jQuery .Post after javascript:submit_contact() - php

I'm trying to submit a little contact form.
Here is my jquery to POST:
<script>
$(document).ready(function(){
function submit_contact()
{
$.post("http://www.domain.com/wp-content/themes/toronto/handlers/contact.php", {
contact_text: $("[name='contact_text']").val(),
contact_email: $("[name='contact_email']").val(),
}, function(data){
console.log( data );
});
}
});
</script>
Here is my html that handles the form:
<form method="post" >
<textarea id="contact_me_text" name="contact_text">Ask me anything!</textarea>
<div>
<input type="text" name="contact_email" value="Email"/><br/><br/>
<a id="contact_submit" href="javascript:submit_contact()">Submit</a>
</div>
</form>
Everything seems to look ok but the form is not submitting. I've run the .php file through a regular submit and it works fine.
Any thoughts?

You need to declare your function outside of $(document).ready() and then call it using anything.
Why can't I ?
As Local Variables cannot be accessed from outside, similarly local functions cannot also be accessed.

Try this:
<script>
$(document).ready(function(){
function submit_contact()
{
$.post("http://www.domain.com/wp-content/themes/toronto/handlers/contact.php", {
contact_text: $("[name='contact_text']").val(),
contact_email: $("[name='contact_email']").val(),
}, function(data){
console.log( data );
});
}
$('#contact_submit').on('click', function(){
submit_contact();
return false;
});
});
</script>
and then remove the JS inside HREF attribute.

You need to declare the function outside ready function of jQuery. Moreover you can use serializeArray to determine data to send. By using this you will not need to mention every control name. On server side you can receive the input with same names you have mentioned in your form.
function submit_contact()
{
var params = $("#formId").serializeArray();
$.post("http://www.domain.com/wp-content/themes/toronto/handlers/contact.php", params, function(data){
console.log( data );
});
}

Related

Getting jquery to work with dynamic content

I am currently using a very similar AJAX post request across many parts of my page:
$(document).ready(function() {
$("#name").change(function(e){
var vname = $("#name").val();
$.post("addit.php", {name:vname}, function(response, status) {
$("#table").html(response);
});
});
});
The above code works perfectly.
I am having a problem getting any functionality with dynamically loaded content. So for example a form grabbed by an AJAX call and put into my page this above does not work.
If we can pretend that I was running the same AJAX call as above but on dynamically loaded content from a PHP script using AJAX. what would my call look like. #table is a static element that is always present on the page.
I have tried this but it is not working:
$(document).ready(function() {
$("#table").on("click", "#btn1", function(e){
e.preventDefault();
var vname = $("#name").val();
$.post("addit.php", {name:vname}, function(response, status) {
$("#table").html(response);
});
});
});
Currently I am getting nothing show up on console and it just does not work.
Is what I am doing here correct?
The html would look like this: echoed from php:
<table id='table'>//this is the static element form is echoed
<form method='post'>
<input id='name' name = 'name'>
<button id='btn1' type='submit'>Add me</button>
</form>
</table>
I have changed my code slightly click on button rather than on change.
Try updating the code with following
$(document).ready(function() {
$("#table #btn1").on("click", function(e){
e.preventDefault();
var vname = $("#name").val();
$.post("addit.php", {name:vname}, function(response, status) {
$("#table").html(response);
});
});
});
It is not possible to set a function on a dynamically added element, when the element is not there in document
And instead of <table> use <div> if possible
I think your problem is that you miss
$( document ).ajaxComplete(function() { "script here will run and be available after ajax load" });

Simple ajax code not working?

