jQuery / JSON / CodeIgniter - Form validation - php

Im trying to get starting with JSON and jQuery. I'm not a JavaScript programmer at all so I'm mixing and matching and having quite a few issues getting my code to work. I thought someone might be able to help me out.
I have a model which uses the following PHP code to check if an email address is registered with the system:
function is_email_available($email) {
$this->db->select('1', FALSE);
$this->db->where('LOWER(email)=', strtolower($email));
$this->db->or_where('LOWER(new_email)=', strtolower($email));
$query = $this->db->get($this->table_name);
return $query->num_rows() == 0;
}
The above code is being called by my ajax controller using the following, and if it is registered returns a json true or false
function email_availability() {
// Check to see if the username is available or taken
if ( $this->users->is_email_available( $this->input->post('emailaddress'))) {
echo json_encode(TRUE);
} else {
echo json_encode(FALSE);
}
}
The above is called from my JS file using the following jQuery, but it doesn't seem to be working at all.
if(iEmail.val()) {
$.ajax({
url: '/ajax/email_availability',
data: 'emailaddress=' + iEmail.val(),
dataType: 'json',
type: 'post',
success: function(msg) {
iEmail.next('.error').text('This Email Address is not registered');
error = true;
}
});
}
I think my jQuery is completely off but can't figure it out. Any help would be greatly appreciated.

You didn't really check if the result was true or false.
success: function(msg) {
if (msg){
//email is available
}
else{
//email is not available
}
}

Related

Call a php function in MVC using AJAX?

I am currently migrating an already built web application to MVC, and I'm figuring out that I'm too newbie to do some kind of changes. There are some ajax calls that are freaking me out. I'll try to be as clear as possible, but due to my inexperience I'm not sure if I won't let some important information by the way.
The point is in the old application, things go this way:
In the php code:
if ($action_user == 'show_alerts') {
$list = array();
$query = "SELECT alert_type FROM alert_contact WHERE NOT
deleted AND user_email=" . typeFormat($email);
$result = mysqli_query($db, $query) or die('Error in query "'.$query . '": ' . mysqli_error($db));
while ($db_field = mysqli_fetch_assoc($result)) {
$list[] = $db_field['alert_type'];
}
echo json_encode($list);
In the jquery code:
$.ajax({
type: 'POST',
url: 'userpost.php',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json'
Here comes my problem, and since I don't have an userpost.php file anymore, I have to send it to the index.php and call my users component by a get petition, which I don't like, but I coudn't find another way to do it. And, what is even worse, I don't know at all how ajax is getting the variables that it needs. It must be a pretty basic mistake, but I recognize my skills at this point are't so good. That's what I'm doing in my version:
In the php code:
if ($action_user == 'show_alerts') {
$list = ModelUser::getAlertContact($act_email);
echo json_encode($list);//I predict that ajax don't reach this line, but not sure
}
In the jquery code:
$.ajax({
type: 'POST',
url: 'index.php?option=users',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json',
success: function(data) {
alert ('gotcha');
$.each(alertsarray, function(index, value) {
if ($.inArray(value, data) === -1) {
$("#sub" + value).prop("checked", false);
$('#alert' + value).removeClass("list_alert_sub");
}
else {
$("#sub" + value).prop("checked", true);
$('#alert' + value).addClass("list_alert_sub");
}
});
},
error: function(data) {
alert("¡Error (ajax)!");
}
});
Any help would be appreciated, and if there's some more information I've missed, please let me know. Thanks in advance.
UPDATE:
I've been making some progress but don't seem to find a real solution. Now I know that the url has to be the controller, so I'm using 'components/userpost/controller.php' as it, and it reaches the ajax call, cause the success alert is showing up. The problem is the MVC way, because I send ajax to the controller, but since I don't have a reload in the page, all the includes are failing so they are obviously not being loaded, and I'm getting errors like this:
PHP Warning: include(components/userpost/model.php): failed to open
stream: No such file or directory in
/var/www/html/viewer_mvc/components/userpost/controller.php on line 3,
referer: http://localhost/viewer_mvc/index.php
Really hope you guys can show me where am I failing, and if there's a special way to do these thing in MVC.
For the JQuery call it makes a POST request to index.php?option=users with JSON data. The form with the ID userForm is serialized using the Jquery serialize method.
The .serialize() method creates a text string in standard URL-encoded notation. It can act on a jQuery object that has selected individual form controls
$.ajax({
type: 'POST',
url: 'index.php?option=users',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json'
Now for your PHP sample
if ($action_user == 'show_alerts') {
$list = ModelUser::getAlertContact($act_email);
echo json_encode($list);//I predict that ajax don't reach this line, but not sure
}
This code will be looking for variables that probably don't exist anymore if it is a different file i.e. is there an $action_user variable?
To start reimplementing it you will need to add the logic so that it checks the POST variable if your not using the framework code. So if you have a form element with the name 'name' then that will be available in your PHP script POST variable
$_POST['name']
[How to call a PHP function in MVC using AJAX]
$.ajax({
type: 'POST',
url: 'save-user.php',
data: { fname: "manish", email: "manishkp#com", role:"admin"},
success: function(data) {
console.log(data);
if(data == 'error')
{
$('#Register_error').text('Must Be filled...');
$('#Register_error').show();
}
else {
$('#Register_error').hide();
$('#Register_success').text('Successfully submit');
$('#Register_success').show();
}
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<?php
$fname = $_POST['fname'];
$email = $_POST['email'];
$role = $_POST['role'];
if(!empty($fname) && !empty($email) && !empty($role))
{
#MYSQL CONNECTION QUERY #
echo"success";
}
else{
echo "error";
}
?>

