Prevent JQuery Timepicker from displaying using beforeShow - php

I'm trying to find out the solution of this one but I am not able to find anything yet.There is beforeShow properties for timepicker. What I want to achieve is, before showing up the timepicker I want to do some validation. If the validation is passed, then the timepicker will come up, but if it is fail, then the timepicker will not pop up. How can I achieve this? I tried to put
beforeShow: function(){return false},
but nothing happens
EDIT:
I came across a solution said that remove that field and replace with a new one. Tt works, the timepicker is not showing up anymore. But, if the validation is passed, that field must can be used again. Now i can't. It seems like the text field is not replace with the correct one. Because when I alert the parentNode, it is getting the <td> node, not the <form> node. I put that form in the table. My JS code:
$('input[id^=timepicker]').timepicker({beforeShow: function(instant){
if(!validation){ //validation fail
var element = document.getElementById(instant.id);
var clonedElement = element.cloneNode(true);
var parentElement = element.parentNode;
parentElement.replaceChild(clonedElement, element);
else{
$("#"+instant.id).timepicker();
}
}
});
My HTML is like
<form>
<table>
<tr><td><input type="text" id="timepicker1" name="tp" readonly="true"/></td></tr>
</table>
</form>

Trt this ;
$('.timepicker').timepicker({
beforeShow: function(){
var validation = true;
if(validation){
$.timepicker.hide();
//this one should not be display since there is an error
}
}
});

Related

Jquery - How to get current input value from a repeating from

I have a comment system in which i want to add delete option, for this i have implemented a POST form in each comment which posts comment-id to delete.php, it is working in php, but not in jquery.
i.e in order to delete comment a comment id must be posted to delete.php file which handles deletion of comment from database.
i am trying to fetch that comment-id from input value to post with jquery like this but it gives me the first comment-id value not the selected value.
Jquery
$('form[name=comments]').submit(function(){
var comment_delete = $("input[name=comment-delete]").val();
//$.post('../../delete.php', {value1:comment_delete}, function(data){alert('deleted')});
alert(comment_delete);
return false;
});
repeating form is like this
<form name="comments" action="../../delete.php" method="post">
<input name="comment-delete" type="hidden" value="<?php echo $list['comment-id']; ?>" />
<input value="Delete" type="submit" />
</form>
if i use .each() or .map() it gives me all the comment-id values.
Please see and suggest any possible way to do this.
Thanks.
To find the relevant input, that is the one of the form you submit, you could use this :
$('form[name=comments]').submit(function(){
var comment_delete = $(this).find("input[name=comment-delete]");
BTW, I'm not totally sure of what you do but you might be missing a .val() to get the value of the input.
You have the same name on each hidden input, naturally you get all those inputs as you have not targeted the correct form when doing:
$("input[name=comment-delete]");
"this" whould point to the form inside your submit function. Try this.
$('form[name=comments]').submit(function(){
var comment_delete = $(this).find("input[name=comment-delete]");
//$.post('../../delete.php', {value1:comment_delete}, function(data){alert('deleted')});
alert(comment_delete);
return false;
});
As dystroy said, you are probably missing .val().
var commentId = $(this).find("input[name=comment-delete]").val();
try this
$('form[name=comments]').submit(function(){
var comment_delete = $("input[name=comment-delete]", this);
//$.post('../../delete.php', {value1:comment_delete}, function(data){alert('deleted')});
alert(comment_delete);
return false;
});
this refers to the form being submitted (more generally, to the event source).
$(...) accepts a second parameter, which is then used as a context for the selector. $(selector, context) is equivalent to $(context).find(selector)

