Seven flags to concise list of days of the week? - php

Question

I have an array/string/integer of 7 flags, one for each day of the week (of a recurring event). How can I convert this to a brief list of the days?
So, for example
Given 1011001, return 'Su, T-W, Sa'.
Given 0111011, return 'M-W, F-Sa'.
What's the shortest way to accomplish this?
EDIT
For comparison, here's my own inelegant code:
<?php
function dowstring($dow) {
if ($dow == 0) return "Error";
$ddow = ["Su", "M", "T", "W", "Th", "F", "Sa"];
$t = strrev( sprintf('%07b', $dow) );
$u = str_split($t);
$out = '';
$cu = count($u);
$nn = 0; // number of days thus far counted
$v = 0; // number in the run
for($i = 0; $i < $cu; $i++) {
if ($u[$i]) {
if ($v == 0) {
$out .= ($nn) ? ", " : '';
$out .= $ddow[$i];
}
$nn++;
$v++;
}
else {
if ($v > 1) {
$out .= ($nn) ? "-" . $ddow[$i-1] : '';
}
$v = 0;
}
}
// in case Saturday is part of a run
if ($v > 1) {
$out .= ($nn) ? "-" . $ddow[$i-1] : '';
}
return $out;
}
echo "<pre>";
// testing script
for ($i = 1; $i < pow(2, 7); $i++) {
$ds = dowstring($i);
$j = strrev( sprintf("%07b", $i) );
printf("%s %s\n", $j, $ds);
}
echo "</pre>";
?>
EDIT
Another attempt, inspired by Prasanth:
function dowstring($dow) {
if ($dow == 0) return "Error";
$ddow = ["Su", "M", "T", "W", "Th", "F", "Sa"];
$t = strrev( sprintf('%07b', $dow) );
$v = array_keys( array_filter( str_split($t) ) );
$cv = count($v); $w = array();
$out = $ddow[$v[0]];
for ($i = 1; $i < $cv; $i++) $w[] = $v[$i] - $v[$i - 1] - 1;
$w = ( $cv == 1 ) ? array($w) : $w;
for ($i = 1; $i < $cv; $i++) {
if (!$w[$i - 1]) $last = $ddow[$v[$i]];
else {
if ( isset($last) ) $out .= '-' . $last;
$out .= ', ' . $ddow[$v[$i]];
unset($last);
}
}
if ($i > 1 && !$w[$i-2] ) $out .= '-' . $ddow[ $v[$i-1] ];
return $out;
}
I'd like to see something better. Anyone?

Answer 1

Try this:
$days=array('1'=>'Monday','2'=>'Tuesay','3'=>'Wednesday','4'=>'Thursday','5'=>'Friday','6'=>'Saturday','7'=>'Sunday');
$pattern = '1000110';
$arr1 = str_split($pattern);
$i=0;
foreach($days as $key => $tes) {
if($key - $arr1[$i] != $key) {
echo $tes;
}
$i++;
}
Adjust days array according to the sequence of days you want

Answer 2

Try this :
<?php
$days = array('Su','M','T','W','Th','F','Sa');
function checkConsec($d) {
for($i=0;$i<count($d);$i++) {
if(isset($d[$i+1]) && $d[$i]+1 != $d[$i+1]) {
return false;
}
}
return true;
}
$str = '0111011';
$array = array_keys(array_filter(str_split($str)));
$temp = array();
$res = array();
for($i=0;$i<count($array);$i++){
$temp[] = $array[$i];
if(checkConsec($temp) && count($temp) > 1){
$res[$temp[0]] = $days[$temp[0]]."-".$days[$temp[count($temp)-1]];
}else{
$res[$array[$i]] = $days[$array[$i]];
$temp = array();
$temp[] = $array[$i];
}
}
echo implode(",",$res);
?>