I want to pass area name selected from drop down menu to query of MySQL through PHP. I retrieved name in JavaScript but I am unable to store value from JavaScript to PHP. My Code is As follows
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title></title>
<script>
function getIndex()
{
var x=document.getElementById("cmbArea").selectedIndex;
var y=document.getElementById("cmbArea").options
var z= y[x].text;
alert(z);
}
</script>
</head>
<body>
<form name ="form1" action="Demo1.php" method="post">
<select id="cmbArea" name="cmbArea">
<?php
include 'Connect.php';
$query = "SELECT varAreaName FROM tbArea" ;
$result = mysql_query($query);
while($row = mysql_fetch_assoc( $result )) {
echo '<option value="'.$row['varAreaName'].'">' . $row['varAreaName'] . '</option>';
}
?>
</select>
</form>
<input type="Button" onclick="getIndex()" value="Alert index of selected option">
</body>
</html>
You need to post your form. The value will be available in $_POST['cmbArea'].
If I am understanding you correctly I would use AJAX in this case. Something like this: http://openenergymonitor.org/emon/node/107
Yes, you can not 'store' value from javascript to PHP, as javascript is in client-side(literally in your Browser-side), not in the server-side.
You need to post the data using ajax(Jquery ajax may be), and post them in JSON format.
Check this thread..
PHP will run on server and then javascript will be run on the browser. So you cannot do both in the same page, as you try.
I think the best way is to submit the form, and read the value there using PHP. There you can execute your query.
If you don't want to submit you can check AJAX which will send an asynchronous server side request, without refreshing the webpage.
Related
I want the variables like screen width screen height color depth and pixel depth to be used in a PHP function. Basically what I want to do is when user come in my webpage eg:localhost/try.php I want to know all above mentioned details of client without setting cookies or session properties or get parameters. Yeah and of course without reloading the page. I know php but not AJAX so can anyone help me with that?
if i understood it right, your question is When user comes to your page(e.g try.php)how to pass javascript variable(e.g screen.width screen.height) to PHP section so that you can make it as a PHP variable.
Here is a working solution.
try.php
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form action="" method="POST" name="myForm" id="myForm">
<input type="hidden" id="screenWidth" name="screenWidth">
<input type="hidden" id="screenHeight" name="screenHeight">
</form>
<script type="text/javascript">
document.getElementById("screenWidth").value = screen.width;
document.getElementById("screenHeight").value = screen.height;
function autoSubmit ()
{
let form = document.getElementById("myForm");
form.submit();
}
window.onload = autoSubmit;
</script>
</body>
</html>
<?php
if($_SERVER["REQUEST_METHOD"] === 'POST')
{
if(!empty($_POST["screenWidth"]))
{
$screenWidth = $_POST["screenWidth"];
echo $screenWidth; // see if it gets the screen.width
}
if(!empty($_POST["screenHeight"]))
{
$screenHeight = $_POST["screenHeight"];
echo $screenHeight; // see if it gets the screen.height
}
}
?>
It basically manipulate the DOM and change the value of input value to be the screen.width and screen.height and then submit the form automatically when the window is onload.
If the the server received an HTTP POST method input then it checks the name of the POST inputs and save it into each PHP variables.
I want to pass JavaScript variables to PHP using a hidden input in a form.
But I can't get the value of $_POST['hidden1'] into $salarieid. Is there something wrong?
Here is the code:
<script type="text/javascript">
// View what the user has chosen
function func_load3(name) {
var oForm = document.forms["myform"];
var oSelectBox = oForm.select3;
var iChoice = oSelectBox.selectedIndex;
//alert("You have chosen: " + oSelectBox.options[iChoice].text);
//document.write(oSelectBox.options[iChoice].text);
var sa = oSelectBox.options[iChoice].text;
document.getElementById("hidden1").value = sa;
}
</script>
<form name="myform" action="<?php echo $_SERVER['$PHP_SELF']; ?>" method="POST">
<input type="hidden" name="hidden1" id="hidden1" />
</form>
<?php
$salarieid = $_POST['hidden1'];
$query = "select * from salarie where salarieid = ".$salarieid;
echo $query;
$result = mysql_query($query);
?>
<table>
Code for displaying the query result.