Collect checkbox values in jQuery and POST them on submit

I've referred to this post:
Post array of multiple checkbox values
And this jQuery forum post:
http://forum.jquery.com/topic/checkbox-names-aggregate-as-array-in-a-hidden-input-value
I am trying to collect an array (or concatenated string with commas, whatever) of checkbox values in a hidden input field using jQuery. Here's the script code I'm using:
<script type="text/javascript">
$("#advancedSearchForm").submit(function() {
var form = this;
$(form).find("input[name=specialty]").val(function() {
return $("input:checkbox",form).map(function() {
return $(this).attr("name");
}).get().join();
});
});
</script>
A snippet of the relevant HTML:
<form id="advancedSearchForm" name="advancedSearchForm" method="post" action="<?php echo site_url('/magcm/advancedSearch#results'); ?>">
<input type="checkbox" name="FCM" id="FCM" class="chk" value="FCM" <?php echo set_checkbox('FCM', 'FCM'); ?>/>
<input type="hidden" name="specialty" id="specialty" value="" />
<input class="button" name="submit3" id="submit3" type="submit" value="Search" />
I've tried changing "submit" to "submit3" in the jQuery, which breaks (obviously). When I print_r($_POST), the checkboxes POST correctly but the condensed hidden variable does not. (It posts, but a blank value.) The checkboxes persist correctly using CI's hacked set_value() function (Derek needs to implement this in the main trunk... but that's another story)
I'm sure I'm doing something that is wrong and easy to point out. I've just been banging my head against the wall for the past 2 hours on it, trying various functions and changing a ton of things and analyzing it in Chrome dev tools (which don't show any errors).
Help is appreciated. :)
Let's say you applied an class, maybe "tehAwesomeCheckboxen" to every checkbox. Then
<script>
$("#advancedSearchForm").submit(function() {
var chkbxValues = $(".tehAwesomeCheckboxen").val();
$("#specialty").val( chkbxValues.join(",") );
});
</script>
EDIT:
I don't think the $_POST array is getting populated, since the submit is being handled locally by the JavaScript engine. SO... let's try this:
<script>
var chkbxValues = new Array();
$(".tehAwesomeCheckboxen").live("change", function(e){
var val = $(this).val();
if( $(this).is(":checked") ) {
if( chkbxValues.length == 0 || chkbxValues.indexOf(val) == -1){
// Add the value
chkbxValues.push(val);
}
}
else {
// remove the value
chkbxValues.splice( chkbxValues.indexOf(val), 1 );
}
$("#specialty").val( chkbxValues.join(",") );
});
</script>
This adds an event handler the checkboxes themselves, such that checking/unchecking the box alters the hidden element. Then your form handles its submission as normal.
Is this more in line with what you're trying to do?
P.S. Those who upvoted this, please note I have modified my answer. Please verify whether you still find it useful and adjust your vote accordingly.
I ended up solving it using PHP arrays rather than jQuery:
<input type="checkbox" name="chk[]" id="RET" class="chk" value="RET" <?php echo set_checkbox('chk', 'RET'); ?>/>
I changed the name to an array and POSTed it to my script, where I looped through the array and handled it there. Still not sure what the problem was with the jQuery-based solutions, but I figured I'd post this for everyone to refer to in the future.
You've got lots of nested functions() in your JavaScript, makes it hard to follow what you're doing.
However, it seems that you're just passing a function to .val() rather than an actual value. Try this instead:
<script type="text/javascript">
$("#advancedSearchForm").submit(function() {
var form = this;
$(form).find("input[name=specialty]").val((function() {
return $("input:checkbox",form).map(function() {
return $(this).attr("name");
}).get().join();
})());
});
</script>
Or even better, calculate the value first:
<script type="text/javascript">
$("#advancedSearchForm").submit(function() {
var form = this;
var value = $("input:checkbox",form).map(function() {
return $(this).attr("name");
}).get().join();
$(form).find("input[name=specialty]").val(value);
});
</script>

