jquery ajax delete record - php

I am trying to delete a value in a comma seperated string in a table. The script that does this (delete_url.php) works fine on it's own if I set the post values manually, but I'm having a problem passing those values to the script with ajax. In the page that I want to pass the values from I have:
<script type="text/javascript">
$(document).ready(function() {
$('.delete').click(function() {
$.ajax({
type: 'POST',
url: '../scripts/delete_link.php',
data: 'link=' + $(this).attr('data_link') + '&topic_pk=' + $(this).attr('data_topic'),
success: function() {
}
});
});
});
</script>
And:
<a class='delete_link' href='#' data_link='<?php echo urlencode($link); ?>' data_topic='<?php echo $topic_pk; ?>' onclick="return confirm('Are you certain you want to DELETE this link?')";><img src="../images/delete.png" width="16" height="16" alt="delete" title="delete this link" border='0' /></a>
I probably should be using json, but not sure of the correct way to do this. Thanks for any help.

I have updated my code with the folowing and now works deleting the record and removing the entry on the page:
<script type="text/javascript">
$(document).ready(function(){
$('table#delTable td a.delete_link').click(function()
{
if (confirm("Are you sure you want to delete this row?"))
{
var id = $(this).parent().parent().attr('id');
var data = 'id=' + id ;
var parent = $(this).parent().parent();
$.ajax(
{
type: "POST",
url: '../scripts/delete_link.php',
data: 'link=' + $(this).attr('data_link') + '&topic_pk=' + $(this).attr('data_topic') + '&topic_introduction=' + $(this).attr('data_introduction'),
cache: false,
success: function()
{
parent.fadeOut('fast', function() {$(this).remove();});
}
});
}
});
});
</script>
And the table:
<table id='delTable' width="100%" border="0" cellpadding="5">
<?php
if(!empty($retrieved_links)){
foreach($retrieved_links as $link){
?>
<tr>
<td><?php echo $link; ?></td>
<td width='16' align='center' valign='middle'><a class='delete_link' href='#' data_link='<?php echo urlencode($link); ?>' data_topic='<?php echo $topic_pk; ?>' data_introduction='<?php echo $topic_introduction; ?>'><img src="../images/delete.png" width="16" height="16" alt="delete" title="delete this link" border='0' /></a></td>
</tr>
<?php }
}
?>
</table>
And delete_link.php:
<?php
require_once('../connection/connect.php');
mysql_select_db($database, $connection);
$link = urldecode($_POST['link']);
$topic_pk = $_POST['topic_pk'];
$topic_introduction = $_POST['topic_introduction'];
if(!empty($link)){
$query_get_topic = "SELECT * FROM topic WHERE topic_pk = '$topic_pk'";
$result_get_topic = mysql_query($query_get_topic, $connection) or die(mysql_error());
$row_get_topic = mysql_fetch_assoc($result_get_topic);
$retrieved_links = explode(",", $row_get_topic['links']);
$delete_link = array_search($link,$retrieved_links);
unset($retrieved_links[$delete_link]);
$updated_links = mysql_real_escape_string(implode(',',$retrieved_links));
$links_body = str_replace(',', '<p>', $updated_links);
$topic = $topic_introduction . '<p>' . $links_body;
$query = "UPDATE topic SET links = '$updated_links', topic = '$topic' WHERE topic_pk = '$topic_pk'";
$result = mysql_query($query, $connection) or die(mysql_error());
}
mysql_close();
?>

Related

Php ajax update button not working in jquery [duplicate]

