jQuery Fileupload and writing filename do MySQL database - php

Question

I'm trying to create a file uploader with jQuery, that uploads a file, renames it with a timestamp and registers it into a DB. Basically it it sends the file with a form to the server where a second script renames it and moves the file to the right directory. This works without any problem. The problem is, that I want to send also the table name where this DB Entry should be made.
So index.php contains the form:
<div id="uploaderMain">
<p>Upload Your Files</p>
<form method="post" enctype="multipart/form-data" action="./upload.php">
<input type="file" name="images" id="images" />
<input type="hidden" name="List" id="List" value="<?php echo $DBTable; ?>" />
<button type="submit" id="btn">Upload Files!</button>
</form>
<div id="response"></div>
<ul id="image-list">
</ul>
</div>
The jQuery Code looks like this:
$.ajax({
url: "./uploader/upload.php",
type: "POST",
data: formdata,
processData: false,
contentType: false,
success: function (res) {
document.getElementById("response").innerHTML = res;
}
});
The upload.php looks like this:
<?php
//include db configuration file
include_once('../../db.php');
$List = $_POST['List'];
// get the time stamp for the uploaded file
date_default_timezone_set('EST');
$date = new DateTime();
$date = $date->getTimestamp();
// echo $date;
foreach ($_FILES["images"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
$name = $_FILES["images"]["name"][$key];
// store the file name and the file ending in 2 variables
$fileEnding = substr($name, -4,4);
$fileName = substr($name, 0, (strlen($name)-4));
$uploadName = $fileName."_".$date.$fileEnding;
move_uploaded_file( $_FILES["images"]["tmp_name"][$key], "./uploads/" . $uploadName);
}
}
after that I want to write to the DB. The problem is, that the $_POST['LIST'] statement doesn't provide my DBTable-name.
Can anyone give me a hint?
Cheers
Dan

Answer 1

I think you need to add this to your jQuery code:
formdata.append('List', '[your value]');
Please note: in PHP everything that is a file will go into $_FILES. Everything else will go into $_POST.
If this does not work, make sure you also have the following code:
var formdata = new FormData();
jQuery.each($('input[type="file"]')[0].files, function(i, file) {
formdata.append(i, file);
});

Answer 2

Can you check the source from browser if the List control has any value.