<form>
<input type="text" id="user"/>
<input type="button" value="Submit" onClick="post();" />
</form>
<div id="result"> </div>
<script type="text/javascript">
function post()
{
var username = $('#user').val();
$.post('battlephp.php',
{postuser:user}
)
}
</script>
Its a simple Ajax code.. It should take username and display the Php code!
But don't know why its not running?? Actually I am learning...so I cant rectify the error or fault??
I am running ii on localhost.. so is there any problem with using:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
display the Php code
No, it shouldn't.
First, you've changed your mind about the variable name you are using (user, username) half way through your script, so you are going to throw a reference error.
Second, you haven't provided a function (the third argument) to $.post, so you aren't doing anything (such as displaying it) with the returned data.
Third, the server should execute the PHP and return its output. You shouldn't get the actual PHP code.
function post() {
var username = $('#user').val();
$.post(
'battlephp.php',
{postuser:username}, // Be consistent about your variable names
function (data) {
alert(data);
}
);
}
Instead
document.ready()
you can use
jQuery(function($){...});
Try to do this:
<script>
$(document).ready(function() {
function post() {
var username = $('#user').val();
$.ajax({
type : 'post',
url : 'batttlephp.php',
data : {
postuser : user
},
success : function(data) {
alert(data);
},
error : function(data) {
alert(data);
}
});
});
});
</script>
if you're doing a ajax request then is good also handle success and error...
Also I suggest to you "to start the document".
Try the code above and let us know if worked

How to pass php variables to jquery AJAX?

I have started learning jquery AJAX. I have run into a problem, and was wondering if you guys could help me. I am trying to pass a php variable back to jquery, but it displays as [object Object]. I will be posting my code below.
index.html:
<!DOCTYPE html>
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js">
</script>
<script>
$(document).ready(function(){
$("button").click(function() {
$("p").text($.get("return.php"));
});
});
</script>
</head>
<body>
<p>This is a test!</p>
<button>Click Here</button>
</body>
</html>
return.php:
<?php
$message = "Another test!";
echo $message;
?>
So what is it that I need to do to pass php variable $message into the paragraph using jquery ajax?
I know I could simply do if I changed index.html to index.php, but then if $message later changes, I have to reload the page. I am trying to learn how to make dynamic content without having to reload the page.
Thanks ahead of time for any help you provide! :-)
You'll have to wait until the data is returned before you can use it:
$(document).ready(function(){
$("button").click(function() {
$.get("return.php", function(data) {
$("p").text(data);
});
});
});
Add a callback to get.
$.get("return.php", function(data) {
$("p").text(data);
});
You can use callback function in .get function.
$(document).ready(function(){
$("button").click(function() {
$.get("return.php",function(data){
$("p").text(data);
});
});
});
Here you can pass the datatype as well in which form you want the response from server.
Suppose you want to return anyother datatype(i.e. json)from server, just use datatype with it like this :
$(document).ready(function(){
$("button").click(function() {
$.get("return.php",function(data){
$("p").text(data);
},"json");
});
});
For more detail,refer : http://api.jquery.com/jQuery.get/

