database saving and retrieving the last saved value - php

Question

I have a confusion in mind regarding a logic.. it is a form that i first want to validate then I want to save in database and then i want to display it on another page.
I have validated it (transferring (i.e. form action) the form to the same page), I have saved it in database, and now I m trying to display the data on another page.
What I have thought, that I'll save the data to the db and transfer some unique value to another page, maybe some sort of number auto generated by database related to the same form.
now I have problem how to do it? Any ideas guys?
Since it is a logic hence I am tagging php, MySQL and JS

Answer 1

Call mysql_insert_id() once you perform INSERT operation something like this,
$lastInsertedId = mysql_insert_id(); # Assuming you have an auto increment column in your table.
header('Location: view.php?id='.$lastInsertedId);
Than in your view.php get the id & fetch record to display it,
$id = $_GET['id'];
Note: Please, don't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO, or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.

Answer 2

After insertion query,use
$lastID = mysql_insert_id();
After then you can redirect to another page like,
header("location:view_page.php?id=$lastID");
Than in view_page.php page,use
$lastID= $_GET['id'];
after then fetch record from database to display data.
NOTE: It will work only when your database table has autoincremented field as index key.

Answer 3

Using mysql_insert_id() is a way. But If you do not want to query your database and still have that then you can do it this way . Below goes the example
<form name="frm" method="POST" action="display.php">
<input type="text" name="your_name" value="" />
<input type="text" name="age" value="" />
<input type="submit" name="save" value="Save" />
</form>
Now in your display.php page
<?php
// DO YOUR DATABASE CONNECTIVITY
$name = $_POST['your_name'];
$age = $_POST['age'];
$query = "insert into table_name values('$name','$age')";
if(mysql_query($insert)) {
?>
<table>
<tr>
<td>Name</td>
<td>Age</td>
</tr>
<tr>
<td><?php echo $name;?></td>
<td><?php echo $age;?></td>
</tr>
</table>
<?php } else { echo "No Insertion"; } ?>
Remember mysql_* function are depreciated. So avoid those. Also check for sql injection