</table>
You cannot pass variable values from the current page JavaScript code to the current page PHP code... PHP code runs at the server side, and it doesn't know anything about what is going on on the client side.
You need to pass variables to PHP code from the HTML form using another mechanism, such as submitting the form using the GET or POST methods.
<DOCTYPE html>
<html>
<head>
<title>My Test Form</title>
</head>
<body>
<form method="POST">
<p>Please, choose the salary id to proceed result:</p>
<p>
<label for="salarieids">SalarieID:</label>
<?php
$query = "SELECT * FROM salarie";
$result = mysql_query($query);
if ($result) :
?>
<select id="salarieids" name="salarieid">
<?php
while ($row = mysql_fetch_assoc($result)) {
echo '<option value="', $row['salaried'], '">', $row['salaried'], '</option>'; //between <option></option> tags you can output something more human-friendly (like $row['name'], if table "salaried" have one)
}
?>
</select>
<?php endif ?>
</p>
<p>
<input type="submit" value="Sumbit my choice"/>
</p>
</form>
<?php if isset($_POST['salaried']) : ?>
<?php
$query = "SELECT * FROM salarie WHERE salarieid = " . $_POST['salarieid'];
$result = mysql_query($query);
if ($result) :
?>
<table>
<?php
while ($row = mysql_fetch_assoc($result)) {
echo '<tr>';
echo '<td>', $row['salaried'], '</td><td>', $row['bla-bla-bla'], '</td>' ...; // and others
echo '</tr>';
}
?>
</table>
<?php endif?>
<?php endif ?>
</body>
</html>
Just save it in a cookie:
$(document).ready(function () {
createCookie("height", $(window).height(), "10");
});
function createCookie(name, value, days) {
var expires;
if (days) {
var date = new Date();
date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
expires = "; expires=" + date.toGMTString();
}
else {
expires = "";
}
document.cookie = escape(name) + "=" + escape(value) + expires + "; path=/";
}
And then read it with PHP:
<?PHP
$_COOKIE["height"];
?>
It's not a pretty solution, but it works.
There are several ways of passing variables from JavaScript to PHP (not the current page, of course).
You could:
Send the information in a form as stated here (will result in a page refresh)
Pass it in Ajax (several posts are on here about that) (without a page refresh)
Make an HTTP request via an XMLHttpRequest request (without a page refresh) like this:
if (window.XMLHttpRequest){
xmlhttp = new XMLHttpRequest();
}
else{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
var PageToSendTo = "nowitworks.php?";
var MyVariable = "variableData";
var VariablePlaceholder = "variableName=";
var UrlToSend = PageToSendTo + VariablePlaceholder + MyVariable;
xmlhttp.open("GET", UrlToSend, false);
xmlhttp.send();
I'm sure this could be made to look fancier and loop through all the variables and whatnot - but I've kept it basic as to make it easier to understand for the novices.
Here is the Working example: Get javascript variable value on the same page in php.
<script>
var p1 = "success";
</script>
<?php
echo "<script>document.writeln(p1);</script>";
?>
Here's how I did it (I needed to insert a local timezone into PHP:
<?php
ob_start();
?>
<script type="text/javascript">
var d = new Date();
document.write(d.getTimezoneOffset());
</script>
<?php
$offset = ob_get_clean();
print_r($offset);
When your page first loads the PHP code first runs and sets the complete layout of your webpage. After the page layout, it sets the JavaScript load up.
Now JavaScript directly interacts with DOM and can manipulate the layout but PHP can't - it needs to refresh the page. The only way is to refresh your page to and pass the parameters in the page URL so that you can get the data via PHP.
