I've got a little doubt.
How I can know the timestamp from day X, about hour 00:00:00 till 23:59:59?
I guess that time() just gives you the current timestamp, and I would need the timestamp from the beginning of a day to the final one so I could check my DB in MySQL for a moment between those times.
strtotime converts date from string to timestamp.
$start_date = "2012-01-10";
$end_date = "2012-04-14";
$start = strtotime($start_date . " 00:00:00");
$end = strtotime($end_date . " 23:59:59");
$today = new DateTime();
$morning = $today->format('Y-m-d 00:00:00');
$evening = $today->format('Y-m-d 23:59:59');
You could use mktime().
http://php.net/manual/en/function.mktime.php
// Set the default timezone to use. Available as of PHP 5.1
date_default_timezone_set('UTC');
// Prints: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));
// Prints something like: 2006-04-05T01:02:03+00:00
echo date('c', mktime(1, 2, 3, 4, 5, 2006));
Have a look at the strtotime function, e.g.
$date1 = 'today 00:00:00';
$date2 = 'today 23:59:59';
$unixTime1 = strtotime($date1);
$unixTime2 = strtotime($date2);
Related
I need to get the timestamp for the current week's Wednesday and Saturday at 22:59, and then convert the timestamp to a human-readable date.
I've tried the following:
date_default_timezone_set('America/New_York');
$wednesdayLimit = strtotime('wednesday this week');
$saturdayLimit = strtotime('saturday this week');
$wednesdayLimit->setTime(22,59,0);
$saturdayLimit->setTime(22,59,0);
echo date("Y-m-d H:i:d", $wednesdayLimit);
echo date("Y-m-d H:i:d", $saturdayLimit);
But I get the following error:
Uncaught Error: Call to a member function setTime() on integer
One liner:
print date('Y-m-d H:i:s', strtotime('wednesday this week 22:59:00'));¸
Yields:
2016-01-27 22:59:00
How about
$wednesday = strtotime('wednesday this week');
$wednesdayStart = $wednesday - ($wednesday % 60*60*24);
$wednesdayEnd = $wednesdayStart + (60 * 60 * 24) - 1;
You could use DateTime and do something like this.
$date = new \DateTime();
$date->setISODate((int)$date->format('o'), (int)$date->format('W'), 3);
$date->setTime(22, 59, 0);
echo $date->format('D d-m-Y H:i:s');
Demo.
Or, if you like one liners.
$date = (new \DateTime())->modify('wednesday this week')->setTime(22, 59, 0);
Demo
I have some data that makes use of date("j/n/y") format i.e date for today is 23/1/15
I have tried
echo strtotime($today);
but this does not give me the timestamp i want.How would i convert a date in date("j/n/y") format to epoch?.
Use DateTime::createFromFormat() to read the date format and then use DateTime::getTimestamp() to format it as a timestamp.
$date = DateTime::createFromFormat('j/n/y', '23/1/15');
$epoch = $date->getTimestamp();
I think you're looking for the mktime function in PHP. It goes a little like this:
$timestamp = mktime(0,0,0,0,0,0);
Where, in order, the arguments are: hour, minute, second, month, day, year. So, in your case:
$today = mktime(0, 0, 0, 1, 23, 2015);
// Would return the timestamp for Jan. 23rd, 2015 at 12:00:00 am (I think)
If you're looking for a dynamic right now timestamp, you may use date() in each of the arguments of mktime. For example:
$rightnow = mktime(date("H"), date("i"), date("s"), date("m"), date("d"), date("Y"));
// Would return the timestamp for Jan. 23rd, 2015 at 10:57:25 am.
But, as John Conde says, it requires you break apart the date before you can use it, so it may not be as efficient.
Hope that helps!
Just to have another approach this one would be good for 85 more years.
$date = date('j/n/y', time());
list($day, $month, $year) = explode("/", $date);
$date = "20" . $year . "-" . $month . "-" . $day;
echo date('m/d/Y', strtotime($date));
I have a date in this format 030512 (ddmmyy).
