selecting in php WHERE x = $array[index]? - php

Question

I've tried searching for answers to my problem but no one else seems to have had this problem! I'm basically trying to select in php using the WHERE statement, I want to compare my $ID to variables stores in an array called $resultAddID2. This array has values [1,2,1]; if I try accessing $resultAddID2[0] it works fine, but if I try to do it with $resultAddID2[1] or $resultAddID2[2] it doesn't work at all! I'm sure this is something silly but for the life of me I just can NOT figure it out! Any help would be much appreciated, thank you.
Here's the part where I try to do this:
$resultAddID = mysql_query("SELECT ADDRESS_ID FROM hospital");
while($resultAddID1=mysql_fetch_array($resultAddID)){
$resultAddID2[]=$resultAddID1['ADDRESS_ID'];
for ($i = 0; $i <= 2; $i++) {
$resultAddT = mysql_query("SELECT * FROM address WHERE ID = $resultAddID2[]");
$resultAddTm= mysql_fetch_array($resultAddT);
$resultAddT2[]=$resultAddTm['GOVER_ID'];
}
}
$response["hospADD"]= $resultAddT2;

Answer 1

You should add {}'s like
$resultAddT = mysql_query("SELECT * FROM address WHERE ID = {$resultAddID2[$i]}");
It would be better if you did something like this because you are querying the second item too many times
$resultAddID = mysql_query("SELECT ADDRESS_ID FROM hospital");
while($resultAddID1=mysql_fetch_array($resultAddID)){
$resultAddID2[]=$resultAddID1['ADDRESS_ID'];
}
for ($i = 0; $i <= 2; $i++) {
$resultAddT = mysql_query("SELECT * FROM address WHERE ID = {$resultAddID2[$i]}");
$resultAddTm= mysql_fetch_array($resultAddT);
$resultAddT2[] = $resultAddTm['GOVER_ID'];
}
$response["hospADD"]= $resultAddT2;
OR simpler yet:
$resultAddID = mysql_query("SELECT ADDRESS_ID FROM hospital");
while($resultAddID1=mysql_fetch_array($resultAddID)){
$resultAddT = mysql_query("SELECT * FROM address WHERE ID = {$resultAddID1['ADDRESS_ID']}");
$resultAddTm= mysql_fetch_array($resultAddT);
$resultAddT2[] = $resultAddTm['GOVER_ID'];
}
$response["hospADD"]= $resultAddT;