So, we use AJAX to get Javascript to interact with PHP without a page reload. AJAX can also be used as an API. One more thing if you have already declared the variable in PHP before the page loads then you can use it with your Javascript example.
<?php $myname= "syed ali";?>
<script>
var username = "<?php echo $myname;?>";
alert(username);
</script>
The above code is correct and it will work, but the code below is totally wrong and it will never work.
<script>
var username = "syed ali";
var <?php $myname;?> = username;
alert(myname);
</script>
Pass value from JavaScript to PHP via AJAX
This is the most secure way to do it, because HTML content can be edited via developer tools and the user can manipulate the data. So, it is better to use AJAX if you want security over that variable. If you are a newbie to AJAX, please learn AJAX it is very simple.
The best and most secure way to pass JavaScript variable into PHP is via AJAX
Simple AJAX example
var mydata = 55;
var myname = "syed ali";
var userdata = {'id':mydata,'name':myname};
$.ajax({
type: "POST",
url: "YOUR PHP URL HERE",
data:userdata,
success: function(data){
console.log(data);
}
});
PASS value from JavaScript to PHP via hidden fields
Otherwise, you can create a hidden HTML input inside your form. like
<input type="hidden" id="mydata">
then via jQuery or javaScript pass the value to the hidden field. like
<script>
var myvalue = 55;
$("#mydata").val(myvalue);
</script>
Now when you submit the form you can get the value in PHP.
I was trying to figure this out myself and then realized that the problem is that this is kind of a backwards way of looking at the situation. Rather than trying to pass things from JavaScript to php, maybe it's best to go the other way around, in most cases. PHP code executes on the server and creates the html code (and possibly java script as well). Then the browser loads the page and executes the html and java script.
It seems like the sensible way to approach situations like this is to use the PHP to create the JavaScript and the html you want and then to use the JavaScript in the page to do whatever PHP can't do. It seems like this would give you the benefits of both PHP and JavaScript in a fairly simple and straight forward way.
One thing I've done that gives the appearance of passing things to PHP from your page on the fly is using the html image tag to call on PHP code. Something like this:
<img src="pic.php">
The PHP code in pic.php would actually create html code before your web page was even loaded, but that html code is basically called upon on the fly. The php code here can be used to create a picture on your page, but it can have any commands you like besides that in it. Maybe it changes the contents of some files on your server, etc. The upside of this is that the php code can be executed from html and I assume JavaScript, but the down side is that the only output it can put on your page is an image. You also have the option of passing variables to the php code through parameters in the url. Page counters will use this technique in many cases.
PHP runs on the server before the page is sent to the user, JavaScript is run on the user's computer once it is received, so the PHP script has already executed.
If you want to pass a JavaScript value to a PHP script, you'd have to do an XMLHttpRequest to send the data back to the server.
Here's a previous question that you can follow for more information: Ajax Tutorial
Now if you just need to pass a form value to the server, you can also just do a normal form post, that does the same thing, but the whole page has to be refreshed.
<?php
if(isset($_POST))
{
print_r($_POST);
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="text" name="data" value="1" />
<input type="submit" value="Submit" />
</form>
Clicking submit will submit the page, and print out the submitted data.
We can easily pass values even on same/ different pages using the cookies shown in the code as follows (In my case, I'm using it with facebook integration) -
function statusChangeCallback(response) {
console.log('statusChangeCallback');
if (response.status === 'connected') {
// Logged into your app and Facebook.
FB.api('/me?fields=id,first_name,last_name,email', function (result) {
document.cookie = "fbdata = " + result.id + "," + result.first_name + "," + result.last_name + "," + result.email;
console.log(document.cookie);
});
}
}
And I've accessed it (in any file) using -
<?php
if(isset($_COOKIE['fbdata'])) {
echo "welcome ".$_COOKIE['fbdata'];
}
?>
Your code has a few things wrong with it.
You define a JavaScript function, func_load3(), but do not call it.
