Use cookie to get id, perform inner join on matching fields - php

Question

This is my first post, but I have found this forum to be very useful! I hope you can help me.
My conundrum is this: I have users log on and then rate each other. Once a user logs in, I want them to be able to see the ratings they made (this one I got working - the reviews I can select by a unique id generated by a form) and also see a summary of the ratings that they have received. This is where it seems to get tricky. I tried an inner join but it didn't produce any results.
Right now I have this part up above my html
<?php
include "connect.php";
if(isset($_COOKIE['ID_my_site']))
{
$username = $_COOKIE['ID_my_site'];
$pass = $_COOKIE['Key_my_site'];
while($info = mysql_fetch_array( $check ))
{
//if the cookie has the wrong password, they are taken to the login page
if ($pass != $info['password'])
{
header("");
}
//otherwise they are shown the admin area
else
{
echo "";
echo "";
}
}
}
else
//if the cookie does not exist, they are taken to the login screen
{
header("");
}
include "settings.php";
?>
And this part after my html
<?php
include('connect.php');
$result = mysql_query("SELECT r.user, r.rating1, r.rating2, r.rating3, u.username
FROM reviews r INNER JOIN users u ON r.user=u.username
WHERE r.user='$userid' ORDER BY r.user DESC")
or die(mysql_error());
echo "<table border='1' cellpadding='10'>";
echo "<tr>
<th></th>
<th>View Comments</th>
<th>Rating 1</th>
<th>Rating 2</th>
<th>Rating 3</th>
</tr>";
while($row = mysql_fetch_array( $result )) {
echo "<tr>";
echo '<td>View/Print</td>';
echo '<td>' . $row['rating1'] . '</td>';
echo '<td>' . $row['rating2'] . '</td>';
echo '<td>' . $row['rating3'] . '</td>';
echo "</tr>";
}
echo "</table>";
?>
Unfortunately, I don't get any results at all, though I see about 20 ratings for this person in the sql table.
It's also throwing a "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in reviews.php on line 19" error.
There's probably a stupid mistake in there, but I'm getting codeblind and frustrated.
Thank you for any help!

Answer 1

if this is line 19:
while($row = mysql_fetch_array( $result )) {
echo "<tr>";
echo '<td>View/Print</td>';
echo '<td>' . $row['rating1'] . '</td>';
echo '<td>' . $row['rating2'] . '</td>';
echo '<td>' . $row['rating3'] . '</td>';
echo "</tr>";
}
you should use the position of the values inside the array like 1,2,3 .. and so on , not ratings1 ,ratings2 .. and so on.