$dts = new DateTime(AppController::getSetting('event_start'));
$dtf = new DateTime(AppController::getSetting('event_finish'));
//CONTROLLER
...
$weekdays = array(0,1,2,3,4,5,6);
$dates = array();
$today = strtotime(date("Y-m-d", $dts->getTimestamp()));
$end_date = strtotime(date("Y-m-d", $dtf->getTimestamp()));
while($today <= $end_date)
{
$weekday = date("w", $today);
if (in_array($weekday, $weekdays))
{
array_push($dates, date("Y-m-d", $today));
}
$today += 86400;
}
$this->set('dates', $dates);
...
//VIEW
...
echo $this->Form->input('date', array('options'=> $dates));
...
dts and dtf are a start and finish date I get from my database...
When I select a date from my drop box in my view, it submits ok but all i get in my database is 0000-00-00?
What am I doing wrong here?
EDIT
My array out puts this with
Debugger::dump($dates);
array(
(int) 0 => '2013-04-01',
(int) 1 => '2013-04-02',
(int) 2 => '2013-04-03',
(int) 3 => '2013-04-04',
(int) 4 => '2013-04-05',
(int) 5 => '2013-04-06',
(int) 6 => '2013-04-07'
)
EDIT
This is what my query looks like
INSERT INTO cake.tickets (first_name, last_name, email, phone, date, quantity) VALUES ('brbt', 'trbb', 'ver#fvef.com', 765657, //THIS IS THE DATE//2, 2).
It seems to only input the key?
Make your keys and your values the same. The key is what is saved, the value is what is seen by the user.
$dates = array();
$today = strtotime(date("Y-m-d", $dts->getTimestamp()));
$end_date = strtotime(date("Y-m-d", $dtf->getTimestamp()));
while($today <= $end_date)
{
$weekday = date("w", $today);
if (in_array($weekday, $weekdays))
{
$dates[date("Y-m-d", $today)] = date("Y-m-d", $today);
}
$today += 86400;
}
$this->set('dates', $dates);
Your date array should now look something like this:
array(
'2013-04-01' => '2013-04-01',
'2013-04-02' => '2013-04-02',
'2013-04-03' => '2013-04-03',
'2013-04-04' => '2013-04-04',
'2013-04-05' => '2013-04-05',
'2013-04-06' => '2013-04-06',
'2013-04-07'=> '2013-04-07'
)
Which will generate the proper select options.
Related
I have a date range and I need it to group by month but I want to keep starting day and ending day. So far I have this:
$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-02-06 23:59:59';
$start = Carbon::createFromFormat('Y-m-d H:i:s', $interval['from'])->startOfMonth();
$end = Carbon::createFromFormat('Y-m-d H:i:s', $interval['to'])->startOfMonth()->addMonth();
$separate = CarbonInterval::month();
$period = new \DatePeriod($start, $separate, $end);
foreach ($period as $dt) {
dump($dt);
}
But as result I'm getting:
Carbon\Carbon(3) {
date => "2017-01-01 00:00:00.000000" (26)
timezone_type => 3
timezone => "Europe/Prague" (13)
}
Carbon\Carbon(3) {
date => "2017-02-01 00:00:00.000000" (26)
timezone_type => 3
timezone => "Europe/Prague" (13)
}
It is grouped by month but I need to get whole month period, I mean from
2017-01-02 00:00:00 to 2017-01-31 23:59:59
2017-02-01 00:00:00 to 2017-02-06 23:59:59.
Output:
$array = [
0 => [
'from' => '2017-01-02 00:00:00',
'to' => '2017-01-31 23:59:59'
],
1 => [
'from' => '2017-02-01 00:00:00',
'to' => '2017-02-06 23:59:59'
]
];
What is the easiest way to achive it?
Edit: Here is a little bit modified Carbon version of accepted answer, maybe somebody will need it:
$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-04-08 23:59:59';
$interval_from = Carbon::createFromFormat('Y-m-d H:i:s', $interval['from']);
$interval_to = Carbon::createFromFormat('Y-m-d H:i:s', $interval['to']);
$result = [];
foreach (range($interval_from->month, $interval_to->month) as $x) {
$to = $interval_from->copy()->endOfMonth();
if ($x == $interval_to->month) {
$result[] = ["from" => $interval_from, "to" => $interval_to];
} else {
$result[] = ["from" => $interval_from, "to" => $to];
}
$interval_from = $to->copy()->addSecond();
}
PHP code demo
Try this solution you can change from one month to another month(not year) and then check. Lengthy solution but hopefully works correctly, putting explaination.