jquery form submit does not work after using a load function

I have an index.html page which, using jquery, calls somepage.php residing within the same site to load the contents of this index.html page.
So this is the intended page load sequence:
index.html -> somepage.php -> submit.php (if submit button is clicked)
The index.html has only the "main-div" and no contents as such. When the somepage.php is called, the "main-div" contents are loaded by running the php script. The main-div contains a sub div with a small form with a submit button. Using jQuery,I see if the submit button is clicked, and when clicked, the submit.php script is called.
This is the barebone code:
<!DOCTYPE html>
<html>
<head>
<script src="js/jquery.js"></script>
<script>
$('document').ready(function(){
$("#main-div").load("http://www.someurl.com/somepage.php");
$('#item-submit').click(function(){
jsURL = $('#input').val();
submit(jsURL);
});
function submit(jsURL){
$.get(
'http://www.someurl.com/submit.php',
{ item: jsURL },
function(data){
if(data=="success")
{
$('#submit-status').html(data);
}
else
{
$('#submit-status').html(data);
}
}
);
}
});
</script>
</head>
<body>
<div id="main-div"> </div>
</body>
</html>
Now the issue:
The index.html page loads with everything displayed correctly (the small form with the submit button, all other main-div contents, everything is displayed). However, the submit button does not call the submit.php script, meaning I believe that the jQuery code corresponding to the click event is not being registered.
I am fairly new to jQuery. Does this have something to do with how I have "ordered" the code in the jQuery .ready()? Something to do with the DOM not being ready before the function is called, or maybe an issue with the .load() in jQuery?
Try this :
<script>
$(document).ready(function(){
$("#main-div").load("http://www.someurl.com/somepage.php",function(){
$("#main-div").on('click', '#item-submit', function(e){
e.preventDefault();
var jsURL = $('#input').attr('value');
submit(jsURL);
});
});
});
function submit(jsURL){
$.ajax({
url:'http://www.someurl.com/submit.php',
type :'GET',
success: function(data){
$('#submit-status').html(data);
}
});
}
</script>
$(document).ready(function(){
$("#main-div").load("http://www.someurl.com/somepage.php");
$("#main-div").on('click', '#item-submit', function(e){
e.preventDefault();
var jsURL = $('#input').val();
submit(jsURL);
});
function submit(jsURL){
$.get('http://www.someurl.com/submit.php', {item: jsURL}, function(data){
$('#submit-status').html(data);
});
}
});
Do not quote the document
load() is a shortcut for $.ajax, and it's async, so #item-submit does'nt exist when you attach the event handler, you need a delegated event handler for that.
If it's really a submit button inside a form, make you sure you prevent the default action so the form does'nt get submitted.
The load function works asynchronously. With your code #item-submit is not yet there when you try to bind the event handler.
Bind the event handler on succes:
$("#main-div").load("http://www.someurl.com/somepage.php", function () {
$('#item-submit').click(function () {
jsURL = $('#input').val();
submit(jsURL);
});
});
load loads the data asynchronously, which means time by the time you are assigning a click handler on submit button the button itself might not be yet on the page. To overcome this you have two options:
Specify a success handler for load.
$("#main-div").load("http://www.someurl.com/somepage.php", function(){
$('#item-submit').click(function(){
jsURL = $('#input').val();
submit(jsURL);
});
});
Use on to indicate that the click handler should be assigned to elements that are or will be on the page.
$('#item-submit').on('click', function(){
jsURL = $('#input').val();
submit(jsURL);
});
As all pointed out, the load function works asynchronously so, your click handler is not working for the 'future' div.
You can bind handler to a future element like this:
$(document).on('click', '#item-submit', function(event){
jsURL = $('#input').val();
submit(jsURL);
});
This way you can bind your handler in the jQuery document ready function.

is the browser or server ignoring the code?

i made this form:
<form id="form" name="msgform" method="" action="">
<input type="text" size="40" id="msg" name="message"/>
<input type="submit" id="button" name="clicker" value="click" />
</form>
and this jquery script:
$(document).ready(function(){
$("#button").click(function(){
$("#form).submit(function(){
var submision= $("#form).val();
$.post("txt/process.php", submision, function(data){
alert(data);
});
});
});
});
and this is the process.php file:
<?php
echo $_POST['message'] . "";
?>
now when i click the button the form is submited, but it sends it using the GET method because i can see it in the adress bar, but it never gets sent to the php file, and i checked to see if the names are correct and if i specify the POST method it still doesnt go to the php file.
is the server or browser ignoring the code? or am i doing the whole thing wrong?
thanks
Please find the following code, it works and please go through with the documentation, it will tell you that what the mistake was being done.
$(document).ready(function(){
$("#button").click(function(){
$("#form").submit(function(){
/* var submision= $("#form).val();
THIS DOESN'T WORK TO GET ALL OF THE ELEMENTS IN
FORMAT TO PASS TO $.post EVENT,
We can do this as I did in following example
*/
$.post("txt/process.php", { msg: $("#msg").val() }, function(data){
alert(data);
});
/* Also you didn't put return false statement just at the end
of submit event which stops propagating this event further.
so it doesn't get submitted as usually it can be without ajax,
So this stops sending the form elements in url. This was because
by default if you define nothing in method property for form
then it consider it as GET method.
*/
return false;
});
});
});
Let me know please you are facing any issue.
You don't need to register the submit event for the form inside the click handler of the button. As it is a submit button it will automatically try to submit the form for which you register the corresponding handler:
$(function() {
$('#form').submit(function() {
// Get all the values from the inputs
var formValues = $(this).serialize();
$.post('txt/process.php', formValues, function(data) {
alert(data);
});
// Cancel the default submit
return false;
});
});
$("#form).submit(function(){
see if this selector is missing a "
$("#form").submit(function(){

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