How I could Render PHP code from MySQL database? - php

I am creating some kind of custom CMS (home automation).
Well I am not a PHP developer - just hobbyist.
What I am trying to achieve is:
In my index.php page I have something like:
"<?php echo $pageBody; ?> "
PageBody I am fetching from Database, well it works well for HTML, JS. But it doesn't work with PHP code source.
I done some research I believe this is related to PHP security restrictions.
My question: Does anybody would be able to provide safe sample (cannot find any samples like this) - how I should do this.
I am trying to insert some php code and render it eventually via browser:
<div id="outer">
<div id="inner">
***PHP Code should go here***
</div>
</div>
At the minute - it is being rendered as text. However I can render properly HTML and JS.
My preferable way would be - as much as possible secure.
Many Thanks Guys!

When you retrieve PHP code from a database text field, the PHP interpreter does not "know" that it should parse the data as a PHP script. To the PHP interpreter, the data in that field is no different from any other data -- it is all strings without any special significance.
You could use eval (docs) to accomplish this if you're dealing with pure PHP scripts. Be forewarned: eval is considered "evil" because using it comes with risks, especially if your users will have any input as to the content of the database.
In your case, it sounds like you want to parse mixed PHP and HTML that is stored in a database field. In order to do this, you'd need to write the database data into a file, then include it so the PHP interpreter can do its thing. You should implement some kind of caching mechanism in this process, otherwise it might become heavy on your server with many users. You may also want to use output buffering (docs) to capture the output instead of immediately sending it out.
Briefly, you'd want to do something like this:
$content_from_db = "<h1>Hello <?php print 'Clarisse'; ?></h1>";
$identifier_from_db = '12'; // like the primary key from the table
$file_handle = fopen('cached_content/CACHE_'.$identifier_from_db.'.php', 'w');
fwrite($file_handle, $content_from_db);
fclose($file_handle);
// here is where you'd start output buffering, if you're going to do that (optional)
include('cached_content/CACHE_'.$identifier_from_db.'.php');
// and then here you retrieve the output buffer's content (optional)
Please note that this is not a "traditional" way of including dynamic content, and the above code is not production-ready. Without knowing your use case, I can't say for certain, but this idea of storing PHP code in the database is a rather unusual way to proceed.
Another alternative to rolling your own is the smarty template library. Check it out here: http://www.smarty.net. With smarty, you can write a resource plugin to pull the templates from the database. It would look something like the code above (more info)
Documentation
fwrite - http://php.net/manual/en/function.fwrite.php
include - http://php.net/manual/en/function.include.php
PHP basics on theopensourcery.com - http://theopensourcery.com/phpbasics.htm
Server-side scripting on Wikipedia - http://en.wikipedia.org/wiki/Server-side_scripting
eval - http://php.net/manual/en/function.eval.php
Output Control (buffering) - http://php.net/manual/en/book.outcontrol.php
Smarty - http://www.smarty.net

to execute PHP that you store in a string (or database) you can use the eval function, but be careful it could be somewhat dangerous.

You can't render (probably you mean execute) php code in the browser, because php scripts execute on the server and then the output is sent to the browser. By the time the browser recieve the response, script has already finished execution.
You can fetch the code from database and use eval() before sending the output. But you must be aware of drawbacks from this approach.

Browser cannot render (execute) PHP code. PHP is something that the server executes and sends to the browser as plain HTML to display.
For testing purposes you can download and install WAMP thats the most hassle free one stop solution for development.
link : http://www.wampserver.com/en/

Related

cURL PHP - load a fully page

I am currently trying to load an HTML page via cURL. I can retrieve the HTML content, but part is loaded later via scripting (AJAX POST). I can not recover the HTML part (this is a table).
Is it possible to load a page entirely?
Thank you for your answers
No, you cannot do this.
CURL does nothing more than download a file from a URL -- it doesn't care whether it's HTML, Javascript, and image, a spreadsheet, or any other arbitrary data; it just downloads. It doesn't run anything or parse anything or display anything, it just downloads.
You are asking for something more than that. You need to download, parse the result as HTML, then run some Javascript that downloads something else, then run more Javascript that parses that result into more HTML and inserts it into the original HTML.
What you're basically looking for is a full-blown web browser, not CURL.
Since your goal involves "running some Javascript code", it should be fairly clear that it is not acheivable without having a Javascript interpreter available. This means that it is obviously not going to work inside of a PHP program (*). You're going to need to move beyond PHP. You're going to need a browser.
The solution I'd suggest is to use a very specialised browser called PhantomJS. This is actually a full Webkit browser, but without a user interface. It's specifically designed for automated testing of websites and other similar tasks. Your requirement fits it pretty well: write a script to get PhantomJS to open your URL, wait for the table to finish rendering, and grab the finished HTML code.
You'll need to install PhantomJS on your server, and then use a library like this one to control it from your PHP code.
I hope that helps.
(*) yes, I'm aware of the PHP extension that provides a JS interpreter inside of PHP, and it would provide a way to solve the problem, but it's experimental, unfinished, would be still difficult to implement as a solution, and I don't think it's a particularly good idea anyway, so let's not consider it for the purposes of this answer.
No, the only way you can do that is if you make a separate curl request to ajax request and put the two results together afterwards.

