Create a delete page form in Yii Framework? - php

Question

I know that usually you would just use the integrated CRUD delete button that is in admin however for my purposes I am requiring an actual page for delete that just has the id in a field and a submit button but so far it just produces the error view so any assistance is appreciated. I have tried to create it the same as my create and update pages are set up, please see the code below:
The link to the delete page:
<?php echo CHtml::link('Delete Article', array('delete', 'id'=>$pageid)); ?>
The link it produces:
http://local/..../Yii/news/index.php/delete?id=3
The controller:
public function actionDelete($id)
{
$model=$this->loadModel($id);
if(isset($_POST['news_model']))
{
$model->attributes=$_POST['news_model'];
if($model->save())
$this->redirect('index');
}
$this->render(array('delete', array(
'model'=>$model,
));
}
Delete.php:
<h2>Delete a news item</h2>
<?php echo $this->renderPartial('_form2', array('model'=>$model)); ?>
_form2.php
<?php echo $form->errorSummary($model); ?>
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'news-model-form',
'enableAjaxValidation'=>false,
)); ?>
<div class="form">
<div class="row">
<?php echo $form->labelEx($model,'id'); ?><br>
<?php echo $form->textField($model,'id',array('size'=>50,'maxlength'=>128)); ?>
<?php echo $form->error($model,'id'); ?>
</div><br>
<div class="row buttons">
<?php echo CHtml::submitButton($model->isNewRecord ? 'Delete a news item'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- form -->
Thanks in advance for any help given.

Answer 1

You got an error in your php synax in _form2.php
<?php echo CHtml::submitButton($model->isNewRecord ? 'Delete a news item'); ?>
more like
<?php echo CHtml::submitButton($model->isNewRecord ? 'Delete a news item':'Delete an old item'); ?>
See the Ternary Operator in PHP: Comparison Operators
... yet I don't se the point in that sentence, to me it would seem a little bit more like:
<?php if (!$model->isNewRecord) echo CHtml::submitButton("Delete Record"); ?>
... but the record is guaranteed to not be new when it is loaded by $model=$this->loadModel($id);
Also, In Delete.php
<?php echo $this->renderPartial('_form2', array('model'=>$model)); ?>
would be more like
<?php echo $this->renderPartial('_form2', array('model'=>$model), true); ?>
or
<?php $this->renderPartial('_form2', array('model'=>$model)); ?>
Seel the documentation renderPartial(), specially pay attention to its return value its third argument. Turns out that you're actually echoing NULL. which explains why there is no display.