list.php: A simple ajax code that I want to display only records of the Mysql table:
<html>
<head>
<script src="jquery-1.9.1.min.js">
</script>
<script>
$(document).ready(function() {
var response = '';
$.ajax({
type: "GET",
url: "Records.php",
async: false,
success: function(text) {
response = text;
}
});
alert(response);
});
</script>
</head>
<body>
<div id="div1">
<h2>Let jQuery AJAX Change This Text</h2>
</div>
<button>Get Records</button>
</body>
</html>
Records.php is the file to fetch records from Mysql.
In the Database are only two fields: 'Name', 'Address'.
<?php
//database name = "simple_ajax"
//table name = "users"
$con = mysql_connect("localhost","root","");
$dbs = mysql_select_db("simple_ajax",$con);
$result= mysql_query("select * from users");
$array = mysql_fetch_row($result);
?>
<tr>
<td>Name: </td>
<td>Address: </td>
</tr>
<?php
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>$row[1]</td>";
echo "<td>$row[2]</td>";
echo "</tr>";
}
?>
This code is not working.
For retrieving data using Ajax + jQuery, you should write the following code:
<html>
<script type="text/javascript" src="jquery-1.3.2.js"> </script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
For mysqli connection, write this:
<?php
$con=mysqli_connect("localhost","root","");
For displaying the data from database, you should write this :
<?php
include("connection.php");
mysqli_select_db("samples",$con);
$result=mysqli_query("select * from student",$con);
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($data = mysqli_fetch_row($result))
{
echo "<tr>";
echo "<td align=center>$data[0]</td>";
echo "<td align=center>$data[1]</td>";
echo "<td align=center>$data[2]</td>";
echo "<td align=center>$data[3]</td>";
echo "<td align=center>$data[4]</td>";
echo "</tr>";
}
echo "</table>";
?>
You can't return ajax return value. You stored global variable store your return values after return.
Or Change ur code like this one.
AjaxGet = function (url) {
var result = $.ajax({
type: "POST",
url: url,
param: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
success: function (data) {
// nothing needed here
}
}) .responseText ;
return result;
}
Please make sure your $row[1] , $row[2] contains correct value, we do assume here that 1 = Name , and 2 here is your Address field ?
Assuming you have correctly fetched your records from your Records.php, You can do something like this:
$(document).ready(function()
{
$('#getRecords').click(function()
{
var response = '';
$.ajax({ type: 'POST',
url: "Records.php",
async: false,
success : function(text){
$('#table1').html(text);
}
});
});
}
In your HTML
<table id="table1">
//Let jQuery AJAX Change This Text
</table>
<button id='getRecords'>Get Records</button>
A little note:
Try learing PDO http://php.net/manual/en/class.pdo.php since mysql_* functions are no longer encouraged..
$(document).ready(function(){
var response = '';
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
response = text;
}
});
alert(response);
});
needs to be:
$(document).ready(function(){
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
alert(text);
}
});
});
This answer was for #
Neha Gandhi but I modified it for people who use pdo and mysqli sing mysql functions are not supported. Here is the new answer
<html>
<!--Save this as index.php-->
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
<?php
// save this as display.php
// show errors
error_reporting(E_ALL);
ini_set('display_errors', 1);
//errors ends here
// call the page for connecting to the db
require_once('dbconnector.php');
?>
<?php
$get_member =" SELECT
empid, lastName, firstName, email, usercode, companyid, userid, jobTitle, cell, employeetype, address ,initials FROM employees";
$user_coder1 = $con->prepare($get_member);
$user_coder1 ->execute();
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($row =$user_coder1->fetch(PDO::FETCH_ASSOC)){
$firstName = $row['firstName'];
$empid = $row['empid'];
$lastName = $row['lastName'];
$cell = $row['cell'];
echo "<tr>";
echo "<td align=center>$firstName</td>";
echo "<td align=center>$empid</td>";
echo "<td align=center>$lastName </td>";
echo "<td align=center>$cell</td>";
echo "<td align=center>$cell</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
// save this as dbconnector.php
function connected_Db(){
$dsn = 'mysql:host=localhost;dbname=mydb;charset=utf8';
$opt = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
#echo "Yes we are connected";
return new PDO($dsn,'username','password', $opt);
}
$con = connected_Db();
if($con){
//echo "me is connected ";
}
else {
//echo "Connection faid ";
exit();
}
?>

