I have a couple functions that are used in multiple controllers in my Symfony project. Instead of copy and pasting them constantly, I'd like to have a separate php file (say functions.php) to store the functions.
I've tried the following:
1) include and require the php file with the functions, but it won't let me use $this->getDoctrine().
I've looked at the following posts for help, but it didn't solve the issue:
Symfony2: get Doctrine in a generic PHP class
Symfony2 Use Doctrine in Service Container
2) I've tried making it a class and having the functions as methods then doing:
$f = new Functions();
$variable = $f->myMethod();
But it returns:
The file was found but the class was not in it, the class name or namespace probably has a typo.
Thanks for any help. I really appreciate it.
UPDATE:
The generic class is Symfony/src/WikiRoster/MainBundle/Controller/DBFunctions.php
I just need to be able to use $this->getDoctrine() or the like somehow in there now. I've tried using the services.yml as suggested in the link above, but no cigar. Thanks!
The file was found but the class was not in it, the class name or
namespace probably has a typo.
This issue happens quite often actually. As the error mentions, there are 2 cases explaining why this error is returned:
If the namespace of your file is not the same as the path of your file
If the name of your file is not the same as the name you are using in your class
Example
Let's say you would like to use a GeneralClass in a different class like that:
use Acme\YourBundle\General\GenericClass
For this to work, GeneralClass needs to be in Acme/YourBundle/General/, and you need to:
use the correct namespace: namespace Acme\YourBundle\General
name your class with the same name: class GenericClass
You would have:
namespace Acme\YourBundle\General;
class GenericClass
{
public function __construct()
{
// some cool stuff
}
}
Related
I have a laravel 4.1 application, and I've created a folder in my app folder to store most of the logic.
/app/Acme/Models/
/app/Acme/Repositories/
these are the two main folders.
In my composer.json I have this in the auto load, and done a dump run.
"psr-4" : {
"Acme\\" : "app/Acme"
}
However I am getting, what I think are silly issues. For example my Acme/Models/Task.php has the following
<?php
namespace Acme\Models;
class Task extends \Eloquent {
public function job()
{
return $this->belongsTo('Job');
}
}
however when I run this, I get an error
Fatal error: Class 'Task' not found in vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php on line 780
In my Job.php I have the same namespace at the top of the file....
Must I manually import/use object which are in the same name space?
use Acme/Models/Job as Job; ? it seems like such a duplicate...
And in my Repositories folder when I set a namespace of namespace Acme/Repositories;, must I use items like
use Acme\Models\Job as Job;
I is, a bit lost!
Namespaces are relative so you do not need to add use to directly reference classes within the same namespace.
The error you are getting is because you need to fully qualify relationships to namespaced models so eloquent knows where to find them eg
$this->belongsTo('\Acme\Models\Jobs');
In the case of your repository namespace, you will need to add a use statement in your file as you suggested, or reference the fully qualified namespace eg new \Acme\Models\Job();
On a side note, I know PHPStorm (and I'm sure other IDEs) will inject the namespaces for you which is super useful and saves you having to write use or the full namespace out every time you reference a class - worth checking out.
Edit: Sorry, I didn't read the question properly first time around - updated my answer.
Im building a custom CMS and have setup an autoloader, and have adapted use of namespaces. For the most part things are loading properly, but in certain cases PHP reports that it cannot find the class, the class file has been included.
Once a file is included (using require), it should be instanced as well.
The parent controller is instanced, then the child controller attempts to instance a few of its own dependencies.
$this->auth = new \Modules\Auth\RT\Auth();
This will look for a file at /modules/auth/rt/auth.php, and it does and the class is instanced properly.
The namespace of Auth is:
namespace Modules\Auth\RT;
The auth class tried to load its own dependencies, a model in particular.
$this->auth_model = new Models\ModelAuth();
Here the file to be included is at /modules/auth/rt/models/modelauth.php
It is included successfully, but this is where PHP says I cannot find this class.
Fatal error: Class 'Modules\Auth\RT\ModelAuth' not found in /Users/richardtestani/Documents/ShopOpen-Master/shopopen/modules/auth/rt/auth.php on line 12
What would cause the class from not being instanced even though the file is included?
