PHP - architecture, issue with variables scope - php

I'm writing now an app, which is supposed to be as simple as possible. My controllers implement the render($Layout) method which just does the following:
public function render($Layout) {
$this->Layout = $Layout;
include( ... .php)
}
I don't really understand the following problem: in my controller, I define a variable:
public function somethingAction() {
$someVariable = "something";
$this->render('someLayout');
}
in the php view file (same I have included in the render function) I try to echo the variable, but there is nothing. However, if I declare my action method like this:
public function somethingAction() {
global $someVariable;
$someVariable = "something";
$this->render('someLayout');
}
and in my view like this:
global $someVariable;
echo $someVariable;
it does work. Still it is annoying to write the word global each time.
How can I do this? I'd rather not use the $_GLOBAL arrays. In Cake PHP, for example, there is a method like $this->set('varName', $value). Then I can just access the variable in the view as $varName. How is it done?

From the PHP Manual on include:
When a file is included, the code it contains inherits the variable scope of the line on which the include occurs. Any variables available at that line in the calling file will be available within the called file, from that point forward. However, all functions and classes defined in the included file have the global scope.
When you do
public function somethingAction() {
$someVariable = "something";
$this->render('someLayout');
}
the $someVariable variable is limited to the somethingAction() scope. Calling your render() method will not magically make the variable available in render(), because the render() method has it's own variable scope. A possible solution would be to do
public function somethingAction() {
$this->render(
'someLayout',
array(
'someVariable' => 'something'
)
);
}
and then change render() to
public function render($Layout, array $viewData) {
$this->Layout = $Layout;
include( ... .php)
}
You will then have access to $viewData in the included file, given that you are not trying to use it in some other function or method, e.g. if your included file looks like this:
<h1><?php echo $viewData['someVariable']; ?></h1>
it will work, but if it is looks like this:
function foo() {
return $viewData['someVariable'];
}
echo foo();
it will not work, because foo() has it's own variable scope.
However, a controller's sole responsibility is to handle input. Rendering is the responsibility of the View. Thus, your controller should not have a render() method at all. Consider moving the method to your View class and then do
public function somethingAction() {
$view = new View('someLayout');
$view->setData('someVariable', 'something');
$view->render();
}
The render() method of your View object could then be implemented like this:
class View
…
$private $viewData = array();
public function setData($key, $value)
{
$this->viewData[$key] = $data;
}
public function render()
{
extract($this->viewData, EXTR_SKIP);
include sprintf('/path/to/layouts/%s.php', $this->layout);
}
The extract function will import the values of an array in the current scope using their keys as the name. This will allow you to use data in the viewData as $someVariable instead of $this->viewData['someVariable']. Make sure you understand the security implications of extract before using it though.
Note that this is just one possible alternative to your current way of doing things. You could also move out the View completely from the controller.

Using global you're implicitly using the $_GLOBALS array.
A not recommended example, because globals are never a good thing:
function something() {
global $var;
$var = 'data';
}
// now these lines are the same result:
echo $_GLOBALS['var'];
global $var; echo $var;
Why don't you use simply the $this->set function?
public function render($Layout) {
$this->Layout = $Layout;
include( ... .php)
}
public function somethingAction() {
$this->set('someVariable', "something");
$this->render('someLayout');
}
// in a framework's managed view:
echo $someVariable;
I'm sorry not to know your framework in detail, but that makes perfectly sense.
Actually how it's done: There is a native extract function, that loads an associative array into the current symbol table:
array( 'var0' => 'val0', 'var1' => 'val1')
becomes
echo $var0; // val0
echo $var1; // val1
That's most likely 'what happens'.

Related

Cannot Access Global Variable inside function INSIDE public function PHP

Good day. I'm trying to execute a function. i declare a global variable to get data (variable) outside the function, and the function i put inside a public function of a Class.
class Test {
public function execute(){
$data = "Apple";
function sayHello() {
global $data;
echo "DATA => ". $data;
}
sayHello();
}
}
$test = new Test;
$test->execute();
The expected result:
DATA => Apple
The real result:
DATA =>
the global variable is not getting the variable outside the function. Why it happened? Thank you for the help.
$data is not a global variable. It's inside another function, inside a class. A global variable sits outside any function or class.
But anyway your use case is unusual - there's rarely a need to nest functions like you've done. A more conventional, logical and usable implementation of these functions would potentially look like this:
class Test {
public function execute(){
$data = "Apple";
$this->sayHello($data);
}
private function sayHello($data) {
echo "DATA => ". $data;
}
}
$test = new Test;
$test->execute();
Working demo: http://sandbox.onlinephpfunctions.com/code/e91b98bb15fcfa71b1c6cbbc305b5a93df678e8b
(This is just one option, but it's a reasonable one, although since this is clearly a reduced, abstract example, it's hard to be sure what your real scenario would actually require or be best served by.)

Accessing variables in included file through helper method in PHP

I am trying to build a php class that will let me include other php "template" files to display. I want all of the variables that are in the scope that it is called from to be available in the included file. Here's the catch, I want to pass off the actual including to a helper method to keep the code DRY. Here is what I have so far:
/* TemplateLoader.php */
class TemplateLoader {
public function foo() {
$var = "FOO!";
//Works
include 'template.php';
}
public function bar() {
$var = "BAR!";
//Doesn't work
$this->render("template");
}
private function render( $name ) {
include $name . '.php';
}
}
/* template.php */
<?php echo $var; ?>
My question is: How can I accomplish the behaviour of including the template directly in the original method while still using helper method to actually do the "heavy lifting"? I would really appreciate any help you can give!
This is what first came to my mind - I'm not sure I like it too much, but I'm not sure of a generic alternative. This captures all of the current variables with get_defined_vars(), and passes them to render(), where they are they extract()ed, and thus accessible by the included file.
You could probably filter the return from get_defined_vars() before you pass it to render(), but I should work.
public function bar() {
$var = "BAR!";
$this->render("template", get_defined_vars());
}
private function render( $name, &$vars) {
extract( $vars);
include $name . '.php';
}
You could probably filter the return from get_defined_vars() before you pass it to render(), but it should work.