<?php
ini_set('display_errors', 1);
$from=$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-03-07 23:59:59';
$month1=date("m", strtotime($interval['from']));
$month2=date("m", strtotime($interval['to']));
$result=array();
foreach(range($month1, $month2) as $x)
{
$dateTimeObj= new DateTime($from);
$dayDifference=($dateTimeObj->format('d')-1);
$dateTimeObj= new DateTime($from);
$dateTimeObj->add(new DateInterval("P1M"));
$dateTimeObj->sub(new DateInterval("P".$dayDifference."DT1S"));
$to= $dateTimeObj->format("Y-m-d H:i:s");
if($x==$month2)
{
$dateTimeObj= new DateTime($interval['to']);
$noOfDays=$dateTimeObj->format("d");
$dateTimeObj->sub(new DateInterval("P".($noOfDays-1)."D"));
$from=$dateTimeObj->format("Y-m-d H:i:s");
$result[]=array("from"=>$from,"to"=>$interval['to']);
}
else
{
$result[]=array("from"=>$from,"to"=>$to);
}
//adding 1 second to $to for next time to be treated as $from
$dateTimeObj= new DateTime($to);
$dateTimeObj->add(new DateInterval("PT1S"));
$from= $dateTimeObj->format("Y-m-d H:i:s");
}
print_r($result);
I am trying to Write Program for Calculating Next 20 dates After Specifying Start date, then from 20 dates i have Exclude Weekends & Holidays(Array holidays('2016-12-13',2016-12-24)) And Result Array which includes only Working Days Excluding Saturday & Sunday, from this Result Array after Passing Holiday array(Eg:- holidays('2016-12-13',2016-12-24))), it must be Excluded from result array. i:e;
I want Expected Output Below mentioned
.
<?php
$Date=array('2016-12-01');
echo "\n <br />Start Date:-" . $Date[0] . "";
/*Code For Generating Next 20 Dates Starts*/
//$start = strtotime($s_row['schedule_start_date']);
$start = strtotime('2016-12-01');
$dates=array();
for($i = 0; $i<20; $i++)
{
array_push($dates,date('Y-m-d', strtotime("+$i day", $start)));
}
echo "\n <br /> Array Of next 20 Days/dates of Given:-";
print_r($dates);
$start=array();
$start=$dates; /*Code For Generating Next 20 Dates Ends*/
$result=array();
$start = strtotime(array_values($Date)[0]);
//$end = strtotime(array_values($Date)[30]);
$result = array();
$begin = new DateTime( '2016-12-01' );
$end = new DateTime( '' );
//$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date)
{
//echo $date->format("Y-m-d") . "<br>";
if (date('N', $start) <= 5) /* 'N' number days 1 (mon) to 7 (sun) */
/*5 weekday */
{
$current = date('Y-m-d', $start); //m/d/Y
$result[$current] = '';
}
$start += 86400;
//echo "Days Without Sat Sun".$result[date($date->format("Y-m-d"))];
//echo "Days Without Sat Sun".$result2[date($current->format("Y-m-d"))];
}
echo " \n <br /> Dates Without Weekends LIKE (Excluding Saturday & Sunday):-";
print_r($result);
/*For Holiday*/
$FinalArray = array();
$holidays = array(
'2016-12-13',
'2016-12-24',
);
echo " \n <br /> Given Holiday Dates Are:-";
print_r($holidays);
$a1 = $result;
$a2 = $holidays;
$array = array_diff(array_merge($a1,$a2),array_intersect($a1,$a2));
echo "\n <br /> Output:-";
print_r($array);
?>
it Gives Output as :- Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-13] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23] => [0] => 2016-12-13 [1] => 2016-12-24 )
> But I Want Expected Output:-
Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23]
You Can Notice That 2016-12-13 is Not There in Above Expected Output as in '2016-12-13', 2016-12-24 is passed as Holiday via holiday array ($holidays = array( '2016-12-13', '2016-12-24', );) i:e; if i pass any date through holidays array it should not be included in result Array(). i:e 2016-12-13 is Available in Result array as well as holiday array So While while printing Final OUTPUT:- 13th date(2016-12-13) Should not be Included in final Output. Anybody Solve this will be Appreciated Thanks in Advance.
When I have to remove duplicates from a array the function that I keep going back to is
array array_unique ( array $array [, int $sort_flags = SORT_STRING ] )
you can find the documentation Here
<?php
$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input);
print_r($result);
?>
the output
Array
(
[a] => green
[0] => red
[1] => blue
)
I hope that this was able to help
I prefer to calculate all dates just in one pass. (You may skip filling $dates and $dates_mon_fri arrays if they doesn't used in output also.) There is yet another approach to avoid array_diff() and array_unique() functions. I've used an array_flip() to exchange keys with values in $holdidays array to use fast array_key_exists() function.
