while loop output with delay - php

i am using while loop to display last 30 albums thumbnail but as you know 30 photo at once will slow down webpage loading time si i want once the webpage is completely loaded i want to load these 30 photo in interval of 5 seconds. first 5 photo will be loaded after 5 seconds of webpage is fully loaded then again after gap of 5 seconds next 5 photo will be loaded i know i can do this with 6 query but why to waste server resources so i want one query but loading as per users convenient.here is my while loop
$res = mysql_query("SELECT * from `"tableA where cat='photos' order by created desc limit 30");
while($row = mysql_fetch_array($res)) {
$photo .= thumbnail($row,150);
}
after that whereever i want i can call $photo

The best way to do this is with javascript (and jQuery for extra ease). Check out this Lazy Loading jQuery plugin for example.

You should output some markup that contains either the URLs of the images or data from which Javascript can recreate the URLs, and then, on the client side you may handle creating images from that markup on the fly, with delays and whatnot.

Try this.. I also fixed the quotes in your query a bit..
<?php
$round =1;
$res = mysql_query("SELECT * from `tableA` where `cat`='photos' order by created desc limit 30");
while($row = mysql_fetch_array($res))
{
$photo .= thumbnail($row,150);
if (($round % 5) == 0 ) { // action only happens when round is divisble by 5
sleep(5); // wait 5 seconds
}
$round += 1;
}
?>

In your case, the page is displayed to the user only AFTER all PHP were executed so you can't count on PHP to delay some display.
As already mentionned you'll have to do it client side (probably in Javascript).
A way would be to construct (using PHP) a Javascript array containing all your image URL and then loop through this array with appropriate delay.
The server side will look like this : (EDIT : assuming tableA contains a column named 'url')
$images = array();
$res = mysql_query("SELECT * from `tableA` where cat='photos' order by created desc limit 30");
while($row = mysql_fetch_array($res)) {
$images[] = $row['url'];
}
echo json_encode($images);

Related

PHP while loop to fetch post data from database

I am creating my own blog from scratch with a homepage that loads the latest posts in order of time published. I call the posts using a front controller and store the data on a MySQL database. The website itself is great and the posts all load perfectly with no issue. The issue is getting the homepage to work.
I created a few PHP functions for the homepage. They generally order the posts (database rows) by ID in descending order, since it's an autoincrement field, and call their data. And then to show the latest post as a sort of 'featured post' right at the top, by fetching the data from the very top row in the database, which is the latest post.
And that works fine - when I echo the result it shows the latest post just as I want it.
Below that I want two boxes, side by side, for the two posts before the first one. So I made this function to call them:
function fetch_rest_posts_1($conn) {
$stuff = $conn->query("SELECT * FROM table WHERE is_post = 1 ORDER BY id DESC LIMIT 1,2");
while ($row = $stuff->fetch_array()) {
$i=1;
return '<div id="post_'.$i.'" style="width:308px;height:215px;padding:5px">
<h2>'.$row['title'].'</h2>
<p>'.date('d/m/Y',strtotime($row['published_date'])).' by '.$row['author'].' | </p>
<p>'.$row['meta_description'].'</p>
</div>';
$i++;
} // style="white-space:nowrap;width:100%;overflow:hidden;text-overflow:ellipsis"
}
And it actually does work great when I echo the result, shows everything I want, but it only shows one div, not two. When I take the SQL query and directly enter it into phpMyAdmin, it gives me two rows. Have I done something wrong?
(I put the auto-increasing $i in there so that I could isolate each box and alter the style later.)
Your problem is caused by the return statement in the loop. You should add $return = '' at the top of your function, replace return by $result .=, and return $result at the end of your function.
In addition, the loop counter $i is reset in every iteration. Move the initial assignment out of the loop.
EDIT: The .= is intentional to append to $result instead of replacing it with another value constructed from the next dataset.
initiate $i outside the loop and use echo() instead of return()
return() breaks the loop
or use
$result .= '<div id="post_'.$i.'" style="width:308px;height:215px;padding:5px">
<h2>'.$row['title'].'</h2>
<p>'.date('d/m/Y',strtotime($row['published_date'])).' by '.$row['author'].' | </p>
<p>'.$row['meta_description'].'</p>
</div>';
and return $result; after the loop
That's because return will stop execution of the function try this approach:
function fetch_rest_posts_1($conn) {
$stuff = $conn->query("SELECT * FROM table WHERE is_post = 1 ORDER BY id DESC LIMIT 1,2");
$post = array();
while ($row = $stuff->fetch_array()) {
$post[] = $row;
}
return $post;
}
So the function purpose is to just get the data, so you can later print it:
$row = fetch_rest_posts_1($conn);
for($i = 0; count(row); $i++){
echo '<div id="post_'.$i.'" style="width:308px;height:215px;padding:5px">
<h2>'.$row[$i]['title'].'</h2>
<p>'.date('d/m/Y',strtotime($row['published_date'])).' by '.$row[$i]['author'].' | </p>
<p>'.$row[$i]['meta_description'].'</p>
</div>';
}