Your function is defined in the wrong place. When it is defined in your page, the HTML objects it refers to have not yet been loaded. Most JavaScript code checks whether the document is fully loaded before executing, or you can just move your code past the elements it refers to in the page.
Your form has no means to submit it. It needs a submit button.
You do not check whether your form has been submitted.
It is possible to set a JavaScript variable in a hidden variable in a form, then submit it, and read the value back in PHP. Here is a simple example that shows this:
<?php
if (isset($_POST['hidden1'])) {
echo "You submitted {$_POST['hidden1']}";
die;
}
echo <<<HTML
<form name="myform" action="{$_SERVER['PHP_SELF']}" method="post" id="myform">
<input type="submit" name="submit" value="Test this mess!" />
<input type="hidden" name="hidden1" id="hidden1" />
</form>
<script type="text/javascript">
document.getElementById("hidden1").value = "This is an example";
</script>
HTML;
?>
You can use JQuery Ajax and POST method:
var obj;
$(document).ready(function(){
$("#button1").click(function(){
var username=$("#username").val();
var password=$("#password").val();
$.ajax({
url: "addperson.php",
type: "POST",
async: false,
data: {
username: username,
password: password
}
})
.done (function(data, textStatus, jqXHR) {
obj = JSON.parse(data);
})
.fail (function(jqXHR, textStatus, errorThrown) {
})
.always (function(jqXHROrData, textStatus, jqXHROrErrorThrown) {
});
});
});
To take a response back from the php script JSON parse the the respone in .done() method.
Here is the php script you can modify to your needs:
<?php
$username1 = isset($_POST["username"]) ? $_POST["username"] : '';
$password1 = isset($_POST["password"]) ? $_POST["password"] : '';
$servername = "xxxxx";
$username = "xxxxx";
$password = "xxxxx";
$dbname = "xxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO user (username, password)
VALUES ('$username1', '$password1' )";
;
if ($conn->query($sql) === TRUE) {
echo json_encode(array('success' => 1));
} else{
echo json_encode(array('success' => 0));
}
$conn->close();
?>
Is your function, which sets the hidden form value, being called? It is not in this example. You should have no problem modifying a hidden value before posting the form back to the server.
May be you could use jquery serialize() method so that everything will be at one go.
var data=$('#myForm').serialize();
//this way you could get the hidden value as well in the server side.
This obviously solution was not mentioned earlier. You can also use cookies to pass data from the browser back to the server.
Just set a cookie with the data you want to pass to PHP using javascript in the browser.
Then, simply read this cookie on the PHP side.
We cannot pass JavaScript variable values to the PHP code directly... PHP code runs at the server side, and it doesn't know anything about what is going on on the client side.
So it's better to use the AJAX to parse the JavaScript value into the php Code.
Or alternatively we can make this done with the help of COOKIES in our code.
Thanks & Cheers.
Use the + sign to concatenate your javascript variable into your php function call.
<script>
var JSvar = "success";
var JSnewVar = "<?=myphpFunction('" + JSvar + "');?>";
</script>`
Notice the = sign is there twice.
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now </button>
<script type="text/javascript">
function funk(){
alert("asdasd");
<?php echo "asdasda";?>
}
</script>
When the button is pressed I want to execute PHP code (at this point to echo asadasda)
You could use http://phpjs.org/ http://locutus.io/php/ it ports a bunch of PHP functionality to javascript, but if it's just echos, and the script is in a php file, you could do something like this:
alert("<?php echo "asdasda";?>");
don't worry about the shifty-looking use of double-quotes, PHP will render that before the browser sees it.
as for using ajax, the easiest way is to use a library, like jQuery. With that you can do:
$.ajax({
url: 'test.php',
success: function(data) {
$('.result').html(data);
}
});
and test.php would be:
<?php
echo 'asdasda';
?>
it would write the contents of test.php to whatever element has the result class.
Interaction of Javascript and PHP
We all grew up knowing that Javascript ran on the Client Side (ie the browser)
and PHP was a server side tool (ie the Server side). CLEARLY the two just cant interact.
