I want to find all strings looking like [!plugin=tesplugin arg=dfd arg=2!] and put them in array.
Important feature: the string could contain arg=uments or NOT(in some cases). and of course there could be any number of arg's. So the string could look like:
[!plugin=myname!] or [!plugin=whatever1 arg=22!] or even [!plugin=gal-one arg=1 arg=text arg=tx99!]. I need to put them all in $strarray items
Here is what i did...
$inp = "[!plugin=tesplugin arg=dfd!] sometxt [!plugin=second arg=1 arg=2!] 1sd";
preg_match_all('/\[!plugin=[a-z0-9 -_=]*!]/i', $inp, $str);
but $str[0][0] contains:
[!plugin=tesplugin arg=dfd!] sometxt [!plugin=second arg=1 arg=2!]
instead of putting each expression in a new array item..
I think my problem in regex.. but can't find one. Plz help...
The last ] needs to be escaped and the - in the character class needs to be at the start, end, or escaped. As is it is a range of ascii characters between a space and underscore.
\[!plugin=[a-z0-9 \-_=]*!\]
Regex101 Demo: https://regex101.com/r/zV4bO2/1
I have coded in PHP for over 10 years and this is the first time I have come across this (legacy code base):
$string = "123456789";
$new_number = $string[1]
$new_number is now 2.
Am I going crazy? I never knew you could add to a string with [x].
EDIT: As many have pointed out, strings in PHP are stored as an array of characters. However, I am right in thinking this is quite unique to PHP? Could you do this in a strongly typed language like C++/C#/Java?
No you don't got crazy. You can access any string within PHP as it would be an array and access each character individual. As you can see here in the manual:
Characters within strings may be accessed and modified by specifying the zero-based offset of the desired character after the string using square array brackets, as in $str[42]. Think of a string as an array of characters for this purpose. [...]
Because a string is effective an array of char's in PHP. This means that you can individually get the characters by accessing the right index. This isnt adding anything really, its just fetching the second character of the string which is '2'. Hope this helps.
Yep! You are not crazy. In PHP you can access the characters in a string by their index. It's treated a lot like an array. You cannot add to the string with $string[] as you would an array, but you can change the value to another character.
$string = "test";
$string[1] = "s";
echo $string; // Echoes 'tsst'
I'm trying to make a replace in a string with a regex, and I really hope the community can help me.
I have this string :
031,02a,009,a,aaa,AZ,AZE,02B,975,135
And my goal is to remove the opposite of this regex
[09][0-9]{2}|[09][0-9][A-Za-z]
i.e.
a,aaa,AZ,AZE,135
(to see it in action : http://regexr.com?3795f )
My final goal is to preg_replace the first string to only get
031,02a,009,02B,975
(to see it in action : http://regexr.com?3795f )
I'm open to all solution, but I admit that I really like to make this work with a preg_replace if it's possible (It became something like a personnal challenge)
Thanks for all help !
As #Taemyr pointed out in comments, my previous solution (using a lookbehind assertion) was incorrect, as it would consume 3 characters at a time even while substrings weren't always 3 characters.
Let's use a lookahead assertion instead to get around this:
'/(^|,)(?![09][0-9]{2}|[09][0-9][A-Za-z])[^,]*/'
The above matches the beginning of the string or a comma, then checks that what follows does not match one of the two forms you've specified to keep, and given that this condition passes, matches as many non-comma characters as possible.
However, this is identical to #anubhava's solution, meaning it has the same weakness, in that it can leave a leading comma in some cases. See this Ideone demo.
ltriming the comma is the clean way to go there, but then again, if you were looking for the "clean way to go," you wouldn't be trying to use a single preg_replace to begin with, right? Your question is whether it's possible to do this without using any other PHP functions.
The anwer is yes. We can take
'/(^|,)foo/'
and distribute the alternation,
'/^foo|,foo/'
so that we can tack on the extra comma we wish to capture only in the first case, i.e.
'/^foo,|,foo/'
That's going to be one hairy expression when we substitute foo with our actual regex, isn't it. Thankfully, PHP supports recursive patterns, so that we can rewrite the above as
'/^(foo),|,(?1)/'
And there you have it. Substituting foo for what it is, we get
'/^((?![09][0-9]{2}|[09][0-9][A-Za-z])[^,]*),|,(?1)/'
which indeed works, as shown in this second Ideone demo.