Delete Records From Database Using jQuery

I want to add a delete button to this table, to delete the query from Database. I have the Ajax and PHP codes here :
<?php
require_once 'dbconfig.php';
$stmt = $pdo->prepare("SELECT * FROM test");
$stmt->execute();
while($row=$stmt->fetch(PDO::FETCH_ASSOC))
{
?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['server']; ?></td>
<td><?php echo $row['reference']; ?></td>
<td align="center"><a id="<?php echo $row['id']; ?>" class="delete-link" href="#" title="Delete">
<img src="images/delete.png" width="20px" />
</a></td>
</tr>
<?php
}
?>
the ajax :
$(document).ready(function(){
/* Data Delete Starts Here */
$(".delete-link").click(function()
{
var id = $(this).attr("id");
var del_id = id;
var parent = $(this).parent("td").parent("tr");
if(confirm('Sure to Delete ID no = ' +del_id))
{
$.post('delete.php', {'del_id':del_id}, function(data)
{
parent.fadeOut('slow');
});
}
return false;
});
/* Data Delete Ends Here */
});
delete.php :
<?php
include_once 'dbconfig.php';
if($_POST['del_id'])
{
$id = $_POST['del_id'];
$stmt=$db_con->prepare("DELETE FROM test WHERE id=:id");
$stmt->bindParam(':id', $id);
$stmt->execute();
}
?>
The row selected doesn't seem to get DELETED in the DB ... i have no error too.
You had pass data incorrectly . Please try this
$(document).ready(function()
{
$('table#delTable td a.delete').click(function()
{
if (confirm("Are you sure you want to delete this row?"))
{
var id = $(this).parent().parent().attr('id');
var data = 'id=' + id ;
var parent = $(this).parent().parent();
$.ajax(
{
type: "POST",
url: "view.php",
data: {id:id},
cache: false,
success: function()
{
parent.fadeOut('slow', function() {$(this).remove();});
}
});
}
});
});

jQuery code does not work after resetting a div's content twice

There is a div element :
...
<div id="liste_secteurs"></div>
...
<script type="text/javascript">
$(document).ready(function() {
rechercheSecteursEtProduits(0); // setting the div's content
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
});
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html); // this is the div element
}
</script>
Code of ListerProduitsUserParSecteursAjax.php :
<?php
... // getting database data
?>
<p>Total : <?php echo $nr; ?></p>
<div><img src="<?php echo HTTP_ICON.'plus.png'; ?>" /></div>
<?php echo $paginationDisplay; ?>
<table id="table" class="data display " >
<thead style="background-color:#CCC">
<tr>
<th><?php echo _getText("service.produit.form.secteur_activite");?></th>
<th><?php echo _getText("service.produit.form.titre");?></th>
<th></th>
<th><?php if($data["secteur"]["cnt"] > 0){ ?><input type="checkbox" id="check_all"><?php }?></th>
</tr>
</thead>
<tbody style="background-color:#FFF">
<?php
if($data["secteur"]["cnt"] > 0){
for($i=0;$i<$data["secteur"]["cnt"];$i++){?>
<tr class="odd gradeX">
<td><?php echo $data["secteur"][$i]["secta_lib_fr"] ?></td>
<td><?php echo $data["secteur"][$i]["produit_lib"] ?></td>
<td align="center" style="vertical-align:middle"><img src="<?php echo HTTP_ICON.'edit.png'; ?>" alt="<?php echo _getText('main.btn.modifier'); ?>" style="height:10px;width:10px;" /></td>
<td align="center" style="vertical-align:middle"><input type="checkbox" id="prod_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_produit']; ?>"><input type="hidden" id="secteur_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_secteur']; ?>"></td>
</tr>
<?php } ?>
<?php
}
else{
?>
<tr class="odd gradeX">
<td colspan="4" align="center"><b><?php echo _getText('main.liste.no_data'); ?></b></td>
</tr>
<?php }?>
</tbody>
</table>
<?php if($data["secteur"]["cnt"] > 0){ ?>
<div align="right"><input name="btnSupprimer" id="btnSupprimer" type="button" value="<?php echo _getText("main.btn.delete"); ?>" class="btn btn-blue"/></div>
<?php } ?>
<?php echo $paginationDisplay; ?>
When the page loads for the first time then the delete button works fine : the selected rows are deleted , and the list reappears accordingly to new database data. But later when I want to delete other rows then the alert does not show when I check some checkboxes and clicking the delete button !
So what is wrong in my approach ?
From what I am reading you are having problems with the row that are added from the database.
What could be the problem is when you execute this peace of code:
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
When you call the $.click() function you add a event to all the existing DOM object that have a id of 'btnSupprimer', however this doesn't update if you add a new DOM object. So what you should do is call this function every time you add a new row. you would get something like this:
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').click(addClickHandler()); // this is the div element
}
function addClickHandler(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
}
I hope it helps
Try using on instead of click as below
$('#btnSupprimer').on("click","#liste_secteurs",function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
Use the dynamic jquery selector instead of the regular 'click' event
$('#liste_secteurs').on('click', '#btnSupprimer', function() {});
// $("container").on("event", "button", function() {});
As from Caveman's answer I made some updates :
function rechercheSecteursEtProduits(pn) {
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_usermer="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').on('click',function(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
if (confirm("Do you want to remove these records ?")) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0);
}
}
});
}
And it works !

