Populate drop down <ul> with directory contents - php

Question

I'm trying to write a simple php script that will populate a drop down unordered list with the file contents of a directory. Specifically .wav files. I'm HTML using and Bootstrap to do so.
Here is the list I've been working on:
<ul class="nav">
<li class="dropdown">
<a class="dropdown-toggle" data-toggle="dropdown" href="#">
<h4 style="color: #333333">Select a Sound -</h4> <b class="caret"></b>
</a>
<ul class="dropdown-menu">
<li>Moose.wav</li>
<li>Duck.wav</li>
<li>Goose.wav</li>
</ul>
</li>
</ul>
<?php
foreach(glob('sounds/*.wav') as $filename){
$rest = substr($filename, 7);
echo "<option>".$rest."</option>";
}
?>
Right now it's populated with hard coded values, Moose, Duck, etc . . . I've been working on this php script, I just don't know how to combine the two.

Answer 1

Is this what you're looking for?
<ul>
<?php
foreach(glob('sounds/*.wav') as $filename){
$rest = substr($filename, 7);
echo "<li><a href='#'>".$rest."</a></li>";
}
?>
</ul>

Answer 2

I'm writing this based on the assumption that all the code you provided are working perfectly as intended.
<ul class="nav">
<li class="dropdown">
<a class="dropdown-toggle" data-toggle="dropdown" href="#">
<h4 style="color: #333333">Select a Sound -</h4> <b class="caret"></b>
</a>
<ul class="dropdown-menu">
<?php foreach(glob('sounds/*.wav') as $filename){
$rest = substr($filename, 7);
echo "<li>".$rest."</li>";
}
?>
</ul>
</li>
</ul>
The idea is to write a PHP loop to generate your list items. This loop would reside within the tags, hence making the list.

Answer 3

You can use basename() to get only the filename, no need for substr()
<ul class="nav">
<li class="dropdown">
<a class="dropdown-toggle" data-toggle="dropdown" href="#">
<h4 style="color: #333333">Select a Sound -</h4> <b class="caret"></b>
</a>
<ul class="dropdown-menu">
<?php foreach(glob('sounds/*.wav') as $filename):?>
<li><?php echo basename($filename);?></li>
<?php endforeach;?>
</ul>
</li>
</ul>