Let's take some time here to simplify your expression, though. [0-9] is equivalent to \d, and you can use case-insensitive matching by adding /i, like so:
'/^((?![09]\d{2}|[09]\d[a-z])[^,]*),|,(?1)/i'
You might even compact the inner alternation:
'/^((?![09]\d(\d|[a-z]))[^,]*),|,(?1)/i'
Try it in more steps:
$newList = array();
foreach (explode(',', $list) as $element) {
if (!preg_match('/[09][0-9]{2}|[09][0-9][A-Za-z]/', $element) {
$newList[] = $element;
}
}
$list = implode(',', $newList);
You still have your regex, see! Personnal challenge completed.
Try matching what you want to keep and then joining it with commas:
preg_match_all('/[09][0-9]{2}|[09][0-9][A-Za-z]/', $input, $matches);
$result = implode(',', $matches);
The problem you'll be facing with preg_replace is the extra-commas you'll have to strip, cause you don't just want to remove aaa, you actually want to remove aaa, or ,aaa. Now what when you have things to remove both at the beginning and at the end of the string? You can't just say "I'll just strip the comma before", because that might lead to an extra comma at the beginning of the string, and vice-versa. So basically, unless you want to mess with lookaheads and/or lookbehinds, you'd better do this in two steps.
This should work for you:
$s = '031,02a,009,a,aaa,AZ,AZE,02B,975,135';
echo ltrim(preg_replace('/(^|,)(?![09][0-9]{2}|[09][0-9][A-Za-z])[^,]+/', '', $s), ',');
OUTPUT:
031,02a,009,02B,975
Try this:
preg_replace('/(^|,)[1-8a-z][^,]*/i', '', $string);
this will remove all substrings starting with the start of the string or a comma, followed by a non allowed first character, up to but excluding the following comma.
As per #GeoffreyBachelet suggestion, to remove residual commas, you should do:
trim(preg_replace('/(^|,)[1-8a-z][^,]*/i', '', $string), ',');
I need a regular expression for php that outputs everything between <!--:en--> and <!--:-->.
So for <!--:en-->STRING<!--:--> it would output just STRING.
EDIT: oh and the following <!--:--> nedds to be the first one after <!--:en--> becouse there are more in the text..
The one you want is actually not too complicated:
/<!--:en-->(.*?)<!--:-->/gi
Your matches will be in capture group 1.
Explanation:
The .*? is a lazy quantifier. Basically, it means "keep matching until you find the shortest string that will still fit this pattern." This is what will cause the matching to stop at the first instance of <!--:-->, rather than sucking up everything until the last <!--:--> in the document.
Usage is something like preg_match("/<!--:en-->(.*?)<!--:-->/gi", $input) if I recall my PHP correctly.
If you have just that input
$input = '<!--:en-->STRING<!--:-->';
You can try with
$output = strip_tags($input);
Try:
^< !--:en-- >(.*)< !--:-- >$
I don't think any of the other characters need to be escaped.
<!--:en--\b[^>]*>(.*?)<!--:-->
This will match the things between your tags. This will break if you nest your tags, but you didnt say you were doing that :)
I am looking for something like trim() but for within the bounds of a string. Users sometimes put 2, 3, 4, or more line returns after they type, I need to sanitize this input.
Sample input
i like cats
my cat is happy
i love my cat
hope you have a nice day
Desired output
i like cats
my cat is happy
i love my cat
hope you have a nice day
I am not seeing anything built in, and a string replace would take many iterations of it to do the work. Before I whip up a small recursive string replace, I wanted to see what other suggestions you all had.
I have an odd feeling there is a regex for this one as well.
function str_squeeze($body) {
return preg_replace("/\n\n+/", "\n\n", $body);
}
How much text do you need to do this on? If it is less than about 100k then you could probably just use a simple search and replace regex (searching something like /\n+/ and replace with \n)
On the other hand if you need to go through megabytes of data, then you could parse the text character by character, copying the input to the output, except when mulitple newlines are encountered, in which case you would just copy one newline and ignore the rest.
I would not recommend a recursive string replace though, sounds like that would be very very slow.
Finally managed to get it, needs preg so you are using the PCRE version in php, and also needs a \n\n replacement string, in order to not wipe all line endings but one:
$body = preg_replace("/\n\n+/", "\n\n", $body);
Thanks for getting me on the right track.
To consider all three line break sequences:
preg_replace('/(?:\r\n|[\r\n]){2,}/', "\n\n", $str)
The following regular expression should remove multiple linebreaks while ignoring single line breaks, which are okay by your definition:
ereg_replace("\n\n+", "\n\n", $string);
You can test it with this PHP Regular Expression test tool, which is very handy (but as it seems not in perfect parity with PHP).
[EDIT] Fixed the ' to ", as they didn't seem to work. Have to admit I just tested the regex in the web tool. ;)