I have 3 tables i want to access with my search php. 2 of them contain all the users profile information. One is called cprofile and the other is bprofile. they are both linked to a user table that contains the username, email, password and most importantly the profile picture.
With the search engine i am trying to access both the info from the search to the individual profile tables and to gather the account information from the user table. This is my code for searching for both types of users:
$search_output = "";
if( isset($_POST['searchquery']) && $_POST['searchquery'] != "" ) {
$searchquery = preg_replace('#[^a-z 0-9?!]#i', '', $_POST['searchquery']);
if($_POST['filter1'] == "Whole Site") {
$sqlCommand = "(SELECT count(*) FROM cprofile WHERE firstname ='%".$searchquery."%' OR lastname ='%".$searchquery."%')
UNION (SELECT count(*) FROM bprofile WHERE cname ='%".$searchquery."%')";
$query = mysqli_query( $db_conx, $sqlCommand ) or die( mysqli_error($db_conx) );
$count = mysqli_num_rows( $query );
while( $row = mysqli_fetch_array($query, MYSQLI_ASSOC) ) {
$userid = $row["userID"];
$ret = mysqli_query($db_conx, "SELECT id, username FROM users WHERE id='$userid'");
while($raw = mysqli_fetch_array($ret, MYSQLI_ASSOC)) {
$username = $raw['username']; $file= $raw['avatar'];
}
}
}
}
Does anyone notice where i am going wrong and how i could resolve this issue? Thanks in advance
I might be going in the wrong direction here but you are getting counts from your query and then looking for a userID in the while loop. If you want both then do something like
$sqlCommand = "
(SELECT userid, count(*) as count FROM cprofile WHERE firstname ='%".$searchquery."%' OR lastname ='%".$searchquery."%')
UNION
(SELECT userid, count(*) as count FROM bprofile WHERE cname ='%".$searchquery."%')
";
Related
I'm trying to count number of messages each user got. I have a users with user's detail id, name etc. I have created another table users_msgs where I have id, msg_id, user_id. I want to display count of messages each user got. what will be the best way to do it?
The web application have more than 2000 users. so the script have to select all of them and count their messages. I think this is not the best solution.
I thinking of count rows for 1 user from users_msgs table as count and then querying the users table for user's name with his id from users_msgs table.
I have tried selecting all users without any limit:
SELECT * FROM users
then iterating over the results like so:
<?php
while ($user = mysqli_fetch_assoc($users)) {
$count = count_user_msgs($user['id']);
echo "{$user['name']} messages: $count";
}
?>
The count_user_msgs function looks like this:
<?php
$sql = "SELECT COUNT(id) as msgs_count FROM users_msgs WHERE user_id = ?";
$stmt = mysqli_stmt_init($db);
if (mysqli_stmt_prepare($stmt, $sql)) {
mysqli_stmt_bind_param($stmt, 's', $user_id);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
$count = mysqli_fetch_assoc($result)['msgs_count'];
return $count;
}
return false;
?>
You need to group by each user and get the count:
$sql = "SELECT user_id, name, count(user_id) as msgs_count from table group by (user_id, name)";
$result = $mysqli->query($query)
while ($user = mysqli_fetch_assoc($users)) {
$user_id = $users['user_id'];
$msgs_count= $users['msgs_count'];
$count[$user_id] = $msgs_count;
echo "{$user['name']} messages: $msgs_count";
}
FWIW, You can get it in a single query...
SELECT u.name, count(m.user_id) message_count
FROM users u
LEFT JOIN users_messages m ON u.user_id=m.user_id
GROUP BY m.user_id, u.name
You want to count the number of msg_ids per user_id, so you'll want to GROUP BY user_id and count msg_id, like this:
$sql = "SELECT COUNT(msg_id) as msgs_count FROM user_msgs WHERE user_id = ? GROUP BY user_id";
The GROUP BY might not be necessary.