But -- good news; it can be made to work and here's how.
The objective is to get some dynamic info (say server configuration items) from the server into the Javascript environment so it can be used when needed - - typically this implies DHTML modification to the presentation.
First, to clarify the DHTML usage I'll cite this DHTML example:
<script type="text/javascript">
function updateContent() {
var frameObj = document.getElementById("frameContent");
var y = (frameObj.contentWindow || frameObj.contentDocument);
if (y.document) y = y.document;
y.body.style.backgroundColor="red"; // demonstration of failure to alter the display
// create a default, simplistic alteration usinga fixed string.
var textMsg = 'Say good night Gracy';
y.write(textMsg);
y.body.style.backgroundColor="#00ee00"; // visual confirmation that the updateContent() was effective
}
</script>
Assuming we have an html file with the ID="frameContent" somewhere,
then we can alter the display with a simple < body onload="updateContent()" >
Golly gee; we don't need PHP to do that now do we! But that creates a structure for
applying PHP provided content.
We change the webpage in question into a PHTML type to allow the server side PHP access
to the content:
**foo.html becomes foo.phtml**
and we add to the top of that page. We also cause the php data to be loaded
into globals for later access - - like this:
<?php
global $msg1, $msg2, $textMsgPHP;
function getContent($filename) {
if ($theData = file_get_contents($filename, FALSE)) {
return "$theData";
} else {
echo "FAILED!";
}
}
function returnContent($filename) {
if ( $theData = getContent($filename) ) {
// this works ONLY if $theData is one linear line (ie remove all \n)
$textPHP = trim(preg_replace('/\r\n|\r|\n/', '', $theData));
return "$textPHP";
} else {
echo '<span class="ERR">Error opening source file :(\n</span>'; # $filename!\n";
}
}
// preload the dynamic contents now for use later in the javascript (somewhere)
$msg1 = returnContent('dummy_frame_data.txt');
$msg2 = returnContent('dummy_frame_data_0.txt');
$textMsgPHP = returnContent('dummy_frame_data_1.txt');
?>
Now our javascripts can get to the PHP globals like this:
// by accessig the globals
var textMsg = '< ? php global $textMsgPHP; echo "$textMsgPHP"; ? >';
In the javascript, replace
var textMsg = 'Say good night Gracy';
with:
// using php returnContent()
var textMsg = '< ? php $msgX = returnContent('dummy_div_data_3.txt'); echo "$msgX" ? >';
Summary:
the webpage to be modified MUST be a phtml or some php file
the first thing in that file MUST be the < ? php to get the dynamic data ?>
the php data MUST contain its own css styling (if content is in a frame)
the javascript to use the dynamic data must be in this same file
and we drop in/outof PHP as necessary to access the dynamic data
Notice:- use single quotes in the outer javascript and ONLY double quotes in the dynamic php data
To be resolved: calling updateContent() with a filename and
using it via onClick() instead of onLoad()
An example could be provided in the Sample_Dynamic_Frame.zip for your inspection, but didn't find a means to attach it
You can't run PHP with javascript. JavaScript is a client side technology (runs in the users browser) and PHP is a server side technology (run on the server).
If you want to do this you have to make an ajax request to a PHP script and have that return the results you are looking for.
Why do you want to do this?
If you just want to echo a message from PHP in a certain place on the page when the user clicks the button, you could do something like this:
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now</button>
<div id="resultMsg"></div>
<script type="text/javascript">
function funk(){
alert("asdasd");
document.getElementById('resultMsg').innerHTML('<?php echo "asdasda";?>');
}
</script>
However, assuming your script needs to do some server-side processing such as adding the item to a cart, you may like to check out jQuery's http://api.jquery.com/load/ - use jQuery to load the path to the php script which does the processing. In your example you could do:
<button type="button" id="okButton" onclick="funk()" value="okButton">Order now</button>
<div id="resultMsg"></div>
<script type="text/javascript">
function funk(){
alert("asdasd");
$('#resultMsg').load('path/to/php/script/order_item.php');
}
</script>
This runs the php script and loads whatever message it returns into <div id="resultMsg">.
