Here is my javascript code which is added in the tag of my php/html page:
<script type="text/javascript">
$(document).ready(function() {
$('#status').change(function(){
var status = $('#status').val();
var html = ''; //string variable for html code for fields
if( status=="closed"){
html += '<th>Close By :</th><td align="left"><select name="close_by">'+<?php $user=mysql_query("SELECT * FROM user");
while($data=mysql_fetch_array($user)){?>+'<option value="'+<?php echo $data['username'] ?>+'">'+<?php echo $data['username']; ?>+'</option>'+<?php } ?>+'</select></td>';
}
$('#close_by').html(html);
});
});
</script>
The code is for that, if Status=="closed" then a select tag will be appeared and the option values will be fetched from the database using mysql functions.But its not working. Please help to sort out this problem.
Thanks in advance.
You can't. PHP/MySQL reside on your server, while JS is executed in the browser.
Of course you may let the browser interact with your server by proper HTTP requests, after setting proper routes on your server.
You can mix PHP into Javascript. The PHP will execute on the server, and then the JS on the client. It's horrible though, extremely bad practice, and a nightmare to debug. Much better to seperate them out and use jQuery ajax to load the data.
Or use PHP to put the data into a JSON object at the start of the javascript, and process that with Javascript, rather than using PHP code to concatenate strings inside Javascript.
But in your example, what exactly is the problem? What is the end result of the PHP (in the HTML source) of the html variable? I suspect there's a bracket or quote wrong somewhere.
You can do it with ajax
$(document).ready(function() {
$('#status').change(function(){
var status = $('#status').val();
if( status=="closed"){
$.ajax({
url: 'ajax.php?',//if you have parameters
success:function (response) {
$('#close_by').html(response);
}
});
}
});
});
And you create a new php file for the ajax request
ajax.php
<th>Close By :</th>
<td align="left">
<select name="close_by">
<?php $user=mysql_query("SELECT * FROM user");
while($data=mysql_fetch_array($user)){?>
<option value="<?php echo $data['username'] ?>"><?php echo $data['username']; ?>
</option>
<?php } ?>
</select>
</td>
Related
I am a new user of ajax; so...
I am using ajax on a simple html page to access a php script to receive data, calculate results using data in an mysql table, and echo results in a div on the same page. My javascript statement to do this is:
$.post('ajax/phpscript.php', {
postuser:theuser,
postname:uans1
}, function(data) {
$('#outputdiv1').html(data);
}
);
The php echo output goes to a div on the main page called outputdiv1.
I got that part; no problem. Not sure exactly how it works, but it does work.
I would also like to echo output to a different div (which I will call outputdiv2) on the same page, using the php script. In my php script, How do I refer to or echo output this other div?
I guess I could have a second $.post statement in the javascript code, accessing a second php script. But that would force me to access the mysql database a second time. Doesn't seem efficient to me.
Is there a better way to do this?
Thanks.
HTML code is here:
theuser is defined earlier
<table width=400 align=center><tr><td>
There is a question here, with 2 possible answers:<p>
<form>
<input type=radio style="width:22px; height:22px" name="ques1" id="opt1" value="answer 1" onclick="post1()"> answer 1<br>
<input type=radio style="width:22px; height:22px" name="ques1" id="opt2" value="answer 2" onclick="post1()"> answer 2<br>
</form>
<div id="outdiv1">first response from php will go here, beneath the question.<br></div>
<script type="text/javascript">
function post1() {
var uans1 = "none"
if (document.getElementById("opt2").checked) {
uans1 = "answer 2"
}
if (document.getElementById("opt1").checked) {
uans1 = "answer 1"
}
$.post('ajax/phpscript.php',{postuser:theuser,postname:uans1}, function(data) {$('#ans1div').html(data);});
}
</script>
</td>
<td width=20%>
<div id="outputdiv2">
second response from php will go here, to the right of the question.<p>
</div>
</td>
</tr></table>
first response will not be the same as the second response.
