I have the following block of code which is expected to return the count
$sql = "SELECT sum(count) as count
FROM multipleowners WHERE owner = ? " . $localityquery;
$queryarray = array($owner, $locality);
$query = $this->db->query($sql, $queryarray);
if ($query->num_rows() > 0)
{
$result = $query->row_array();
$count = $result['count'];
}
But I am getting empty values when i try to print $count.
I have used print_r($this->db->last_query()); and I got the following query,
SELECT sum(count) as count FROM multipleowners WHERE owner = 'Davenports Harbour Trustee (2012) Limited' and locality = 'Auckland Central'
When I executed this query directly onto my Postgresql IDE i got the output of count as 2.
What and where could this query be gone wrong ? I doubt the existence of ( and ) in the WHERE clause. How do I fix this ?
Update
When I enabled the profiler I got the following query,
SELECT sum(count) as count
FROM multipleowners WHERE owner = 'Davenports Harbour Trustee (2012) Limited' and locality = 'Auckland Central'
So obviously the problem exists on the ( and ) !!
Bingo!! I have added the following line before I passed the variable $owner to the query and it worked,
$owner = html_entity_decode($owner);
Have you tried doing select sum(db.[count] as icount because in the language count could be a reserved word as well. so bracket the field or rename it, try to not name the new output as count..
Related
i have this code
$opslaglimit = 5;
$fag = "dansk";
$fagquery = "%".ucfirst($fag)."%";
$fagopslag = $db->prepare("
SELECT
*,
teacher_opslag.id as mainid,
teacher_opslag.created AS opslagcreated,
teacher_opslag.subject AS opslagsubject,
teacher_opslag.deleted AS maindeleted
FROM
teacher_opslag
WHERE
teacher_opslag.subject LIKE ?
ORDER BY
teacher_opslag.id DESC
LIMIT
$opslaglimit
");
$fagopslag->bind_param("s", $fagquery);
$fagopslag->execute();
$fagresult = $fagopslag->get_result();
$ensuranced = $fagresult->num_rows;
The query should select all data where dansk is present from the table. one of my rows might look like this Dansk_Engelsk_Svensk. The num_rows returns 0.
It is the first time i use LIKE in a WHERE clause. I dont know why it returns 0 when i have 3 matching rows in the db.
please help, thanks
I need to get number of rows from table as string.
I execute this code:
$phql = "SELECT COUNT(*) FROM Model WHERE id = $this->id";
$count = $this->getModelsManager()->createQuery($phql)->execute();
Now $count is Phalcon\Mvc\Model\Resultset\Complex object. To get a proper result I need to do something like that:
$count[0]->{0}
In my opinion this is awful. Is there any other way to get this result?
Few solutions:
1) Use simple queries:
$count = $this->db->fetchOne('SELECT COUNT(*) AS total FROM products');
2) Model aggregations
$count = Products::count(
"area = 'Testing'"
);
More info and methods: https://docs.phalconphp.com/ar/3.2/db-models in section Generating Calculations
3) If you insist of using executeQuery() you should add getFirst() in order to get only one result. Similar to PDO's fetchOne().
$phql = "SELECT COUNT(*) AS total FROM Models\Products";
$count = $this->modelsManager->executeQuery($phql)->getFirst();
I am trying to get single rank for a user for each stat "column" in the table. I am trying to do this as more efficiently because i know you can.
So I have a table called userstats. in that table i have 3 columns user_id, stat_1, stat_2, and stat_3. I want to me able to get the rank for each stat for the associated user_id. with my current code below i would have to duplicate the code 3x and change the column names to get my result. please look at the examples below. Thanks!
this is how i currently get the rank for the users
$rankstat1 = getUserRank($userid);
<code>
function getUserRank($userid){
$sql = "SELECT * FROM ".DB_USERSTATS." ORDER BY stat_1 DESC";
$result = mysql_query($sql);
$rows = '';
$data = array();
if (!empty($result))
$rows = mysql_num_rows($result);
else
$rows = '';
if (!empty($rows)){
while ($rows = mysql_fetch_assoc($result)){
$data[] = $rows;
}
}
$rank = 1;
foreach($data as $item){
if ($item['user_id'] == $userid){
return $rank;
}
++$rank;
}
return 1;
}
</code>
I believe there is a way for me to get what i need with something like this but i cant get it to work.
$rankstat1 = getUserRank($userid, 'stat_1'); $rankstat2 =
getUserRank($userid, 'stat_2'); $rankstat3 = getUserRank($userid,
'stat_3');
You can get all the stat ranks using one query without doing all the PHP looping and checking.
I have used PDO in this example because the value of the $userid variable needs to be used in the query, and the deprecated mysql database extension does not support prepared statements, which should be used to reduce the risk of SQL injection.
The function could be adapted to use the same query with mysqli, or even mysql if you must use it.
function getUserRanks($userid, $pdo) {
$sql = "SELECT
COUNT(DISTINCT s1.user_id) + 1 AS stat_1_rank,
COUNT(DISTINCT s2.user_id) + 1 AS stat_2_rank,
COUNT(DISTINCT s3.user_id) + 1 AS stat_3_rank
FROM user_stats f
LEFT JOIN user_stats s1 ON f.stat_1 < s1.stat_1
LEFT JOIN user_stats s2 ON f.stat_2 < s2.stat_2
LEFT JOIN user_stats s3 ON f.stat_3 < s3.stat_3
WHERE f.user_id = ?"
