Here is my code:
$counter = 0;
$result = mysql_query("select * from funds_backup");
echo mysql_num_rows($result)."</br>"; // <--this prints 48,173
while ($row = mysql_fetch_object($result)) {
$counter++;
$name = $row->Name;
$ticker = $row->Ticker ;
$current[$ticker] = $name;
echo $counter." ".$current[$ticker]."</br>"; //<--this prints to 48,173
}
echo count($current); // <--this prints 45,650
I cannot get mysql_fetch_object to initialize all 48,173 rows to the php array.
I have done this with larger queries before. I have no idea why this does not work. It does not truncate the end of the array ie omit 45,651-48,173. It is random. I have used TRIM() and this does not work. It is consistent in a way too. The same rows are always omitted.
Ideas?
Sounds like you have multiple rows that contain the same data - which means that the value of $ticker ends up the same more than once. In this case you are then overwriting the previous array entry with that key. Try $current[] = $name; or $current[$counter] = $name; to ensure that all array keys are unique.
The mysql_* functions are actually deprecated in PHP5.5, so you might want to consider changing your code to use PDO or MySQLi, instead.
Make sure that the field 'Ticker' is actually unique, otherwise values will keep getting overwritten. Also, are you getting any memory exhausted errors while running this? That might be one cause of this happening.
What does echo $counter; return? If it is 48,173 then the values are getting overwritten.
Related
I'm updating some old code that has deprecated MySQL functions. But for some reasons I cannot get all the results from the column. The strange part is that if I run the query directly on the server I get all results fine. So this is an issue with PHP getting the results, not the MySQL server or my query.
Here is the new and old code:
My current updated code:
$sql = "SELECT user, monitor FROM users WHERE `status` = 'y'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
// This works. It shows all results
echo $row["user"];
// This does not work! Only shows one result:
$account= $row["user"];
}
else {
echo 'No results';
}
When I use that query directly on DB server, I get all results. So the SQL query is correct. I actually also get all results as well in PHP if I echo the row directly like:
echo $row["user"];
But for some reason when I try to use it with a PHP with variable it only lists one user result.
In the past I used this but the mysql_fetch_array function is now deprecated
while ($row = mysql_fetch_array($result)) {
array_push($data, $row["user"]);
}
foreach($data as $value) {
$account = $value
}
I cannot use my previous code anymore as those MySQL functions are obsolete today. I need to write the results into a file and my old method worked fine. The new one using mysqli does not.
Any suggestions?
You just need to add one of these [, and one of these ].
$account[] = $row["user"];
// ^^ right here.
$account= $row["user"]; means you're storing the value of $row["user"] in $account each time the loop executes. $account is a string, and it gets a new value each time.
$account[] = $row["user"]; means you're appending each value of $row["user"] to an array instead.
You should not use array_push for this. It's overkill for appending a single value to an array. And if the array isn't defined beforehand, it won't work at all.
I'm trying to create a while loop in PHP which retrieves data from a database and puts it into an array. This while loop should only work until the array its filling contains a certain value.
Is there a way to scan through the array and look for the value while the loop is still busy?
to put it bluntly;
$array = array();
$sql = mysql_query("SELECT * FROM table");
while($row = mysql_fetch_array($sql)){
//Do stuff
//add it to the array
while($array !=) //<-- I need to check the array here
}
You can use in_array function and break statement to check if value is in array and then stop looping.
First off, I think it'd be easier to check what you're filling the array with instead of checking the array itself. As the filled array grows, searching it will take longer and longer. Insted, consider:
$array = array_merge($array, $row);
if (in_array('ThisisWhatIneed', $row)
{
break;//leaves the while-loop
}
However, if you're query is returning more data, consider changing it to return what you need, only process the data that needs to be processed, otherwise, you might as well end up with code that does something like:
$stmt = $db->query('SELECT * FROM tbl');
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
if ($row['dataField'] === 'username')
{
$user = $row;
break;
}
}
WHERE could help a lot here, don't you think? As well taking advantage of MySQL's specific SELECT syntax, as in SELECT fields, you, need FROM table, which is more efficient.
You may also have noticed that the code above uses PDO, not mysql_*. Why? Simply because the mysql_* extension Is deprecated and should not be used anymore
Read what the red-warning-boxes tell you on every mysql* page. They're not just there to add some colour, and to liven things up. They are genuine wanrings.
Why don't you just check each value when it gets inserted into the array? It is much more efficient than iterating over the whole array each time you want to check.
$array = array();
$stopValue = ...
