Reading through several posts, I have got the basic idea of creating google charts but I am still not clear with how it is created from data extracted from tables in DB. Some json parsing of objects is done, but not clear with it. I have written some code. Please provide me with some direction ahead.
//chartDraw.php
<html>
<head>
<!--Load the AJAX API -->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>">
<script type="text/javascript">
//Load the visualization API and the piechart package
google.load('visualization','1',{'packages':['corechart']});
//Set a callback to run when the google visualization API is loaded
google.setOnLoadCallback(drawchart);
function drawChart(){
var jsonData = $.ajax({
url:"getdata.php",
dataType:"json",
async:false
}).responseText;
//Create our data table out of JSON data loaded from server
var data=new google.visualization.DataTable(jsonData);
//Instantiate and draw our chart, passing in some options
var chart=new google.visualization.PieChart(document.getElementById('chart_div'));
chart.draw(data,{width:400,height:240});
}
</script>
</head>
<body>
<!--Div that will hold the pie chart -->
<div id="chart_div"></div>
</body>
</html>
//getdata.php specified in the url property
<?php
mysql_connect('localhost','uname','123456');
mysql_select_db('rcusers');
$sqlquery1="select userid,group_name,req_nodes,actualPE from jobs where userid='zhang' limit 200";
$sqlresult1=mysql_query($sqlquery1);
while($row=mysql_fetch_assoc($sqlresult1)){
$userDetails[]=$row;
}
?>
What next and How am I supposed to send the data to json objects and where? I am confused..
This simple example may be help you
<html>
<head>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready( function() {
$('#test').click(function() {
$.ajax({
type: 'POST',
url: 'fetch_data.php',
dataType: 'json',
cache: false,
success: function(result) {
var data = google.visualization.arrayToDataTable([
['T', result[0]],
['W', result[1]],
['E', result[2]]
]);
var options = {
title: 'My Daily Activities'
};
var chart = new google.visualization.PieChart(document.getElementById('chart_div'));
chart.draw(data, options);
},
});
});
});
</script>
</head>
<body>
<div id="chart_div" style="width: 900px; height: 500px;"></div>
click
</body>
</html>
fecth_data.php
<?php
$array = array(1,2,3,4);
echo json_encode($array);
?>
Related
I'm trying to get a Graph from mySQL database, but somehow it doesn't show a graph on my webpage.
This is the graph.html file, which should be showing the graph on the webpage.
<h1>Graphs</h1>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<title>
Google Visualization API Sample
</title>
<script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load('visualization', '1', {packages: ['corechart']});
</script>
<script type="text/javascript">
function drawVisualization() {
var jsonData = null;
var json = $.ajax({
url: "data.php", // make this url point to the data file
dataType: "json",
async: false,
success: (
function(data) {
jsonData = data;
})
}).responseText;
// Create and populate the data table.
var data = new google.visualization.DataTable(jsonData);
// Create and draw the visualization.
var chart= new google.visualization.LineChart(document.getElementById('visualization')).
draw(data, {curveType: "function",
width: 500, height: 400,
vAxis: {maxValue: 10}}
);
}
google.setOnLoadCallback(drawVisualization);
</script>
</head>
<body style="font-family: Arial;border: 0 none;">
<div id="visualization" style="width: 500px; height: 400px;"></div>
</body>
</html>
In the browser I get an error saying:
Uncaught (in promise) TypeError: $.ajax is not a function and
Error: Could not establish connection. receiving end does not exist.
Any idea how to fix this?
Thanks.
Edit:
In the head I've changed: <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script> to <script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script> <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script> <script type="text/javascript"></script>, I tought i used a slim version of jquery, so i've chand the head of the html file, but it still doesn't work.
I tried downloading jquery using npm install jquery, but that doesn't do anything for either.
Most of my code for the html page is from https://developers.google.com/chart/interactive/docs/php_example.
So i'm kind of lost where to look for errors.
I'm creating a simple bar chart using Google Charts with the data fetched from Mysql Database. The chart is displayed properly but I'm unable to format the title of the graph. I have referred to many sites and I'm sure the syntax for 'titleTextStyle' is fine. But the title does not change with the options at all. Can somebody tell me where the problem lies ?
I have attached my full code below.
Thanks in advance.