$stmt = $pdo->prepare($sql);
$stmt->bindValue(1, $userid);
$stmt->execute();
$ranks = $stmt->fetchObject();
return $ranks;
}
This should return an object with properties containing the ranks of the given user for each stat. An example of using this function:
$pdo = new PDO($dsn, $user, $pw);
$ranks = getUserRanks(3, $pdo); // get the stat ranks for user 3
echo $ranks->stat_2_rank; // show user 3's rank for stat 2
$sql = "SELECT user_id, stat_1, stat_2, stat_3 FROM ".DB_USERSTATS." ORDER BY stat_1 DESC";
Also, unless there is a reason you need ALL users results, limit your query with a WHERE clause so you're only getting the results you actually need.
Assuming you limit your sql query to just one user, this will get that user's stats.
foreach($data as $item){
$stat_1 = $item['stat_1'];
$stat_2 = $item['stat_2'];
$stat_3 = $item['stat_3'];
}
If you get more than one user's stats with your sql query, consider passing your $data array back to the calling function and loop through the array to match the users stats to particular user id's.
I have a SELECT statement that pulls a limited number of items based on the value of one of the fields. (ie ORDER BY rate LIMIT 15).
However, I need to do some comparisons that and change the value of rate, and subsequently could alter the results that I want.
I could pull everything (without the LIMIT), alter the rate, re-sort, and then just process the number that I need. However, I don't know if it's possible to alter values in a php result array. I'm using:
$query_raw = "SELECT dl.dragon_list_id, dl.dragon_id, dl.dragon_name, dl.dragon_level, d.type, d.opposite, d.image, dr.dragon_earn_rate
FROM dragon_list dl
LEFT JOIN dragons d ON d.dragon_id = dl.dragon_id
LEFT JOIN dragon_rates dr ON dr.dragon_id = dl.dragon_id
AND dr.dragon_level = dl.dragon_level
WHERE dl.dragon_id IN (
SELECT dragon_id
FROM dragon_elements
WHERE element_id = 3
)
AND dl.dragon_list_id NOT IN (
SELECT dh.dragon_list_id
FROM dragon_to_habitat dh, dragon_list dl
WHERE dl.user_id = 1
AND dh.dragon_list_id = dl.dragon_list_id
AND dl.is_deleted = 0
)
AND dl.user_id = " . $userid . "
AND dl.is_deleted = 0
ORDER BY dr.dragon_earn_rate DESC, dl.dragon_name
LIMIT 15;";
$query = mysqli_query($link, $query_raw);
if (!$query) {
echo "DB Error, could not query the database\n";
echo 'MySQL Error: ' . mysqli_error($link);
exit;
}
$d = mysqli_fetch_array($d_query);
Well, after a lot of research and some trial and error I found my answers....
Yes, I CAN alter the result rows using something like:
$result['field'] = $newvalue;
I also learned I could reset the pointer by using:
mysqli_data_seek($d_query,0);
However, when I reset the counter, I lost the changes I made. So ultimately, I'm still a little stuck, but individually I had the answers.
I have a table containing 4 articles with id 1,2,3 and 4 as well as ordering value 1,2,3,4.
They have separate columns for their title, image etc. I need to get them distinctly with where clause. So i did:
For article 1:
//topstory1
$sql_topstory1 ="SELECT * FROM topstory WHERE story_active='1' && story_order='1'";
$result_topstory1 = mysql_query($sql_topstory1);
$row_topstory1 = mysql_fetch_array($result_topstory1);
$story1_title = $row_topstory1['story_title'];
$story1_abstract = $row_topstory1['story_text'];
And for article 2
//topstory2
$sql_topstory2 ="SELECT * FROM topstory WHERE story_active='1' && story_order='2'";
$result_topstory2 = mysql_query($sql_topstory2);
$row_topstory2 = mysql_fetch_array($result_topstory2);
$story2_title = $row_topstory2['story_title'];
$story2_abstract = $row_topstory2['story_text'];
As I have to reuse them in a page.
PROBLEM IS, the first query works but the second one doesn't. It seems like MySql cannot execute two consecutive queries on the same table in a single php file. But I think there is a simple solution to this...
Please help me soon :( Love you guys :)
There are several possible reasons for the second query to fail, but the fact that it's the second query in the file does not cause it to fail.
I would expect that article 2 does not have the active flag set to 1, causing you to get an empty result set.
Another option is that you may have closed the mysql connection after the first query, then you can't execute another query. (General rule: don't close database connections. PHP takes care of that.)
Why not just get them both with 1 query?
$sql_topstory ="SELECT * FROM topstory WHERE story_active='1' && story_order IN(1, 2) ORDER BY story_order DESC";
$result_topstory = mysql_query($sql_topstory) or trigger_error('Query Failed: ' . mysql_error());
while ($row = mysql_fetch_assoc($result_topstory)) {
$title[] = $row['story_title'];
$abstract[] = $row['story_abstract'];
}
// Then to display
echo 'Story 1 is ' . $title[0] . ' with an abstract of ' . $abstract[1];
There are plenty of ways to do this, this is just a simple demonstration.
$query = <<<SQL
SELECT
story_title
, story_text
FROM
topstory
WHERE
story_active
ORDER BY
story_order ASC
SQL;
$result = mysql_query($query);
$stories = array();
while ($row = mysql_fetch_assoc($result)) {
$stories[] = $row;
}
Now you have an array of stories like so:
array(
0 => array(
'story_title' => ?
, 'story_text' => ?
)
, 1 => array(
'story_title' => ?
, 'story_text' => ?
)
)
Should be pretty easy to iterate through.