Stop PHP parsing but output the rest of the file

I'm developing a web application where an html page is created for the user. The page could include anything that the user puts in it. We take these pages and add a little PHP at the top to check some things before outputting the actual html. It would look kind of like this:
<?php
require 'checksomestuff.php';
// User's html below
?>
<html>
<!-- user's html -->
</html>
Is there a way to stop PHP from parsing anything after my require? I need the html to be outputted, but, since the user can add anything they want to the html, I don't want any user-added PHP to be executed. Obviously that would be a security issue. So, I want the user's html to be outputted, but not parse any PHP. I would rather not have to put the user's html into another file.
One sensible way would be to offload the user created content to another file and then you should load this file (in your main php file) and output it as is - without parsing it as PHP.
There are many other ways to do this but if creating another file does the job for you then thats probably the best way forward.
UPDATE: Really must read last line of question!
You could encode the html into a variable using base64 encoding which you then just print out the decoded string.
If you don't store the file data in a php file, say n a txt or html file, the php won't be evaluated.
Alternatively you could read the file via file_get_contents() or by some other means which doesn't involve evaluating php.
Though I'm still tempted to ask why you want to do this (particularly this way), it sounds to me like one of the only things that can help you is the special __halt_compiler() function...
That should prevent it from executing the rest of the page, and may or may not output the rest of it. If not, well, read the first (and currently only) example in the PHP's manual for that function (linked above) for how to do it manually.
The only trouble I see with this method is that you'd probably have to have that code in every file you want to do this for, after your require.

silently use PHP/Javascript to get user's resolution

I was wondering if I can use PHP and Javascript to get the screen resolution from my users. Altho this is a simple thing, I was wondering if I can execute the JavaScript within a PHP statement and not output the Javascript code to the browser as HTML
I thought maybe putting it in an EOF block, but that didn't work, the output was the actual script haha.
I want to be able to populate a $width and $height within my PHP script and create a variable to look something like
$resolution = 800x600
I know I can place the javascript in the HTML page and then have a PHP block capture the javascript output, but I am using the Smarty template engine and have disabled the use of PHP within the templates for security reasons.
Is there a way to accomplish this?
I don't want to use the resolution for any url manipulating but rather to store the information for my statistical reasons.
I don't think what you want is really possible. It has to be in the HTML output for the browser to execute it.
You can capture it in the page JavaScript and use an AJAX call to POST it back to the server... but at that point you may as well use Google Analytics, because I'm pretty sure that's essentially what they do (but their framework is supported by, well... Google). Using Google Analytics will also prove to be useful, since they capture a number of other statistics as well.

Is it possible to execute PHP code returned from a MySQL query result?

The issue I am having is as follows: I have a MySQL table that contains details for page content I wish to display on my site. The content for one of my pages however I wanted to contain some actual PHP code to be executed, not just printed as a string. For example:
require_once("Class.php");
Class::Function("Some Text For a Parameter");
I want this code to execute somehow when the sql query is returned but as it stands, it just prints that text out. Is there a way to achieve what I want?
Thankyou in advance for your time,
Regards,
Stephen.
You can do it with eval(), but you shouldn't.
they are several ways to achieve the storage of dynamic elements :
eval(str) : you can evaluate as php code any string coming from you database. This is not very wise if what is stored in the database comes directly from a user input field. You never know what is going to be inserted and it could potentially be harmful code (harmful to the security of your server)
save / include : you could save what comes from your database in a temporary file and include() that file in-place in your php code. This does not seem to be secure either if anyone can store anything in your database
use a templating engine that has a reasonnable command footprint like smarty or mustache. you can store the templates in your database and execute them. If you trust the implementation of the templating language (and disable native php calls inside smarty for example) the template will need to have a correct syntax before execution can begin
As a general rule of thumb, it is very hard to protect such dynamic php code inclusion, so it should be considered as bad practice.
You should consider a DSL (domain specific language) for which you will trust the parser/compiler and execution engine.
If security is not a concern (because your application will not be public for example) then it can be perfectly valid and effective to store php fragments in the database.
I hope this will help you
Jerome Wagner
I do a variation of this in my personal CMS by doing a bbcode of sorts. I enclose php to evaluate inside of [code][/code] tags, then when displaying I have a function that uses regular expressions to grab the contents of code inside the [code] tags to run. It in turn builds the code such that it closes the text echo, runs the script, then starts the text echo again. Perhaps the explanation is a bit simplistic, but you get the idea.
I would definitely avoid eval!

Display any website source code for copy/paste

I have a website displaying data from MySQL in a php file (/something.php).... i want to copy the source code of that page as HTML so i can use it in a textfield box so users can copy paste that code...
It's almost like an HTML generator using info from mySQL, so users can custimize each HTML code.
I have everything covered... except the display HTML thing.
echo htmlspecialchars(eval(file_get_contents('path/to/your/file')));
Eval is generally frowned upon however but this is a quick and easy solution.
You need to escape the HTML into HTML entities. For instance, convert < into <.
You need to actually request the page from the web server, not simply read its contents in order for the PHP to execute and produce the result. That is, if I understand correctly that PHP (the file you were simply reading) is querying the database to actually fetch the desired HTML to display.
So, something like (if permitted) file_get_contents("http://url_of_php_file_you_were_simply_reading_not_requesting"); , then of course run that through htmlspecialchars();
Better to just use CURL to stay portable when requesting the page.
There's a php function htmlspecialchars you should look into.
For rendering check either eval (quick & dirty) or ob_start and friends (the more complex way to do it, though safer and generally supported by more hosters).

Categories