I have this statement that works fine, but list alphabetical from left to right across 3 columns. I want it to list alphabetical vertically down the column and then continue onto the next column. Anyone know how I can do this.
$models = mysql_query("SELECT model, id FROM model where make='$phonemake' order by model asc") or die(mysql_error());
$count = 0;
$max = 3;
while($model = mysql_fetch_array( $models ))
{
$count++;
echo "<div style='float:left; width:31%; padding-right:5px;'>".$model['model']." <a href='include/delete-model.php?id=".$model['id']."' onclick='return makesure".$model['id']."();'>Delete</a></div>";
if($count >= $max){
//reset counter
$count = 0;
//end and restart
echo"<div style='clear:both;'></div>";
You have two options:
You can buffer result into array and change the order of adding of divs
The code could look like this:
$allmodels = array();
while($model = mysql_fetch_array( $models ))
{
$allmodels[] = $model;
}
for($i = 0; 3 * $i < count($allmodels); $i++)
{
for($j = 0; $j < 3; $j++)
{
if(isset($allmodels[($i * 3) + $j]))
{
$model = $allmodels[($i * 3) + $j];
// print your stuff here...
}
}
}
Or you can somehow reorder items in the sql query, maybe dump that to the temporary table or play with mysql_data_seek.
echo the data in a UL LIST , and use your counter to set the number of rows in the UL LIST , when counter is reaches max, create a new list and continue displaying. Personally i would use:
if($counter%3==0) {
create new list
}
this way you dont need to reset the counter everytime.
Related
I need to create a 'wall' of images.
There's my code:
<?php
$q = $db->prepare("SELECT * FROM wall");
$q->execute();
while($row = $q->fetch(PDO::FETCH_ASSOC)) { ?>
<div class="col-4-perc"><img src="<?=$site?>/assets/img/wall/<?=$row['source']?>.png"
alt="Foto wall" class="img-fluid"></div>
<?php } ?>
I would like to repeat the while loop repeating the photos in the database at least 3/4 times but I don't know how to do it.
As explained in the comments, you have to use FetchAll instead of fetch in a while. Here is a example script for the result you want:
$q = $db->prepare("SELECT * FROM wall");
$q->execute();
$allImage = $q->fetchAll() ;
$limit = 100 ;
$activeKey = 0 ;
for ($i = 0; $i < $limit ;$i++){
if (!isset($allImage[$activeKey]['source'])) {
$activeKey = 0 ;
// if the line does not exist, reset to the first key (0)
}
echo "<div class='col-4-perc'><img src='{$site}/assets/img/wall/{$allImage[$activeKey]['source']}.png'
alt='Foto wall' class='img-fluid'></div>";
$activeKey++ ;
}
Images are saved in $allImage, a table with numeric indexes. Next we just have to loop with a simple for using $limit (the max image you want display).
And $activeKey for the curent displayed image, if $allImage[$activeKey] is not set, reset to 0.
I ask in connection to this article:
How to get the columns names along with resultset in php/mysql?
$selecttable = mysql_query("SELECT * FROM $tablename WHERE (preis_bis <= '$price_upper' AND preis_bis > '$price_lower') LIMIT 1");
for ($i = 0; $i < mysql_num_fields($selecttable); $i++) {
$field_info = mysql_fetch_field($selecttable, $i);
// not WORKING
while($rowvalue = mysql_fetch_row($selecttable)) {
echo "<tr><td>Price: ".$rowvalue[$i]."</td></tr>";
}
echo "<tr><td style='border:1px solid #c0c0c0;padding:10px;'><!-- {$field_info->name} -->";
// get Logo and provider name
$select_getlogo = mysql_query("SELECT * FROM rrv_anbieter WHERE aid = '$field_info->name' LIMIT 1");
while($row_logo = mysql_fetch_object($select_getlogo)){
echo $row_logo->name.'<br><img src="images/'.$row_logo->logo.'" style="max-width: 200px;">';
}
#while($rowvalues2 = mysql_fetch_row($selecttable)) {
# foreach($rowvalues2 as $_column) {
# echo "<td>{$_column}</td>";
# }
#}
echo "</td></tr>";
}
I do not get it to get the correct row value within the "for" loop. Writing col names is working, but showing additionally the right value in same loop not.
