:
foreach ($_POST as $key => $val) {
if ($key == "check" || $key == "gen") { // If this is an array post field
foreach ($val as $val2) { // We need to loop through again since they're array post fields
$actVal .= "'" . strtolower($val2) . "'";
}
} else {
$actVal .= "'".strtolower($key)."|".strtolower($val)."',";
}
//$sqlin .= " ".strtolower($key)." VARCHAR(255) , "; // Worry about this separately, should be the same process
}
I can't figure out a way around that one. But there is an alternative:
<input type="checkbox" name="check" value="php" />PHP
<input type="hidden" name="checklist" value="php" />
<input type="checkbox" name="check" value="MySQL" />MySQL
<input type="hidden" name="checklist" value="MySQL" />
The idea is to store the list of all the values of a checkbox/radio button, in a hidden input so that you get the list of those values server-side, when the form is submitted.
BTW, why do you need it anyway?
Related
how to save multiple radio button in database using php without save button value.
my code :
$user_id = $_POST['user_id'];
foreach ( $_POST as $key => $val ) {
if ($key <> 'user_id') {
$bidder_interst_insert="INSERT INTO bidder_interest_list(id, bidder_id, bidder_interest_name) VALUES ('','$user_id','$val')";
$bidder_interst_insert_result = mysql_query($bidder_interst_insert);
if (mysql_affected_rows() > 0) {
$interest_list_success = "Thank you Successfull insert your interst list.";
$_SESSION['interest_list_success_msg'] = $interest_list_success;
} else {
$insert_error = "interst list Insert Error.";
$_SESSION['insert_error_msg'] = $insert_error;
header("location:interest_list.php");
}
}
}
This code work but database extra save in save button value how to solved this problem??
foreach ( $_POST as $key => $val ){
You are directly looping the $_POST, so the SAVE button value is also saving in the database. Take the values individually instead of looping the whole $_POST, then the SAVE button value won't be saved in the database.
And moreover you are using mysql functions which are deprecated, use mysqli or PDO.
EDIT::
Just take it the same way as u took user_id ==> $variablename = $_POST['fieldname'];
EDIT:::
Let me suppose i have a form like this
<form name="form1" id="form1" method="post" action="">
<input type="checkbox" name="products[]" value="A" checked="checked" />A <br />
<input type="checkbox" name="products[]" value="B" checked="checked" />B <br />
<input type="checkbox" name="products[]" value="C" checked="checked" />C <br />
<input type="checkbox" name="products[]" value="D" checked="checked" />D <br />
<input type="checkbox" name="products[]" value="E" checked="checked" />E <br />
<input type="checkbox" name="products[]" value="F" checked="checked" />F <br />
<input type="submit" name="save" id="save" value="Save" />
</form>
then i can do it like:
<?php
if(isset($_POST['save']))
{
$products = $_POST['products'];
foreach($products as $key => $value)
{
$qry = mysql_query("INSERT INTO tbl(product) VALUES('$value')");
}
}
?>
Try this
unset($_POST['name-of-save-button']);
$data = $_POST;
foreach ( $data as $key => $val ){//your code here}
I have html checkbox like this:
<form action="" method="post">
<input type="checkbox" name="language[]" value="php" />PHP<br />
<input type="checkbox" name="language[]" value="html" />HTML<br />
<input type="checkbox" name="language[]" value="java" />Java<br />
<input type="checkbox" name="language[]" value="c++" />C++<br />
<input type="submit" value="send" />
</form>
Now I want to detect the checkbox is not checked using this PHP
if($_POST)
{
if(empty($_POST['language']))
{
echo "bla";
}
else
{
foreach($_POST['language'] as $value)
{
echo 'Checked: '.$value.'
';
}
}
}
The output is always show the checbox checked.
My question is, how can I detect the checkbox is not checked?
Example I do not check PHP and Java.
