$sql = "UPDATE `shows` SET `title` = '$title', `tagline` = '$tagline', `desc` = '$desc' , `img_src = '$imgsrc' WHERE id = $showid";
The query above does not want to work, I simply get a mysql_error saying error at '' on line 1;
Any idea where I am going wrong?
You're missing a tick:
`img_src = '$imgsrc' WHERE id = $showid";
should be:
`img_src` = '$imgsrc' WHERE id = $showid";
Related
I have an UPDATE query and using Ajax, I wanted to know if any value is empty can I only update the values that not empty in the database. I don't know if this is possible to have a if statement or something to check to skip the empty values. I know I can just add another form element but just wanted to know if there was another solution.
Only if the data is POST from front end form. If data not POST don't update this Title = '.$title .',
$id = $_POST['id'];
$title = "";
$description = $_POST['Description'];
$date = $_POST['Date'];
$query = 'UPDATE user SET
`id` = '.$id.',
`Title` = '.$title .',
`Description` = '.$description.',
`Date` = '.$date =.'
WHERE `id` = '.$id;
$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.<br />Query: ".$query."<br />Error: (".mysql_errno().") ".mysql_error());
Update: This is what worked for me. Thanks Karim Daraf
$query = " UPDATE user SET
Title = Coalesce($title,Title ) etc...
Try it with Coalesce .
$query = " UPDATE user
SET
`Title` = CASE WHEN `Title`='' or `Title` IS NULL THEN '$title' END,
`Description` = CASE WHEN `Description`='' Or `Description` IS NULL THEN '$description' END,
`Date` = CASE WHEN `Date`='' Or Date` IS NULL THEN '$date' END
WHERE `id` = '".$id."' ";
or :
$query = " UPDATE user
SET
`id` = Coalesce('$id''".$id."' , NULLIF(`id`,'')),
`Title` = Coalesce('$title''".$title."',NULLIF(`Title`,'') ) ,
`Description` = Coalesce('$description''".$description."' , NULLIF(`Description`,'') ) ,
`Date` = Coalesce('$date''".$date."',NULLIF(`Date`,''))
WHERE `id` = '$id''".$id."' ";
$query = 'UPDATE user SET
`id` = '.$id.',
`Title` = COALESCE(NULLIF("'.$title.'", ""),`Title`),
`Description` = "'.$description.'",
`Date` = "'.$date.'"
WHERE `id` = "'.$id.'"';
Not sure to understand: you have data and want to update, but only if some fied in the DB are empty?
In the case perfom only a where:
$query = 'UPDATE user SET
`id` = '.$id.',
`Title` = '.$title .',
`Description` = '.$description.',
`Date` = '.$date =.'
WHERE `id` = '.$id.' AND Title = '';
for example
for(some loop condition):
mysql_query("UPDATE `details` SET
`url_battlelog` = '".$stats[$out]['url_battlelog']."',
`url_bf3stats` = '".$stats[$out]['url_bf3stats']."',
`rank_img_medium` = '".$stats[$out]['rank_img_medium']."',
`country_name` = '".$stats[$out]['country_name']."',
`country` = '".$stats[$out]['country']."',
`country_flag` = '".$stats[$out]['country_flag']."',
`rank_number` = '".$stats[$out]['rank_number']."',
`score_total` = '".$stats[$out]['score_total']."',
`time_total` = '".$stats[$out]['time_total']."',
`dogtag_basic_img` = '".$stats[$out]['dogtag_basic_img']."',
`dogtag_basic` = '".$stats[$out]['dogtag_basic']."',
`dogtag_advance_img` = '".$stats[$out]['dogtag_advance_img']."',
`dogtag_advance` = '".$stats[$out]['dogtag_advance']."'
WHERE `name_player` = '".$stats[$out]['name_player']."'
")
or die(mysql_error());
for(2nd loop condition):
mysql_query("UPDATE `weapons` SET
`img` = '".$gun_img."',
`name` = '".$gun_name."',
`kit` = '".$gun_kit."',
`time` = '".$gun_time."',
`kills` = '".$gun_kills."',
`headshots` = '".$gun_hs."',
`shots` = '".$gun_shots."',
`hits` = '".$gun_hits."',
`star_total` = '".$gun_star_c."',
`star_img` = '".$gun_star_i."',
`star_need` = '".$gun_star_n."',
`rank_curr` = '".$gun_rank_c."',
`rank_all` = '".$gun_rank_w."',
`desc` = '".$gun_desc."',
`category` = '".$gun_cat."',
`range` = '".$gun_range."',
`fire_rate` = '".$gun_fire_rate."',
`ammo` = '".$gun_ammo."',
`auto_fire` = '".$gun_fire_auto."',
`burst_fire` = '".$gun_fire_burst."',
`single_fire` = '".$gun_fire_single."',
`unlock_total` = '".$unlock_total."',
`unlock_done` = '".$unlock_done."',
`unlock_p` = '".round($unlock_p)."'
