THIS IS THE OUTPUT OF THE QUERY:
SELECT * FROM
((SELECT
privatemsgs.id,
privatemsgs.useradn,
privatemsgs.useraid,
privatemsgs.title,
privatemsgs.created,
privatemsgs.timee,
privatemsgs.isread,
u.photo AS creatorphoto,
privatemsgs.relatedto
FROM privatemsgs
LEFT JOIN
users AS u ON(privatemsgs.useraid = u.id)
WHERE userbid='$myid'
AND relatedto=0 and bdel=1)
UNION
(SELECT
privatemsgs.id,
privatemsgs.useradn,
privatemsgs.useraid,
privatemsgs.title,
privatemsgs.created,
privatemsgs.timee,
privatemsgs.isread,
u.photo AS creatorphoto,
rel.relatedto
FROM privatemsgs AS rel
JOIN privatemsgs ON(rel.relatedto = privatemsgs.id)
LEFT JOIN
users AS u ON(rel.useraid = u.id)
WHERE rel.userbid='$myid'
)) privatemsgs
GROUP BY id
ORDER BY timee DESC
I got double id "2". first 1 with "isread = 0", second with "isread = 1".
When I added "group by id", I've got (line 2)
But i need the output to show that isread = 1 (like line 3)
How do i fix it?
add MAX(isread) near the *. GROUP BY works only on Aggregate functions
Related
I have a query that LEFT JOINS another table to group rows. I am trying to only select records from the first table "googleimage" where the user_id is a certain number. (user_id is a column in "googleimage" table.
SELECT g.*
FROM googleimage g
LEFT JOIN (SELECT image_id, COUNT(*) AS cnt
FROM googleimagefound WHERE status = 0
GROUP BY image_id) gf ON gf.image_id = g.id
ORDER BY COALESCE(cnt, 0) DESC");
I have tried adding a new ON statement beiside the
gf ON gf.image_id = g.id
I have also tried changing
SELECT g.*
FROM googleimage g
to
SELECT g.*
FROM googleimage WHERE user_id = 1 g
but none of them seem to work, any help will be appriciated
Try changing you query a bit like below
SELECT g.*
FROM googleimage g
LEFT JOIN (SELECT image_id, COUNT(*) AS cnt
FROM googleimagefound WHERE status = 0
GROUP BY image_id) gf ON gf.image_id = g.id
WHERE g.user_id = 1 <-- add this condition
ORDER BY COALESCE(gf.cnt, 0) DESC;
i need select some data from two tables ,
please help me use inner join for this selection .
players in selction2 must not be in selection1...
first select :
$rs = "SELECT *
FROM `player`
WHERE `status`=1 AND `credit`>=1 AND `username` NOT LIKE '$user'
ORDER BY ls ASC,credit DESC
LIMIT 0 ,10;
Second: this players must remove from result of selection1
$rs2 = "SELECT *
FROM `ip_log`
WHERE `playerid`='$ui' AND `win`='1' AND `date`='$date' ";`
You can use LEFT JOIN for this:
This shows the log messages for everyone not in selection 1.
SELECT l.*
FROM ip_log AS l
LEFT JOIN
(SELECT username
FROM player
WHERE status = 1 AND credit >= 1 AND username NOT LIKE '$user'
ORDER BY ls ASC, credit DESC
LIMIT 10) AS p
ON l.player = p.username
WHERE win = 1 and date = '$date'
AND p.username IS NULL
This shows the top 10 player data, except the ones with log messages in selection 2
SELECT p.*
FROM player AS p
LEFT JOIN ip_log AS l ON l.player = p.username AND l.win = 1 AND l.date = '$date'
WHERE p.status = 1 AND p.credit >= 1 AND p.username NOT LIKE '$user'
AND l.player IS NULL
ORDER BY p.ls ASC, p.credit DESC
LIMIT 10
In both cases, testing a column in the second table with IS NULL makes it return only the rows in the first table that don't have a match in the second table. See
Return row only if value doesn't exist
You can do it with LEFT JOIN
SELECT player.*,ip_log.* FROM `player` LEFT JOIN `ip_log` ON player.id!=ip_log.playerid GROUP BY player.id
My query is too long (3-4s). Any idea's how make this faster?