You don't need to validate checkbox by checkbox in order to determine if they are checked or not, you won't get the unchecked checkboxes values at the time you send the form, so, sending the form like this:
<form action="" method="post">
<input type="checkbox" name="language[]" value="php" />PHP<br /> <!-- checked -->
<input type="checkbox" name="language[]" value="html" />HTML<br /><!-- checked -->
<input type="checkbox" name="language[]" value="java" />Java<br /><!-- unchecked -->
<input type="checkbox" name="language[]" value="c++" />C++<br /><!-- unchecked -->
<input type="submit" value="send" />
</form>
In your PHP, you will get an array as follows:
$_POST['languages'] = array("php", "html");
Now, lets say you have an array of all the values in order to check which ones you need to delete, and which ones you need to add, a rough code example would be as follows:
$allValues = array('php', 'html', 'java', 'c++');
$valuesForAdd = $_POST['language'];
$valuesForDeletion = array_diff($allValues, $valuesForAdd);
First you need the selectable items array in the backend:
$items = array('php','html','java','c++');
You have the posted (selected) languages array here:
$_POST['language']
Not selected languages array:
$not_selected_languages = array_diff($items,$_POST['language']);
I hope it helps.
Only 'checked' checkboxes get sent as parameters in a POST request.
If you want to know which aren't checked, you could have the value list stored on PHP side; then once you receive POST data - compare the array on PHP side with POST array.
$all_vals = array('php', 'c++', 'html', 'java');
$post_vals = $_POST['languages'];
foreach ($post_vals as $post_val)
if in_array($post_val, $all_vals)
$checkbox checked
else
$checkbox not checked
I assume this gives you enough liberty to do what you need.
I have multiple checkbox groups, and once the form is submitted, I want each group of checkboxes that were selected to be added to their own variable.
This is the form:
<form action="" method="get">
<p>apple <input type="checkbox" value="apple" name="fruits[]" /></p>
<p>orange <input type="checkbox" value="orange" name="fruits[]" /></p>
<p>peach <input type="checkbox" value="peach" name="fruits[]" /></p>
<br>
<p>red <input type="checkbox" value="red" name="colors[]" /></p>
<p>green <input type="checkbox" value="green" name="colors[]" /></p>
<p>blue <input type="checkbox" value="blue" name="colors[]" /></p>
<br>
<p>chicken <input type="checkbox" value="chicken" name="meats[]" /></p>
<p>pork <input type="checkbox" value="pork" name="meats[]" /></p>
<p>lamb <input type="checkbox" value="lamb" name="meats[]" /></p>
<button>submit</button>
</form>
And this is my code:
$string = 'fruits,colors,meats';
$str_array = explode(',', $string);
foreach ($str_array as $value) {
if (isset($_GET[$value])) {
$group_name = $_GET[$value];
foreach ($group_name as $group_item) {
$group_string .= ' ' . $group_item;
}
}
}
echo $group_string;
With that code, if I choose for example the first checkbox in each group and hit submit, I will get the following value of $group_string = apple red chicken in one string.
What I get does make sense to me as per the code I wrote, but what I want is for each option group to have its own variable to which its values are asigned, so what I want is to get is the following (assuming I again chose the first option from each group):
$fruits = 'apple';
$colors = 'red';
$meats = 'chicken';
But I don't know how to rewrite it so I get that. Also, the number of options groups is not known upfront, it has to happen dynamically.
Ok, I took the liberty of rewriting part of your php for my convenience but here it is
your new and improved php file
<?php
// assume we know beforehand what we are looking for
$groups = explode(',','fruits,colors,meats');
foreach ($groups as $group) {
if (isset($_GET[$group])) {
$vv = array();
foreach ($_GET[$group] as $item) $vv[] = $item;
$$group = implode(' ',$vv);
}
}
var_dump($fruits,$colors,$meats);
?>
I used a construct in PHP called variable variables. This is actually an almost identical answer as the one #Lohardt gave. I hope this can help you out. If it doesn't then post me a comment
You could do something like:
<input type="checkbox" value="apple" name="groups[fruits][]" />
<input type="checkbox" value="apple" name="groups[colors][]" />
<input type="checkbox" value="apple" name="groups[meats][]" />
Your $_POST will look like this:
Array
(
[groups] => Array
(
[fruits] => Array
(
[0] => apple
)
[colors] => Array
(
[0] => red
)
)
)
And it should be simple to use a foreach loop to get the keys and values.
