MySql PHP Update Error - php

I've been messing about with this code for a few hours now and can't work out why it's not working. It's a profile update php page that is passed through JQuery and all seems to be fine except for it actually updating into the table. Here is the code I'm using:
session_start();
include("db-connect.php");//Contains $con
$get_user_sql = "SELECT * FROM members WHERE username = '$user_username'";
$get_user_res = mysqli_query($con, $get_user_sql);
while($user = mysqli_fetch_array($get_user_res)){
$user_id = $user['id'];
}
$name = mysqli_real_escape_string($con, $_REQUEST["name"]);
$location = mysqli_real_escape_string($con, $_REQUEST["location"]);
$about = mysqli_real_escape_string($con, $_REQUEST["about"]);
$insert_member_sql = "UPDATE profile_members SET id = '$user_id', names = '$name', location = '$location', about = '$about' WHERE id = '$user_id'";
$insert_member_res = mysqli_query($con, $insert_member_sql) or die(mysqli_error($con));
if(mysqli_affected_rows($con)>0){
echo "1";
}else{
echo "0";
}
All I get as the return value is 0, can anybody spot any potential mistakes? Thanks

To begin with, use
require("db-connect.php");
instead of
include("db-connect.php");
And now, consider using prepared statements, your code is vulnerable to sql injections.
Consider using PDO instead of the mysql syntax, in the long run I find it much better to use and it avoids a lot of non-sense-making problems, you can do it like this (You can keep it in the db-connect file if you want, and even make the database conncetion become global):
// Usage: $db = connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword);
// Pre: $dbHost is the database hostname,
// $dbName is the name of the database itself,
// $dbUsername is the username to access the database,
// $dbPassword is the password for the user of the database.
// Post: $db is an PDO connection to the database, based on the input parameters.
function connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword)
{
try
{
return new PDO("mysql:host=$dbHost;dbname=$dbName;charset=UTF-8", $dbUsername, $dbPassword);
}
catch(PDOException $PDOexception)
{
exit("<p>An error ocurred: Can't connect to database. </p><p>More preciesly: ". $PDOexception->getMessage(). "</p>");
}
}
And then init the variables:
$host = 'localhost';
$user = 'root';
$databaseName = 'databaseName';
$pass = '';
Now you can access your database via
$db = connectToDatabase($host, $databaseName, $user, $pass);
Now, here's how you can solve your problem (Using prepared statements, avoiding sql injection):
function userId($db, $user_username)
{
$query = "SELECT * FROM members WHERE username = :username;";
$statement = $db->prepare($query); // Prepare the query.
$statement->execute(array(
':username' => $user_username
));
$result = $statement->fetch(PDO::FETCH_ASSOC);
if($result)
{
return $result['user_id'];
}
return false
}
function updateProfile($db, $userId, $name, $location, $about)
{
$query = "UPDATE profile_members SET name = :name, location = :location, about = :about WHERE id = :userId;";
$statement = $db->prepare($query); // Prepare the query.
$result = $statement->execute(array(
':userId' => $userId,
':name' => $name,
':location' => $location,
':about' => $about
));
if($result)
{
return true;
}
return false
}
$userId = userId($db, $user_username); // Consider if it is not false.
$name = $_REQUEST["name"];
$location = $_REQUEST["location"];
$about = $_REQUEST["about"];
$updated = updateProfile($db, $userId, $name, $location, $about);
You should check the queries though, I fixed them a little bit but not 100% sure if they work.
You can easily make another function which inserts into tha database, instead of updating it, or keeping it in the same function; if you find an existance of the entry, then you insert it, otherwise you update it.

