FancyBox PHP form submit issue - php

Question

Okay, so I've been having a problem for the past four days, and a couple hours ago, I think I may have solved part of it (fancybox example #5, on their site, seems to be something that I want), however, I cannot get any part of it to work.
<? if($_GET['page'] != "startTime"){ ?>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="/./fancybox/jquery.mousewheel-3.0.2.pack.js"></script>
<script type="text/javascript" src="/./fancybox/jquery.fancybox-1.3.1.js"></script>
<link rel="stylesheet" type="text/css" href="/./fancybox/jquery.fancybox-1.3.1.css" media="screen" />
<script type="text/javascript">
$(document).ready(function() {
$("#startTime").fancybox({
'padding' : 0,
'scrolling' : 'no',
'titleShow' : false,
'onClosed' : function() {
$("#login_error").hide();}
})
});
$("#startTimeForm").bind("submit", function() {
if ($("#year").val().length < 4) {
$("#login_error").show();
$.fancybox.resize();
return false;
}
$.fancybox.showActivity();
$.ajax({
type : "POST",
cache : false,
url : "downTime.php?page=ajax",
data : $(this).serializeArray(),
success : function(data) {
$.fancybox(data);
}
});
return false;
});
</script>
<? } ?>
<? if($_GET['page'] == "ajax"){
var_dump($_POST); } ?>
<? if($_GET['page'] == "startTime"){?>
<div style="width:250px" class="new">
<table cellpadding="0" cellspacing="0" border="0" width="100%" class="new">
<tr>
<form id="startTimeForm" method=post>
<p id="login_error">Please, enter data</p>
<tr>
<td>Enter Year</td>
<td><input class="czas" id="sec" name="year" type="text" size="5" maxlength="5" value="00" /></td></tr>
<tr>
<td colspan="2" align="center"><br /><input class="czas" type="submit" name="newTime" value="Set Start Time" /></td></tr>
</form>
I also had used a javascript function, below, and I'd eventually like that to work in the code above, but I cannot get the above to work properly. It just does nothing. Firebug also reports no errors.
<script>
function closeFB() {
<? $unix = mktime(0, 0, 0, 1, 1, $_POST['year']); ?>
$("#startTimeDiv").html("<div id='message'></div>");
$("#message").html("<p>Contact Form Submitted!</p>")
.append("<p>We will be in touch soon.<br><? echo $unix; ?></p>");
$.fancybox.close();
}
</script>
So, any help would be appreciated. Please tell me what I'm doing wrong.

Answer 1

The demonstration here worked to solve the problem. It created another problem, but that is for another question. I believe that was your demo, JFK, so thank you.

Answer 2

$.ajax({
type : "POST",
cache : false,
url : "downTime.php?page=ajax",
data : $(this).serializeArray(),
success : function(data) {
Instead of:
$.fancybox(data);
Try
$("#fancyboxdiv").fancybox(data);
}
});
Where fancyboxdiv is the name of your element that hosts the fancybox.
You will change the other functions to
$("#fancyboxdiv").fancybox().close()
etc..
Most JQuery UI components require a element to work off of as its parent and it will usually modify that element adding/removing elements to it and changing CSS to give appearance that is needed