Thanks
Rich
try this:
$this->auth_model = new Modules\Auth\RT\Models\ModelAuth();
try this:
$this->auth_model = new \Modules\Auth\RT\Models\ModelAuth();
OR
$this->auth_model = new Models\ModelAuth();
when you are in this namespace \Modules\Auth\RT
There was a Missing \ , so the code trys to include the namespace twice;
FOR REAL ;)
On a web project there are two classes that have the same name. This was never an issue until now, because the two classes where never used at the same time / in the same script.
Now we require to use both classes in one script, and therefor got ourselves an "Cannot redeclare class" fatal error.
My question is: What options are there to resolve this issue?
The one possible solution would be to rename one of the classes in question, but it is something I would very much like to avoid - one of the classes is part of a third-party software that should not be modified at this level, to remain updateable.
I know there are namespaces - are they a valid option to this problem? I have never used namespaces until now.
Assuming we would put one of the classes into a namespace: Would this resolve the issue? Also, what measures would we need to take to access the now-namespaced class?
Namespaces would surely solve your problem.
For example I got multiple classes named 'core', but because they're all classes of a different namespace it doesn't give any conflict at all.
This does mean you have to go over all your code and refer to the namespaced class with the correct path.
$item = new doubleClass();
would become
$item = new \my_namespace\doubleClass();
Also make sure that your other scripts don't get namespaced otherwise it wouldn't be able to find the non namespaced class anymore.
How Namespace work:
consider we have 2 classes named User in file structure
/Package1/User.php
with content
<?php
namespace Package1;
class user {...}
and
/Package2/User.php
with content
<?php
namespace Package2;
class user {...}
and now for some reason we decide to use both in some class UserManager in:
/Package3/UserManager.php
with content:
<?php
namespace /Package3;
use package1/User as User1;
use package2/User as User2;
class UserManager {
public function __construct(User1 $user1, User2 $user2) {...}
...
}
I'm trying to rewrite an OO PHP site (that loosely follows an MVC structure) so it uses namespaces - and want to follow PSR-0.
In the current site I have a class (called APP) which is full of static methods that I call all over the place to handle things such as getting config data eg; APP::get_config('key').
Obviously with namespacing, I would need to call \TheNameSpace\App::get_config('key'). I use this class frequently, so want to avoid having to prefix the namespace every time I use it. I do call methods in it from within other classes, which would usually be under a sub-namespace - so changing the namespace at the top of the file won't really work.
So, I guess my question is, what is the easiest way to have a 'global' class with methods that I can call anywhere without having to prefix with the namespace each time?
namespace Foo;
use Bar;
Then you do not have to do \Bar\fn
So in your case:
namspace Foo;
use TheNameSpace\App;
App::get_config('blah')
Read the section in the php manual on using/aliasing namespaces.
http://www.php.net/manual/en/language.namespaces.importing.php
You can exclude the namespace by using "use". You can name it whatever you want.
use TheNamespace\App as App //You can name it anything here
App:config('key');
At top of your scripts add
use TheNameSpace\App as MyApp
for example. You can then use it like
app = new MyApp();
in your scripts. Of course you needn't to use an alias here. Just
use TheNameSpace\App
app = new App();
will work, too.
A global class that's implementing this one is bad style and you shouldn't do it like this:
class MyApp extends TheNameSpace\App { }
....
myApp = new MyApp();
I have a file with a class Resp. The path is:
C:\xampp\htdocs\One\Classes\Resp.php
And I have an index.php file in this directory:
C:\xampp\htdocs\Two\Http\index.php
In this index.php file I want to instantiate a class Resp.
$a = new Resp();
I know I can use require or include keywords to include the file with a class:
require("One\Classes\Resp.php"); // I've set the include_path correctly already ";C:\xampp\htdocs". It works.
$a = new Resp();
But I want to import classes without using require or include. I'm trying to understand how use keyword works. I tried theses steps but nothing works:
use One\Classes\Resp;
use xampp\htdocs\One\Classes\Resp;
use htdocs\One\Classes\Resp;
use One\Classes;
use htdocs\One\Classes; /* nothing works */
$a = new Resp();
It says:
Fatal error: Class 'One\Classes\Resp' not found in C:\xampp\htdocs\Two\Http\index.php
How does the keyword use work? Can I use it to import classes?