Ajax not sending var to url php

i am trying to send the variables to server but url does not go to the php file.. What am i doing wrong? Is it because i am not using a submit button? Here is my code..
<table id="table">
<?php for($i=0; $i<$totalbesin; $i++) { ?>
<tr>
<td class="td" id="<?php echo "name".$i?>"><?php echo $besin[$i]['n']?></td>
<td class="td" id="<?php echo "kal".$i?>"><?php echo $besin[$i]['kal']?></td>
<td class="td" id="<?php echo "pro".$i?>"><?php echo $besin[$i]['pro']?></td>
<td class="td" id="<?php echo "kar".$i?>"><?php echo $besin[$i]['kar']?></td>
<td class="td" id="<?php echo "yag".$i?>"><?php echo $besin[$i]['yag']?></td>
<td class="ekle" id="yuk<?php echo $i?>">Ekle</td>
</tr>
<script type="text/javascript" >
$(function() {
$("#yuk<?php echo $i?>").click(function()
{
var name = $("#<?php echo "name".$i?>").val();
var kal = $("#<?php echo "kal".$i?>").val();
var pro = $("#<?php echo "pro".$i?>").val();
var kar = $("#<?php echo "kar".$i?>").val();
var yag = $("#<?php echo "yag".$i?>").val();
var dataString = '&name='+ name + '&kal=' + kal + '&pro=' + pro + '&kar=' + kar + '&yag=' + yag;
$.ajax({
type: "POST",
url: "dietup.php",
data: dataString,
cache: false,
success: function(html){
$("span#sonuc").text("<?php echo $i?>");
}
});
return false;
}); });
</script>
<?php } ?>
</table>
you need to change the val() to text(); like below as"td" tags not having an value tag
var name = $("#<?php echo "name".$i?>").text();
var kal = $("#<?php echo "kal".$i?>").text();
var pro = $("#<?php echo "pro".$i?>").text();
var kar = $("#<?php echo "kar".$i?>").text();
var yag = $("#<?php echo "yag".$i?>").text();
Take a look at ajaxForm & ajaxSubmit, otherwise you need a submit button.
http://malsup.com/jquery/form/
Try this
$.ajax({
type: "POST",
url: "dietup.php",
data: {
name: name,
kal: kal,
pro: pro
//and so on
},
cache: false,
success: function(html){
$("span#sonuc").text("<?php echo $i?>");
}
});
Use this to set the value into your variables:
var name = $("#name<?php echo$i?>").val();
var kal = $("#kal<?php echo $i?>").val();
var pro = $("#pro<?php echo $i?>").val();
var kar = $("#kar<?php echo $i?>").val();
var yag = $("#yag<?php echo $i?>").val();
In your code, as I understand, it seems that you are trying to assign values to your javscript variables using php.
There is a problem with syntax where you are assigning the values to your javscript variables.
Notice the following snippet from your code below:
var name = $("#<?php echo "name".$i?>").val();
var kal = $("#<?php echo "kal".$i?>").val();
var pro = $("#<?php echo "pro".$i?>").val();
var kar = $("#<?php echo "kar".$i?>").val();
var yag = $("#<?php echo "yag".$i?>").val();
Does anything seems not right?
Gotcha!!!! You are using double quotes to assign value in to your jquery selector and as well as for the php echo statement which is terminating your double quote.