Ajax returning object instead of data

What is the correct way to handle Ajax success callback events using jquery?
In my code, when I run instead of displaying data, it alerts object:object. However, if I use say msg.box it returns the data correctly.
I am trying to create an if statement where if text equals a certain word then the variable from json is placed in the html of the result div BA_addbox.
I cannot seem to get this to work and would be grateful if someone could point out my error. I have only included the relevant code as the form is posting the correct data and the php code is catching all the posts. Many thanks.
ajax code
$.ajax({
type: "POST",
url: "/domain/admin/requests/boxes/boxesadd.php",
data: formdata,
dataType: 'json',
success: function(msg){
if(msg == "You need to input a box") {
$("#BA_addbox").html(msg.boxerrortext);
}
else {
$("#BA_addbox").html(msg.box);
}
//alert(msg);
console.log(msg);
//$("#BA_addbox").html(msg.box);
//$("#formImage .col_1 li").show();
//$("#BA_boxform").get(0).reset();
//$("#boxaddform").hide();
}
});
boxesadd.php
$box = mysql_real_escape_string($_POST['BA_box']);
$boxerrortext = "You need to input a box";
if (isset($_POST['submit'])) {
if (!empty($box)) {
$form = array('dept'=>$dept, 'company'=>$company, 'address'=>$address, 'service'=>$service, 'box'=>$box, 'destroydate'=>$destroydate, 'authorised'=>$authorised, 'submit'=>$submit);
$result = json_encode($form);
echo $result;
}
else
{
$error = array('boxerrortext'=>$boxerrortext);
$output = json_encode($error);
echo $output;
//echo "You need to input a box";
}
}
In javascript associative arrays are called objects, so there's no bug in the transmitted data.
Why do you compare msg to "You need to input a box"? You cannot compare object and string, this makes no sense.
if(typeof msg.boxerrortext !== "undefined" && msg.boxerrortext == "You need to input a box") {
$("#BA_addbox").html(msg.boxerrortext);
} else {
$("#BA_addbox").html(msg.box);
}
Try this instead:
if(msg.boxerrortext) {
$("#BA_addbox").html(msg.boxerrortext);
}
else {
$("#BA_addbox").html(msg.box);
}
Hope this will help !!