order_item.php would add the item to cart and just echo whatever message you would like displayed. To get the example working this will suffice as order_item.php:
<?php
// do adding to cart stuff here
echo 'Added to cart';
?>
For this to work you will need to include jQuery on your page, by adding this in your <head> tag:
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js"></script>
Any server side stuff such as php declaration must get evaluated in the host file (file with a .php extension) inside the script tags such as below
<script type="text/javascript">
var1 = "<?php echo 'Hello';?>";
</script>
Then in the .js file, you can use the variable
alert(var1);
If you try to evaluate php declaration in the .js file, it will NOT work
put your php into a hidden div and than call it with javascript
php part
<div id="mybox" style="visibility:hidden;"> some php here </div>
javascript part
var myfield = document.getElementById("mybox");
myfield.visibility = 'visible';
now, you can do anything with myfield...
We can use php in JavaScript by creating a form element and put the action as a .php page.
Then we use JavaScript to submit that form.
EX:
<!doctype html>
<html>
<head>
<title>PHP Executed with JS</title>
</head>
<body>
<form action="phpCode.php" id="phpCode">.
</form> <!-- This is the form-->
<script>
function runPhp() {
var php =
document.getElementById("phpCode")
php.submit() //submit the form
}
</script>
</body>
The PHP file name would be phpCode.php.
In that file would be your PHP code.
May be this way:
<?php
if($_SERVER['REQUEST_METHOD']=="POST") {
echo 'asdasda';
}
?>
<form method="post">
<button type="submit" id="okButton">Order now</button>
</form>
If you do not want to include the jquery library you can simple do the following
a) ad an iframe, size 0px so it is not visible, href is blank
b) execute this within your js code function
window.frames['iframename'].location.replace('http://....your.php');
This will execute the php script and you can for example make a database update...
Use ajax to send request and echo the response
when successfully executed. Like this:
$.get("site.com/ajax", function(status,data){
alert(status);
});
This can be achieved with jquery library.
You could run PHP at the start of the Page and grap the results from inputs
<?php
c = a * b;
?>
<input type="hidden" name="c" value="<?php c ?>"/>
<button type="submit">Submit</button>
</form>
<script>
let cValue = $('input[name="c"]').val();
alert(cValue);
</script>
Right now, I have variables that default to the current d/m/y, which is then popped into a mySQL query that displays all data from a table WHERE date='$dday' AND month='$dmonth' AND year='$dyear'.
$ddate = date("d");
$dmonth = date("m");
$dyear = date("Y");
Instead, I'd like to have a select box that will change the variables based on the option selected. So the default option for the Day select will be the current date, but if I change that to day 12 for example, I want the variable to change when the select option changes, and then re-query the database automatically. I'm assuming this would be done with AJAX.
Is what I'm talking about even possible? If the automation of the query adds a big layer of complexity, I'd be fine with just changing the variable and updating based on the press of a submit button.
I promise to take a break from asking questions and start answering some, if questions below my simple level are even asked.
Yes, this is possible. jQuery even makes it easy.
Create your <select> element and give it an ID so it can be used in jQuery.
Add an event listener in jQuery that is fired when the <select> changes, like $("#date").change().
In the event handler for the change event, get the current value of the <select>, and then use jQuery's AJAX $.post() function to send that data to a PHP file.
In that PHP file, sanitize the data to prevent MySQL Injections, and then query the database for the new data.
Use PHP's echo function to send back the data.
In the jQuery $.post() callback function (third parameter), receive the echoed data and put it into a variable.
Use jQuery to update your HTML with the data.
Both of the solutions you suggest would work. You can send the values from the select box to a php script using AJAX, or you could just submit the form and access them that way via $_POST or $_GET depending on your form method.
