PHP Array not accessible - php

Question

Basically, i'm trying to get users data from a database using a class i found, it's parsing all data inside an array as shown here from the following function :
public function Get($field = NULL) {
if ($field == NULL)
{
$data = array();
while ($row = mysql_fetch_array($this->last_query))
{
$data[] = $row;
}
}
else
{
$row = mysql_fetch_array($this->last_query);
$data = $row[$field];
}
return $data;
}
Here's the PHP code i'm using to get the call this function
if($_SERVER['REQUEST_METHOD'] == 'POST'){
if($_SESSION['csrfToken'] == $_POST['csrfToken']) {
$email = $_POST['email'];
$password = $Security->Salt($Security->secParam($_POST['password']));
$DB->Query("SELECT * FROM `table` WHERE `email` = '$email' AND `password` = '$password'");
if($DB->num_rows() > 0) {
$results = $DB->Get();
} else {
echo "Account not found";
}
}
}
If i do a var_dump on $results it shows the following
array(1) {
[0]=> array(8) {
[0]=> string(1) "1" ["id"]=> string(1) "1"
[1]=> string(35) "email#email.com" ["email"]=> string(35) "email#email.com"
[2]=> string(32) "4f14dfef1efe0de64e2b176eac6051cd" ["password"]=> string(32) "4f14dfef1efe0de64e2b176eac6051cd"
[3]=> string(1) "1" ["status"]=> string(1) "1"
}
}
how can i access this data ? I've tried calling it by doing the following
$email = $results['email'];
echo $email;
But it's not displaying anything ?

Answer 1

Even though there's only one result in this instance (I guess?) the array supports multiple.
So find the first result, then take the email from that:
echo $results[0]['email'];
// ^^^^^^^^^^^
// first result

Answer 2

You need to tracking how arrays works. First you have array(1) and then into array another vars such as "email" or 1.
array(1) { <---- THIS IS ARRAY OCCURED FOR FIRST "0" ARRAY.
What's about
this
\/
echo $results[0]["email"]; ?

Answer 3

if($_SERVER['REQUEST_METHOD'] == 'POST' && $_SESSION['csrfToken'] == $_POST['csrfToken']) {
$password = $Security->Salt($Security->secParam($_POST['password']));
$password = $DB->quoteStr($password);
$email = $DB->quoteStr($_POST['email']);
$DB->Query("SELECT * FROM `table` WHERE `email` = $email AND `password` = $password");
return $DB->GetRow();
}
public function GetRow() {
return mysql_fetch_array($this->last_query);
}
public function quoteStr($str) {
return "'".mysql_real_escape_string($str)."'";
}

Answer 4

Marin Sagovac question is the answer.
To break it down a little more, your var_dump output shows that $results is a nested array. The first part of the output:
array(1) {
[0]=>
shows that $results consists of an array containing 1 element, at index 0, since that's where PHP starts indexing. This is the $results[0] part of Marin's response.
The element 0 of the $results array consists of an array with 8 elements.
[0]=>array(8) {
[0]=> string(1) "1" ["id"]=> string(1) "1"
[1]=> string(35) "email#email.com" ["email"]=> string(35) "email#email.com"
Even though there are only 4 actual results, index 1-4, each one exists twice so that they can either be accessed by index or by its key. Arrays that can be accessed by a unique key, as opposed to an index, are known as associative arrays.
So, in this case, either will return the same value:
echo $results[0]["email"];
echo $results[0][1];
The print_r function would also work, instead of var_dump.