<?php
include("toconnect.php");
$result = mysqli_query($connection,"SELECT Product_name,COUNT(*) FROM Items_Sold GROUP BY Product_name");
?>
<!DOCTYPE html>
<html lang="en">
<head>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {'packages':['bar']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = google.visualization.arrayToDataTable([
['Product Name', 'Frequency'],
<?php
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result))
{
echo "['".$row["Product_name"]."','".$row["COUNT(*)"]."'],";
}
}
?>
]);
var options = {
chart: {
title: "Frequently Bought items",titleTextStyle:{ color: '#007DB0',fontName: "Times",fontSize: 60,bold: true},
}
};
var chart = new google.charts.Bar(document.getElementById('columnchart_material'));
chart.draw(data, google.charts.Bar.convertOptions(options));
}
</script>
</head>
<body>
<div id="columnchart_material" style="width: 800px; height: 500px;display:inline-block;"></div>
</body>
</html>
you are working with a material chart...
google.charts.Bar
the list of features not working in Material charts can be found here...
Tracking Issue for Material Chart Feature Parity #2143
which includes...
titleTextStyle
try working with a classic chart instead...
google.visualization.ColumnChart
with option...
theme: 'material'
I'm trying to get Google Charts to work from a MySQL DB.
I've created an array & can see that it is populated, when viewing source on the live page
However, the chart doesn't appear. Would anyone be able to advise me why this might be?
Head Script
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart);
function drawChart() {
var data = google.visualization.arrayToDataTable([
['Date', 'Total Orders'],
['2017-9-6',200],['2017-8-6',1500],['2017-7-7',800],['2017-7-3',1,800],['2017-7-2',200],['2017-6-13',10000],['2017-10-5',800],['2017-10-12',4,500],['',],
]);
var options = {
title: 'Orders Per Day'
};
var chart = new google.visualization.ColumnChart(document.getElementById("columnchart"));
chart.draw(data, options);
}
</script>
Body Script
<h3>Column Chart</h3>
<div id="columnchart" style="width: 900px; height: 500px;"></div>
I'm trying to keep true to the DRY principle by moving my jquery auto complete code to a scripts.js file but i'm having trouble getting the auto complete functionality to work when i move it.
Here's how its setup at the moment.
add form
<head>
<?php
require_once ('includes/connect-db.php');
require_once ('includes/functions.php');
?>
<link href="css/jquery-ui-1.8.21.custom.css" rel="stylesheet" type="text/css">
<script type="text/javascript" src="includes/js/jquery-ui-1.8.21.custom.min.js"></script>
<script type="text/javascript">
$('document').ready(function() {
$('#datepickerID').datepicker({
changeYear:true,
changeMonth:true,
dateFormat:'yy-mm-dd'
})
<?php $productArray = autoComplete();?>
$(function() {
var js_products_array = <?php echo json_encode($productArray); ?>;
$( "#autocompleteID" ).autocomplete({
source: js_products_array
});
});
});
</script>
</head>
I'm uncertain as to how to get this to work between the addForm.php and scripts.js when there is embeded php code in the javascript, if that makes sense.
You will have to keep js_products_array outside of the .js file as it contains data from PHP scripts and initilize the autocomplete() on document ready.
so you can keep only
<?php $productArray = autoComplete();?>
<script type="text/javascript">
var js_products_array = <?php echo json_encode($productArray); ?>;
</script>
and in your file.js you can add
$('document').ready(function() {
$('#datepickerID').datepicker({
changeYear:true,
changeMonth:true,
dateFormat:'yy-mm-dd'
})
$( "#autocompleteID" ).autocomplete({
source: js_products_array
});
});
i want that when we click on Ajax 1 then content of ajax1 is change but Ajax 2 will remain same and vice verse plz help i want to do that with jquery
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#pas").click(function(){
$.ajax({url:"001.php?q=1 & l=111", success:function(result){
$("#pas").html(result);
}});
});});
</script>
</head>
<body>
<div id="pas"><h2>AJAX 1</h2></div>
<div id="pas"><h2> AJAX2 </h2></div>
</body>
</html>
Two elements cannot have the same id. You should change to using classes.
<div class="pas"><h2>AJAX 1</h2></div>
<div class="pas"><h2> AJAX2 </h2></div>
Once you've done that, you can use this to target the correct item.
$(document).ready(function(){
$(".pas").click(function(){
var $this = $(this); // "this" is the clicked element
$.ajax({url:"001.php?q=1 & l=111", success:function(result){
$this.html(result);
}});
});
});
you have to differentiate div's ids: give them two different id (i.e. pas1 and pas2 ) and same class 'pas', then fire actions on div.pas
Don't use duplicated id's, use class instead. Use a refference to the clicked object to update your content. Here is your modified code:
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("div").click(function(){
var _this = this;
$.ajax({url:"001.php?q=1 & l=111", success:function(result){
$(_this).html(result);
}});
});});
</script>
</head>
<body>
<div><h2>AJAX 1</h2></div>
<div><h2> AJAX2 </h2></div>
</body>
</html>