What is my last row_number in mysql query?

I have a query like this:
$sql = "SELECT * FROM doctors WHERE city ='$city' LIMIT 10 ";
$result = $db->query($sql);
And I show the result like this :
while($row = $result->fetch_object()){
echo $row->city;
}
The Problem :
Mysql , will search through my database to find 10 rows which their city field is similar to $city.
so far it is OK;
But I want to know what is the exact row_number of the last result , which mysql selected and I echoed it ?
( I mean , consider with that query , Mysql selected 10 rows in my database
where row number are:
FIRST = 1
Second = 5
Third = 6
Forth = 7
Fifth = 40
Sixth = 41
Seventh = 42
Eitghth = 100
Ninth = 110
AND **last one = 111**
OK?
I want to know where is place of this "last one"????
)
MySQL databases do not have "row numbers". Rows in the database do not have an inherent order and thereby no "row number". If you select 10 rows from the database, then the last row's "number" is 10. If each row has a field with a primary id, then use that field as its "absolute row number".
You could let the loop run and track values. When the loop ends, you will have the last value. Like so:
while($row = $result->fetch_object()){
echo $row->city;
$last_city = $row->city;
}
/* use $last_city; */
To get the row number in the Original Table of the last resultant (here, tenth) row, you could save the data from the tenth row and then, do the following:
1. Read whole table
2. Loop through the records, checking them against the saved data
3. Break loop as soon as data found.
Like So:
while($row = $result->fetch_object()){
echo $row->city;
$last_row = $row;
}
Now, rerun the query without filters:
$sql = "SELECT * FROM doctors";
$result = $db->query($sql);
$rowNumber = 0;
while($row = $result->fetch_object()) {
if($row == $last_row) break;
$rowNumber++;
}
/* use $rowNumber */
Hope this helps.
What you can do is $last = $row->id; (or whatever field you want) inside your while loop - it will keep getting reassigned with the end result being that it contains the value of the last row.
You could do something like this:
$rowIndex = 0;
$rowCount = mysqli_num_rows($result);
You'd be starting a counter at zero and detecting the total number of records retrieved.
Then, as you step through the records, you could increment your counter.
while ( $row = $result->fetch_object() ) {
$rowIndex++;
[other code]
}
Inside the While Loop, you could check to see whether the rowIndex is equal to the rowCount, as in...
if ($rowIndex == $rowCount) {
[your code]
}
I know this is a year+ late, but I completely why Andy was asking his question. I frequently need to know this information. For instance, let's say you're using PHP to echo results in a nice HTML format. Obviously, you wouldn't need to know the record result index in the case of simply starting and ending a div, because you could start the div before the loop, and close it at the end. However, knowing where you are in the result set might affect some styling decisions (e.g., adding particular classes to the first and/or last rows).
I had one case in which I used a GROUP BY query and inserted each set of records into its own tabbed card. A user could click the tabs to display each set. I wanted to know when I was building the last tab, so that I could designate it as being selected (i.e., the one with the focus). The tab was already built by the time the loop ended, so I needed to know while inside of the loop (which was more efficient than using JavaScript to change the tab's properties after the fact).