But I'm having trouble with converting this to a date usable format I can add days to.
Basically.. I extracted the date above from a text file, Now I need to be able to add a number of days to it. But I am having trouble parsing the date in this format.
Is there another way of doing this rather then something like this:
// I have a date in this format
$date = '030512'; // 03 May 2012
$day = substr($date,0,2);
$month = substr($date, 2,2);
$year = substr($date, 4,2);
$date_after = $day . "-" . $month . "-".$year;
// Now i need to add x days to this
$total_no_nights = 010; // must be this format
$days_to_add = ltrim($total_no_nights,"0"); // 10, remove leading zero
// how do i add 10 days to this date.
You can do this (php >= 5.3):
$date = DateTime::createFromFormat('dmy', '030512');
$date->modify('+1 day');
echo $date->format('Y-m-d');
http://www.php.net/manual/en/datetime.createfromformat.php
For php < 5.3 :
$dateArray = str_split('030512', 2);
$dateArray[2] += 2000;
echo date("d/m/Y", strtotime('+1 day', strtotime(implode('-', array_reverse($dateArray)))));
try this using the month/day/year you already have:
$date = "$month/$day/$year";
$change = '+10 day';
echo date("d/m/Y", strtotime($change, strtotime($date)));
Assuming the date will always be in the future (or at least after 1st Jan 2000), you're not far wrong:
// I have a date in this format
$date = '030512'; // 03 May 2012
$day = substr($date,0,2);
$month = substr($date, 2,2);
$year = substr($date, 4,2);
// dd-mm-yy is not a universal format but we can use mktime which also gives us a timestamp to use for manipulation
$date_after = mktime( 0, 0, 0, $month, $day, $year );
// Now i need to add x days to this
$total_no_nights = "010"; // must be this format
$days_to_add = intval( $total_no_nights ); // No need to use ltrim
// Here's the "magic". Again it returns a timestamp
$new_date = strtotime( "+$days_to_add days", $date_after );
Using the DateTime object would be easier but you say you're not on PHP5.3.
You can't do date manipulation with strings becase, well, they are not dates. In PHP, you can use Unix timestamps (which are actually integers...) or DateTime objects. In you case:
$timestamp = strtotime('-10 days', mktime(0, 0, 0, $month, $day, $year));
echo date('r', $timestamp);
... or:
$object = new DateTime("$year-$month-$day");
$object->modify('-10 days');
echo $object->format('r');
Also, please note that 010 is an octal number that corresponds to 8 in decimal.
using the convert function in sql the date can be obtained in appropriate format.
anter that operations can be performed in php to manipulate the date. i hope that answers your query.
I'm trying to take a date object that's coming out of my Drupal CMS, subtract one day and print out both dates. Here's what I have
$date_raw = $messagenode->field_message_date[0]['value'];
print($date_raw);
//this gives me the following string: 2011-04-24T00:00:00
$date_object = date_create($date_raw);
$next_date_object = date_modify($date_object,'-1 day');
print('First Date ' . date_format($date_object,'Y-m-d'));
//this gives me the correctly formatted string '2011-04-24'
print('Next Date ' . date_format($next_date_object,'Y-m-d'));
//this gives me nothing. The output here is always blank
So I'm not understanding why the original date object is coming out fine, but then I'm trying to create an additional date object and modify it by subtracting one day and it seems like I can't do that. The output always comes out blank.
You can try:
print('Next Date ' . date('Y-m-d', strtotime('-1 day', strtotime($date_raw))));
date('Y-m-d',(strtotime ( '-1 day' , strtotime ( $date) ) ));
$date = new DateTime("2017-05-18"); // For today/now, don't pass an arg.
$date->modify("-1 day");
echo $date->format("Y-m-d H:i:s");
Using DateTime has significantly reduced the amount of headaches endured whilst manipulating dates.