Sending data with AJAX to a PHP file and using that data to run a PHP script

I'm currently trying to make live form validation with PHP and AJAX. So basically - I need to send the value of a field through AJAX to a PHP script(I can do that) and then I need to run a function inside that PHP file with the data I sent. How can I do that?
JQuery:
$.ajax({
type: 'POST',
url: 'validate.php',
data: 'user=' + t.value, //(t.value = this.value),
cache: false,
success: function(data) {
someId.html(data);
}
});
Validate.php:
// Now I need to use the "user" value I sent in this function, how can I do this?
function check_user($user) {
//process the data
}
If I don't use functions and just raw php in validate.php the data gets sent and the code inside it executed and everything works as I like, but if I add every feature I want things get very messy so I prefer using separate functions.
I removed a lot of code that was not relevant to make it short.
1) This doesn't look nice
data: 'user=' + t.value, //(t.value = this.value),
This is nice
data: {user: t.value},
2) Use $_POST
function check_user($user) {
//process the data
}
check_user($_POST['user'])
You just have to call the function inside your file.
if(isset($_REQUEST['user'])){
check_user($_REQUEST['user']);
}
In your validate.php you will receive classic POST request. You can easily call the function depending on which variable you are testing, like this:
<?php
if (isset($_POST['user'])) {
$result = check_user($_POST['user']);
}
elseif (isset($_POST['email'])) {
$result = check_email($_POST['email']);
}
elseif (...) {
// ...
}
// returning validation result as JSON
echo json_encode(array("result" => $result));
exit();
function check_user($user) {
//process the data
return true; // or flase
}
function check_email($email) {
//process the data
return true; // or false
}
// ...
?>
The data is send in the $_POST global variable. You can access it when calling the check_user function:
check_user($_POST['user']);
If you do this however remember to check the field value, whether no mallicious content has been sent inside it.
Here's how I do it
Jquery Request
$.ajax({
type: 'POST',
url: "ajax/transferstation-lookup.php",
data: {
'supplier': $("select#usedsupplier").val(),
'csl': $("#csl").val()
},
success: function(data){
if (data["queryresult"]==true) {
//add returned html to page
$("#destinationtd").html(data["returnedhtml"]);
} else {
jAlert('No waste destinations found for this supplier please select a different supplier', 'NO WASTE DESTINATIONS FOR SUPPLIER', function(result){ return false; });
}
},
dataType: 'json'
});
PHP Page
Just takes the 2 input
$supplier = mysqli_real_escape_string($db->mysqli,$_POST["supplier"]);
$clientservicelevel = mysqli_real_escape_string($db->mysqli,$_POST["csl"]);
Runs them through a query. Now in my case I just return raw html stored inside a json array with a check flag saying query has been successful or failed like this
$messages = array("queryresult"=>true,"returnedhtml"=>$html);
echo json_encode($messages); //encode and send message back to javascript
If you look back at my initial javascript you'll see I have conditionals on queryresult and then just spit out the raw html back into a div you can do whatever you need with it though.

