Pass form data to another page with php - php

I have a form on my homepage and when it is submitted, it takes users to another page on my site. I want to pass the form data entered to the next page, with something like:
<?php echo $email; ?>
Where $email is the email address the user entered into the form. How exactly do I accomplish this?


The best way to accomplish that is to use POST which is a method of Hypertext Transfer Protocol https://developer.mozilla.org/en-US/docs/Web/HTTP/Methods
index.php
<html>
<body>
<form action="site2.php" method="post">
Name: <input type="text" name="name">
Email: <input type="text" name="email">
<input type="submit">
</form>
</body>
</html>
site2.php
<html>
<body>
Hello <?php echo $_POST["name"]; ?>!<br>
Your mail is <?php echo $_POST["mail"]; ?>.
</body>
</html>
output
Hello "name" !
Your email is "whatyou#addedonindex.com" .

Related

Reading data using post

Consider following html page:
index.html
<html>
<body>
<form action="welcome.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>
</body>
</html>
If GET is used for reading the data let's say "name" then following is understandable:
welcome.php
<html>
<body>
Welcome <?php echo $_GET["name"]; ?><br>
Your email address is: <?php echo $_GET["email"]; ?>
</body>
</html>
When POST is meant for writing the data How is it possible to read the "name" using POST? Why should the following work?
<html>
<body>
Welcome <?php echo $_POST["name"]; ?><br>
Your email address is: <?php echo $_POST["email"]; ?>
</body>
</html>

First of all add a name in your submit input <input name="submit" type="submit">
Second into welcome.php add if(isset($_GET["submit"])){ $submit = preg_replace('#[^a-z0-9]#i', '', $_GET['submit']); }
and then use Welcome <?php echo $submit; ?>
i suggest to use preg_replace if you want to pass values from page to page

Why is my PHP form not posting data correctly?

I've just started using PHP forms for my website prototype, and it wasn't working so I decided to try to make a basic form example. No fancy CSS, just pure data. This is the code.
Index.html
<html>
<body>
<form action="welcome.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>
</body>
</html>
welcome.php
<html>
<body>
Welcome <?php echo $_POST["name"]; ?>
<br />
Your email address is: <?php echo $_POST["email"]; ?>
</body>
</html>
The code works as far as displaying the 'Welcome ___ Your email address is: ____.
It just doesn't display the data entered in the form. For clarification as to whether my PHP works, I have tried just displaying some text and it worked fine. I use the PHP Editor phpDesigner8.
Thanks!

php code wont work and display data

This code is from w3schools which displays the email address and name once the user submits the form. However when I tried copying the code it wouldn't let me display the same output and would only say Cannot POST /welcome.php or it would display the welcome.php code whenever i submit.
I didn't even alter it in anyway but why wont it work? D:
index.html
<!DOCTYPE HTML>
<html>
<body>
<form action="welcome.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>
</body>
</html>
welcome.php
<html>
<body>
Welcome <?php echo $_POST["name"]; ?><br>
Your email address is: <?php echo $_POST["email"]; ?>
</body>
</html>

PHP code doesn't print any value

Here i entered name nd email id but when i click on submit button my entered information is blank like below image.
In PHP clicking on the submit button doesn't print the information. I used $GET and $POST, both are not working.
<!DOCTYPE HTML>
<html>
<body>
<form action="php_forms.php" method="post">
Name: <input type="text" name="name"><br>
Email: <input type="text" name="email"><br>
<input type="submit">
</form>
</body>
</html>
<html>
<body>
Welcome <?php echo $_POST["name"]; ?><br>
Your email address is: <?php echo $_POST["email"]; ?>
</body>
</html>

It should be work.Change your action (php_forms.php) file code.I have tried in my server.Hope it will be helped.
<html>
<body>
Welcome <?php echo htmlspecialchars($_POST["name"]); ?><br>
Your email address is: <?php echo htmlspecialchars($_POST["email"]); ?>
</body>
</html>
Read More dealing with html forms in PHP.NET.