WHERE `name_player` = '".$stats[$out]['name_player']."'
")
or die(mysql_error());
the problem is that only 2nd table (weapons) is updating, 1st table (details) is not showing any changes. Doesn't show any error.
I have same type of script for inserting data into both tables and its working fine.
I'm new to MySQL and PHP. sorry for bad English....
did you test by writing your SQL ? I think your [WHERE] condition is not fully filled
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1. the code is a follows where i get the error and that is come going from http://cms2.br-de.tk/editinfo.php to http://cms2.br-de.tk/updateinfo.php
<?php
mysql_connect("mysql10.000webhost.com","******_12","*******") or die("Error:".mysql_error());
mysql_select_db("******_1");//add your dbname
//get the variables we transmitted from the form
$Title = $_POST['Title'];
$Author = $_POST['Author'];
$Date = $_POST['Date'];
$Content = $_POST['Content'];
//replace TestTable with the name of your table
//replace id with the ID of your user
$sql = "UPDATE `posts` SET `Tilte` = '$Tilte',`Author` = '$Author',`Date` = '$Date',`Content` = '$Content' WHERE `posts`.`ID` = '$ID' 1 ";
mysql_query($sql) or die ("Error: ".mysql_error());
echo "Database updated. <a href='editinfo.php'>Return to edit info</a>";
?>
You have added additional 1 at the end of query. It should be like this:
$sql = "UPDATE `posts` SET `Tilte` = '$Title',`Author` = '$Author',`Date` = '$Date',`Content` = '$Content' WHERE `posts`.`ID` = '$ID'";
You have a spare 1 at the end of your statement.
UPDATE `posts` SET `Tilte` = '$Title',`Author` = '$Author',`Date` = '$Date',`Content` = '$Content' WHERE `posts`.`ID` = '$ID';"
As Grigore correctly spotted, you might also have a typo in your statement depending on your column names.
UPDATE `posts` SET `Title` = '$Title',`Author` = '$Author',`Date` = '$Date',`Content` = '$Content' WHERE `posts`.`ID` = '$ID';"
`Tilte` = '$Title'
maybe this is title not tilte, besides that there's a "1" right at the ending of the query
I want to update a mysql database. That has become a common practice for me, but for some reason with no error, it just doesn't work. The only thing I have never done is compare against 2 variables(in this case, ID && Name)
$name = $_POST['name'];
$duty = $_POST['duty'];
$number = $_POST['number'];
$url = $_POST['url'];
$insert = "UPDATE vendors SET name = '$_POST[name]', duty = '$_POST[duty]', number = '$_POST[number]', url = '$_POST[url]' WHERE id = '$id' && name = '$name'";
$result=mysql_query($insert) or die(mysql_error());
if ($result) {
header("location:**HIDDEN**");
Any help would be appreciated.
Instead of &&, you should use AND to add another where-condition.
Write this instead:
$name = $_POST['name'];
$duty = $_POST['duty'];
$number = $_POST['number'];
$url = $_POST['url'];
$insert = "UPDATE `vendors` SET `name` = '{$_POST['name']}', `duty` = '{$_POST['duty']}', `number` = '{$_POST['number']}', `url` = '{$_POST['url']}' WHERE (`id` = '$id' AND `name` = '$name')";
$result = #mysql_query($insert) or die(mysql_error());
header("location:**HIDDEN**");
It should now work. Notify me if there still is a problem.
replace && with AND and you should be good
Your Query is wrong. Following is the correct one.
The way you have used the variables is wrong.
You had not written any code for $id. What is that?
$insert = "UPDATE vendors SET name = '".$_POST['name']."', duty = '".$_POST['duty']."', number = '".$_POST['number']."', url = '".$_POST['url']."' WHERE id = '$id' AND name = '$name'";
If i'm doing multiple mysql queries on the same table, occasionally some get skipped.
Why is that?
For example:
<?php
mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'");
mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'");
mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'");
?>
Sometimes one of the queries will not be executed?
Why is that?
-Or is it something wrong with my server not general mysql?
(Obviously I know now to update the same table in the same query, but before that I was very confused as to why it happens, can anyone please explain?)
Thanks!
You do not need to make 3 queries, if you are updating the same rows:
$q = "
UPDATE table
SET field = '',
field2 = '',
field3 = 0
WHERE Id = :id
";
$statement = $pdo->prepare( $q );
$statement->bindParam(':id', $something, PDO::PARAM_INT);
$statement->execute();
Also, you should stop using the ancient mysql_* functions. They are not maintained anymore and process for deprecation has already begun.
Maybe you should avoid the 10+ year old API and learn something for this decade: PDO Tutorial for MySQL Developers.
debug your code to see if a query fails:
$result = mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
$result = mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
$result = mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
Use the following to debug the code:
mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'") or die(mysql_error());
mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'") or die(mysql_error());
mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'") or die(mysql_error());
UPDATE
Make sure you are escaping $something using:
$something = mysql_real_escape_string($something);