Insert ajax populated dropdown into database in php - php

Question

<select id="country" name="country" onChange="getState(this.value)" class="dropdown">
<option value="0">Select Country</option>
<?php
echo $country;
?>
</select>
the above code takes country from database, according to the country using ajax, i have created one dropdown using below code, am not able to insert the state value. how can I get the state value in php dbpage for inserting the state valu
<div id="statediv" >
<select id="ddlstate" name="ddlstate" class="dropdown" value="0">
<option>Select Country First</option>
</select>
</div>
this is my full ajax code
function getState(countryId)
{
var strURL="findState.php?country="+countryId;
var req = getXMLHTTP();
if (req) {
req.onreadystatechange = function() {
if (req.readyState == 4) {
if (req.status == 200) {
document.getElementById('statediv').innerHTML=req.responseText;
}
else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
this is findState.php
<?php $country=intval($_GET['country']);
$query="SELECT stateid,statename FROM state WHERE countryid='$country'";
$result=mysql_query($query);
?>
<select name="state" onchange="getCity(<?php echo $country?>,this.value)">
<option>Select State</option>
<?php while($row=mysql_fetch_array($result)) { ?>
<option value=<?php echo $row['stateid']?>>
<?php echo $row['statename']?>
</option>
<?php } ?>
</select>

Answer 1

As long as your Ajax is generating and populating the drop down properly, like so:
<select id="country" name="country" onChange="getState(this.value)" class="dropdown">
<option value="0">Select Country</option>
<option value="1">Country1</option>
<option value="2">Country2</option>
<option value="3">Country3</option>
</select>
Check with firebug, or by viewing the source code of the page. Once you know thats correct, submit the form and use PHP code like this to check:
if( isset($_REQUEST['country'] ) ) {
echo $_REQUEST['country'];
} else {
echo "Country not sent from form";
}
Once you know the country is being sent from your form, you can use the value to put into a database or whatever you like.

Answer 2

please find the states using countryid and execute in such a manner.
<?php $states= getStates($countryid);
$str ='';
$str .='<select id="ddlstate" name="ddlstate" class="dropdown" value="0">';
foreach($states as $val){
$str.='<option value="'.$val->id.'">'.$val->name.'</option>';
}
$str.='</select>';
echo $str; exit; ?>
This is just sample code which you need to use in php file

Answer 3

I guess your insert into query is wrong. Check the number of fields and the values provided.
insert into query_mas(employee_id,country_id,state_id,city_id,experience,query) values('".$employee_id."','".$country_id."','".$state_id."','".$city_id."','".$e‌​xperience."')";