I am looking to count the number of times 'yes' in present for a user in a table, then post the result into anther table for that same user. Both tables have the username. I would like this done for each user. I have the following but it is not working.
$sql = $item_count = "SELECT SUM(if(strike='yes',1,0)) AS strike_total FROM weekpicks WHERE username = 'username'";
// execute SQL query and get result
$sql_result = mysql_query($sql) or die (mysql_error());
if (!$sql_result) {
echo "Something has gone wrong!";
}
else {
//loop through record and get values
while ($row = mysql_fetch_array($sql_result)) {
$item_result = ($row = #mysql_query($item_count)) or die(mysql_error());
$strike_total = ($row = #mysql_result($item_result,"strike_total"));
$strikes = ($row = $strike_total ['strike_total']);
$username = $row["username"];
// the following will insert number of strikes into table for each user.
$sql = "UPDATE authorize SET strikes = '($strikes)' WHERE username='$username'";
//mysql_query(" UPDATE authorize SET " . "strikes = '" . ($strikes) . "' WHERE username='$username' ");
$result = mysql_query($sql) or die (mysql_error());
Just one query should be enough
Update for single user..
UPDATE authorize SET strikes = (select count(*) from weekpicks WHERE username = '$username' and strike='yes') WHERE username='$username';
For bulk update all users
UPDATE authorize as A SET strikes = (select count(*) from weekpicks B WHERE strike='yes' and A.username=B.username group by B.username)
Isn't that simple.
I have a MySQL query where I am trying to search 2 tables simultaneously. This is for an autocomplete search box that searches for regular clients and business clients. Here is the code:
$query = mysql_query("SELECT * FROM clients WHERE lastname LIKE '$q%' AND agentid = '$agentid'
UNION
SELECT * FROM busclients WHERE busname LIKE '$q%' AND agentid = '$agentid'")or die(mysql_error());
if($query) {
while ($result = mysql_fetch_array($query)) {
$busname = $result['busname'];
print_r($result);
if(isset($busname)){
$description['id'] = 'viewbusiness.php?id=' . $result['ID'];
$description['value'] = $busname ;
array_push($return_arr,$description);
}
else
{
$description['id'] = 'viewclient.php?id=' .$result['ID'];
$description['value'] = $result['lastname'] . ", " . $result['firstname'] ;
array_push($return_arr,$description);
}
}
}
The problem is that the business clients get assigned the table names from the regular clients, so the code never uses the if(isset($busname)) because busname becomes lastname instead, and directs you to the veiwclient page.
SELECT
a.lastname ,
b.busname
FROM clients as a
INNER JOIN
busclients as b
on b.agent_id = a.agent_id
WHERE a.agent_id = $agent_id
AND (a.lastname LIKE '$q%' OR b.busname LIKE '$q%')
By specifically selecting the column names you want from that table, and selecting a blank string for the others, I believe you can get the results you're looking for using something like this:
SELECT firstname, lastname, '' AS busname FROM clients WHERE ... UNION SELECT '' AS firstname, '' AS lastname, busname FROM busclients WHERE ...
I am getting a bunch of id's from the database - for each id, I want to do a mysql query to get the relating row in another table. This works fine although I also need to get similiar data for the logged in user. With the mysql query I am using - it duplicates the logged in user data according to how many id's it originally pulled. This makes sense although isnt what I want. I dont want duplicate data for the logged in user and I need the data to come from one query so I can order things with the timestamp.