You could use JSON to communicate and return an array. something like this in js
$.ajax({
url: 'ajax/phpscript.php',
method: 'POST',
data: {
postuser: theuser,
postname: uans1
},
dataType: 'JSON'
}).done(function(data) {
if ($.isArray(data)) {
$('#outputdiv1').html(data[0]);
$('#outputdiv2').html(data[1]);
}
});
And your php script should do something look like this
<?php
include('dbconnection.php');
$result = [];
//SELECT data for div1 (part you already have)
$result[] = $mysql_result_as_html_for_outputdiv_1; // In your case this would be a html string
//SELECT other data for div2
$result[] = $mysql_result_as_html_for_outputdiv_2; // In your case this would be a html string
header('Content-Type: application/json');
echo json_encode($result);
?>
An even more clean solution would be to just return the data as objects from php and make some templates in js suitable for your data.
You need to understand this: who write in the div is javascript, not php, cause you are using ajax. Ajax is a way to comunicate with php, and give a response. Now you need to handle this response with javascript.
If you want to put the same content in outputdiv1 and outputdiv2, you not need to post ajax again, only write it in two divs.
$.post('ajax/phpscript.php',{postuser:theuser,postname:uans1}, function(data) {$('#outputdiv1').html(data);$('#outputdiv2').html(data);});
if you want different data i suggest you think the system to get all result that you need in one post request and return it in a json format (see http://php.net/manual/es/function.json-encode.php), so you can handle better with JSON.parse() in client side.
I want to pass JavaScript variables to PHP using a hidden input in a form.
But I can't get the value of $_POST['hidden1'] into $salarieid. Is there something wrong?
Here is the code:
<script type="text/javascript">
// View what the user has chosen
function func_load3(name) {
var oForm = document.forms["myform"];
var oSelectBox = oForm.select3;
var iChoice = oSelectBox.selectedIndex;
//alert("You have chosen: " + oSelectBox.options[iChoice].text);
//document.write(oSelectBox.options[iChoice].text);
var sa = oSelectBox.options[iChoice].text;
document.getElementById("hidden1").value = sa;
}
</script>
<form name="myform" action="<?php echo $_SERVER['$PHP_SELF']; ?>" method="POST">
<input type="hidden" name="hidden1" id="hidden1" />
</form>
<?php
$salarieid = $_POST['hidden1'];
$query = "select * from salarie where salarieid = ".$salarieid;
echo $query;
$result = mysql_query($query);
?>
<table>
Code for displaying the query result.
</table>
You cannot pass variable values from the current page JavaScript code to the current page PHP code... PHP code runs at the server side, and it doesn't know anything about what is going on on the client side.
You need to pass variables to PHP code from the HTML form using another mechanism, such as submitting the form using the GET or POST methods.
<DOCTYPE html>
<html>
<head>
<title>My Test Form</title>
</head>
<body>
<form method="POST">
<p>Please, choose the salary id to proceed result:</p>
<p>
<label for="salarieids">SalarieID:</label>
<?php
$query = "SELECT * FROM salarie";
$result = mysql_query($query);
if ($result) :
?>
<select id="salarieids" name="salarieid">
<?php
while ($row = mysql_fetch_assoc($result)) {
echo '<option value="', $row['salaried'], '">', $row['salaried'], '</option>'; //between <option></option> tags you can output something more human-friendly (like $row['name'], if table "salaried" have one)
}
?>
</select>
<?php endif ?>
</p>
<p>
<input type="submit" value="Sumbit my choice"/>
</p>
</form>
<?php if isset($_POST['salaried']) : ?>
<?php
$query = "SELECT * FROM salarie WHERE salarieid = " . $_POST['salarieid'];
$result = mysql_query($query);
if ($result) :
?>
<table>
<?php
while ($row = mysql_fetch_assoc($result)) {
echo '<tr>';
echo '<td>', $row['salaried'], '</td><td>', $row['bla-bla-bla'], '</td>' ...; // and others
echo '</tr>';
}
?>
</table>
<?php endif?>
<?php endif ?>
</body>
</html>
Just save it in a cookie:
$(document).ready(function () {
createCookie("height", $(window).height(), "10");
});
function createCookie(name, value, days) {
var expires;
if (days) {
var date = new Date();
date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
expires = "; expires=" + date.toGMTString();
}
else {
expires = "";
}
document.cookie = escape(name) + "=" + escape(value) + expires + "; path=/";
}
And then read it with PHP:
<?PHP
$_COOKIE["height"];
?>
It's not a pretty solution, but it works.