<?php
$start = strtotime('2016-12-01');
$holidays = [
'2016-12-13',
'2016-12-24',
];
$dates = [];
$dates_mon_fri = [];
$dates_working = [];
$flip_holidays = array_flip($holidays);
for ($i = 0; $i < 20; $i++) {
$timestamp = strtotime("+$i day", $start);
$date = date('Y-m-d', $timestamp);
$dates[] = $date;
$mon_fri = false;
if (date('N', $timestamp) <= 5) {
$dates_mon_fri[] = $date;
$mon_fri = true;
}
if ($mon_fri && !array_key_exists($date, $flip_holidays)) {
$dates_working[] = $date;
}
}
var_dump($dates);
var_dump($dates_mon_fri);
var_dump($dates_working);
You can avoid using explicit looping:
$begin = new DateTimeImmutable('2016-12-01');
$end = $begin->modify('+20 days');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval, $end);
$allDates = iterator_to_array($daterange);
$datesExcludingWeekends = array_filter($allDates, function ($date) {
return (int) $date->format("N") < 6;
});
$datesExcludingWeekends = array_map(
'date_format',
$datesExcludingWeekends,
array_fill(1, count($datesExcludingWeekends), 'Y-m-d')
);
$holidays = [
'2016-12-13',
'2016-12-24',
];
$datesExcludingWeekendsIncludingHolidays = array_flip(array_merge(
$datesExcludingWeekends,
array_diff($holidays, $datesExcludingWeekends)
));
Here is working demo.
Also, take a look at the Carbon library. If you need some exhaustive working with dates this library can really ease your life.
I have 2 dates. I want to get all months with total days in each.
How can I do this in PHP?
For example
$date1 = '2013-11-13'; // yy-mm-dd format
$date2 = '2014-02-14';
Output
Months Total Days
-----------------------
11-2013 30
12-2013 31
01-2014 31
02-2014 28
Just try with:
$date1 = '2013-11-15';
$date2 = '2014-02-15';
$output = [];
$time = strtotime($date1);
$last = date('m-Y', strtotime($date2));
do {
$month = date('m-Y', $time);
$total = date('t', $time);
$output[] = [
'month' => $month,
'total' => $total,
];
$time = strtotime('+1 month', $time);
} while ($month != $last);
var_dump($output);
Output:
array (size=4)
0 =>
array (size=2)
'month' => string '11-2013' (length=7)
'total' => string '30' (length=2)
1 =>
array (size=2)
'month' => string '12-2013' (length=7)
'total' => string '31' (length=2)
2 =>
array (size=2)
'month' => string '01-2014' (length=7)
'total' => string '31' (length=2)
3 =>
array (size=2)
'month' => string '02-2014' (length=7)
'total' => string '28' (length=2)
Try the below given code :
$date1 = '2013-11-15'; // yy-mm-dd format
$date2 = '2014-02-15';
$start = new DateTime($date1);
$start->modify('first day of this month');
$end = new DateTime($date2);
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") ." " ;
echo cal_days_in_month(CAL_GREGORIAN,$dt->format("m"),$dt->format("Y")) . "<br/>";
}
Also, checkout this link for more
i used timestamp and date:
$date1 = '2013-11-15'; // yy-mm-dd format
$date2 = '2014-02-15';
$d1 = strtotime('2013-11-15');
$d2 = strtotime('2014-02-15');
while ($d1 <= $d2) {
echo date('m-d-Y', $d1)." | ";
echo cal_days_in_month(CAL_GREGORIAN, date('m', $d1), date('Y', $d1)) ."<br>";
$d1 = strtotime("+1 month", $d1);
}
This should help you, Check out,
$date1 = new DateTime('2013-11-15');
$date1->modify('first day of this month');
$date2 = new DateTime('2014-02-15');
$date2->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$value = new DatePeriod($date1, $interval, $date2);
foreach ($value as $dates) {
echo $dates->format("m- Y")."-->".cal_days_in_month(0,$dates->format("m"),$dates->format("Y"))."<br>\n";
}
This is what i came up with:
$arr_months = array();
$date1 = new DateTime('2013-11-15');
$date2 = new DateTime('2014-02-15');
$month1 = new DateTime($date1->format('Y-m')); //The first day of the month of date 1
while ($month1 < $date2) { //Check if the first day of the next month is still before date 2
$arr_months[$month1->format('Y-m')] = cal_days_in_month(CAL_GREGORIAN, $month1->format('m'), $month1->format('Y')); //Add it to the array
$month1->modify('+1 month'); //Add one month and repeat
}
print_r($arr_months);
It creates an associative array with the month as key and the number of days as value.
