This question already has an answer here:
PHP: getting weekdays numbers of a given month
(1 answer)
Closed 10 years ago.
I am thingking if how to get all the date of weekdays between a given date
example: I have a date given 2013-01-01 and 2013-20-01
It must return all date of weekdays like 2013-01-01
how could this be done using php
thankz
Look into DatePeriod Class, this is available from PHP 5.3.
Here is an example from the site
$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
// You can manipulate the date here
echo $date->format("Ymd") . "<br>";
}
You can get the weekday from the timestamp using the multitude of formatting options avalaible:
echo date("D",strtotime("2013-01-01"));
tues
Related
This question already has answers here:
Get date range between two dates excluding weekends
(4 answers)
Closed 2 years ago.
I want to hide Saturday and Sunday in PHP.
I´ve build the following code:
$begin = new DateTime($row['date']);
$end = new DateTime($row['dateul']);
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
$array[] = $date->format("Y-m-d");
}
Until here the code is working but it outputs the complete week/days in this daterange.
I found this code:
if (strcasecmp($daterange, 'Sun') != 0
&& strcasecmp($daterange, 'Sat') != 0){
}
Do I understand it right, that if value = 1 it will output Saturday for example?
Because the main idea was the following:
if day for example sunday = 0 hide it in array, if sunday=1 show it in array.
The values are coming from MySQL.
You can use the N format for DateTime::format to check the day of week, it returns 6 for Saturday and 7 for Sunday, so as long as the value is less than 6, add it to the array:
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
$array = array();
foreach($daterange as $date){
if ($date->format('N') < 6) {
$array[] = $date->format("Y-m-d");
}
}
Demo on 3v4l.org
Update
Based on comments from the OP, days to be included have $row[<dayname>] = 1. In that case, you can use this foreach loop, using l format to get the full day of week name and strtolower to convert to lowercase to use as an index into $row:
foreach($daterange as $date){
if ($row[strtolower($date->format('l'))]) {
$array[] = $date->format("D Y-m-d");
}
}
Demo on 3v4l.org
This question already has answers here:
PHP: Return all dates between two dates in an array [duplicate]
(26 answers)
Closed 4 years ago.
I want to get all the dates between two given specific dates which will be changing dynamically according to the user requirements.
This works fine for me :
$begin = new DateTime( '2018-07-01' );
$end = new DateTime( '2018-08-10' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
$dates = [];
foreach($daterange as $date){
array_push($dates,$date->format('Y-m-d'));
}
return $dates;
But this gives me NULL array when I insert dates dynamically. For example,
$begin = new DateTime($request->date1);
$end = new DateTime(today());
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
$dates = [];
foreach($daterange as $date){
array_push($dates,$date->format('Y-m-d'));
}
return dates;
I have tried many inputs like storing today's date in a variable, changing it's format and then using that variable as an input. I tried changing date variable to string using (string) function and also I have used Carbon classes for dates, but somehow I am making mistake using DateTime, DateInterval and DatePeriod as I don't know the basics of them.
I need to get all the dates between two specific dates for charts in my admin panel.
Finally got the solution for this question. It worked by converting the dates to UNIX timestamp. Here's the code, how it worked:
$date_from = "2018-07-01";
$date_from = strtotime($date_from); // Convert date to a UNIX timestamp
// Specify the end date. This date can be any English textual format
$date_to = strtotime(today()); // Convert date to a UNIX timestamp
$dates = [];
// Loop from the start date to end date and output all dates inbetween
for ($i=$date_from; $i<=$date_to; $i+=86400) {
array_push($dates,date("Y-m-d", $i));
}
return $dates;
Here is the reference where I found this solution, hope this helps others too.
This question already has answers here:
Checking if there's a leap day in a timerange
(2 answers)
Closed 7 years ago.
How to check if there is Feb 29 in between two dates using php
$fromDate = strtotime($contract->from);
$toDate = strtotime($contract->to);
DateTime, DateInterval and DatePeriod is a good way to work with dates in PHP:
$begin = new DateTime( '2015-12-20' );
$end = new DateTime( '2016-03-10' );
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($begin, $interval, $end);
foreach ( $period as $dt ) {
if(($dt->format('m') === '02') && ($dt->format('d') === '29')) {
echo 'got date February 29th!';
}
}
This script will take first date, last date and loop over the interval day by day to check for the desired date.
This question already has answers here:
How to list all months between two dates
(6 answers)
Closed 7 years ago.
How do I retrieve all the months on 2015-October to 2016-May date range with PHP?
ex - 2015-November, 2015-December, 2016-January.. so on
There is greate example in the PHP docs.
http://php.net/manual/en/class.dateperiod.php
<?php
$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
echo $date->format("Ymd") . "<br>";
}
?>
Just provide the needed date format and you are done.
Change it here:
$date->format("Ymd")
As #Uchiha said there is an answer here:
https://stackoverflow.com/a/18743012/2160958
Is there anyway to find the date difference in php? I have the input of from date 2003-10-17 and todate 2004-03-24. I need the results how many days is there within these two days. Say if 224 days, i need the output in days only.
I find the solution through mysql but i need in php. Anyone help me, Thanks in advance.
$start = new DateTime( '2003-10-17' );
$end = new DateTime( '2004-03-24' );
$diff = $start->diff( $end );
echo $diff->format( '%d days' );
...should do it.
For reference see DateTime and DateInterval.
Mind you though, this is only available as of PHP 5.3.
You can use the parse timestamp feature to convert dates to timestamps, subtract the timestamps, and then convert the resulting timestamp (seconds) to days:
floor((strtotime("2004-03-24") - strtotime("2003-10-17"))/86400);
Example is as below:
$startDate = new DateTime( '2013-04-01' ); //intialize start date
$endDate = new DateTime( '2013-04-30' ); //initialize end date
$holiday = array('2013-04-11','2013-04-25'); //this is assumed list of holiday
$interval = new DateInterval('P1D'); // set the interval as 1 day
$daterange = new DatePeriod($startDate, $interval ,$endDate);
foreach($daterange as $date){
if($date->format("N") <6 AND !in_array($date->format("Y-m-d"),$holiday))
$result[] = $date->format("Y-m-d");
}
echo "<pre>";print_r($result);
A detail blog is here: http://goo.gl/YOsfPX