Your form uses get method and php_forms.php uses post method. Try
<form action="php_forms.php" method="post">

PHP form - on submit stay on same page

I have a PHP form that is located on file contact.html.
The form is processed from file processForm.php.
When a user fills out the form and clicks on submit,
processForm.php sends the email and direct the user to - processForm.php
with a message on that page "Success! Your message has been sent."
I do not know much about PHP, but I know that the action that is calling for this is:
// Die with a success message
die("<span class='success'>Success! Your message has been sent.</span>");
How can I keep the message inside the form div without redirecting to the
processForm.php page?
I can post the entire processForm.php if needed, but it is long.

In order to stay on the same page on submit you can leave action empty (action="") into the form tag, or leave it out altogether.
For the message, create a variable ($message = "Success! You entered: ".$input;") and then echo the variable at the place in the page where you want the message to appear with <?php echo $message; ?>.
Like this:
<?php
$message = "";
if(isset($_POST['SubmitButton'])){ //check if form was submitted
$input = $_POST['inputText']; //get input text
$message = "Success! You entered: ".$input;
}
?>
<html>
<body>
<form action="" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>

The best way to stay on the same page is to post to the same page:
<form method="post" action="<?=$_SERVER['PHP_SELF'];?>">

There are two ways of doing it:
Submit the form to the same page: Handle the submitted form using PHP script. (This can be done by setting the form action to the current page URL.)
if(isset($_POST['submit'])) {
// Enter the code you want to execute after the form has been submitted
// Display Success or Failure message (if any)
} else {
// Display the Form and the Submit Button
}
Using AJAX Form Submission which is a little more difficult for a beginner than method #1.

You can use the # action in a form action:
<?php
if(isset($_POST['SubmitButton'])){ // Check if form was submitted
$input = $_POST['inputText']; // Get input text
$message = "Success! You entered: " . $input;
}
?>
<html>
<body>
<form action="#" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>

Friend. Use this way, There will be no "Undefined variable message" and it will work fine.
<?php
if(isset($_POST['SubmitButton'])){
$price = $_POST["price"];
$qty = $_POST["qty"];
$message = $price*$qty;
}
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<form action="#" method="post">
<input type="number" name="price"> <br>
<input type="number" name="qty"><br>
<input type="submit" name="SubmitButton">
</form>
<?php echo "The Answer is" .$message; ?>
</body>
</html>

You have to use code similar to this:
echo "<div id='divwithform'>";
if(isset($_POST['submit'])) // if form was submitted (if you came here with form data)
{
echo "Success";
}
else // if form was not submitted (if you came here without form data)
{
echo "<form> ... </form>";
}
echo "</div>";
Code with if like this is typical for many pages, however this is very simplified.
Normally, you have to validate some data in first "if" (check if form fields were not empty etc).
Please visit www.thenewboston.org or phpacademy.org. There are very good PHP video tutorials, including forms.

You can see the following example for the Form action on the same page
<form action="" method="post">
<table border="1px">
<tr><td>Name: <input type="text" name="user_name" ></td></tr>
<tr><td align="right"> <input type="submit" value="submit" name="btn">
</td></tr>
</table>
</form>
<?php
if(isset($_POST['btn'])){
$name=$_POST['user_name'];
echo 'Welcome '. $name;
}
?>

simple just ignore the action attribute and use !empty (not empty) in php.
<form method="post">
<input type="name" name="name">
<input type="submit">
</form>
<?PHP
if(!empty($_POST['name']))
{
echo $_POST['name'];
}
?>

Try this... worked for me
<form action="submit.php" method="post">
<input type="text" name="input">
<input type="submit">
</form>
------ submit.php ------
<?php header("Location: ../index.php"); ?>

I know this is an old question but since it came up as the top answer on Google, it is worth an update.
You do not need to use jQuery or JavaScript to stay on the same page after form submission.
All you need to do is get PHP to return just a status code of 204 (No Content).
That tells the page to stay where it is. Of course, you will probably then want some JavaScript to empty the selected filename.

What I do is I want the page to stay after submit when there are errors...So I want the page to be reloaded :
($_SERVER["PHP_SELF"])
While I include the sript from a seperate file e.g
include_once "test.php";
I also read somewhere that
if(isset($_POST['submit']))
Is a beginners old fasion way of posting a form, and
if ($_SERVER['REQUEST_METHOD'] == 'POST')
Should be used (Not my words, read it somewhere)

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