Object oriented version
$dateObject = new DateTime( $date_raw );
print('Next Date ' . $dateObject->sub( new DateInterval('P1D') )->format('Y-m-d');
A one-liner option is:
echo date_create('2011-04-24')->modify('-1 days')->format('Y-m-d');
Running it on Online PHP Editor.
mktime alternative
If you prefer to avoid using string methods, or going into calculations, or even creating additional variables, mktime supports subtraction and negative values in the following way:
// Today's date
echo date('Y-m-d'); // 2016-03-22
// Yesterday's date
echo date('Y-m-d', mktime(0, 0, 0, date("m"), date("d")-1, date("Y"))); // 2016-03-21
// 42 days ago
echo date('Y-m-d', mktime(0, 0, 0, date("m"), date("d")-42, date("Y"))); // 2016-02-09
//Using a previous date object
$date_object = new DateTime('2011-04-24');
echo date('Y-m-d',
mktime(0, 0, 0,
$date_object->format("m"),
$date_object->format("d")-1,
$date_object->format("Y")
)
); // 2011-04-23
Online PHP Editor
Not sure why your current code isn't working but if you don't specifically need a date object this will work:
$first_date = strtotime($date_raw);
$second_date = strtotime('-1 day', $first_date);
print 'First Date ' . date('Y-m-d', $first_date);
print 'Next Date ' . date('Y-m-d', $second_date);
Answear taken from Php manual strtotime function comments :
echo date( "Y-m-d", strtotime( "2009-01-31 -1 day"));
Or
$date = "2009-01-31";
echo date( "Y-m-d", strtotime( $date . "-1 day"));
You can add strtotime() in date() with parameter number of day week or month.
Example for day:
date("Y-m-d", strtotime("-1 day"));
For week:
date("Y-m-d", strtotime("-1 week"));
For month:
date("Y-m-d", strtotime("-1 months"));
How about this: convert it to a unix timestamp first, subtract 60*60*24 (exactly one day in seconds), and then grab the date from that.
$newDate = strtotime($date_raw) - 60*60*24;
echo date('Y-m-d',$newDate);
Note: as apokryfos has pointed out, this would technically be thrown off by daylight savings time changes where there would be a day with either 25 or 23 hours
In my PHP code I have a date in my variable "$postedDate".
Now I want to get the date after 7 days, 15 days, one month and 2 months have elapsed.
Which date function should I use?
Output date format should be in US format.
Use strtotime.
$newDate = strtotime('+15 days',$date)
$newDate will now be 15 days after $date. $date is unix time.
http://uk.php.net/strtotime
try this
$date = date("Y-m-d");// current date
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 day");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +2 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 month");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +30 days");
Since PHP 5.2.0 the DateTime build in class is available
$date = new DateTime($postedDate);
$date->modify('+1 day');
echo $date->format('Y-m-d');
http://php.net/manual/en/class.datetime.php
$date=strtotime(date('Y-m-d')); // if today :2013-05-23
$newDate = date('Y-m-d',strtotime('+15 days',$date));
echo $newDate; //after15 days :2013-06-07
$newDate = date('Y-m-d',strtotime('+1 month',$date));
echo $newDate; // after 1 month :2013-06-23
This is very simple; try this:
$date = "2013-06-12"; // date you want to upgade
echo $date = date("Y-m-d", strtotime($date ." +1 day") );
What’s the input format anyway?
1) If your date is, say, array of year, month and day, then you can mktime (0, 0, 0, $month, $day + 15, $year) or mktime (0, 0, 0, $month + 1, $day, $year). Note that mktime is a smart function, that will handle out-of-bounds values properly, so mktime (0, 0, 0, 13, 33, 2008) (which is month 13, day 33 of 2008) will return timestamp for February, 2, 2009.
2) If your date is a timestamp, then you just add, like, 15*SECONDS_IN_A_DAY, and then output that with date (/* any format */, $postedDate). If you need to add one month 30 days won’t of course always work right, so you can first convert timestamp to month, day and year (with date () function) and then use (1).
3) If your date is a string, you first parse it, for example, with strtotime (), then do whatevee you like.