SELECT u.id AS id_uzytkownika,
u.login,
u.ranga,
u.online_light AS online,
(SELECT MAX(id)
FROM uzytkownicy_zdjecia
WHERE id_uzytkownika = u.id
AND prywatna =0) AS id_fotki,
(SELECT fotka
FROM uzytkownicy_zdjecia
WHERE id = id_fotki) AS fotka ,
(SELECT srednia_ocen
FROM uzytkownicy_zdjecia
WHERE id = id_fotki) AS srednia_ocen,
(SELECT ile_ocen
FROM uzytkownicy_zdjecia
WHERE id = id_fotki) AS ile_ocen
FROM uzytkownicy u
WHERE u.foto =1
AND u.plec = "mezczyzna"
ORDER BY srednia_ocen DESC,
ile_ocen DESC,
id_fotki DESC LIMIT 42
Could you maybe explain your table structure and what this query is about? Since the column names are not in English, most readers will probably have a problem understanding what you are trying to do here...
In general, it looks like you have a LOT of nested SELECTS here to the same table - is there any special reason for that?
Try this:
SELECT u.id AS id_uzytkownika,
u.login,
u.ranga,
u.online_light AS online,
(SELECT MAX(id)
FROM uzytkownicy_zdjecia
WHERE id_uzytkownika = u.id
AND prywatna =0) AS id_fotki,
z.fotka,
z.srednia_ocen,
z.ile_ocen
FROM uzytkownicy u
JOIN uzytkownicy_zdjecia z
ON u.id_fotki = z.id
WHERE u.foto =1
AND u.plec = "mezczyzna"
ORDER BY srednia_ocen DESC,
ile_ocen DESC,
id_fotki DESC LIMIT 42
I've substituted 3 subqueries with a JOIN. The first subquery has a different condition, if you can merge that condition withn others queries you can remove that.
Pay attention You have named id_fokta the result of subquery, but the same name has the primary key of uzytkownicy table
You don't have to query the same table with the same criteria again and again. Replace your sub-selects with a simple join. A LEFT JOIN, if it is possible that no matching record exists.
SELECT
u.id AS id_uzytkownika,
u.login,
u.ranga,
u.online_light AS online,
(
SELECT MAX(id)
FROM uzytkownicy_zdjecia
WHERE id_uzytkownika = u.id
AND prywatna =0
) AS id_fotki,
uz.fotka,
uz.srednia_ocen,
uz.ile_ocen
FROM uzytkownicy u
LEFT JOIN uzytkownicy_zdjecia uz ON uz.id = u.id_fotki
WHERE u.foto = 1
AND u.plec = "mezczyzna"
ORDER BY u.srednia_ocen DESC,
u.ile_ocen DESC,
u.id_fotki DESC LIMIT 42
An alternative way to write the query above is to aggregate first and then join:
SELECT
u.id AS id_uzytkownika,
u.login,
u.ranga,
u.online_light AS online,
uzz.id_fotki,
uz.fotka,
uz.srednia_ocen,
uz.ile_ocen
FROM uzytkownicy u
LEFT JOIN uzytkownicy_zdjecia uz ON uz.id = u.id_fotki
LEFT JOIN
(
SELECT id_uzytkownika, MAX(id) AS id_fotki
FROM uzytkownicy_zdjecia
WHERE prywatna =0
GROUP BY id_uzytkownika
) uzz ON uzz.id_uzytkownika = u.id
WHERE u.foto = 1
AND u.plec = "mezczyzna"
ORDER BY u.srednia_ocen DESC,
u.ile_ocen DESC,
u.id_fotki DESC LIMIT 42
By the way: What is "mezczyzna"? A string? Then this should be single quotes.