Try using single quotes for the jquery selector and double quotes for the php echo statement as follows:
var name = $('#<?php echo "name".$i?>').val();
First of all, ajax parameter data must be object, not url string. If you want to send string url, add url string to url like this:
$.ajax({
url: "dietup.php?&name='+ name + '&kal=' + kal + '&pro=' + pro + '&kar=' + kar + '&yag=' + yag;"
})
But it will be wrong approach
I have divided yours script into two logical components.
First: is php loop generates the html table
Second: javascript function, who's sending ajax request
<table id="table">
<?php for($i=0; $i<$totalbesin; $i++) { ?>
<tr rel="<?php echo $i ?>">
<td class="td name" id="<?php echo "name".$i?>"><?php echo $besin[$i]['n']?></td>
<td class="td kal" id="<?php echo "kal".$i?>"><?php echo $besin[$i]['kal']?></td>
<td class="td pro" id="<?php echo "pro".$i?>"><?php echo $besin[$i]['pro']?></td>
<td class="td kar" id="<?php echo "kar".$i?>"><?php echo $besin[$i]['kar']?></td>
<td class="td yag" id="<?php echo "yag".$i?>"><?php echo $besin[$i]['yag']?></td>
<td class="ekle" id="yuk<?php echo $i?>">Ekle</td>
</tr>
<?php } ?>
</table>
<script type="text/javascript" >
$(function() {
$(".ekle").click(function()
{
var parent = $(this).closest('tr');
var data = {
name: parent.find('.name').val(),
kal: parent.find('.kal').val(),
pro: parent.find('.pro').val(),
kar: parent.find('.kar').val(),
yag: parent.find('.yag').val()
};
$.ajax({
type: "POST",
url: "dietup.php",
data: data,
cache: false,
success: function(html){
$("span#sonuc").text(parent.attr('rel'));
}
});
return false;
});
});
</script>
I found the problem.. It is because it does not get data from td, i tried getelementById but it did not work either.. Then i used
var name = '<?php echo $besin[$i]['n']?>';
and put the data in var like this.. Now it works.. Thank you for your time.. It would be better if i could get the data from td but its ok for now.. :)
I have a similar script, hope this help you:
<script type="text/javascript">
$(function() {
$("#yuk<?php echo $i?>").click(function(event)
{
var name = $("#<?php echo "name".$i?>").text();
var kal = $("#<?php echo "kal".$i?>").text();
var pro = $("#<?php echo "pro".$i?>").text();
var kar = $("#<?php echo "kar".$i?>").text();
var yag = $("#<?php echo "yag".$i?>").text();
var dataString = 'name='+ name + '&kal=' + kal + '&pro=' + pro + '&kar=' + kar + '&yag=' + yag;
//Uncomment to check the querystring
//alert("dietup.php?"+dataString);
$.ajax({
url:"dietup.php?"+dataString,
type:'GET',
dataType:'text',
cache:false,
success:function(data){
alert (data);
},
error:function(jxhr){
alert('Ops, error: '.jxhr.responseText);
}
}); //End Ajax
}); //End Click Function
}); //End Root Function
And here is the dietup.php example:
<?
//Get the parameters
$name = $_GET['name'];
//Do and return what you need
echo "your name is: ". $name;
?>