There are several ways of passing variables from JavaScript to PHP (not the current page, of course).
You could:
Send the information in a form as stated here (will result in a page refresh)
Pass it in Ajax (several posts are on here about that) (without a page refresh)
Make an HTTP request via an XMLHttpRequest request (without a page refresh) like this:
if (window.XMLHttpRequest){
xmlhttp = new XMLHttpRequest();
}
else{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
var PageToSendTo = "nowitworks.php?";
var MyVariable = "variableData";
var VariablePlaceholder = "variableName=";
var UrlToSend = PageToSendTo + VariablePlaceholder + MyVariable;
xmlhttp.open("GET", UrlToSend, false);
xmlhttp.send();
I'm sure this could be made to look fancier and loop through all the variables and whatnot - but I've kept it basic as to make it easier to understand for the novices.
Here is the Working example: Get javascript variable value on the same page in php.
<script>
var p1 = "success";
</script>
<?php
echo "<script>document.writeln(p1);</script>";
?>
Here's how I did it (I needed to insert a local timezone into PHP:
<?php
ob_start();
?>
<script type="text/javascript">
var d = new Date();
document.write(d.getTimezoneOffset());
</script>
<?php
$offset = ob_get_clean();
print_r($offset);
When your page first loads the PHP code first runs and sets the complete layout of your webpage. After the page layout, it sets the JavaScript load up.
Now JavaScript directly interacts with DOM and can manipulate the layout but PHP can't - it needs to refresh the page. The only way is to refresh your page to and pass the parameters in the page URL so that you can get the data via PHP.
So, we use AJAX to get Javascript to interact with PHP without a page reload. AJAX can also be used as an API. One more thing if you have already declared the variable in PHP before the page loads then you can use it with your Javascript example.
<?php $myname= "syed ali";?>
<script>
var username = "<?php echo $myname;?>";
alert(username);
</script>
The above code is correct and it will work, but the code below is totally wrong and it will never work.
<script>
var username = "syed ali";
var <?php $myname;?> = username;
alert(myname);
</script>
Pass value from JavaScript to PHP via AJAX
This is the most secure way to do it, because HTML content can be edited via developer tools and the user can manipulate the data. So, it is better to use AJAX if you want security over that variable. If you are a newbie to AJAX, please learn AJAX it is very simple.
The best and most secure way to pass JavaScript variable into PHP is via AJAX
Simple AJAX example
var mydata = 55;
var myname = "syed ali";
var userdata = {'id':mydata,'name':myname};
$.ajax({
type: "POST",
url: "YOUR PHP URL HERE",
data:userdata,
success: function(data){
console.log(data);
}
});
PASS value from JavaScript to PHP via hidden fields
Otherwise, you can create a hidden HTML input inside your form. like
<input type="hidden" id="mydata">
then via jQuery or javaScript pass the value to the hidden field. like
<script>
var myvalue = 55;
$("#mydata").val(myvalue);
</script>
Now when you submit the form you can get the value in PHP.
I was trying to figure this out myself and then realized that the problem is that this is kind of a backwards way of looking at the situation. Rather than trying to pass things from JavaScript to php, maybe it's best to go the other way around, in most cases. PHP code executes on the server and creates the html code (and possibly java script as well). Then the browser loads the page and executes the html and java script.
It seems like the sensible way to approach situations like this is to use the PHP to create the JavaScript and the html you want and then to use the JavaScript in the page to do whatever PHP can't do. It seems like this would give you the benefits of both PHP and JavaScript in a fairly simple and straight forward way.
One thing I've done that gives the appearance of passing things to PHP from your page on the fly is using the html image tag to call on PHP code. Something like this:
<img src="pic.php">
The PHP code in pic.php would actually create html code before your web page was even loaded, but that html code is basically called upon on the fly. The php code here can be used to create a picture on your page, but it can have any commands you like besides that in it. Maybe it changes the contents of some files on your server, etc. The upside of this is that the php code can be executed from html and I assume JavaScript, but the down side is that the only output it can put on your page is an image. You also have the option of passing variables to the php code through parameters in the url. Page counters will use this technique in many cases.