No, you can not import a class with the use keyword. You have to use include/require statement. Even if you use a PHP auto loader, still autoloader will have to use either include or require internally.
The Purpose of use keyword:
Consider a case where you have two classes with the same name; you'll find it strange, but when you are working with a big MVC structure, it happens. So if you have two classes with the same name, put them in different namespaces. Now consider when your auto loader is loading both classes (does by require), and you are about to use object of class. In this case, the compiler will get confused which class object to load among two. To help the compiler make a decision, you can use the use statement so that it can make a decision which one is going to be used on.
Nowadays major frameworks do use include or require via composer and psr
1) composer
2) PSR-4 autoloader
Going through them may help you further.
You can also use an alias to address an exact class. Suppose you've got two classes with the same name, say Mailer with two different namespaces:
namespace SMTP;
class Mailer{}
and
namespace Mailgun;
class Mailer{}
And if you want to use both Mailer classes at the same time then you can use an alias.
use SMTP\Mailer as SMTPMailer;
use Mailgun\Mailer as MailgunMailer;
Later in your code if you want to access those class objects then you can do the following:
$smtp_mailer = new SMTPMailer;
$mailgun_mailer = new MailgunMailer;
It will reference the original class.
Some may get confused that then of there are not Similar class names then there is no use of use keyword. Well, you can use __autoload($class) function which will be called automatically when use statement gets executed with the class to be used as an argument and this can help you to load the class at run-time on the fly as and when needed.
Refer this answer to know more about class autoloader.
use doesn't include anything. It just imports the specified namespace (or class) to the current scope
If you want the classes to be autoloaded - read about autoloading
Don’t overthink what a Namespace is.
Namespace is basically just a Class prefix (like directory in Operating System) to ensure the Class path uniqueness.
Also just to make things clear, the use statement is not doing anything only aliasing your Namespaces so you can use shortcuts or include Classes with the same name but different Namespace in the same file.
E.g:
// You can do this at the top of your Class
use Symfony\Component\Debug\Debug;
if ($_SERVER['APP_DEBUG']) {
// So you can utilize the Debug class it in an elegant way
Debug::enable();
// Instead of this ugly one
// \Symfony\Component\Debug\Debug::enable();
}
If you want to know how PHP Namespaces and autoloading (the old way as well as the new way with Composer) works, you can read the blog post I just wrote on this topic: https://enterprise-level-php.com/2017/12/25/the-magic-behind-autoloading-php-files-using-composer.html
You'll have to include/require the class anyway, otherwise PHP won't know about the namespace.
You don't necessary have to do it in the same file though. You can do it in a bootstrap file for example. (or use an autoloader, but that's not the topic actually)
The issue is most likely you will need to use an auto loader that will take the name of the class (break by '\' in this case) and map it to a directory structure.
You can check out this article on the autoloading functionality of PHP. There are many implementations of this type of functionality in frameworks already.
I've actually implemented one before. Here's a link.
I agree with Green, Symfony needs namespace, so why not use them ?
This is how an example controller class starts:
namespace Acme\DemoBundle\Controller;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
class WelcomeController extends Controller { ... }
Can I use it to import classes?
You can't do it like that besides the examples above. You can also use the keyword use inside classes to import traits, like this:
trait Stuff {
private $baz = 'baz';
public function bar() {
return $this->baz;
}
}
class Cls {
use Stuff; // import traits like this
}
$foo = new Cls;
echo $foo->bar(); // spits out 'baz'
The use keyword is for aliasing in PHP and it does not import the classes. This really helps
1) When you have classes with same name in different namespaces
2) Avoid using really long class name over and over again.
Using the keyword "use" is for shortening namespace literals. You can use both with aliasing and without it. Without aliasing you must use last part of full namespace.
<?php
use foo\bar\lastPart;
$obj=new lastPart\AnyClass(); //If there's not the line above, a fatal error will be encountered.
?>
Namespace is use to define the path to a specific file containing a class e.g.
namespace album/className;
class className{
//enter class properties and methods here
}
You can then include this specific class into another php file by using the keyword "use" like this:
use album/className;
class album extends classname {
//enter class properties and methods
}
NOTE: Do not use the path to the file containing the class to be implements, extends of use to instantiate an object but only use the namespace.