I got the time difference between dates like this :
$time1 = "2013-02-25 12:00:00";
$time2 = "2013-01-01 12:00:00";
$tdiff = strtotime($time1) - strtotime($time2);
I want extract days, hours and minutes from $tdiff. Output should like : 35 days 6 hours 14 minutes
I really searched and try to do something by myself. But I can't get true value.
---- EDIT ----
I can found date diff. I want extract days, hours, minutes from calculated time...
---- EDIT 2 ----
Here is my complete mysql code
select (
select avg(UNIX_TIMESTAMP(tarih)) from table1
where action in (6) and who = '".$user."' and dates between '".$date1."' and '".$date."'
) - (
select avg(UNIX_TIMESTAMP(tarih_saat)) from table2
where action in (6) and active = 1 and dates between '".$date1."' and '".$date2."
)
This query returns to me true value of time. This query is working correctly for me. Result is like : 215922. result type of UNIX_TIMESTAPM. So I want to learn how many days, hours and minutes in this timestamp.
PHP has a DateInterval class which can be used like so:
$date1 = new DateTime('2013-02-25 12:00:00');
$date2 = new DateTime('2013-01-01 12:00:00');
$diff = $date2->diff($date1); // Get DateInterval Object
echo $diff->format('%d Day and %h hours and %i minutes');
you could use date object to get more accurate.
the default var type doesnt give the time difference.
most often they are considered as string types when assinged like you did it
Related
So I have a database entry that update the date/time in yyyy-mm-dd hh:mm:ss.
Now I want to check, if there is a space inbetween the the database and the actual time from 60 minutes. How can I do that?
Example:
DB: 2020-02-14 10:00:00
Time now: 2020-02-14 11:01:00
Do something
DB: 2020-02-14 10:00:00
Time now: 2020-02-14 10:59:00
Do nothing
You can use something like this:
$t1 = strtotime( '2006-04-14 11:30:00' );
$t2 = strtotime( '2006-04-12 12:30:00' );
$diff = round(($t1 - $t2) / 3600);
In MySQL, you can do date arithmetics:
update mytable
set mydatetime = now()
where mydatetime <= now() - interval 1 hour and id = ?
The where clause filters on record whose column mydatetimeis more than one hour old. You did not tell what you want to do , so I assumed an update query, that resets the date/time to the current date/time.
This assumes that you want to update the timestamp of a given record, not accross the whole table, hence condition id = ?, which you can adapt - or remove - for your use case.
Hello Schmaniel at first i think you should use Carbon()
https://carbon.nesbot.com/docs/ to get the right results. It's a great way to work with timeformats and timestamps.
$now = Carbon::now();
$dbtime = Carbon::createFromFormat('Y-m-d H:i:s', '1975-05-21 22:10:22');
$totalDuration = $now->diffForHumans($dbtime);
dd($totalDuration);
$currentDate = new DateTime();
$databaseDate = new DateTime($dateFromDatabase);
$interval = $datetime1->diff($datetime2);
Then you can check using the $interval variable
You can use mysql TIMESTAMPDIFF like this:
SELECT TIMESTAMPDIFF(HOUR,'2003-02-01','2003-05-01 12:05:55');
you can use one of the follwing units:
MICROSECOND (microseconds), SECOND, MINUTE, HOUR, DAY, WEEK, MONTH,
QUARTER, or YEAR.
I'm really not grasping how dates and times get formatted in PHP for use in mathematical equations. My goal is this;
Get a date and time from the database;
// Get array for times in
$sth = mysqli_query($conn,"SELECT * FROM ledger ORDER BY ID");
$timeins = array();
while($r = mysqli_fetch_assoc($sth)) {
$timeins[] = $r["timein"];
//OR
array_push($timeins, $r['timein']);
}
And then find the distance between the current time and the variable in the array, $timeins[0], and then put the minutes, hours, and days difference in separate simple variables for later use. These variables will be used on their own in if statements to find out if the person has passed certain amounts of time.
edit: the format of the dates being returned from the DB is in the default TIMESTAMP format for MySQL. E.g. 2018-08-06 17:38:37.
It is also possible to perform datetime operations in SQL, to get a difference between two datetime/timestamp values in days, hours, minutes... We can use expressions in the SELECT list, to return the results as columns in the resultset.
Ditching the SELECT * pattern, and specifying an explicit list of expressions that we need returned:
$sql = "
SELECT t.id
, t.timein
, TIMESTAMPDIFF(DAY ,t.timein,NOW()) AS diff_days
, TIMESTAMPDIFF(HOUR ,t.timein,NOW()) AS diff_hours
, TIMESTAMPDIFF(MINUTE ,t.timein,NOW()) AS diff_minute
FROM ledger t
ORDER BY t.id ";
if( $sth = mysqli_query($conn,$sql) ) {
// execution successful
...