Related

Query is TRUE when its not

Please be gentle with me i have just recently trying to learn PHP/SQL.
The problem is that the first query is ALWAYS TRUE when it shouldn't (base on what i know).
The query simply state to get the 'username' where betakey=$betakey provided by user. The fact that my datebase columns is still empty except column betakey doesn't make that query statement true at all.
Please help, maybe i am missing some knowledge on this.
<?php
header('Access-Control-Allow-Origin: *');
$firstName = $_GET['rfirstname'];
$lastName = $_GET['rlastname'];
$username = $_GET['rusername'];
$password = $_GET['rpass'];
$betakey = $_GET['rkey'];
$host="localhost"; // Host name
$db_username="**"; // Mysql username
$db_password="**"; // Mysql password
$db_name="**"; // Database name
$conn = mysqli_connect("$host", "$db_username", "$db_password","$db_name");
if (!$conn){
die ("Error: ".mysqli_connect_error());
}
$query1 = "SELECT username='$username' FROM users2 WHERE betakey='$betakey';";
$result_1 = mysqli_query($conn,$query1);
if(mysqli_num_rows($result_1) > 0){
echo 'Beta key is used';
}else{
$query2 = "UPDATE users2 SET firstName='$firstName',lastName='$lastName',username='$username',password='$password' WHERE betakey='$betakey'";
echo 'Registration Successful';
}
mysqli_close($conn);//Close off the MySQL connection to save resources.
?>
You have plenty of problems in your code. Let me help you fix some of them
You should learn how to properly open mysqli connection. You need to enable error reporting and set the correct charset.
You should never concatenate PHP variables into SQL query. Always use parameterized prepared statements instead of manually building your queries.
Your first SQL query has an error. username='$username' is meaningless and wrong. If all you want to do is check existence use COUNT(1) or something similar.
Here is my take on your fixed code:
<?php
header('Access-Control-Allow-Origin: *');
$firstName = $_GET['rfirstname'];
$lastName = $_GET['rlastname'];
$username = $_GET['rusername'];
$password = $_GET['rpass'];
$betakey = $_GET['rkey'];
$host = "localhost"; // Host name
$db_username = "**"; // Mysql username
$db_password = "**"; // Mysql password
$db_name = "**"; // Database name
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($host, $db_username, $db_password, $db_name);
$conn->set_charset('utf8mb4');
$stmt = $conn->prepare("SELECT COUNT(username) FROM users2 WHERE betakey=?");
$stmt->bind_param('s', $_GET['rusername']);
$stmt->execute();
$result_1 = $stmt->get_result();
$used = $result_1->fetch_row()[0];
if ($used) {
echo 'Beta key is used';
} else {
$stmt = $conn->prepare("UPDATE users2 SET firstName=?, lastName=?, username=?, password=? WHERE betakey=?");
$stmt->bind_param('sssss', $firstName, $lastName, $username, $password, $betakey);
$stmt->execute();
echo 'Registration Successful';
}

PDO Username validation if already exists

I have a problem with register form.My form works properly but whenever i try to insert username that already exists it doesn't shows any error.
here is my php register file:
<?php
$servername = "localhost";
$username = "root";
$password = "";
try {
$conn = new PDO("mysql:host=$servername;dbname=dblogin", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
if (isset($_POST['submit'])) {
$user_name = $_POST['user_name'];
$user_email = $_POST['user_email'];
$user_pass = $_POST['user_pass'];
$hash = password_hash($user_pass, PASSWORD_DEFAULT);
$stmt = $con->prepare("SELECT user_name FROM users WHERE user_name = :user_name");
if($stmt->rowCount() > 0){
echo "exists!";
}
else{
$insert = $conn->prepare("INSERT INTO users (user_name,user_email,user_pass) values(:user_name,:user_email,:user_pass)");
$insert->bindparam(':user_name',$user_name);
$insert->bindparam(':user_email',$user_email);
$insert->bindparam(':user_pass',$hash);
$insert->execute();
}
}
catch(PDOException $e)
{
echo "connection failed";
}
?>
Thanks for your support
You are not executing the select statement. You need to bind params and execute the select statement, try this after the select statemnt.
$stmt->bindparam(':user_name',$user_name);
$stmt->execute();
public function usernameCheck($username)
{
$sql = "SELECT * FROM $this->table where username = :username";
$query = $this->pdo->prepare($sql);
$query->bindValue(':username', $username);
$query->execute();
if ($query->rowCount() > 0) {
return true;
} else {
return false;
}
}
use this one in your project hope it will work... :)
missing } in if statement
if (isset($_POST['submit'])) {
$user_name = $_POST['user_name'];
$user_email = $_POST['user_email'];
$user_pass = $_POST['user_pass'];
$hash = password_hash($user_pass, PASSWORD_DEFAULT);
$stmt = $con->prepare("SELECT user_name FROM users WHERE user_name = :user_name");
if($stmt->rowCount() > 0){
echo "exists!";
}
}else{
}
I notice 4 things (2 of which have been mentioned by others):
First and smallest is you have a spelling error ($con instead of $conn) - don't worry it happens to the best of us - in you first $stmt query which means your select-results becomes NULL instead of 0 - so you rowCount find that it is not over 0 and moves on without your error message
Second you forgot to bind and execute the parameters in your first $stmt query which gives the same result for your rowCount results
Third always clean your variables even when using prepared statements - at a bare minimum use
$conn->mysql_real_escape_string($variable);
and you can with advantage use
htmlspecialchars($variable);
And fourth since you are not doing anything with the database (other than looking) you could simplify your code by simply writing:
$stmt = $conn->query("SELECT user_name FROM users WHERE user_name = '$user_name' LIMIT 1")->fetch();
as I said - no need to bind or execute in the first query
and as a general rule - don't use rowCount - ever - if you have to know the number of results (and in 99% of cases you don't) use count(); but if you as here just want to know if anything at all was found instead use:
if ( $stmt ) {
echo "exists!";
} else {
// insert new user as you did
}
Edit:
Also - as a side note - there are a few things you should consider when you initially create your connection...
Ex:
// Set variables
$servername = "localhost";
$username = "***";
$password = "***";
$database = "***";
$charset = 'utf8'; // It is always a good idea to also set the character-set
// Always create the connection before you create the new PDO
$dsn = "mysql:host=$servername;dbname=$database;charset=$charset";
// Set default handlings as you create the new PDO instead of after
$opt = [
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC, // And add default fetch_mode
PDO::ATTR_EMULATE_PREPARES => false, // And ALWAYS set emulate_prepares to false
];
// And now you are ready to create your new PDO
$conn = new PDO($dsn, $username, $password, $opt);
Just a suggestion... happy trails