Heres an example, ill leave you to do the query:
<?php
//Some pseudo data kinda as your receive it from your query
$datafromSql = array(
array('id'=>1,'date'=>1,'month'=>1,'year'=>2012,'theData'=>'This is some data when the user select 1/1/2012'),
array('id'=>2,'date'=>2,'month'=>2,'year'=>2012,'theData'=>'This is some data when the user select 2/2/2012'),
array('id'=>3,'date'=>3,'month'=>3,'year'=>2012,'theData'=>'This is some data when the user select 3/3/2012'),
);
//Super simple API to access the data
if($_SERVER['REQUEST_METHOD']=='POST' && isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest'){
header('Content-Type: text/html');
//pseudo code, really you would just format your query result
$return=array();
foreach($datafromSql as $row){
//Select all from array which match select choice
if($row['date']==$_POST['day'] || $row['month']==$_POST['month'] || $row['year']==$_POST['year']){
$return[]=$row['theData'].'<br />';
}
}
//output, with a fancy horizontal rule
echo implode('<hr />',$return);
die;
}?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.7.2.min.js" charset="utf-8"></script>
<script type="text/javascript">
function update(){
$.post('./<?php echo basename(__FILE__)?>',
{
day: $("#day").val(),
month: $("#month").val(),
year: $("#year").val()
},
function(data) {
$('#result').replaceWith('<div id="result"><h1>The Result:</h1>'+ data +'</div>');
});
}
$(document).ready(function(){
update();
});
</script>
</head>
<body>
<form id="dateform" >
<p>Select Date:
<select size="1" name="day" id="day" onChange="update()">
<?php foreach(range(1,31) as $i){echo '<option value="'.$i.'">'.$i.'</option>';} ?>
</select>
<select size="1" name="month" id="month" onChange="update()">
<?php foreach(range(1,12) as $i){echo '<option value="'.$i.'">'.$i.'</option>';} ?>
</select>
<select size="1" name="year" id="year" onChange="update()">
<?php foreach(range(2008,2012) as $i){echo '<option value="'.$i.'">'.$i.'</option>';} ?>
</select>
</p>
</form>
<p id='result'></p>
</body>
</html>
I have the following code to get the selected item value and post it to a DIV. That is okay, it is working fine, my DIV shows the selected value. But my question is how can I use that value in the DIV ? so that I can create a php msyql query.
<head>
<style>
.response {
padding:10px;
background-color:#9F9;
border:2px solid #396;
margin-bottom:20px;
}
</style>
<script type="text/javascript" src="jquery.js"></script>
<script>
$(document).ready(function(){
$("#developer").change(onSelectChange);
});
function onSelectChange(){
var selected = $("#developer option:selected");
var output = "";
if(selected.val() != 0){
output = selected.val();
}
$("#output").html(output);
$('#output').slideDown("slow");
}
</script>
</head>
<select id="developer">
<option value="0">Select</option>
<option value="1">name</option>
<option value="2">name2</option>
</select>
<div align=center class=response id=output style="display:none;">
<?php
$sql = "SELECT * FROM users WHERE name='$name'";
$result = mysql_query($sql) or die("err");
while($row=mysql_fetch_array($result)){
$age = $row[age]; }
echo $age;
?>
</div>
Javascript executes on the front-end, in the user's browser. PHP and mysql are executed on the backend, on your server. If you want to use values from your javascript in PHP and mysql, you will need to make a request to the back-end.
You should read up on
http://api.jquery.com/jQuery.ajax/
and/or
http://api.jquery.com/jQuery.post/
The answer to your question is that you submit the form or send an ajax request back to your server. Your server using PHP, in your case, uses that data to form the DB query.
I think that you are mixing up the timing for when this code is being run.
PHP process and sends to Html loads
Javascript runs (hopefully after
HTML loads) Request is submited from
HTML or Javascript Back to the top
I think you can use $("#output").text(output) instead of $("#output").html(output).
Then you can use $("#output").text(output) to get the value your need.