jQuery JSON PHP Request

I've been trying to figure out what I have done wrong but when I use my JavaScript Console it shows me this error : Cannot read property 'success' of null.
JavaScript
<script>
$(document).ready(function() {
$("#submitBtn").click(function() {
loginToWebsite();
})
});
</script>
<script type="text/javascript">
function loginToWebsite(){
var username = $("username").serialize();
var password = $("password").serialize();
$.ajax({
type: 'POST', url: 'secure/check_login.php', dataType: "json", data: { username: username, password: password, },
datatype:"json",
success: function(result) {
if (result.success != true){
alert("ERROR");
}
else
{
alert("SUCCESS");
}
}
});
}
</script>
PHP
$session_id = rand();
loginCheck($username,$password);
function loginCheck($username,$password)
{
$password = encryptPassword($password);
if (getUser($username,$password) == 1)
{
refreshUID($session_id);
$data = array("success" => true);
echo json_encode($data);
}
else
{
$data = array("success" => false);
echo json_encode($data);
}
}
function refreshUID($session_id)
{
#Update User Session To Database
session_start($session_id);
}
function encryptPassword($password)
{
$password = $encyPass = md5($password);
return $password;
}
function getUser($username,$password)
{
$sql="SELECT * FROM webManager WHERE username='".$username."' and password='".$password."'";
$result= mysql_query($sql) or die(mysql_error());
$count=mysql_num_rows($result) or die(mysql_error());
if ($count = 1)
{
return 1;
}
else
{
return 0;;
}
}
?>
I'm attempting to create a login form which will provide the user with information telling him if his username and password are correct or not.
There are several critical syntax problems in your code causing invalid data to be sent to server. This means your php may not be responding with JSON if the empty fields cause problems in your php functions.
No data returned would mean result.success doesn't exist...which is likely the error you see.
First the selectors: $("username") & $("password") are invalid so your data params will be undefined. Assuming these are element ID's you are missing # prefix. EDIT: turns out these are not the ID's but selectors are invalid regardless
You don't want to use serialize() if you are creating a data object to have jQuery parse into formData. Use one or the other.
to make it simple try using var username = $("#inputUsername").val(). You can fix ID for password field accordingly
dataType is in your options object twice, one with a typo. Remove datatype:"json", which is not camelCase
Learn how to inspect an AJAX request in your browser console. You would have realized that the data params had no values in very short time. At that point a little debugging in console would have lead you to some immediate points to troubleshoot.
Also inspecting request you would likely see no json was returned
EDIT: Also seems you will need to do some validation in your php as input data is obviously causing a failure to return any response data
Try to add this in back-end process:
header("Cache-Control: no-cache, must-revalidate");
header('Content-type: application/json');
header('Content-type: text/json');
hope this help !
i testet on your page. You have other problems. Your postvaribales in your ajax call are missing, because your selectors are wrong!
You are trying to select the input's name attribute via ID selector. The ID of your input['name'] is "inputUsername"
So you have to select it this way
$('#inputUsername').val();
// or
$('input[name="username"]').val();
I tried it again. You PHP script is responsing nothing. Just a 200.
$.ajax({
type: 'POST',
url: 'secure/check_login.php',
dataType: "json",
data: 'username='+$("#inputUsername").val()+'&password='+$("#inputPassword").val(),
success: function(result) {
if (result.success != true){
alert("ERROR");
} else {
alert("HEHEHE");
}
}
});
Try to add following code on the top of your PHP script.
header("Content-type: appliation/json");
echo '{"success":true}';
exit;
You need to convert the string returned by the PHP script, (see this question) for this you need to use the $.parseJSON() (see more in the jQuery API).

php validation using jquery and ajax

i have a jquery ajax form.
i have validation at server side for repeated username and email ID.
which works fine without jquery/ajax.
in my php code i have used die() to return if any error occurs. my main problem is at ajax
here is the code
$(document).ready(function () {
$("form#regist").submit(function () {
var str = $("#regist").serialize();
$.ajax({
type: "POST",
url: "submit1.php",
data: $("#regist").serialize(),
success: function () {
$("#loading").append("<h2>you are here</h2>");
}
});
return false;
});
});
The success function works properly. if my data is valid then it is added in the db, if my data is repeated then it is not added in the db. Now what i want to know is how do i return the error from my php file and use it at success event. Thanks in advance..
edit : this is how my php script looks
$query = "SELECT username from userdetails WHERE username = '$username'";
$q = mysql_query($query) or die("error" . mysql_error());
$numrows = mysql_num_rows($q);
if($numrows > 0)
{
die("username already exixt");
//should i put something like this
//$error = "username already exists";
//return $error; --->> i am not sure about this..
}
thanks in advance
Php side:
if($numrows > 0)
{
echo "username already exist";
}
Javascript side:
success: function(msg)
{
if(msg == 'username already exist') alert(msg);
}
But this is so crude, If you plan to develop this further try to read some articles on JSON, so you can use json to communicate to server side. And also you should try to use some default error controlling, like return an array with php:
echo json_encode(array('error' => true, 'notice' => 'username exists'));
Then on the javascript side (jquery), use json ajax request and always check if error variable is true or not, if it is maybe you can use a default function for error controlling.
Hope this helped.
In the function definition which you have done like:
success: function(){
introduce a parameter like: success: function(retVal){
Now in the function you can check for the value of retVal.
Say, you return from your PHP script, "successful" for success case and "this email exists" for failure.
Now you can directly compare this here and do whatever you want to, like:
if(retVal == 'this email exists')
{
window.alert('please re-enter the email, this record exists!');
}
and so on...
Hope this helps.
$(document).ready(function () {
$("form#regist").submit(function () {
var str = $("#regist").serialize();
$.ajax({
type: "POST",
url: "submit1.php",
data: $("#regist").serialize(),
success: function (msg) {
alert(msg);
}
});
return false;
});
});
Here from server side send the message and show it, how i have shown it :)

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