If checkbox changes, use jquery to call php

I have a simple checkbox on a page that allows a user to say if they'd like to receive email notifications. I am using jquery for this to call some php code when the checkbox changes. However, I am not having much luck even calling the jquery function (clicking the checkbox does nothing) let alone test the backend functionality.
Any help in pointing out the error would be great. Thanks.
The checkbox HTML:
<input id="notify_checkbox" type="checkbox" value="y" name="notify">
The jquery:
$('#notify_checkbox').change(function(){
if($('#notify_checkbox').attr('checked'))
{
$.post("/update_notify", { checked: "y", email: "<?php echo $this->session->userdata('email');?>" });
$( "#notifyresult" ).html( "<p>Awesome, we'll send you an email!</p>" );
}
else
{
$.post("/update_notify", { checked: "n", email: "<?php echo $this->session->userdata('email');?>" });
$( "#notifyresult" ).html( "<p>Okay, we won't email you.</p>" );
}
});
And finally the PHP:
function update_notify()
{
// Passed through AJAX
$notify = $_POST[checked];
$email = $_POST[email];
$this->load->model('musers');
$query = $this->musers->update_user_notify($email, $notify);
}
RESOLUTION: The comments below were helpful but not the ultimate solution. The solution was to add the following around my code.
$(document).ready(function() {
{);
Why not use .click() instead?
JSFIDDLE
Also, as you can see in my JSFiddle example, use .is(':checked') instead of attr('checked').
edit after #Rocket commented on your post:
You should indeed quote your $_POST values in your php! Didn't notice it myself, credits to rocket
What's the name of your controller? You need to put that in the URL.
$.post("/controller/update_notify", ...
The problem is with the redefinition of the attr function in jQuery 1.6, and with the difference between attributes and properties.
With attributes (retrieved with attr), the value of checked="checked" or its absence stays the same, regardless of whether the element is actually checked or not.
With properties (retrieved with prop as of jQuery 1.6), the actual state of the element is found. This is equivalent to checking the checked property of the element (which is preferable because you don't need to do a new jQuery selection). The best soltion would be as follows:
if (this.checked) {
See jsFiddles showing this:
your current solution
using prop
using this.checked

Check in ajax/jquery a form beform submit ( check the value whether it is in database)

ajax is not yet sothin i master.
I have two forms field
code :
name :
and the submit button like :
<form><input type=text name=code><input type =text name=name/></form>
I would like in php/jquery to check if the code the user fill exist in a table of my db.
If it does not exits, when the user leave the textfield to fill the next one, i would like to print a message like: this code is not in the db and then clean the fied. Until the user provide a valide code.
If your php service returns true or false for validation.
and the placeholder for the error is a label called
then an example (in jQuery) would be
$(document).ready(function() {
$("form").submit(function(e) {
var code = $("input[name='code']");
var error = $("#error");
e.preventDefault();
var form = this;
$.getJSON('urlToPhp',
{ code: code.val() },
function(valid) {
if (!valid) {
error.text(code.val() + ' is not found try another code...');
code.val('');
} else {
form.submit();
}
}
);
});
});
I've created a simple example at http://jsfiddle.net/nickywaites/e4rhf/ that will show you have to create a jQuery ajax post request.
I'm not too familiar with php so that part of it I'll have to leave aside although you can use something along the lines of $_POST["Name"].
Here is php example that I googled http://php4every1.com/tutorials/jquery-ajax-tutorial/ that might be better for you.

Form is removed from AJAX response

I'm trying to add a table row with ajax/jquery that has a form element in it. Everything works just fine if I set it without the ajax, but somehow everything inside the <form> tag is just completely lost.
I'm not sure where I'm losing the form (jquery's .html() is effectively the same as innerHTML right? If that's the case I suspect that's where I'm losing it).
Anyway, here's some code:
var worow = document.getElementById('worow_' + row);
var wotable = document.getElementById('tbl_workorders');
// add a new row to the table underneath our existing row.
var newrow = wotable.insertRow(worow.rowIndex+1);
var x = newrow.insertCell(0);
// set up the row a little bit
x.colSpan = 13;
x.style.padding = '10px';
x.style.backgroundColor = '#ccc';
x.align = "center";
x.innerHTML = '<img src="/images/loading.gif" />';
// a little ajax cuz we're cool that way
$.post("getwotrans.php",
{
workorder: row
},
function(response)
{
// set the value of the row = response object from the AJAX
$(x).html(response);
});
And in getwotrans.php: (paraphrased)
<table>
<thead><tr><td>blahblah</td></tr></thead>
<tbody><form><tr><td><input></td></tr></form></tbody>
</table>
So what happens is I'll run the javascript function to add the row, and the row is added fine and I see the table headers, but the 'form' inside the tbody is just not there.
I had some simliar problem. I used a hidden form and javascript to copy the values of the row clicked to the hidden form elements and then submit the form via javascript. Maybe that's an idea.
a form cannot be a child element of tbody
What happens when you put the form outside of the table?
<form><table>
<thead><tr><td>blahblah</td></tr></thead>
<tbody><tr><td><input></td></tr></tbody>
</table></form>
Just curious if this will fix the issue or not? It is odd that this would happen without something equally odd to fix it!

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