PHP runs on the server before the page is sent to the user, JavaScript is run on the user's computer once it is received, so the PHP script has already executed.
If you want to pass a JavaScript value to a PHP script, you'd have to do an XMLHttpRequest to send the data back to the server.
Here's a previous question that you can follow for more information: Ajax Tutorial
Now if you just need to pass a form value to the server, you can also just do a normal form post, that does the same thing, but the whole page has to be refreshed.
<?php
if(isset($_POST))
{
print_r($_POST);
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="text" name="data" value="1" />
<input type="submit" value="Submit" />
</form>
Clicking submit will submit the page, and print out the submitted data.
We can easily pass values even on same/ different pages using the cookies shown in the code as follows (In my case, I'm using it with facebook integration) -
function statusChangeCallback(response) {
console.log('statusChangeCallback');
if (response.status === 'connected') {
// Logged into your app and Facebook.
FB.api('/me?fields=id,first_name,last_name,email', function (result) {
document.cookie = "fbdata = " + result.id + "," + result.first_name + "," + result.last_name + "," + result.email;
console.log(document.cookie);
});
}
}
And I've accessed it (in any file) using -
<?php
if(isset($_COOKIE['fbdata'])) {
echo "welcome ".$_COOKIE['fbdata'];
}
?>
Your code has a few things wrong with it.
You define a JavaScript function, func_load3(), but do not call it.
Your function is defined in the wrong place. When it is defined in your page, the HTML objects it refers to have not yet been loaded. Most JavaScript code checks whether the document is fully loaded before executing, or you can just move your code past the elements it refers to in the page.
Your form has no means to submit it. It needs a submit button.
You do not check whether your form has been submitted.
It is possible to set a JavaScript variable in a hidden variable in a form, then submit it, and read the value back in PHP. Here is a simple example that shows this:
<?php
if (isset($_POST['hidden1'])) {
echo "You submitted {$_POST['hidden1']}";
die;
}
echo <<<HTML
<form name="myform" action="{$_SERVER['PHP_SELF']}" method="post" id="myform">
<input type="submit" name="submit" value="Test this mess!" />
<input type="hidden" name="hidden1" id="hidden1" />
</form>
<script type="text/javascript">
document.getElementById("hidden1").value = "This is an example";
</script>
HTML;
?>
You can use JQuery Ajax and POST method:
var obj;
$(document).ready(function(){
$("#button1").click(function(){
var username=$("#username").val();
var password=$("#password").val();
$.ajax({
url: "addperson.php",
type: "POST",
async: false,
data: {
username: username,
password: password
}
})
.done (function(data, textStatus, jqXHR) {
obj = JSON.parse(data);
})
.fail (function(jqXHR, textStatus, errorThrown) {
})
.always (function(jqXHROrData, textStatus, jqXHROrErrorThrown) {
});
});
});
To take a response back from the php script JSON parse the the respone in .done() method.
Here is the php script you can modify to your needs:
<?php
$username1 = isset($_POST["username"]) ? $_POST["username"] : '';
$password1 = isset($_POST["password"]) ? $_POST["password"] : '';
$servername = "xxxxx";
$username = "xxxxx";
$password = "xxxxx";
$dbname = "xxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO user (username, password)
VALUES ('$username1', '$password1' )";
;
if ($conn->query($sql) === TRUE) {
echo json_encode(array('success' => 1));
} else{
echo json_encode(array('success' => 0));
}
$conn->close();
?>
Is your function, which sets the hidden form value, being called? It is not in this example. You should have no problem modifying a hidden value before posting the form back to the server.
May be you could use jquery serialize() method so that everything will be at one go.
var data=$('#myForm').serialize();
//this way you could get the hidden value as well in the server side.
This obviously solution was not mentioned earlier. You can also use cookies to pass data from the browser back to the server.
Just set a cookie with the data you want to pass to PHP using javascript in the browser.
Then, simply read this cookie on the PHP side.
We cannot pass JavaScript variable values to the PHP code directly... PHP code runs at the server side, and it doesn't know anything about what is going on on the client side.
So it's better to use the AJAX to parse the JavaScript value into the php Code.