Using Jquery Ajax to retrieve data from Mysql

list.php: A simple ajax code that I want to display only records of the Mysql table:
<html>
<head>
<script src="jquery-1.9.1.min.js">
</script>
<script>
$(document).ready(function() {
var response = '';
$.ajax({
type: "GET",
url: "Records.php",
async: false,
success: function(text) {
response = text;
}
});
alert(response);
});
</script>
</head>
<body>
<div id="div1">
<h2>Let jQuery AJAX Change This Text</h2>
</div>
<button>Get Records</button>
</body>
</html>
Records.php is the file to fetch records from Mysql.
In the Database are only two fields: 'Name', 'Address'.
<?php
//database name = "simple_ajax"
//table name = "users"
$con = mysql_connect("localhost","root","");
$dbs = mysql_select_db("simple_ajax",$con);
$result= mysql_query("select * from users");
$array = mysql_fetch_row($result);
?>
<tr>
<td>Name: </td>
<td>Address: </td>
</tr>
<?php
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>$row[1]</td>";
echo "<td>$row[2]</td>";
echo "</tr>";
}
?>
This code is not working.
For retrieving data using Ajax + jQuery, you should write the following code:
<html>
<script type="text/javascript" src="jquery-1.3.2.js"> </script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
For mysqli connection, write this:
<?php
$con=mysqli_connect("localhost","root","");
For displaying the data from database, you should write this :
<?php
include("connection.php");
mysqli_select_db("samples",$con);
$result=mysqli_query("select * from student",$con);
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($data = mysqli_fetch_row($result))
{
echo "<tr>";
echo "<td align=center>$data[0]</td>";
echo "<td align=center>$data[1]</td>";
echo "<td align=center>$data[2]</td>";
echo "<td align=center>$data[3]</td>";
echo "<td align=center>$data[4]</td>";
echo "</tr>";
}
echo "</table>";
?>
You can't return ajax return value. You stored global variable store your return values after return.
Or Change ur code like this one.
AjaxGet = function (url) {
var result = $.ajax({
type: "POST",
url: url,
param: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
success: function (data) {
// nothing needed here
}
}) .responseText ;
return result;
}
Please make sure your $row[1] , $row[2] contains correct value, we do assume here that 1 = Name , and 2 here is your Address field ?
Assuming you have correctly fetched your records from your Records.php, You can do something like this:
$(document).ready(function()
{
$('#getRecords').click(function()
{
var response = '';
$.ajax({ type: 'POST',
url: "Records.php",
async: false,
success : function(text){
$('#table1').html(text);
}
});
});
}
In your HTML
<table id="table1">
//Let jQuery AJAX Change This Text
</table>
<button id='getRecords'>Get Records</button>
A little note:
Try learing PDO http://php.net/manual/en/class.pdo.php since mysql_* functions are no longer encouraged..
$(document).ready(function(){
var response = '';
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
response = text;
}
});
alert(response);
});
needs to be:
$(document).ready(function(){
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
alert(text);
}
});
});
This answer was for #
Neha Gandhi but I modified it for people who use pdo and mysqli sing mysql functions are not supported. Here is the new answer
<html>
<!--Save this as index.php-->
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
<?php
// save this as display.php
// show errors
error_reporting(E_ALL);
ini_set('display_errors', 1);
//errors ends here
// call the page for connecting to the db
require_once('dbconnector.php');
?>
<?php
$get_member =" SELECT
empid, lastName, firstName, email, usercode, companyid, userid, jobTitle, cell, employeetype, address ,initials FROM employees";
$user_coder1 = $con->prepare($get_member);
$user_coder1 ->execute();
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($row =$user_coder1->fetch(PDO::FETCH_ASSOC)){
$firstName = $row['firstName'];
$empid = $row['empid'];
$lastName = $row['lastName'];
$cell = $row['cell'];
echo "<tr>";
echo "<td align=center>$firstName</td>";
echo "<td align=center>$empid</td>";
echo "<td align=center>$lastName </td>";
echo "<td align=center>$cell</td>";
echo "<td align=center>$cell</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
// save this as dbconnector.php
function connected_Db(){
$dsn = 'mysql:host=localhost;dbname=mydb;charset=utf8';
$opt = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
#echo "Yes we are connected";
return new PDO($dsn,'username','password', $opt);
}
$con = connected_Db();
if($con){
//echo "me is connected ";
}
else {
//echo "Connection faid ";
exit();
}
?>

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