I have the following SQL query:
SELECT p.id, title, l.id, username FROM photoTable p JOIN userTable
l ON (l.id = p.iduser) ORDER BY p.id DESC LIMIT 50
I need to change the p.id to p.IdPhoto but the problem is that I only want this done temporarily within the call. I have seen ALTER TABLE as an option, but I am a bit unsure of how I can do this without altering both id fields. Any ideas?
Would this work?
SELECT p.id as idPhoto, title, l.id,
username
FROM photoTable p
JOIN userTable l ON (l.id = p.iduser)
ORDER BY p.id DESC LIMIT 50
I currently have:
SELECT tbl_review.*, users.first_name, users.last_name, (
SELECT order_ns.tran_date
FROM order_ns
LEFT JOIN product_2_order_ns.external_order_id = order_ns.order_id
WHERE product_2_order_ns.bkfno IN :id
ORDER BY order_ns.trandate ASC
LIMIT 1
) as purchase_date
FROM tbl_review
LEFT JOIN users ON users.sequal_user_id = tbl_review.user_id
WHERE tbl_review.product_id IN :id AND tbl_review.approved = 1
Which, in its sub query, selects an order the user has which has a product in question (defined in :id) get the the oldest transaction date on file for one of the found orders.
I would really like to keep this to one call of the database (don't really want to call again for each returned user for just one field, or even do a range query of all users) but obviously this particular query isn't working.
What can I do, if anything, to get this working?
I cannot make the sub query into a join since they are two distinct pieces of data, the sub query needs to return detail for each row in the main query.
I think you just want a correlated subquery. It is unclear exactly what the relationship is between the inner query and the outer one. My guess is that it is on users and orders:
SELECT tbl_review.*, users.first_name, users.last_name,
(SELECT order_ns.tran_date
FROM order_ns LEFT JOIN
product_2_order_ns
on product_2_order_ns.external_order_id = order_ns.order_id and
product_2_order_ns.bkfno = tbl_review.product_id and
WHERE order_ns.user_id = tbl_review.user_id
ORDER BY order_ns.trandate ASC
LIMIT 1
) as purchase_date
FROM tbl_review LEFT JOIN
users
ON users.sequal_user_id = tbl_review.user_id
WHERE tbl_review.product_id IN :id AND tbl_review.approved = 1;
EDIT:
Oh, the inner query has no relationship to the outer query. Then it is easier. Move it to the from clause using cross join:
SELECT tbl_review.*, users.first_name, users.last_name,
innerquery.tran_date as purchase_date
FROM tbl_review LEFT JOIN
users
ON users.sequal_user_id = tbl_review.user_id cross join
(SELECT order_ns.tran_date
FROM order_ns LEFT JOIN
product_2_order_ns
on product_2_order_ns.external_order_id = order_ns.order_id
WHERE product_2_order_ns.bkfno IN :id
ORDER BY order_ns.trandate ASC
LIMIT 1
) innerquery
WHERE tbl_review.product_id IN :id AND tbl_review.approved = 1;
#Gordons answer is really close but I wanted it to return even if no data was found for tran_date so I changed my query to:
SELECT tbl_review.*, users.first_name, users.last_name, order_ns.tran_date
FROM tbl_review
LEFT JOIN users ON users.sequal_user_id = tbl_review.user_id
LEFT JOIN order_ns ON order_ns.order_id = (
SELECT order_ns.order_id
FROM order_ns
LEFT JOIN product_2_order_ns on product_2_order_ns.external_order_id = order_ns.order_id
WHERE product_2_order_ns.bkfno IN :id
ORDER BY order_ns.tran_date ASC
LIMIT 1
)
WHERE tbl_review.product_id IN :id AND tbl_review.approved = 1;
This will return the distinct data of tran_date irrespective of whether it is found or not.