Style image from database as background image - php

Question

I want to use the image reference I made in the database as a background: url. I've made the design already => [IMG]http://i49.tinypic.com/30ihudz.png[/IMG]. In my current code I use div style in which I retrieve the image, but that doesn´t show up no image. Could somebody please guide me? Thanks in advance.
public function displayProduct()
{
if($product = $this->db->query("SELECT id, title, description, price, filename FROM trips ORDER BY id"))
{
while ($row = $product->fetch_assoc())
{
$output .= '<div class="reisbox">';
$output .= '<div id="reis_insidebox1" style=" background: url("C:/xampp/htdocs/webshop/public/img/content/"'.$row['filename'].' ") width="1000" height="500">';
$output .= '<div class="reis_textbox">';
$output .= '<h2>'.ucfirst($row['title']).'</h2>';
$output .= '<article>';
$output .= ucfirst($row['description']);
$output .= '</article>';
$output .= '</div>';
$output .= '<div class="rightboxx">';
$output .= '<div class="reis_price_box">';
$output .= '<div class="reis_price_box_text">';
$output .= '€'.$row['price'];
$output .= '</div>';
$output .= '<div class="more_box">';
$output .= '<p>Lees meer..</p>';
$output .= '</div>';
$output .= '</div>';
$output .= '</div>';
$output .='<br />';
$output .= '<div id="add">';
$output .='<p>Add to cart</p>';
$output .= '</div>';
$output .= '</div>';
$output .= '</div>';
}
return $output;
}
}

Answer 1

If you really want to fetch the file from "C:/xampp/.../" you should add a file:/// infront but I guess you simply want to use a relative path, such as "img/content/andthefilenamefromdatabase.png"
And to continue, you are actually closing your style-tag with the " in your CSS background, you might want to use ' there or simply skip the string literal completely
With all this is mind, it could look like so:
$output .= '<div id="reis_insidebox1" style="background: url(\'img/content/'.$row['filename'].'\')" width="1000" height="500">';
Note that I am escaping the ' in the CSS here, using a backslash.