$sql = mysql_query("SELECT * FROM table");
while($row = mysql_fetch_assoc($sql)){
array_push($array,$row['column']);
if($row['column'] == $stopValue){
// The array now contains the stop value
break;
}
I continue to struggle with array! This is probably easy to answer.
I'm retrieving a data set from MYSQL w/ PHP. I get an array that has the 1st row (ala the mysql_fetch_array). Typically I would just loop through this and get each value, but in this case I'm already in the middle of a loop and I need to find out if a particular value exists in the full data set (which will be more than 1 row).
I figured I could just loop through and put all the values into an array with something like:
$query = "SELECT MapId FROM Map Where GameId = $gl_game_id";
$result_set = mysql_query($query, $connection);
confirm_query($result_set);
$map_set = array();
while($row = mysql_fetch_assoc($result_set)) {
$map_set[] = $row;
}
When I print_r this, I do in fact get the full data set (e.g. all rows of MapId from table Map).
So now, when I go to look in there and see if a value (that is coming out of this other loop) exists, it won't find it.
So my code looks like:
if (in_array($i, $map_set)) {
echo "yes, it's there baby!";
}
But it doesn't work. I tried hard coding the array, and that does in fact work. So there is simply something wrong with the way I'm constructing my array that this function doesn't like it.
if (in_array($i, array(40,12,53,65))) {
echo "yes, it's there baby!";
}
arrrg... I do hate being a noobie at this.
Function mysql_fetch_assoc returned array.
If you make print_r($map_set) then you will see that is 2-dimension array. Sure in_array not worked.
Just replace $map_set[] = $row; by $map_set[] = $row["MapId"]; and then try again.
In this script, I basically want to echo out data from a mysql table when the certain row record matches the name in browser address bar. But for some reason, no data is echoed. Any reason my while loop doesn't work?
$users = $_GET['username'];
$other_friend_query = mysql_query("SELECT * FROM friend WHERE RelatingUser='$users'");
$other_friend_assoc = mysql_fetch_assoc($other_friend_query);
while ($other_friend_assoc = mysql_fetch_assoc($other_friend_query)) {
$friend_related = $other_friend_assoc['RelatedUser'];
echo $friend_related;
}
That's because you call mysql_fetch_assoc before your while loop. When you call this, it fetches a result. Then when you go to your loop, that result has already been fetched. Just remove that and you'll be good to go. As stated in the comments, stop using mysql_ functions. The code below will escape your posted variable and also check for errors. It's also better practice to use a column list, instead of SELECT *.
$users = mysql_real_escape_string($_GET['username']);
$other_friend_query = mysql_query("SELECT * FROM friend WHERE RelatingUser='$users'") or die( mysql_error() );
while( $other_friend_assoc = mysql_fetch_assoc($other_friend_query) ) {
$friend_related = $other_friend_assoc['RelatedUser'];
echo $friend_related;
}
Any reason my while loop doesn't work?
May not be the only reason, but you're skipping the first result.
// the following line is unused and therefore unnecessary
$other_friend_assoc = mysql_fetch_assoc($other_friend_query);
while ($other_friend_assoc = mysql_fetch_assoc($other_friend_query)) {
UPDATE: I solved it using a for loop:
for ($i=0; $i < mysql_num_rows($result); $i++) {
$row = mysql_fetch_assoc($result);
echo $row['name'];
}
ORIGINAL QUESTION:
This looks kinda stupid. I'm sure im missing something that's very simple, since I was able to accomplish this before. Anyways, I want to echo some text for every item in an array. This array is derived from mySQL.
here's the code
while ($row = mysql_fetch_assoc(mysql_query("SELECT * FROM files"))) {
echo $row['name'];
}
can you post the complete code? I think you forgot the database connection.
Try this:
$result = mysql_query("SELECT * FROM files") or die (mysql_error());
while ($row = mysql_fetch_assoc($result)) {
var_dump($row['name']);
}
This will throw an error, I guess you made a mistake over there. Also, var_dump() your $row in the while to make 100% sure you have "a" value.
Also, are you sure the row does exist? If don't have any records, the echo on your $row will not work sinc it does not exist.
Also, set error reporting to E_ALL like so.
error_reporting(E_ALL);
Also, since you are running your query inside the while() loop, it will continue to run forever. So first run the query, and put it in a variable, and then loop through the results. (see my piece of code above)
You can execute query individual instead of while loop because if your query return more than 1 rows it will goes under the loop. show your loop print only first data of result and your loop is infinite.
From your question it seems so simple, try this way it's working.
$sql="SELECT name From files";
$names = $db->query($sql);
while($name1 = $db->fetchByAssoc($names))
{
echo $name1['name'];
}