<?php
mysql_select_db($database_runner, $runner);
$query_friends_status = "SELECT DISTINCT rel2 FROM friends WHERE rel1 = '" . $_SESSION ['logged_in_user'] . "'";
$friends_status = mysql_query($query_friends_status, $runner) or die(mysql_error());
$totalRows_friends_status = mysql_num_rows($friends_status);
while($row_friends_status = mysql_fetch_assoc($friends_status))
{
$friends_id = $row_friends_status['rel2'];
mysql_select_db($database_runner, $runner);
$query_activity = "SELECT * FROM activity WHERE user_id = '$friends_id' OR user_id = '" . $_SESSION['logged_in_user'] . "' ORDER BY `timestamp` DESC LIMIT 15";
$activity = mysql_query($query_activity, $runner) or die(mysql_error());
$totalRows_activity = mysql_num_rows($activity);
echo "stuff here";
}
?>
You can try this single query and see if it does what you need
$userID = $_SESSION['logged_in_user'];
"SELECT * FROM activity WHERE user_id IN (
SELECT DISTINCT rel2 FROM friends
WHERE rel1 = '$userID')
OR user_id = '$userID' ORDER BY `timestamp` DESC LIMIT 15";
You probably want something like this:
$user = $_SESSION['logged_in_user'];
$query_friends_status = "SELECT * FROM friends, activity WHERE activity.user_id = friends.rel2 AND rel1 = '$user' ORDER BY `timestamp` DESC LIMIT 15";
You can replace * with the fields you want but remember to put the table name before the field name like:
table_name.field_name
I hope this helps.
<?php
require_once "connect.php";
$connect = #new mysqli($host, $db_user, $db_password, $db_name);
$result = $connect->query("SELECT p.name, p.user, p.pass, p.pass_date_change,p.email, p.pass_date_email, d.domain_name, d.domain_price, d.domain_end, d.serwer, d.staff, d.positioning, d.media FROM domains d LEFT JOIN persons p
ON d.id_person = p.id AND d.next_staff_id_person != p.id");
if($result->num_rows > 1)
{
while($row = $result->fetch_assoc())
{
echo '<td class="box_small_admin" data-column="Imię i nazwisko"><div class="box_admin">'.$row["name"].'</div></td>';
echo '<td class="box_small_admin" data-column="Domena"><div class="box_admin">'.$row["domain_name"].'</div></td>';
}}
?>
I need to create a friend system, but my loop always skips the first match and sometimes it prints copies of the same name
$result = mysql_query("SELECT * FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id");
while($row = mysql_fetch_array($result))
{
if ($row['username_id'] == 1)//the 1 will be a variable, username_id is in friends
$count = $row['friendname'];//friendname is in friends
if ($row['id'] == $count)//id is in users
echo $row['username'];//username is in users
}
Can someone see what my problem is ?
2 things:
if ($row['username_id'] == 1)
you should put that in your sql:
$result = mysql_query("SELECT username, friendname FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id where tbusers.id = ".$yourVariable);
In your query, user and friend are linked, and can only be equal.
Now, this:
$count = $row['friendname'];//friendname is in friends
if ($row['id'] == $count)//id is in users
is equal to
if ( $row['id'] == $row['friendname'] )
this sounds plain wrong. You compare a numerical id with a name. Moreover, your sql query already retrives all friends from users. In the version I showed here, it retrieves only friends of the user you are interested in.
finally, you print (echo) the name of the user, not of the friend. In my opinion the following code will do what you want:
$result = mysql_query("SELECT friendname FROM tbfriends WHERE username_id = ".$yourUserVariable);
while($row = mysql_fetch_array($result))
{
echo $row['friendname']; // or better: echo $row['friendname'], '<br>';
}
edit: after comment...
so if ( $row['id'] == $row['friendname'] ) means the user is his own friend. can that happen?
this code shall print what you want, friend names.
/*
$result = mysql_query("
SELECT username as friend_name,
friendname as friend_id,
username_id as user_id
FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id
WHERE tbusers.id = ".$yourVariable);
*/
$result = mysql_query("
SELECT username as friend_name,
friendname as friend_id,
username_id as user_id
FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.friendname
WHERE tbfriends.username_id = ".$yourVariable);
while($row = mysql_fetch_array($result))
{
echo $row['friend_name']; // or better: echo $row['friend_name'], '<br>';
}