Extract img src from string with preg_match_all - php

Question

I've been trying to use preg_match_all for 30 minutes but it looks like I can't do it.
Basically I have a $var which contains a string of HTML code. For example:
<br>iihfuhuf
<img title="Image: http://www.jlnv2.local/temp/temp513caca536fcd.jpeg"
src="http://www.jlnv2.local/temp/temp513caca536fcd.jpeg">
<img src="http://www.jlnv2.local/temp/temp513caca73b8da.jpeg"><br>
I want to get the src attribute values of img tags that contain /temp/temp[a-z0-9]{13}\.jpeg in their src value.
This is what I have so far:
preg_match_all('!(<img.*src=".*/temp/temp[a-z0-9]{13}\.jpeg"(.*alt=".*")?>)!', $content, $matches);

Answer 1

<img[^>]*src="([^"]*/temp/temp[a-z0-9]{13}\.jpeg)"
<img[^>]* Select IMG tags
src="([^"]*)" gets src value and save it as a match
/temp/temp[a-z0-9]{13}\.jpeg is the filter for src values
For quick RegEx tests use some online tool like http://regexpal.com/

Answer 2

All you need to do is add another group to your regular expression. You have du surround everything you want to extract from the match with braces:
preg_match_all('!(<img.*src="(.*/temp/temp[a-z0-9]{13}\.jpeg)"(.*alt=".*")?>)!', $content, $matches);
You can see that working here. You can find the URLs in $matches[2].
But just for having said it: Regular expressions are no reasonable approach to extract anything from HTML. You would be better off using DOMDocument, XPath or something along that line.

Answer 3

Try this:
preg_match_all('/src="([^"]+temp[a-z0-9]{13}\.jpeg)"/',$url,$matches);
var_dump($matches);

Answer 4

<?php
$text = '<br>iihfuhuf<img title="Image: http://www.jlnv2.local/temp/temp513caca536fcd.jpeg" src="http://www.jlnv2.local/temp/temp513caca536fcd.jpeg"><img src="http://www.jlnv2.local/temp/temp513caca73b8da.jpeg"><br>';
$pattern = '#src="([^"]+/temp/temp[a-z0-9]{13}\.jpeg)"#';
preg_match_all($pattern, $text, $out);
echo '<pre>';
print_r($out);
?>
Array
(
[0] => Array
(
[0] => src="http://www.jlnv2.local/temp/temp513caca536fcd.jpeg"
[1] => src="http://www.jlnv2.local/temp/temp513caca73b8da.jpeg"
)
[1] => Array
(
[0] => http://www.jlnv2.local/temp/temp513caca536fcd.jpeg
[1] => http://www.jlnv2.local/temp/temp513caca73b8da.jpeg
)
)

Answer 5

Here is a DOMDocument/DOMXPath based example of how to do it. This is arguably the only right way to do it, because unless you are really good at regular expressions there will most likely always be edge cases that will break your logic.
$doc = new DOMDocument;
$xpath = new DOMXPath($doc);
$doc->loadHTML($content);
$candidates = $xpath->query("//img[contains(#src, '/temp/temp')]");
$result = array();
foreach ($candidates as $image) {
$src = $image->getAttribute('src');
if (preg_match('/temp[0-9a-z]{13}\.jpeg$/', $src, $matches)) {
$result[] = $src;
}
}
print_r($result);

Answer 6

$text = '<br>iihfuhuf<img title="Image: http://www.jlnv2.local/temp/temp513caca536fcd.jpeg" src="http://www.jlnv2.local/temp/temp513caca536fcd.jpeg"><img src="http://www.jlnv2.local/temp/temp513caca73b8da.jpeg"><br>';
$pattern = '#src="([^"]+/temp/temp[a-z0-9]{13}\.jpeg)"#';
preg_match( '#src="([^"]+)"#' , $text, $match );
$src = array_pop($match);
echo $src;