Retrieve all values in my loop and format it to json - php

Question

I'm trying to build a page which queries my database and then formats output so another webservice/page can access the data.
Ideally I wanted to explore having the data in JSON format, but that is not working. The other problem I have which is more major than the JSON not working is, if I have 3 records in $reportsResult, only the last one is displayed.
Anyone with some help please. Oh do I also need to print_r for the external webpage to retrieve the data or is there a better way?
class Pupil {
public $FirstName = "";
public $LastName = "";
}
foreach($reportsResult->getRecords() as $reportRecord) {
$Pupil = new Pupil();
$Pupil->FirstName = $reportRecord->getField('FName');
$Pupil->LastName = $reportRecord->getField('SName');
}
json_encode($Pupil);
OK managed to figure out how how to get all records from the loop, but its still not displaying in json format when I do a print_r - am I missing something?
$AllPupils = array();
foreach($reportsResult->getRecords() as $reportRecord)
{
$Pupil = new Pupil();
$Pupil->FamID = $reportRecord->getField('FName');
$Pupil->ChildName = $reportRecord->getField('SName');
array_push($AllPupils, $Pupil);
}
json_encode($AllPupils);

Answer 1

Everytime your foreach loop starts again, it will override your $Pupil variable.
Try an array instead:
$Pupil = array()
$i = 0;
foreach($reportsResult->getRecords() as $reportRecord) {
$Pupil[$i] = new Pupil();
$Pupil[$i]->FirstName = $reportRecord->getField('FName');
$Pupil[$i]->LastName = $reportRecord->getField('SName');
$i++;
}
echo json_encode($Pupil);
Edit: mikemackintosh's solution should also work and could be a little bit faster (depending on the size of your foreach loop).
To display the results you need to echo your data (not only json_encode).

Answer 2

You will probably run into issues since json_encode wont handle the whole object. for that, you may want to serialize the $Pupil object.
Something like below may work for you though. It will assign the values to a returned array, which will allow json_encode to execute gracefully:
class Pupil {
public $FirstName = "";
public $LastName = "";
public function getAttr(){
return array("FirstName" => $this->FirstName, "LastName" => $this->LastName);
}
}
$json = array();
foreach($reportsResult->getRecords() as $reportRecord) {
$Pupil = new Pupil();
$Pupil->FirstName = $reportRecord->getField('FName');
$Pupil->LastName = $reportRecord->getField('SName');
$json[] = $Pupil->getAttr();
}
echo json_encode($json);

Answer 3

I am not sure why you have that class defined, but you know what in your for each have something like
foreach ($reportsResult->getRecords() as $key => $record) {
$data[$key]['firstname'] = $record->getField('Fname');
$data[$key]['lastname'] = $record->getField('Sname');
}
And then you can check the final array using print_r
and while output you can simply do a print json_encode($data) and it will give you a json string of all the items in the data array.

Answer 4

In php (at least), json_encode takes an array as parameter.
Therefore you should add a constructor to your class
function __construct($first, $last)
{
this.$FirstName = $first;
this.$LastName = $last;
}
and one for getting the full name as an array, ready to be jsoned
function getNameArray()
{
$nameArray = array();
$nameArray['firstName'] = this.$FirstName;
$nameArray['lastName'] = this.$LastName;
return $nameArray;
}
then in that foreach you build another array with all the pupils
$pupils = array();
foreach (bla bla)
{
$first = $reportRecord->getField('FName');
$last = $reportRecord->getField('SName');
$Pupil = new Pupil($first, $last);
array_push($pupils, $pupil.getNameArray());
}
finally, you have everything preped up
json_encode($pupils);
I'm sure there's other ways to debug your stuff, I use print_r mainly also.