phpsass returns a fatal error - php

Question

I am using a very simple code to test phpsass
$sass = new SassParser();
$c = file_get_contents('/_www/_projects/cdn/public_html/test/test.sass');
$css = $sass->toCss($c);
The sass file is very basic:
$blue: #3bbfce;
$margin: 16px;
table.hl {
margin: 2em 0;
td.ln {
text-align: right;
}
}
li {
font: {
family: serif;
weight: bold;
size: 1.2em;
}
}
.content-navigation {
border-color: $blue;
color:
darken($blue, 9%);
}
.border {
padding: $margin / 2;
margin: $margin / 2;
border-color: $blue;
}
And I get the following error:
Fatal error: Uncaught exception 'SassNumberException' with message ' in D:\_www\_git\phpsass\script\literals\SassNumber.php on line 201
SassNumberException: Number must be a number: Array::26 Source: padding: $margin / 2; in D:\_www\_git\phpsass\script\literals\SassNumber.php on line 201
If it can help, there's also the following notice thrown before (I tried to change the error_reporting level but having the notice disappear of course didn't solve the problem):
Notice: Array to string conversion in D:\_www\_git\phpsass\SassException.php on line 25
If I use the same sass code against their online PHP compiler at http://www.phpsass.com/try/ it compiles correctly... I don't get it

Answer 1

Take a look at the SassParser class. The function toCss() has a second parameter called $isFile which by default is true:
public function toCss($source, $isFile = true) {
return $this->parse($source, $isFile)->render();
}
If you notice, you're passing in the source not the filename. You can either pass in the filename like so:
$sass = new SassParser();
$c = '/_www/_projects/cdn/public_html/test/test.sass';
$css = $sass->toCss($c);
Or do what you're trying to do but with an additional parameter on toCss():
$sass = new SassParser();
$c = file_get_contents('/_www/_projects/cdn/public_html/test/test.sass');
$css = $sass->toCss($c, false);

Answer 2

Your sass file is not really sass at all; this would be the correct syntax, basically take out all the trailing semi-colons:
$blue: #3bbfce
$margin: 16px
table.hl {
margin: 2em 0
td.ln {
text-align: right
}
}
li {
font: {
family: serif
weight: bold
size: 1.2em
}
}
.content-navigation {
border-color: $blue
color
darken($blue, 9%)
}
.border {
padding: $margin / 2
margin: $margin / 2
border-color: $blue
}
Or, like you suggested:
$sass = new SassParser(['syntax' => SassFile::SCSS]);

Answer 3

In fact that was a pure syntaxic problem. I tried to remove the variables from the sass code, and realized it worked - not well (margin: 2em 0 became margin: 20) but there was no error anymore.
The sass snippets that I took from http://sass-lang.com/ were not sass but scss format. The SassParser class has a parameter called syntax, which is set to 'sass' by default and needs to be set to scss when calling $scss = new SassParser(['syntax' => 'scss']).
However I needed to parse a string, not a file, but if you pass a file with a scss extension you don't need this extra parameter.