Can someone help?
You need to iterate once more in the inner loop to get all rows of the table's columns.
while($rowvalue = mysql_fetch_row($selecttable)) {
foreach($rowvalue as $r){
echo "<tr><td> ".$r."</td></tr>";
}
}
$rowvalue[$i] showed rows incorrectly because it's following index based on the outer loop which is $i.
So basically the loop will print all rows of each column for n-times where n=number of all columns, not just the price column.
.
And you can also print all elements per-$rowvalue at once with :
while($rowvalue = mysql_fetch_row($selecttable)) {
$allElements = implode(",",$rowvalue ); // comma ',' is the separator
echo "<tr><td>". $allElements."</td></tr>";
}
}
I'm having problems getting my PHP file to function properly. It is supposed to display a two-columned table containing departments (unordered list) and department categories (ordered list beneath each department).
The result at the moment is that the SECOND column is appearing perfectly fine, with the bulleted unordered list and numbered ordered lists beneath each bulleted department. The FIRST column, however, is being displayed WITHOUT any bullets or numbers. The data is there, but not in the format (ul and ol) that I was expecting.
Thanks for you help. Let me know if you need more information.
<?php
//displayDepartments.php
$query = "SELECT * FROM product_categories_reference
ORDER BY department_name DESC";
$category = mysql_query($query)
or die(mysql_error());
$numRecords = mysql_num_rows($category);
$catCount = 0;
$currentDepartment = "";
echo "<table><tr><td><ul>";
for ($i = 0; $i < $numRecords; $i++)
{
$row = mysql_fetch_array($category);
if ($currentDepartment != $row["department_name"])
{
if ($currentDepartment != "") echo "</ol></li>";
if ($catCount > $numRecords/2)
{
echo "</ul></td><td valign='top'><ul>";
$catCount = 0;
}
$currentDepartment = $row["department_name"];
echo "<li>$currentDepartment<ol>";
}
echo "<li><a href=\"category.php?cat='"
.$row["product_category_code"] . "'\">"
.$row["product_category_description"]
."</a></li>";
$catCount++;
}
echo "</ol></li></ul></td></tr></table>";
?>
You haven't provided css or a link, so this is a guess.
I'm assuming your css has a list-style-type set to none.
Change it to
ul {
list-style-type: disc;
}
I'm trying to get a value to be inserted into a table on a webpage if the value equals $i.
$i starts at a number and decreases every loop. i can get it to work but it outputs multiple lines for each $i equivalent to the results in the table
I've reworked the code using everyones feedback to get this.
Echo "<tr><th colspan='3'><center>$rackname</th> </tr>" ;
for ($i=$RUtotal; $i > 0; $i--)
{
echo" <tr class='rackbg'><td class='i'><center>$i</td>" ;
$sql1 = "SELECT racks.rackID, racks.rackname, devices.deviceID, devices.deviceName, racks.rackRU, devices.deviceRU, devices.RUcount
FROM racks LEFT JOIN devices ON racks.rackID = devices.rackID
WHERE devices.rackID = '$rackID'";
$query1 = mysql_query($sql1);
while ($row = mysql_fetch_assoc($query1))
{
$deviceru = $row['deviceRU'];
$deviceID = $row['deviceID'];
$device = $row['deviceName'];
$deviceRUC = $row['RUcount'];
if ($deviceru == $i)
{
echo '<td class="device" rowspan='.$deviceRUC.'><a onclick=window.location="/devices.php?id='.$deviceID.'">'.$device.'</a></td><td rowspan='.$deviceRUC.'></td></tr>';
}
else
{
;
}
}
}
Echo "<tr class='rackb'><th colspan='3'>a</th></tr> " ;
This works to a degree (picture1) but when i add echo "" to the else statement it displays all wrong. (picture 2)
Any help would be greatly appreciated
Picture1 - http://imageshack.us/photo/my-images/263/examplewq.png/
Picture2 - http://imageshack.us/photo/my-images/269/example2jp.png/
I can't quite see what you're trying to do but what it looks like to me is that you want all the items from racks joined with their relevant device and displayed in order of deviceRU. Does this help:
echo "<tr><th colspan='3'><center><b>$rackname</th></tr>" ;
$sql1 = "SELECT racks.rackID, racks.rackname, devices.deviceID, devices.deviceName, racks.rackRU, devices.deviceRU, devices.RUcount
FROM racks LEFT JOIN devices ON racks.rackID = devices.rackID
WHERE racks.rackID = '$rackID' AND devices.deviceRU <= ".intval($RUtotal)."