Javascript loop not setting PHP value via sqlite_fetch_array() when adding series in Highcharts

I have a SQLite database and am trying to graph data on a linechart using Highcharts, PHP, and Javascript. I am graphing one series per user (a user being a text value per tuple), but am running into trouble with retrieving a subsequent user via a PHP loop.
$dbhandle = sqlite_open('db/test.db', 0666, $error);
if (!$dbhandle) die ($error);
$query5 = "SELECT DISTINCT User FROM Events";
$ok0 = sqlite_query($dbhandle, $query5, $error_msg);
if (!$ok0)
{
die("dead" . $error_msg);
}
$rows = sqlite_num_rows($ok0);
echo
"for(var i=2; i<$rows; i++) // start of JS loop.
//$rows is 4; I am graphing 2 series here
{";
$array = sqlite_fetch_array($ok0, SQLITE_ASSOC); // $ok0 is the unique list
// of users. After graphing one series, I want to grab the next user to graph
echo "chart.addSeries({
name: '{$array["User"]}',
data: [";
for($i=0; $i<$diff+1; $i++)
{
$target = date("D, j M", (strtotime($_GET["start"]) + $i * 24 * 3600));
$query6 = "SELECT * FROM Events WHERE User = '{$array["User"]}' AND Start LIKE '%{$target}%'";
$result6 = sqlite_query($dbhandle, $query6);
if (!$result6) die("Cannot execute query.");
$num = sqlite_num_rows($result6);
if($i==($diff))
{
echo $num;
}
else
echo $num . ", ";
}?>],
pointStart:
<?php
$date = DateTime::createFromFormat('D M d Y', urldecode($_GET["start"]));
echo $date->getTimestamp()*1000;?>,
pointInterval: 24 * 3600 * 1000 // one day
});
<?php echo "}";?> // end of JS loop
The result does graph two additional series, but they are both the same data from the same user. It doesn't look like the loop with sqlite_fetch_array() correctly returns the next user. Can anyone see the problem here? Maybe something with the way I'm integrating Javascript with PHP?
This line of code always does the same thing every time you call it:
$query6 = "SELECT * FROM Events WHERE User = '{$array["User"]}' AND Start LIKE '%{$target}%'";
$array supposedly has a list of distinct users, but you don't show the query for $ok0. You're doing the user lookup inside this loop for($i=0; $i<$diff+1; $i++), but you use none of those variables in determining which user to fetch.
I'd like to post the correct way to look up the next user from $array, but I have no idea what the structure is. If you can't figure out how to make your $query6 unique to each user, you'll have to post more information, like a var_dump of $array or the query text of $ok0.
Maybe you just need to move this line $array = sqlite_fetch_array($ok0, SQLITE_ASSOC); inside your for loop, but then you run the risk of $i and $diff+1 disagreeing with the number of rows available from your result.
I've figured it out. I believe that due to PHP being executed server-side, the block of code within the echoed Javascript loop results in the same values when the browser executes the Javascript. The server simply echoes the string that represents the js loop, and will run the code block after. When everything is sent to the browser, the Javascript will loop normally and simply output the results of the code block twice. I've just forgone the JS loop via PHP and replaced it with a PHP loop.