Edit: then you can assign the value to variables like this:
${$key} = $value;
and use it you would do any variable:
echo $color;
So I am trying to email the results of a form using PHP. inside my form I have a bunch of checkboxes. The script below works when at least 1 checkbox in a group is checked. If none of the checkboxes are checked I receive the following error:
Warning: Implode() [function.implode]: Invalid augments passed in {name of php doc} on line {xxx} Array
Here is a sample of the code I'm using:
<?php
$data = array();
foreach ($_POST as $key => $value) {
$data[] = $value;
}
if(!$data[14]) //$data[14] is an array of checkbox values
{echo 'No User Selection';}
else
{echo implode(" | ", $data[14]);} //This is where the error occurs
?>
HTML code
<label for="b0" class="left">Item 1</label>
<input type="checkbox" name="b[0]" id="b0" value="Item 1"/>
<label for="b1" class="left">Item 2</label>
<input type="checkbox" name="b[1]" id="b1" value="Item 2"/>
<label for="b2" class="left">Item 3</label>
<input type="checkbox" name="b[2]" id="b2" value="Item 3"/>
ect....
Does anyone have an idea why I'm receiving this error?
Make sure the variable a) is set and b) is an array.
$data = array();
foreach ($_POST as $key => $value) {
$data[] = $value;
}
if ( !isset($data[14]) || !is_array($data[14]) ) {
echo 'No User Selection';
} else {
echo implode(" | ", $data[14]);
}
Always properly check variables using isset(), unless of course you like giant error logs! I also suggest using the $_POST keys as the keys for $data, thus making life even easier when you want to look up a specific $_POST item.
If the checkbox is not checked, it is not sent to the server.
I suggest you to do something like this:
<label for="b0" class="left">Item 1</label>
<input type="hidden" name="b[0]" value=""/>
<input type="checkbox" name="b[0]" id="b0" value="Item 1"/>
<label for="b1" class="left">Item 2</label>
<input type="hidden" name="b[1]" value=""/>
<input type="checkbox" name="b[1]" id="b1" value="Item 2"/>
<label for="b2" class="left">Item 3</label>
<input type="hidden" name="b[2]" value=""/>
<input type="checkbox" name="b[2]" id="b2" value="Item 3"/>
This way, you are sure that b[0], b[1], etc. are always sent
You are causing the problem yourself by making the data array. Just go straight to the POST array. Everything else is overcomplicating the problem.
<?php
if(!isset ($_POST['b']) || !is_array($_POST['b'])) {
echo 'No User Selection';
} else {
echo implode(" | ", $_POST['b']);
}
?>
In addition, if the content of your form changes slightly, or you want to reorder the fields then your magic number 14 will no longer work.
Your code will be unbelievably fragile unless you change it.
I have a form with a variable number of inputs. The inputs are inside the table and I need to get three values from them: the row, the column and the actual value inside the input.
Some may be populated some may not and I need all their values to update a mysql db (row and column to know what to update, value to know the new value to insert in the database).
This is my form (an example version of it):
<form method="post" action="">
<input name="data[111][222]" value="2" />
<input name="data[112][221]" value="0" />
<input name="data[113][223]" value="4" />
//goes on
<input name="data[324][435]" value="11" />
<input name="data[325][436]" value="" />
</form>
And that's as far as I go. How can I get the data from this form so I can do a simple update in my database that goes like this (for all the affected inputs):
update table set res="value_from_input" where row="row_value" and col="col_value"
<form method="post" action="">
<input name="data[111][222]" value="2" />
<input name="data[112][221]" value="0" />
<input name="data[113][223]" value="4" />
<input name="data[324][435]" value="11" />
<input name="data[325][436]" value="" />
<input type="submit" />
</form>
<?php
foreach ($_POST['data'] as $k1 => $v1)
{
foreach ($v1 as $k2 => $v2)
{
echo "<p>k1:".$k1."; k2: ".$k2."; value: ".$v2."</p>";
$query = "update table set res='$v2' where row='$k1' and col='$k2'";
mysql_query($query);
}
}
?>
foreach($_POST['data'] as $row => $row_array)
{
foreach($row_array as $col => $value)
{
// Sanitize all input data before entry
$mysql = "UPDATE table SET res='$value' WHERE row='$row' AND col='$col'";
}
}