ORDER BY devices.deviceRU;"
$query1 = mysql_query($sql1);
while ($row = mysql_fetch_array($query1))
{
$deviceru = $row['deviceRU'];
$deviceID = $row['deviceID'];
$device = $row['deviceName'];
$deviceRUC = $row['RUcount'];
echo'<tr class="rackbg"><td class="i">'.$i.'</td><td class="device">'.$device.'</td><td></td></tr>';
}
I've used a LEFT (inner) JOIN in the SQL instead of the outer join that was there before as it'll return less results and might solve your problem. I've ordered the results by deviceRU and only returned results which have deviceRU less than or equal to $RUtotal (as I think the example was showing).
I've also removed the tags, these should be replaced by using CSS to centre either all td elements or centering class="device" and class="i" e.g.:
.device, .i {
text-align: center;
}
I've also swapped your abc to abc which is the correct format for a link.
Could you describe more of the context as it's difficult to see your intention from your post.
Mat
As Peetz said, you don't need nested loop. You need something like:
$i = $RUtotal;
// ...
while ($row = mysql_fetch_array($query1)) {
// ...
if ($deviceru == $i) {
// ...
} else {
// ...
}
// ...
$i--;
}
This is looping $i times, within the outer while loop. This means you are getting the table repeated over and over again.
I suggest you remove the outer while loop.
I've already created a query to mysql that will give 20 results from mysql table etc. "cat"
heres the calling:
if(isset($_GET['cat']))
{
$query = "SELECT game_title,game_desc,....
FROM games WHERE cat_id='".validate_input($_GET['cat'])."' LIMIT 20";
}
...
by this I manage to get the results I wanted. What I am asking here is how can I create a "button" that will load the next "20" records from table "cat" (something like Buttons).
<?
$cn=mysql_connect("localhost","root","root") or die(mysql_error());
mysql_select_db("db56") or die(mysql_error());
$sql="select count(*) from emp";
$result=mysql_query($sql);
$r=mysql_fetch_row($result);
$record=$r[0];
$pagesize=20;
$totalpages=$record/$pagesize;
$currpage=$_GET["pg"];
if(!isset($currpage))
$start=0;
else {
$currpage--;
$start= $currpage * $pagesize;
}
$end=$start+$pagesize;
$sql="select * from emp limit $start,$pagesize";
$result=mysql_query($sql);
if($result){
print "<table border='1'>";
print "<tr><th>No</th><th>Name</th><th>Date</th></tr>";
while($r=mysql_fetch_row($result))
{
print "<tr><td>$r[0]</td><td>$r[1]</td><td>$r[2]</td></tr>";
}
print "</table>";
}
for($i=1;$i<=$totalpages;$i++){
print "<a href='listemp.php?pg=$i'> $i </a>";
}
?>
If you keep track of what page you're on, in the URL or a hidden field or session variable, you can use that to work out the limit. For example, page 2 should show limit 20 from row 20 (20 times the page offset).
You can pass two SQL parameters to LIMIT (put a comma between them) If you do, the first tells SQL how many records to skip (ie the offset of the first record) and the 2nd parameter is the one you're already using (how many records to return).
So just put a variable in your "next" link that says what page to display. You can pass the offset in this link, but it's pretty common to pass the "page number" instead, and multiply by the number of records per page before sticking it in the sql.
next page
With a bit more work, you can make a "previous page" link, and make the correct links non-clickable when you're at the first/last page.
Pass along a parameter that tells the script that you want another chunk of the results and not just the first batch.
So for the link it could be like this:
example.com/results.php?cat=1&page=2
Where page= will tell the script what page you want to return.