Infinite Scroll with MySQL Data

I have followed help located in this topic: Using infinite scroll w/ a MySQL Database
And have gotten close to getting this working properly. I have a page that is displayed in blocks using jquery masonry, in which the blocks are populated by data from a mysql database. When I scroll to the end of the page I successfully get the loading.gif image but immediately after the image it says "No more posts to show." which is what it should say if that were true. I am only calling in 5 posts initially out of about 10-15, so the rest of the posts should load when I reach the bottom of the page but I get the message that is supposed to come up when there really aren't any more posts.
Here is my javascript:
var loading = false;
$(window).scroll(function(){
if($(window).scrollTop() == $(document).height() - $(window).height()) {
var h = $('.blockContainer').height();
var st = $(window).scrollTop();
var trigger = h - 250;
if((st >= 0.2*h) && (!loading) && (h > 500)){
loading = true;
$('div#ajaxLoader').html('<img src="images/loading.gif" name="HireStarts Loading" title="HireStarts Loading" />');
$('div#ajaxLoader').show();
$.ajax({
url: "blocks.php?lastid=" + $(".masonryBlock:last").attr("id"),
success: function(html){
if(html){
$(".blockContainer").append(html);
$('div#ajaxLoader').hide();
}else{
$('div#ajaxLoader').html('<center><b>No more posts to show.</b></center>');
}
}
});
}
}
});
Here is the php on the page the blocks are actually on. This page initially posts 5 items from the database. The javascript grabs the last posted id and sends that via ajax to the blocks.php script, which then uses the last posted id to grab the rest of the items from the database.
$allPosts = $link->query("/*qc=on*/SELECT * FROM all_posts ORDER BY post_id DESC LIMIT 5");
while($allRows = mysqli_fetch_assoc($allPosts)) {
$postID = $link->real_escape_string(intval($allRows['post_id']));
$isBlog = $link->real_escape_string(intval($allRows['blog']));
$isJob = $link->real_escape_string(intval($allRows['job']));
$isVid = $link->real_escape_string(intval($allRows['video']));
$itemID = $link->real_escape_string(intval($allRows['item_id']));
if($isBlog === '1') {
$query = "SELECT * FROM blogs WHERE blog_id = '".$itemID."' ORDER BY blog_id DESC";
$result = $link->query($query);
while($blogRow = mysqli_fetch_assoc($result)) {
$blogID = $link->real_escape_string($blogRow['blog_id']);
$blogTitle = $link->real_escape_string(html_entity_decode($blogRow['blog_title']));
$blogDate = $blogRow['pub_date'];
$blogPhoto = $link->real_escape_string($blogRow['image']);
$blogAuthor = $link->real_escape_string($blowRow['author']);
$blogContent = $link->real_escape_string($blogRow['content']);
//clean up the text
$blogTitle = stripslashes($blogTitle);
$blogContent = html_entity_decode(stripslashes(truncate($blogContent, 150)));
echo "<div class='masonryBlock' id='".$postID."'>";
echo "<a href='post.php?id=".$blogID."'>";
echo "<div class='imgholder'><img src='uploads/blogs/photos/".$blogPhoto."'></div>";
echo "<strong>".$blogTitle."</strong>";
echo "<p>".$blogContent."</p>";
echo "</a>";
echo "</div>";
}
}
Here is the php from the blocks.php script that the AJAX calls:
//if there is a query in the URL
if(isset($_GET['lastid'])) {
//get the starting ID from the URL
$startID = $link->real_escape_string(intval($_GET['lastid']));
//make the query, querying 25 fields per run
$result = $link->query("SELECT * FROM all_posts ORDER BY post_id DESC LIMIT '".$startID."', 25");
$html = '';
//put the table rows into variables
while($allRows = mysqli_fetch_assoc($result)) {
$postID = $link->real_escape_string(intval($allRows['post_id']));
$isBlog = $link->real_escape_string(intval($allRows['blog']));
$isJob = $link->real_escape_string(intval($allRows['job']));
$isVid = $link->real_escape_string(intval($allRows['video']));
$itemID = $link->real_escape_string(intval($allRows['item_id']));
//if the entry is a blog
if($isBlog === '1') {
$query = "SELECT * FROM blogs WHERE blog_id = '".$itemID."' ORDER BY blog_id DESC";
$result = $link->query($query);
while($blogRow = mysqli_fetch_assoc($result)) {
$blogID = $link->real_escape_string($blogRow['blog_id']);
$blogTitle = $link->real_escape_string(html_entity_decode($blogRow['blog_title']));
$blogDate = $blogRow['pub_date'];
$blogPhoto = $link->real_escape_string($blogRow['image']);
$blogAuthor = $link->real_escape_string($blowRow['author']);
$blogContent = $link->real_escape_string($blogRow['content']);
$blogTitle = stripslashes($blogTitle);
$blogContent = html_entity_decode(stripslashes(truncate($blogContent, 150)));
$html .="<div class='masonryBlock' id='".$postID."'>
<a href='post.php?id=".$blogID."'>
<div class='imgholder'><img src='uploads/blogs/photos/".$blogPhoto."'></div>
<strong>".$blogTitle."</strong>
<p>".$blogContent."</p>
</a></div>";
}
}
echo $html;
}
I have tried using the jquery infinite-scroll plugin, but it seemed much more difficult to do it that way. I don't know what the issue is here. I have added alerts and did testing and the javascript script is fully processing, so it must be with blocks.php right?
EDIT: I have made a temporary fix to this issue by changing the sql query to SELECT * FROM all_posts WHERE post_id < '".$startID."' ORDER BY post_id DESC LIMIT 15
The blocks are now loading via ajax, however they are only loading one block at a time. The ajax is sending a request for every single block and they are fading in one after another, is it possible to make them all fade in at once with jquery masonry?
I seen your code in another answer, and I would recommend using the LIMIT functionality in MySql instead of offsetting the values. Example:
SELECT * FROM all_posts ORDER BY post_id DESC LIMIT '".(((int)$page)*5)."',5
This will just take a page number in the AJAX request and get the offset automatically. It's one consistent query, and works independent of the last results on the page. Send something like page=1 or page=2 in your jQuery code. This can be done a couple different ways.
First, count the number of elements constructed on the page and divide by the number on the page. This will yield a page number.
Second, you can use jQuery and bind the current page number to the body:
$(body).data('page', 1)
Increment it by one each page load.
Doing this is really the better way to go, because it uses one query for all of the operations, and doesn't require a whole lot of information about the data already on the page.
Only thing to note is that this logic requires the first page request to be 0, not 1. This is because 1*5 will evaluate to 5, skipping the first 5 rows. If its 0, it will evaluate to 0*5 and skip the first 0 rows (since 0*5 is 0).
Let me know any questions you have!
Have you tried doing any debugging?
If you are not already using, I would recommend getting the firebug plugin.
Does the ajax call return empty? If it does, try echoing the sql and verify that is the correct statement and that all the variables contain the expected information. A lot of things could fail considering there's a lot of communication happening between client, server and db.
In response to your comment, you are adding the html in this piece of code:
if(html){
$(".blockContainer").append(html);
$('div#ajaxLoader').hide();
}
I would do a console.log(html) and console.log($(".blockContainer").length) before the if statement.