PDO delete from MySQL

I have a problem with a PDO code.
I try the code below.
$id = null;
if ( !empty($_GET['t_id'])) {
$id = $_REQUEST['t_id'];
}
$action = isset($_POST['_DELETE_']) ? $_POST['_DELETE_'] : "";
if ($action == 'do_not_delete') {
header("Location: index.php?action=DEL_ERROR");
}
if($action=='delete') {
$host = "localhost";
$db_name = "_notice";
$username = "root";
$password = "111";
$con = new PDO("mysql:host={$host};dbname={$db_name}", $username, $password);
$id = $_REQUEST['t_id'];
$query = "DELETE FROM topics WHERE topic_id = ?";
$stmt = $con->prepare($query);
$stmt->bindParam(1, $id);
$exc = $stmt->execute();
if($exc){
$con = null;
header("Location: index.php?action=DEL_OK");
}else{
$con = null;
header("Location: index.php?action=DEL_ERROR");
}}
Anything happens (dose not delete element from the database).
I have no errors on page; even when i use a try catch block, or page parameter like index.php?action=DELETE
You need to call $stmt->execute() after preparing the query and binding parameters.
Update:
You are checking the content of $_GET['t_id'] but always setting $id to $_REQUEST['t_id'], and everything will execute only if $_POST['_DELETE_'] contains delete.
Also, try to check the resulting query and parameters with $stmt->debugDumpParams() before executing and maybe replace your bindParam with $stmt->bindParam(1, $id, PDO::PARAM_INT).