The array created from the example would be:
Array
(
[2013-11] => 30
[2013-12] => 31
[2014-01] => 31
[2014-02] => 28
)
With a foreach loop you will be able to scroll trough the array easily.
You can use the DateTime class along with cal_day_in_month() like this
$datetime1 = "2014-02-15";
$datetime2= "2013-03-15";
$date1 = new DateTime($datetime1);
$date2 = new DateTime($datetime2);
while (date_format($date2, 'Y-m') <= date_format($date1, 'Y-m'))
{
$date2 = $date2->add(new DateInterval('P1M'));
echo $date2->format('Y-m')." | ".cal_days_in_month(CAL_GREGORIAN, $date2->format('m'), $date2->format('Y'))."<br>";
}
I'm looping through an array of days in the current month to generate another array of days that are on or after the current day. I'm also doing the same for the next month (which will always include all days as they are after the current date).
The complexity is when the next month is in a different year to the current month. The format of the final array is like this:
array("year" => array("month" => array(days)));
When both months are in the same year it might look like this:
$allDays = array("2013" => array( "11" => array(28,29,30), "12" => array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31)));
When the 2 months are in different years (i.e. Dec and Jan) it might look like this:
$allDays = array("2013" => array("12" => array(2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31)), "2014" => array("1" => array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31) )) ;
Here's my code that generates the list of dates for the current month and the next month:
// Set the default timezone
date_default_timezone_set('Australia/Sydney');
// Get days for current month
$day = date("Y-m-d");
$i = strtotime($day);
array("year" => array("month" => array(days)));
$linked_days = array(
date('Y', $i) => array(
date('m') => range(date('d', $i), intval(date('t'))),
),
);
// Get days for next month
$day2 = date("Y-m-d", strtotime('first day of next month')) ;
$i2 = strtotime($day2);
array("year" => array("month" => array(days)));
$linked_days2 = array(
date('Y', $i2) => array(
date('m') => range(date('d', $i2), intval(date('t'))),
),
);
I'm not sure how to go about combining them into the 1 array with a different sytanx if they are in the same year or not?
You can check if there is already an entry for the year in your array with isset function :
Change this
$day2 = date("Y-m-d", strtotime('first day of next month')) ;
$i2 = strtotime($day2);
array("year" => array("month" => array(days)));
$linked_days2 = array(
date('Y', $i2) => array(
date('m') => range(date('d', $i2), intval(date('t'))),
),
);
To
$day2 = date("Y-m-d", strtotime('first day of next month')) ;
$i2 = strtotime($day2);
array("year" => array("month" => array(days))); //useless line ??
if(!isset($linked_days[date('Y', $i2)])){
//if no entry for this year in array, create new entry
$linked_days[date('Y', $i2)] = array(date('m') => range(date('d', $i), intval(date('t'))));
}
else{
//else, just add the month entry
$linked_days[date('Y', $i2)][date('m')] = range(date('d', $i2), intval(date('t'))) ;
}
What is the most efficient way to get an array of months, from a specified date, up until the present day, grouped by year.
Eg getMonths("August 2012") would output
array(
array("Year"=>"2013", "months" = array(
"February", "January")
),
array("Year"=>"2012", "months" = array(
"December", "November","October", "September", "August")
)
)
So far I've got:
$start = strtotime('2012-08-01');
$end = time();
$month = $start;
$months[] = date('F', $start);
while($month <= $end) {
$month = strtotime("+1 month", $month);
$months[] = date('F', $month);
}
This is outputting the correct months, but not grouping them into years.
Thanks
You can try
function getMonths($month,$count = 1) {
$now = new DateTime();
$start = DateTime::createFromFormat("F Y", $month);
$list = array();
$interval = new DateInterval(sprintf("P%dM",$count));
while ( $start <= $now ) {
$list[$start->format("Y")][] = $start->format("F");
$start->add($interval);
}
return $list;
}
print_r(getMonths("August 2012"));
Output
Array
(
[2012] => Array
(
[0] => August
[1] => September
[2] => October
[3] => November
[4] => December
)
[2013] => Array
(
[0] => January
[1] => February
)
)
Since the answer posted here did not work for me (also tried online sandbox to be sure) i wrote a method that works with the very most versions of PHP:
function getMonths($monat, $year) {
$list = array();
for(;$monat <= 12;$monat++) {
if($year == date("Y") && $monat == date("m")) { // exit on current month+year
break;
}
if(!isset($list[ $year ])) {
$list[ $year ] = array();
}
$list[ $year ][ str_pad($monat, 2, '0', STR_PAD_LEFT) ] = date("F", strtotime('01.' . $monat . '.' . $year));
if($monat == 12) {
$monat = 0;
$year++;
}
}
return $list;
}