} else {
// handle sql error
}
You should use the DateTime class in PHP to do any date manipulation. You can convert a string representation of a MySQL format time to a PHP DateTime object using
$date = DateTime::createFromFormat('Y-m-d H:i:s', $mysqldate);
Also you can create a DateTime object representing the current time using the constructor with no argument:
$now = new DateTime();
To get the difference between two dates as a DateInterval object, use the builtin diff method:
$diff = $now->diff($date);
As a complete example:
$now = new DateTime();
$mysqldate = '2018-04-03 12:30:01';
$date = DateTime::createFromFormat('Y-m-d H:i:s', $mysqldate);
$diff = $now->diff($date);
$diff_days = (int)$diff->format('%a');
$diff_hours = $diff->h;
$diff_minutes = $diff->m;
echo "$diff_days days, $diff_hours hours, $diff_minutes minutes";
Output:
125 days, 9 hours, 4 minutes
Note that you have to use $diff->format('%a') rather than $diff->d to get the days between two dates, as $diff->d will not include the days in any months between the two dates (in this example it will return 3 for today being August 6).
Using the DateTime Class in php is the best way to get accurate results.
$dateNow = new DateTime('now');
$dateIn = DateTime::createFromFormat('d-m-Y H:i:s', $timeins[0]);
$interval = $dateNow->diff($dateIn);
echo $interval->format('%d days, %h hours, %i minutes, %s seconds');
$deltaDays = $interval->d;
$deltaHours = $interval->h;
...
You have to make sure the input format for you DB date is correct, in this case, I assumed d-m-y H:i:s, and then you can output in any format you need as well, as shown in the date docs: http://php.net/manual/en/function.date.php
I have a couple of columns in my mysql table of datatype time. The times are listed in military hours I believe, and i need get the difference(hours/mins) between the two times in PHP. Example:
MYSQL:
Start_time End_time
08:00:00 09:15:00
In php how can calculate (Start_time) - (End_time) = (result should be in mins).
You can get it in mysql using this.
SELECT TIMESTAMPDIFF(SECOND, column1, column2);
to get it in php see this answer
Getting time difference between two times in PHP
Or use something like the following where you would use the dates you got from mysql as the strings to DateTime.
1 <?php
2
3 $time1 = new DateTime('13:00:59');
4 $time2 = new DateTime('19:01:00');
5 $interval = $time1->diff($time2);
6 print_r($interval->format('%h:%s'));
To get the interval in a different format change the format string. You can find the valid string values in the DateTime documentation here
To get minutes use "%i" or "%l", the latter has leading zeros.
1 <?php
2
3 $time1 = new DateTime('13:00:59');
4 $time2 = new DateTime('19:01:00');
5 $interval = $time1->diff($time2);
6 print_r($interval->format('%l'));
I'm trying to count the rows with a datetime less that 10 minutes ago but the current time its being compared to seems to be 1 hour ahead so Imm getting 0 results, if I go into my table and put some fields forward an hour then I get results.
Getting results:
$stmt = $db->query('SELECT check_log FROM members WHERE check_log >= DATE_SUB(NOW(), INTERVAL 10 MINUTE)');
$row_count = $stmt->rowCount();
echo $row_count.' Members online.';
The datetime of the field of of typing this is 2013-07-11 16:54:12 and I'm getting no results but if I manually change the date time to 2013-07-11 17:54:12 I get 1 result the datetime was input seconds ago using:
$date = date("Y-m-d H:i:s");
The 17:54:12 is my local time and 16:54:12 seem to be my servers time, is my compare trying to look into the future or is it using my local time as a reference?
PHP and MySQL don't agree on the current timezone.
Pass the desired time in as a literal from PHP to SQL instead of using NOW().
Always store date times in php's timezone.
One function you can particularly make use of is strtotime.
$now = strtotime("now"); // current timestamp
$hour_later = strtotime("+1 hour"); // hour later
$now = date("Y-m-d H:i:s", $now);
$hour_later = date("Y-m-d H:i:s", $hour_later);
I was looking at this post, and it is close to what I need:
PHP - How to count 60 days from the add date
However, in that post, the calculation is performed by adding 60 days to the current date. What I need to do is calculate the date based on a variable date (and not the current date).
Something like this:
$my_date = $some_row_from_a_database;
$date_plus_10_days = ???;
Anyone know how to do that?
Thanks
You can put something before the "+10 days" part:
strtotime("2010-01-01 +10 days");
Use date_add
http://www.php.net/manual/en/datetime.add.php
$my_date = new DateTime($some_row_from_a_database);
$date_plus_10_days = date_add($my_date, new DateInterval('P10D'));
You will have to look into strtotime(). I'd imagine your final code would look something like this:
$dateVariable = strtotime('2017-01-29');//your date variable goes here
$date_plus_60_days = date('Y-m-d', strtotime('+ 60 days', $dateVariable));
echo $date_plus_60_days;
If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
$date_plus_60_days = new DateTime("2006-12-12");
$date_plus_60_days->modify("+60 days");
echo $date_plus_60_days->format("Y-m-d");
I see you are retriving data from a database.
If you are using mysql you can do it on the select:
Example: you need the last date of the table and this date-7 days
select max(datefield) as ultimaf, DATE_SUB(max(datefield),INTERVAL 7 DAY) as last7
from table
It´s easy use curdate() if you want todays date.
If you need a dynamic between that selects the count of last 7 days:
select count(*) from table
where DATE_SUB(CURDATE(),INTERVAL 7 DAY)<=datefield"
date('Y-m-d H:i:s', strtotime("2014-11-24 06:33:39" +35 days"))
this will get the calculated date in defined format.
Suppose today's date is
date_default_timezone_set('Asia/Calcutta');
$today=date("Y-m-d");
And i can add 10 days in current date as follows :
$date_afte_10_days = date('Y-m-d', strtotime("$today +10 days"));