Then you want to turn that LIMIT number you have so that you can work out some simple maths
$results_cnt = 20; //--rows you want per page of results
Now in your script you'll check to see if the page variable has been set. If not, default the start row to return from the first. But as you want to return different pages/sets of results, a little math is needed in order to start at the proper row.
if(isset($_GET["page"]) //--see if the variable is even there
{
$page_num = (int)$_GET["page"]; //--forcing it to always be an integer
$start_row = $results_cnt * ($page_num - 1);
/* --
what happens:
($results_cnt currently at 20)
on page one (page=1), start at row 0
math: 20 * (1 - 1) = 0
on page two (page=2), start at row 20
math: 20 * (2 - 1) = 20
on page three (page=3), start at row 40
math: 20 * (3 - 1) = 40
etc.
*/
}
else
$start_row = 0;
Now, having set the correct starting row, adjust the SQL query to use the variables like so:
if(isset($_GET['cat']))
{
$query = "SELECT game_title,game_desc,....
FROM games
WHERE cat_id='".validate_input($_GET['cat'])."'
LIMIT $start_row, $results_cnt";
}
OK I got it fixed I guess...
in index.php:
<?php
$games = array();
$count = 1;
$total = 0;
if(isset($_GET['cat']))
{
$query = "SELECT game_title,game_desc,.... FROM games WHERE cat_id='".validate_input($_GET['cat'])."' LIMIT 20";
$total = mysql_num_rows(mysql_query("SELECT 1 FROM games WHERE cat_id='".validate_input($_GET['cat'])."'"));
}
$query_result = #mysql_query ($query) OR error(mysql_error(), __LINE__, __FILE__, 0, '', '');
while ($info = #mysql_fetch_array($query_result))
{
/* -- here goes the infos.. */
$games[$info['game_title']]['game_title'] = $info['game_title'];
etc..
if(isset($_GET['cat']))
{
/* -- for template engine */
$page->SetLoop ('PAGES', pagenav($total,$_GET['page'],20,$config['site_url'].'?cat='.$_GET['cat'],1,$lang));
}
--end php
and in funct.php
--start php
function pagenav($total,$page,$perpage,$url,$posts=0)
{
$page_arr = array();
$arr_count = 0;
if($posts)
{
$symb='&';
}
else
{
$symb='?';
}
$total_pages = ceil($total/$perpage);
$llimit = 1;
$rlimit = $total_pages;
$window = 5;
$html = '';
if ($page<1 || !$page)
{
$page=1;
}
if(($page - floor($window/5)) <= 0)
{
$llimit = 1;
if($window > $total_pages)
{
$rlimit = $total_pages;
}
else
{
$rlimit = $window;
}
}
else
{
if(($page + floor($window/2)) > $total_pages)
{
if ($total_pages - $window < 0)
{
$llimit = 1;
}
else
{
$llimit = $total_pages - $window + 1;
}
$rlimit = $total_pages;
}
else
{
$llimit = $page - floor($window/2);
$rlimit = $page + floor($window/2);
}
}
if ($page>1)
{
$page_arr[$arr_count]['title'] = 'Prev';
$page_arr[$arr_count]['link'] = $url.$symb.'page='.($page-1);
$page_arr[$arr_count]['current'] = 0;
$arr_count++;
}
for ($x=$llimit;$x <= $rlimit;$x++)
{
if ($x <> $page)
{
$page_arr[$arr_count]['title'] = $x;
$page_arr[$arr_count]['link'] = $url.$symb.'page='.($x);
$page_arr[$arr_count]['current'] = 0;
}
else
{
$page_arr[$arr_count]['title'] = $x;
$page_arr[$arr_count]['link'] = $url.$symb.'page='.($x);
$page_arr[$arr_count]['current'] = 1;
}
$arr_count++;
}
if($page < $total_pages)
{
$page_arr[$arr_count]['title'] = 'Next';
$page_arr[$arr_count]['link'] = $url.$symb.'page='.($page+1);
$page_arr[$arr_count]['current'] = 0;
$arr_count++;
}
return $page_arr;
}
?>
and call it by
{LOOP: PAGES}{PAGES.title} {/LOOP: PAGES}
in an .html file..
it works perfectly but when I press the number 2 or next to get the next 20 records it jumps back to the first 20...
on the browser it reads http://siteurl/?cat=1&page=2
I can't figure out why.