Determine If Business Is Open/Closed Based On Business Hours - php

Question

My code works fine if the times are AM to PM (Ex: 11 AM - 10 PM), but if the locations hours of operation are AM to AM (Ex: 9 AM - 1 AM) it breaks. Here is my code:
$datedivide = explode(" - ", $day['hours']); //$day['hours'] Example 11:00 AM - 10:00 PM
$from = ''.$day['days'].' '.$datedivide[0].'';
$to = ''.$day['days'].' '.$datedivide[1].'';
$date = date('l g:i A');
$date = is_int($date) ? $date : strtotime($date);
$from = is_int($from) ? $from : strtotime($from);
$to = is_int($to) ? $to : strtotime($to);
if (($date > $from) && ($date < $to) && ($dateh != 'Closed')) {
?>
<script type="text/javascript">
$(document).ready(function(){
$('.entry-title-container').append('<div class="column two"><h2 style="color:green;text-align: left;margin: 0;">OPEN<br /><span style="color:#222;font-size:12px;display: block;">Closes at <?php echo $datedivide[1]; ?></span></h2></div><br clear="all" />');
});
</script>
<?php
}

Answer 1

You would first need to create an array which will hold your days of the week, and their respective close/open time range(s).
/**
* I setup the hours for each day if they carry-over)
* everyday is open from 09:00 AM - 12:00 AM
* Sun/Sat open extra from 12:00 AM - 01:00 AM
*/
$storeSchedule = [
'Sun' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM'],
'Mon' => ['09:00 AM' => '12:00 AM'],
'Tue' => ['09:00 AM' => '12:00 AM'],
'Wed' => ['09:00 AM' => '12:00 AM'],
'Thu' => ['09:00 AM' => '12:00 AM'],
'Fri' => ['09:00 AM' => '12:00 AM'],
'Sat' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM']
];
You then loop over the current day's time range(s) and check to see if the current time or supplied timestamp is within a range. You do this by using the DateTime class to generate a DateTime object for each time range's start/end time.
The below will do this and allow you to specify a timestamp in case you are wanting to check a supplied timestamp instead of the current time.
// current or user supplied UNIX timestamp
$timestamp = time();
// default status
$status = 'closed';
// get current time object
$currentTime = (new DateTime())->setTimestamp($timestamp);
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times
$startTime = DateTime::createFromFormat('h:i A', $startTime);
$endTime = DateTime::createFromFormat('h:i A', $endTime);
// check if current time is within a range
if (($startTime < $currentTime) && ($currentTime < $endTime)) {
$status = 'open';
break;
}
}
echo "We are currently: $status";
See DEMO of above

Answer 2

Modified from the accepted answer for use on a AWS Debian Server (located on the west coast) where our store hours are actually EST... also dropped into a PHP function.
/*
* decide based upon current EST if the store is open
*
* #return bool
*/
function storeIsOpen() {
$status = FALSE;
$storeSchedule = [
'Mon' => ['08:00 AM' => '05:00 PM'],
'Tue' => ['08:00 AM' => '05:00 PM'],
'Wed' => ['08:00 AM' => '05:00 PM'],
'Thu' => ['08:00 AM' => '05:00 PM'],
'Fri' => ['08:00 AM' => '05:00 PM']
];
//get current East Coast US time
$timeObject = new DateTime('America/New_York');
$timestamp = $timeObject->getTimeStamp();
$currentTime = $timeObject->setTimestamp($timestamp)->format('H:i A');
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times and format as string (24hr AM/PM)
$startTime = DateTime::createFromFormat('h:i A', $startTime)->format('H:i A');
$endTime = DateTime::createFromFormat('h:i A', $endTime)->format('H:i A');
// check if current time is within the range
if (($startTime < $currentTime) && ($currentTime < $endTime)) {
$status = TRUE;
break;
}
}
return $status;
}

Answer 3

You should regroup all opening hours in a array since the openings hours of yesterday could be of influence if you stay opened after midnight. Also having the possibility to have several opening hours per day might be handy.
<?php
$times = array(
'mon' => '9:00 AM - 12:00 AM',
'tue' => '9:00 AM - 12:00 AM',
'wed' => '9:00 AM - 12:00 AM',
'thu' => '9:00 AM - 12:00 AM',
'fri' => '9:00 AM - 1:00 AM',
'sat' => '9:00 AM - 1:00 PM, 2:00 PM - 1:00 AM',
'sun' => 'closed'
);
function compileHours($times, $timestamp) {
$times = $times[strtolower(date('D',$timestamp))];
if(!strpos($times, '-')) return array();
$hours = explode(",", $times);
$hours = array_map('explode', array_pad(array(),count($hours),'-'), $hours);
$hours = array_map('array_map', array_pad(array(),count($hours),'strtotime'), $hours, array_pad(array(),count($hours),array_pad(array(),2,$timestamp)));
end($hours);
if ($hours[key($hours)][0] > $hours[key($hours)][1]) $hours[key($hours)][1] = strtotime('+1 day', $hours[key($hours)][1]);
return $hours;
}
function isOpen($now, $times) {
$open = 0; // time until closing in seconds or 0 if closed
// merge opening hours of today and the day before
$hours = array_merge(compileHours($times, strtotime('yesterday',$now)),compileHours($times, $now));
foreach ($hours as $h) {
if ($now >= $h[0] and $now < $h[1]) {
$open = $h[1] - $now;
return $open;
}
}
return $open;
}
$now = strtotime('7:59pm');
$open = isOpen($now, $times);
if ($open == 0) {
echo "Is closed";
} else {
echo "Is open. Will close in ".ceil($open/60)." minutes";
}
?>
On the other hand if you only want to resolve the problem with time like 9am - 5am you should check if $from > $to and add 1 day to $to if necessary.