Passing variables to an included file

I have a template class which goes like this:
class Template{
public $pageTitle = "";
public function __construct($pageTitle){
$this->pageTitle = $pageTitle;
}
public function display(){
include "/includes/head.php";
include "/includes/body.php";
}
}
Now, I'm used to Java's workings but I don't understand why I'm getting an undefined variable ($pageTitle) error. The included files need to be able to access that variable. I know it's going to be very simple but I actually haven't found out why.
What do I need to do to allow includes to see this variable?
The includes will also have to use $this->pageTitle. Effectively, the include makes them part of the method body.
The included file lives in the same scope as your object. So you need to call:
$this->pageTitle
If you don't want to do the whole $this->, you can do something like the following... The extract function will extract the array $this->data into variables with names respective to the key/index of each item. So now you will be able to do echo $pageTitle;
class Template{
public $data = Array();
public function __construct($pageTitle){
$this->data['pageTitle'] = $pageTitle;
}
public function display(){
extract($this->data);
include "/includes/head.php";
include "/includes/body.php";
}
}
Scope is a little different in PHP than in java.
For your specific case you need
$this->pageTitle
To access a variable declared outside the class, you'll need to make it global
global $myVar;

how can i include php file in php class

i have php with an array i.e
$var = array(
"var" => "var value",
"var2" => "var value1"
);
and have another file with a class i.e
class class1{
function fnc1(){
echo $var['var2'];
//rest of function here
}
}
now how can i get $var['var'] in class file in function fnc1()
You can pass it as an argument, or use the global keyword to put it in the current scope.
However, using global is discouraged, try passing it as an argument.
Pass it as an argument?
class class1{
function fnc1($var) {
echo $var['var2'];
}
}
And in your other file call this class method with your array as an argument.
From: http://php.net/manual/en/function.include.php
When a file is included, the code it contains inherits the variable scope of the line on which the include occurs. Any variables available at that line in the calling file will be available within the called file, from that point forward. However, all functions and classes defined in the included file have the global scope.
So you could do
class class1
{
function fnc1()
{
include 'thefile.php'
echo $var['var2'];
//rest of function here
}
}
but like others pointed out before, you dont want to do that, because it introduces a dependency on the filesystem in your class. If your method requires those variables to work, then inject them as method arguments or pass them into the constructor and make them a property (if you need them more often). This is called Dependency Injection and it will make your code much more maintainable in the long run, e.g. do
class class1
{
private $data;
public function __construct(array $var)
{
$this->data = $var;
}
function fnc1()
{
echo $this->data['var2'];
//rest of function here
}
}
and then do
$obj = new class1($var);
echo $obj->fnc1();
or require the data to be passed into the method on invocation
class class1
{
function fnc1(array $var)
{
echo $var['var2'];
//rest of function here
}
}
and then
$obj = new class1;
$obj->fnc1($var);
You might use global $var in your included file, but it's really a bad practice, as another script, before your included file, might redefine the value/type of $var.
Example :
class class1{
function fnc1(){
global $var;
echo $var['var2'];
//rest of function here
}
}
A better solution, is to pass your $var as a parameter to your fnc1(), even to your class1::__construct()
#Vindia: I'd prefer the argumant-style too, but would recommend either using type hint or a simple check to avoid warnings when accessing *non_array*['var2']:
// acccepts array only. Errors be handled outside
function fnc1(Array $var) {
echo $var['var2'];
}
// accepts any type:
function fnc1(Array $var) {
if (is_array($var)) {
echo $var['var2'];
}
}
class class1{
function fnc1(){
include 'otherFile.php';
echo $var['var2'];
//rest of function here
}
}

PHP access external $var from within a class function

In PHP, how do you use an external $var for use within a function in a class? For example, say $some_external_var sets to true and you have something like
class myclass {
bla ....
bla ....
function myfunction() {
if (isset($some_external_var)) do something ...
}
}
$some_external_var =true;
$obj = new myclass();
$obj->myfunction();
Thanks
You'll need to use the global keyword inside your function, to make your external variable visible to that function.
For instance :
$my_var_2 = 'glop';
function test_2()
{
global $my_var_2;
var_dump($my_var_2); // string 'glop' (length=4)
}
test_2();
You could also use the $GLOBALS array, which is always visible, even inside functions.
But it is generally not considered a good practice to use global variables: your classes should not depend on some kind of external stuff that might or might not be there !
A better way would be to pass the variables you need as parameters, either to the methods themselves, or to the constructor of the class...
Global $some_external_var;
function myfunction() {
Global $some_external_var;
if (!empty($some_external_var)) do something ...
}
}
But because Global automatically sets it, check if it isn't empty.
that's bad software design. In order for a class to function, it needs to be provided with data. So, pass that external var into your class, otherwise you're creating unnecessary dependencies.
Why don't you just pass this variable during __construct() and make what the object does during construction conditional on the truth value of that variable?
Use Setters and Getters or maybe a centralized config like:
function config()
{
static $data;
if(!isset($data))
{
$data = new stdClass();
}
return $data;
}
class myClass
{
public function myFunction()
{
echo "config()->myConfigVar: " . config()->myConfigVar;
}
}
and the use it:
config()->myConfigVar = "Hello world";
$myClass = new myClass();
$myClass->myFunction();
http://www.evanbot.com/article/universally-accessible-data-php/24

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