Or alternatively we can make this done with the help of COOKIES in our code.
Thanks & Cheers.
Use the + sign to concatenate your javascript variable into your php function call.
<script>
var JSvar = "success";
var JSnewVar = "<?=myphpFunction('" + JSvar + "');?>";
</script>`
Notice the = sign is there twice.
My question is simple.
I have the following code:
<div class="last"
<?php
if hasClass(last){
echo " style='width:100%;' ";
}
?>
></div>
I know the if statement is wrong, but the idea is there. I want to know how can I check if this div has the .last class then echo something.
I've been searching around but didn't work anything (didn't find much though).
Best regards.
As already in the comments told it's possible with PHP with DOM parsers.
I'm gonna give you 2 very simple solutions which will save you a lot of work:
CSS:
<style>
.last {
width:100%;
}
</style>
jQuery:
<script type="text/javascript">
$(document).ready(function(){
if($('div').hasClass('last')){
$('div').css('width', '100%');
}
});
</script>
PHP runs on server, so it generates HTML. If you have that class="last" you don't need to check - it's part of the code....hard-coded.
But you can have some PHP variable and depending on it's place print out class and also style for that other element:
<?php
$print_last = true;
?>
...
<div <?php if ($print_last) echo 'class="last" ';
<?php
if ($print_last){
echo " style='width:100%;' ";
}
?>
></div>
But if you want to check on html element you have to do it on client side (browser) from JavaScript and jQuery can be helpful too.
It is possible to check that using PHP, however that couldn't be done easliy (you'll need to parse buffered HTML using DOM parser, then look up for divs, etc...).... Much better solution is to do that with Javascript/jQuery, using Document.getElementsByClassName() function.
Sample solution:
var elements = document.getElementsByClassName("last");
for(var i = 0; i < elements.length; i++)
{
var element = elements[i];
element.style.width = "100%";
}
#azhpo
Obviously the HTML being the front end language you have to pass the elements either through some submit button or via ajax request.
Using submit button: select the class name of div using either javascript
var className = document.getElementById("myDIV").className
document.getElementById("myHiddenField").value = className;
Now on clicking the submit button it would get submitted
Using ajax:
Again take the classname either through javascript / jquery
var className = jQuery("#myDiv").attr("class");
Now fire ajax query and send the class name to your script
jQuery.ajax({
url: 'file.php',
type: 'POST',
data: 'class='+className,
success: function(data){//do whatever you want},
error:function(){//do whatever you want}
});
Getting down and dirty with javascript and JSON.
I want to store some html values inside a JSON array, so I can call them when needed (usually from some jquery event listener)
This beats constantly using $.ajax for client-to-server calls.
So, I have a <select> that has database populated options:
<select name="emailmsgid" id="emailmsgid">
<option value="0">------select a template-------</option>
<?php
$q = mysql_query("SELECT emailmsgid,emailmsgsubject,emailmsg_html FROM tbl_email_templates");
while ($r = mysql_fetch_array($q)){
$emailmsgid = $r['emailmsgid']; // int
$emailmsgsubject= $r['emailmsgsubject']; // short desc
$emailmsg_html = $r['emailmsg_html']; // usually html with images (save to json, somehow)
?>
<option value="<?=$emailmsgid;?>"><?=$emailmsgsubject;?></option>
<? } ?>
</select>
<br>
<textarea name="selectedmsg" id="selectedmsg"></textarea>
<script language="javascript" type="text/javascript">
$(document).ready(function(){
// populate the textarea above
$("#emailmsgid").change(function(){
var selectedID = $(this).val();
/* how to look into json here with selectedID */
$("#selectedmsg").val("whatever the json has saved for that emailmsgid");
});
});
</script>
This is what's missing above.
-Creating the json string, (from inside the php/mysql while statement), so the jquery below can reference the json, matching up the selectedID to what's inside json?
I do admit I am new to JSON, and this is a great way for me to learn how to work with it, as well as call the name/value pairs from jquery.
I'm hoping to save the emailmsg_html inside json, then load it into the textarea when I select it's matching emailmsgid in the select input.