Answer 4

A bit late but I have a solution for others, if the one's here don't quite fit their needs. I do like the solution of having multiple time sets for days that close after midnight but then this would add extra data handling to display the hours. You would first have to check if there are multiple time sets available then confirm that they are connected (no time in between).
My solution was instead to write a function that you pass the opening time, closing time, and time-in-question and it will return true for open and false for closed:
function is_open($open, $close, $query_time){
$open = new DateTime($open);
$close = new DateTime($close);
$query_time = new DateTime($query_time);
$is_open = false;
//Determine if open time is before close time in a 24 hour period
if($open < $close){
//If so, if the query time is between open and closed, it is open
if($query_time > $open){
if($query_time < $close){
$is_open = true;
}
}
}
elseif($open > $close){
$is_open = true;
//If not, if the query time is between close and open, it is closed
if($query_time < $open){
if($query_time > $close){
$is_open = false;
}
}
}
return $is_open;
}

Answer 5

Maybe this? I found it here and tweaked it a bit.
<?php
date_default_timezone_set('Europe/Stockholm'); // timezone
$today = date(N); // today ex. 6
//Opening hours
$opening_hours[1] = "12:00"; $closing_hours[1] = "00:00";
$opening_hours[2] = "12:00"; $closing_hours[2] = "00:00";
$opening_hours[3] = "12:00"; $closing_hours[3] = "00:00";
$opening_hours[4] = "12:00"; $closing_hours[4] = "02:00";
$opening_hours[5] = "12:00"; $closing_hours[5] = "04:00";
$opening_hours[6] = "13:00"; $closing_hours[6] = "04:00";
$opening_hours[7] = "13:00"; $closing_hours[7] = "00:00";
// correction for opening hours after midnight.
if(intval($closing_hours[$today - 1]) > 0)
$today = date(N,strtotime("-".intval($closing_hours[$today - 1])." hours"));
// now check if the current time is after openingstime AND smaller than closing hours of tomorrow
if (
(date("H:i") > $opening_hours[$today] &&
((date("Y-m-d H:i") < date("Y-m-d H:i", strtotime('tomorrow +'.intval($closing_hours[$today]).' hours'))))
) ||
date("H:i") < $closing_hours[$today] &&
((date("Y-m-d H:i") < date("Y-m-d H:i", strtotime('today +'.intval($opening_hours[$today]).' hours'))))
) {
$label = "label-success";
$label_text = "OPEN";
$label_time = $closing_hours[$today];
} else {
$label = "label-danger";
$label_text = "GESLOTEN";
$label_time = $opening_hours[$today];
}
?>

Answer 6

I tried this code for a day several different ways and found this to be a solution for me. Posting it in case it might help others. It is important to convert the time from AM/PM format back to UNIX time.
I use times pulled from a database so you would have to define $startTime and $endTime.
// define each days time like so
$monsta = "07:00 AM";
$monend = "05:00 PM";
$storeSchedule = [
'Mon' => ["$monsta" => "$monend"],
'Tue' => ["$tuessta" => "$tuesend"],
'Wed' => ["$wedssta" => "$wedsend"],
'Thu' => ["$thurssta" => "$thursend"],
'Fri' => ["$frista" => "$friend"],
'Sat' => ["$satsta" => "$satend"],
'Sun' => ["$sunsta" => "$sunend"]
];
// default time zone
$timestamp = time() - 18000;
// default status
$status = 'Closed';
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times
$startTime = strtotime($startTime);
$endTime = strtotime($endTime);
// check if current time is within a range
if ($startTime <= $timestamp && $timestamp <= $endTime ) {
$status = 'Open';
}
}
echo '<p><b>Today\'s Hours</b><br />'.$days[$d].'<br />';
echo "<b>We are currently: $status </b></p>";

Answer 7

Here is my version since the 12hr time format does not work for me.
Note that $pancits[] came from my database
$status = 'Closed';
// get current time object
$timestamp = time();
// $currentTime = (new DateTime())->setTimestamp($timestamp);
$currentTime = date('H:i');
$startTime = date('H:i', strtotime($pancits['p_oTime']));
$endTime = date('H:i', strtotime($pancits['p_cTime']));
if (($startTime <= $currentTime) && ($currentTime <= $endTime)) {
$status = 'Open';
//echo $status;
}
echo "<b>Currently $status</b>";
echo '
<p><b>Time Open: </b>'.date('h:ia', strtotime($pancits['p_oTime'])).'</p>
<p><b>Time Close: </b>'.date('h:ia', strtotime($pancits['p_cTime'])).'</p>
';

Answer 8

I would suggest making use of PHP's DateTime class. It was developed to solve all these problems by giving a simple interface for hard to accomplish tasks like this.