PHP PDO MySQL get entries from Access and INSERT into MySQL

My goal here is to replicate a local MS Access database into my MySQL database (using php PDO)
The MS Access database is located on a network shared drive and updates itself with new entries every 6 hours.
In the code below I retrieved the max id number from MySQL table 'production_schedule', then I made an ODBC connection to retrieve all entries from MS ACCESS database that are greater than the max id number.
But now I cannot figure out how to insert these new entries into the MySQL table 'production_schedule'.
Can anyone please help?
<?php
/*USING XAMPP*/
$dsn = "mysql:host=localhost;dbname=qmsdb;charset=utf8";
$uname = "root";
$pword = "";
$db = null;
$limit = 10;
$counter = 0;
while (true) {
try {
$db = new PDO($dsn, $uname, $pword);
$db->exec( "SET CHARACTER SET utf8" );
$db->setAttribute( PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC );
$db->setAttribute( PDO::ATTR_PERSISTENT, true );
break;
}
catch (Exception $e) {
$db = null;
$counter++;
if ($counter == $limit)
throw $e;
}
}
$aid = $db->prepare("SELECT MAX(id) FROM production_schedule");
$aid->execute();
$big_id = $aid->fetchColumn();
$refid = intval($big_id);
$conn=odbc_connect('Prod_Schedule','','');
if (!$conn) {
exit("Connection Failed: " . $conn);
}
$sql="SELECT * FROM Schedule WHERE ID > $refid";
$rs=odbc_exec($conn,$sql);
if (!$rs) {
exit("Error in SQL");
}
***** INSERT CODE TO PUT THESE MS ACCESS ENTRIES INTO THE MYSQL TABLE ******
?>
something like this maybe:
while(odbc_fetch_row($rs)){
$sql = "INSERT INTO production_schedule (fieldName1, fieldName2, fieldName3) VALUES (?, ?, ?)";
$stmt = $dbh->prepare($sql);
for($i=1;$i<=odbc_num_fields($rs);$i++){
$stmt->bindValue($i, odbc_result($rs,$i));
}
$stmt->execute();
}
Note: depends on how many data you have to dump, you should use a solution like this: PDO Prepared Inserts multiple rows in single query to reduce risk of PHP timeout.
I just tested the following code and it seems to work okay for me:
$dsn = "mysql:host=localhost;port=3307;dbname=myDb;charset=utf8";
$uname = "root";
$pword = "whatever";
$mysqlDb = new PDO($dsn, $uname, $pword);
$mysqlDb->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$mysqlSql = "INSERT INTO clients (LastName, FirstName) VALUES (?, ?)";
$mysqlCmd = $mysqlDb->prepare($mysqlSql);
$LastName = '';
$FirstName = '';
$mysqlCmd->bindParam(1, $LastName, PDO::PARAM_STR, 255);
$mysqlCmd->bindParam(2, $FirstName, PDO::PARAM_STR, 255);
$connStr =
'Driver={Microsoft Access Driver (*.mdb, *.accdb)};' .
'Dbq=C:\\Users\\Public\\Database1.accdb;';
$accessDb = odbc_connect($connStr, "", "");
$accessSql = "SELECT LastName, FirstName FROM Clients";
$accessResult = odbc_exec($accessDb, $accessSql);
while ($accessData = odbc_fetch_array($accessResult)) {
$LastName = $accessData["LastName"];
$FirstName = $accessData["FirstName"];
$mysqlCmd->execute();
}
First create a function to insert the values into MySQL, then loop through the ODBC results;
function createProductionSchedule($company,$person,$order){
$mysqli_con=mysqli_connect(DBHOST,DBUSER,DBPASS,DBNAME);
if (mysqli_connect_errno($mysqli_con))
{
echo 'Failed to connect to MySQL';
}
//Obviously your own fields here
$company = mysqli_real_escape_string($mysqli_con, $company);
$person = mysqli_real_escape_string($mysqli_con, $person);
$order = mysqli_real_escape_string($mysqli_con, $order);
$sql = "INSERT INTO production_schedule VALUES ('$company','$person','$order')";
mysqli_query($mysqli_con, $sql);
return mysqli_insert_id($mysqli_con);
mysqli_close($mysqli_con);
}
Then in your code section
while (odbc_fetch_row($rs))
{
$company=odbc_result($rs,"Company");
$person=odbc_result($rs,"Person");
$order=odbc_result($rs,"Order");
//Call the function to insert the record
createProductionSchedule($company,$person,$order);
}
odbc_close($conn);

mysqli does not execute Select statement

I have the code bellow. When I use this code without the WHERE clause, all the users from the table are displayed, as expected. But when the WHERE clause is used, nothing is displayed.
What could be the cause and how can I fix it?
Thank you!
function requestUser($user) {
$DBHost = "localhost";
$DBUser = "dbUser";
$DBPass = "dbPass";
$DBName = "dbName";
$db = new mysqli($DBHost, $DBUser, $DBPass, $DBName);
if ($db -> connect_errno > 0) {
$lbOK = false;
}
else {
$lbOK = $db -> set_charset('utf8');
}
if ($lbOK) {
$id = NULL;
$user_name = NULL;
$user = htmlentities($user, ENT_QUOTES);
$lcSQL = "SELECT `user_name` FROM `users` WHERE user_name=?";
$stmt = $db -> prepare($lcSQL);
$ok = $stmt -> bind_param('s', $user);
$ok = $stmt -> execute();
$ok = $stmt -> bind_result($user_name);
while ($row = $stmt -> fetch()){
echo $user_name;
}
$stmt->close();
}
}
There are many major faults with your code, some of them can be responsible for the problem, and some not. But nevertheless, they all have to be corrected
Never connect co database inside of an application function. Connect somewhere in the bootstrap file, once, and use that single connection throughout all the application.
Do not use htmlentities with whatever database interactions. It may easily spoil the data
Always check for the the errors
Do not use mysqli, it is unusable. Use PDO instead.
$dsn = "mysql:host=DBHost;dbname=DBName;charset=utf8";
$opt = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
$pdo = new PDO($dsn,$DBUser, $DBPass, $opt);
function requestUser($user) {
global $db;
$sql = "SELECT `user_name` FROM `users` WHERE user_name=?";
$stmt = $db->prepare($sql);
$stmt->execute(array($user));
return $stmt->fetchColumn();
}
echo requestUser($user);
if it still doesn't work, verify it this way
$sql = "SELECT `user_name` FROM `users` WHERE user_name='$user'";
var_dump($sql);
and then try to run in console/phpmyadmin to find out what's wrong with your data/value

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