(I'm basically working at eliminating any times my code needs to call the server, and seems this is the best route)
Have you tried using json_encode(): http://php.net/manual/en/function.json-encode.php
You can pass it objects, arrays, etc and it will convert them for you.
Extra Comment
Your code is pretty messy. Having MySQL requests in the middle of the HTML isn't great. You might want to do some research into MVC frameworking.
What I would do, to prevent various encoding and transport issues, is to place the html in hidden containers that you can access later:
<div style="display:none">
<?php while ($r = mysql_fetch_array($q)){ ?>
<div id="container_<?php echo $r['emailmsgid']; ?>">
<div class="description">
<?php echo $r['emailmsgsubject']; // short desc ?>
</div>
<div class="html">
<?php echo $r['emailmsg_html']; // usually html with images (save to json, somehow) ?>
</div>
<?php } ?>
</div>
Then your script would become:
$(document).ready(function(){
// populate the textarea above
$("#emailmsgid").change(function(){
var selectedID = $(this).val();
var msgHtml = $('#container_' + selectedID).find('.html').html(); // This line is how you get the html
$("#selectedmsg").val("whatever the json has saved for that emailmsgid");
});
});
</script>
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now </button>
<script type="text/javascript">
function funk(){
alert("asdasd");
<?php echo "asdasda";?>
}
</script>
When the button is pressed I want to execute PHP code (at this point to echo asadasda)
You could use http://phpjs.org/ http://locutus.io/php/ it ports a bunch of PHP functionality to javascript, but if it's just echos, and the script is in a php file, you could do something like this:
alert("<?php echo "asdasda";?>");
don't worry about the shifty-looking use of double-quotes, PHP will render that before the browser sees it.
as for using ajax, the easiest way is to use a library, like jQuery. With that you can do:
$.ajax({
url: 'test.php',
success: function(data) {
$('.result').html(data);
}
});
and test.php would be:
<?php
echo 'asdasda';
?>
it would write the contents of test.php to whatever element has the result class.
Interaction of Javascript and PHP
We all grew up knowing that Javascript ran on the Client Side (ie the browser)
and PHP was a server side tool (ie the Server side). CLEARLY the two just cant interact.
But -- good news; it can be made to work and here's how.
The objective is to get some dynamic info (say server configuration items) from the server into the Javascript environment so it can be used when needed - - typically this implies DHTML modification to the presentation.
First, to clarify the DHTML usage I'll cite this DHTML example:
<script type="text/javascript">
function updateContent() {
var frameObj = document.getElementById("frameContent");
var y = (frameObj.contentWindow || frameObj.contentDocument);
if (y.document) y = y.document;
y.body.style.backgroundColor="red"; // demonstration of failure to alter the display
// create a default, simplistic alteration usinga fixed string.
var textMsg = 'Say good night Gracy';
y.write(textMsg);
y.body.style.backgroundColor="#00ee00"; // visual confirmation that the updateContent() was effective
}
</script>
Assuming we have an html file with the ID="frameContent" somewhere,
then we can alter the display with a simple < body onload="updateContent()" >
Golly gee; we don't need PHP to do that now do we! But that creates a structure for
applying PHP provided content.
We change the webpage in question into a PHTML type to allow the server side PHP access
to the content:
**foo.html becomes foo.phtml**
and we add to the top of that page. We also cause the php data to be loaded
into globals for later access - - like this:
<?php
global $msg1, $msg2, $textMsgPHP;
function getContent($filename) {
if ($theData = file_get_contents($filename, FALSE)) {
return "$theData";
} else {
echo "FAILED!";
}
}
function returnContent($filename) {
if ( $theData = getContent($filename) ) {
// this works ONLY if $theData is one linear line (ie remove all \n)
$textPHP = trim(preg_replace('/\r\n|\r|\n/', '', $theData));
return "$textPHP";
} else {
echo '<span class="ERR">Error opening source file :(\n</span>'; # $filename!\n";
}
}
// preload the dynamic contents now for use later in the javascript (somewhere)
$msg1 = returnContent('dummy_frame_data.txt');
$msg2 = returnContent('dummy_frame_data_0.txt');
$textMsgPHP = returnContent('dummy_frame_data_1.txt');
?>
Now our javascripts can get to the PHP globals like this:
// by accessig the globals
var textMsg = '< ? php global $textMsgPHP; echo "$textMsgPHP"; ? >';
In the javascript, replace
var textMsg = 'Say good night Gracy';
with:
// using php returnContent()
var textMsg = '< ? php $msgX = returnContent('dummy_div_data_3.txt'); echo "$msgX" ? >';
Summary:
the webpage to be modified MUST be a phtml or some php file
the first thing in that file MUST be the < ? php to get the dynamic data ?>
the php data MUST contain its own css styling (if content is in a frame)
the javascript to use the dynamic data must be in this same file
and we drop in/outof PHP as necessary to access the dynamic data
Notice:- use single quotes in the outer javascript and ONLY double quotes in the dynamic php data
To be resolved: calling updateContent() with a filename and
using it via onClick() instead of onLoad()
An example could be provided in the Sample_Dynamic_Frame.zip for your inspection, but didn't find a means to attach it
You can't run PHP with javascript. JavaScript is a client side technology (runs in the users browser) and PHP is a server side technology (run on the server).