PHP link only passing part of a mysql result

OK i have a php link which is made up of several variables
<a href=\year.php? manufacturer='.$manufacturer.'&fuel_type='.$fuel_type.'&model_type='.$model_type.'>'.$model_type.'</a>
The whole code is really long as it has a lot of pagination, so i will just include the basic query and the loop part.
$query1 = "SELECT Distinct model_type from $tableName where manufacturer='$manufacturer' AND fuel='$fuel_type' LIMIT $start, $limit";
$result = mysql_query($query1);
And then the bottom part where i get and show the results.
$count = 0;
$max = 2;
while($row = mysql_fetch_array($result))
{
$model_type = $row['model_type'];
$count++;
echo '<td class="manu"><div align="center">'.'<a href=\year.php? manufacturer='.$manufacturer.'&fuel_type='.$fuel_type.'&model_type='.$model_type.'>'.$model_type.'</a>'.'</div></td>';
if($count >= $max){
//reset counter
$count = 0;
//end and restart
echo '</tr><tr>';
}
}
now this works fine except when i take the mode type variable from the database it shows as 1 series, however when it is passed in this link it only gets the 1 and doesn't pick up the series.
Thanks
try to pass it like:
'.urlencode($model_type).'
Try To access it on next page with urldecode($_REQUEST['$model_type'])
I am not shure but you probably have a missing encoding Problem.
try this:
'.$model_type.'
Its url_encoding the values so your url doesnt get broken by ',",spaces and so on.
additional Hint:
Enclose your URL with " or ' so you do not get problems at the end.

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