PHP can not echo each array - php

Question

I can not echo each Array. Dont know what i am doing wrong. What would be the way to echo each Array? Have tried some ways like below to echo but no success.
function simple_social_sharing( $attr_twitter = null, $attr_items = null ) {
// parse variables
$twitter_account = $attr_twitter;
$item_toggles = $attr_items;
// get post content and urlencode it
global $post;
$browser_title_encoded = urlencode( trim( wp_title( '', false, 'right' ) ) );
$page_title_encoded = urlencode( get_the_title() );
$page_url_encoded = urlencode( get_permalink($post->ID) );
// create share items array
$share_items = array ();
// set each item
$item_facebook = array(
"class" => "facebook",
"href" => "http://www.facebook.com/sharer.php?u={$page_url_encoded}&t={$browser_title_encoded}",
"text" => "Share on Facebook"
);
$item_twitter = array(
"class" => "twitter",
"href" => "http://twitter.com/share?text={$page_title_encoded}&url={$page_url_encoded}&via={$twitter_account}",
"text" => "Share on Twitter"
);
$item_google = array(
"class" => "google",
"href" => "http://plus.google.com/share?url={$page_url_encoded}",
"text" => "Share on Google+"
);
// test whether to display each item
if($item_toggles) {
// explode into array
$item_toggles_array = explode( ",", $item_toggles );
// set each item on or off
$show_facebook = $item_toggles_array['0'];
$show_twitter = $item_toggles_array['1'];
$show_google = $item_toggles_array['2'];
}
else {
$display_all_items = 1;
}
// form array of items set to 1
if( $show_facebook==1 || $display_all_items ) {
array_push( $share_items, $item_facebook );
}
if( $show_twitter==1 || $display_all_items) {
array_push( $share_items, $item_twitter );
}
if( $show_google==1 || $display_all_items) {
array_push( $share_items, $item_google );
}
// if one or more items
if ( ! empty( $share_items ) ) {
// create output
$share_output = "<ul class=\"ss-share\">\n";
foreach ( $share_items as $share_item ) {
$share_output .= "<li class=\"ss-share-item\">\n";
$share_output .= "<a class=\"ss-share-link ico-{$share_item['class']}\" href=\"{$share_item["href"]}\" rel=\"nofollow\" target=\"_blank\">{$share_item['text']}</a>\n";
$share_output .= "</li>\n";
}
$share_output .= "</ul>";
// echo output
echo $share_output;
}
}
// add shortcode to output buttons
function simple_social_sharing_shortcode( $atts, $content = null ) {
// parse variables / set defaults
extract( shortcode_atts( array(
'twitter' => '',
'display' => '1,1,1',
), $atts ) );
// output buttons
ob_start();
simple_social_sharing( $twitter, $display );
$output_string = ob_get_contents();
ob_end_clean();
return force_balance_tags( $output_string );
}
Developers call function is not working too
<?php simple_social_sharing('twitteraccount', '1,1,1'); ?>
I have tried to call each Array by this way but it's wrong.
<?php simple_social_sharing([1]); ?>

Answer 1

Down towards the bottom you have this snippet in your foreach block:
... href=\"{$share_item["href"]}\" ...
The double quotes around href are going to cause you a problem.
You need to have it as
... href=\"{$share_item['href']}\" ...

Answer 2

Function should RETURN values and does not ECHO it..
Instead of echo $share_output;, you should have it return $share_output;
Echo the function's return value (if array, then print_r it else echo it) to see output
<?php echo simple_social_sharing('twitteraccount', '1,1,1'); //NOTE THE 'echo' HERE.. ?>