If you want to do this you have to make an ajax request to a PHP script and have that return the results you are looking for.
Why do you want to do this?
If you just want to echo a message from PHP in a certain place on the page when the user clicks the button, you could do something like this:
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now</button>
<div id="resultMsg"></div>
<script type="text/javascript">
function funk(){
alert("asdasd");
document.getElementById('resultMsg').innerHTML('<?php echo "asdasda";?>');
}
</script>
However, assuming your script needs to do some server-side processing such as adding the item to a cart, you may like to check out jQuery's http://api.jquery.com/load/ - use jQuery to load the path to the php script which does the processing. In your example you could do:
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now</button>
<div id="resultMsg"></div>
<script type="text/javascript">
function funk(){
alert("asdasd");
$('#resultMsg').load('path/to/php/script/order_item.php');
}
</script>
This runs the php script and loads whatever message it returns into <div id="resultMsg">.
order_item.php would add the item to cart and just echo whatever message you would like displayed. To get the example working this will suffice as order_item.php:
<?php
// do adding to cart stuff here
echo 'Added to cart';
?>
For this to work you will need to include jQuery on your page, by adding this in your <head> tag:
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js"></script>
Any server side stuff such as php declaration must get evaluated in the host file (file with a .php extension) inside the script tags such as below
<script type="text/javascript">
var1 = "<?php echo 'Hello';?>";
</script>
Then in the .js file, you can use the variable
alert(var1);
If you try to evaluate php declaration in the .js file, it will NOT work
put your php into a hidden div and than call it with javascript
php part
<div id="mybox" style="visibility:hidden;"> some php here </div>
javascript part
var myfield = document.getElementById("mybox");
myfield.visibility = 'visible';
now, you can do anything with myfield...
We can use php in JavaScript by creating a form element and put the action as a .php page.
Then we use JavaScript to submit that form.
EX:
<!doctype html>
<html>
<head>
<title>PHP Executed with JS</title>
</head>
<body>
<form action="phpCode.php" id="phpCode">.
</form> <!-- This is the form-->
<script>
function runPhp() {
var php =
document.getElementById("phpCode")
php.submit() //submit the form
}
</script>
</body>
The PHP file name would be phpCode.php.
In that file would be your PHP code.
May be this way:
<?php
if($_SERVER['REQUEST_METHOD']=="POST") {
echo 'asdasda';
}
?>
<form method="post">
<button type="submit" id="okButton">Order now</button>
</form>
If you do not want to include the jquery library you can simple do the following
a) ad an iframe, size 0px so it is not visible, href is blank
b) execute this within your js code function
window.frames['iframename'].location.replace('http://....your.php');
This will execute the php script and you can for example make a database update...
Use ajax to send request and echo the response
when successfully executed. Like this:
$.get("site.com/ajax", function(status,data){
alert(status);
});
This can be achieved with jquery library.
You could run PHP at the start of the Page and grap the results from inputs
<?php
c = a * b;
?>
<input type="hidden" name="c" value="<?php c ?>"/>
<button type="submit">Submit</button>
</form>
<script>
let cValue = $('input[name="c"]').val();
alert(cValue);
</script>