I've written this simple shell script:
#!/bin/sh
STORAGE_PATH=/tmp/;
export STORAGE_PATH;
cd STORAGE_PATH;
perl /{SOME_PATH}/perl-script.pl;
When I call it from shell, it works perfectly as expected. But from PHP it hangs infinitely, and when debugging, I found that it hangs during the Perl execution which doesn't really make any sense since it continues if it was called in shell.
Did I make any mistake with the shebang #!/bin/sh? I tried with #!/bin/bash too.
I tried with all variations in php: exec, system, shell_exec, callthru but nothing is working..
Did I miss something?
Well, I can't see how it worked in shell.
You are calling /{SOME_PATH}/perl-script.pl but the variable SOME_PATH is not defined. Did you mean STORAGE_PATH? Also, you forgot the $ before {.
While you're at it, check that the user running the webserver has permissions to execute both scripts.
Related
I have tried to use exec() with 'whoami' to check if it works and I got the result of
nt authority\system
Now I need to run a .exe file with parameters from php via exec() function.
I tried this in command prompt and it actually runs the program with given parameters. This is the example command.
NOTE the exe file gets 3 inputs (folder, file_name, report_file_nmae)
> ..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml
But when I run this command from php file:
exec('..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml');
nothing is happening. This is the first time I am using exec() function, so I am not familiar with its details. What is wrong?
I tried using:
\\ instead of \
escapeshellarg() on the directory
added "" around directory folder names
No luck
Addendum:
echo exec($command) // echos < .... why?
or
exec($command, $output);
print_r($output); // Array()
I even changed the permission on the file to full control to all users.
If I call the program from command prompt, I can see the icon appearing next to clock for a second.
But the same call from php will not even call the program.
Edit
Even exec('notepad.exe'); is not working. Something has to be done with php configurations maybe?
I already said that I was new to exec() function. After doing some more digging, I came upon 2>&1 which needs to be added at the end of command in exec().
Thanks #mattosmat for pointing it out in the comments too. I did not try this at once because you said it is a Linux command, I am on Windows.
So, what I have discovered, the command is actually executing in the back-end. That is why I could not see it actually running, which I was expecting to happen.
For all of you, who had similar problem, my advise is to use that command. It will point out all the errors and also tell you info/details about execution.
exec('some_command 2>&1', $output);
print_r($output); // to see the response to your command
Thanks for all the help guys, I appreciate it ;)
You might also try giving the full path to the binary you're trying to run. That solved my problem when trying to use ImageMagick.
I am calling a shellscript from php using shell_exec() command. Following is the simple version of the shell script:
args[0] = "tom"
echo "hello"
echo "${args[0]}"
When I run this script from terminal, it gives the following output in terminal:
hello
tom
Whereas when I call this from php using shell_exec() only "hello" is printed and not "tom" . ie; variable assignment is not working when the script is called from php. Why this happens and how can I resolve this.
Any help is appreciated.
Probably PHP executes the script with sh, not Bash; thus arrays (which are a Bash feature) are not supported by the shell.
Workarounds: don't use arrays, or explicitly inboke Bash on the script. (If PHP understands shebangs, having a correct shebang line as the first line of the script may well be sufficient.)
First, args[0] = "tom" should not have space. It should be args[0]="tom"
(I'm not sure is this the problem, but worth to try).
Try this at the end of your code, to see which shell is running your script.
echo "`ps -p $$`"
Try both on terminal and PHP scripts to see if it same shell or not.
I have a script that uses passthru() to run a command. I need to set some shell environment variables before running this command, otherwise it will fail to find it's libraries.
I've tried the following:
putenv("LD_LIBRARY_PATH=/path/to/lib");
passthru($cmd);
Using putenv() doesn't appear to propagate to the command I'm running. It fails saying it can't find it libraries. When I run export LD_LIBRARY_PATH=/path/to/lib in bash, it works fine.
I also tried the following (in vain):
exec("export LD_LIBRARY_PATH=/path/to/lib");
passthru($cmd);
How can I set a shell variable from PHP, that propagates to child processes of my PHP script?
Am I limited to checking if a variable does not exist in the current environment and asking the user to manually set it?
I'm not 100% familiar with how PHP's exec works, but have you tried: exec("LD_LIBRARY_PATH=/path/to/lib $cmd")
I know that this works in most shells but I'm not sure how PHP doing things.
EDIT: Assuming this is working, to deal with multiple variables just separate them by a space:
exec("VAR1=val1 VAR2=val2 LD_LIBRARY_PATH=/path/to/lib $cmd")
You could just prepend your variable assignments to $cmd.
[ghoti#pc ~]$ cat doit.php
<?php
$cmd='echo "output=$FOO/$BAR"';
$cmd="FOO=bar;BAR=baz;" . $cmd;
print ">> $cmd\n";
passthru($cmd);
[ghoti#pc ~]$ php doit.php
>> FOO=bar;BAR=baz;echo "output=$FOO/$BAR"
output=bar/baz
[ghoti#pc ~]$
A couple things come to mind. One is for $cmd to be a script that includes the environment variable setup before running the actual program.
Another thought is this: I know you can define a variable and run a program on the same line, such as:
DISPLAY=host:0.0 xclock
but I don't know if that work in the context of passthru
https://help.ubuntu.com/community/EnvironmentVariables#Bash.27s_quick_assignment_and_inheritance_trick
I am having an issue using the PHP function shell_exec().
I have an application which I can run from the linux command line perfectly fine. The application takes several hours to run, so I am trying to spawn a new instance using shell_exec() to manage better. However, when I run the exact same command (which works on the command line) through shell_exec(), it returns an empty string, and it doesn't look like any new processes were started. Plus it completes almost instantly. shell_exec() is suppose to wait until the command has finished correct?
I have also tried variations of exec() with the same outcome.
Does anyone have any idea what could be going on here?
There are no symbolic links or anything funky in the command: just the path to the application and a few command line parametes.
Some thing with you env
See output of env from cli (command line interface) and php script
Also see what your shell interpreter?
And does script and cli application runs from one user?
If so, se option safe_mode
Make sure the user apache is running on (probably www-data) has access to the files and that they are executable (ls -la). A simple chmod 777 [filename] would fix that.
By default PHP will timeout after 30 sec. You can disable the limit like this:
<?php
set_time_limit(0);
?>
Edit:
Also consider this: http://www.rabbitmq.com/
I am trying to run a shell script from a php script.
I have complete control of the environment (unix on mac), I should have all the permissions, etc. set correctly.
The web script is in /htdocs/
The shell script can be executed from anywhere so when I go to /htdocs/ in the shell, I can easily run it like this:
$ my_shellscript
.. but when my php script (which is located in htdocs) tries to call it:
shell_exec('my_shellscript');
I get nothing.
I have proven the script can be called from that location and I have temporarily granted full access to try to get it working somehow. I am going crazy, please help.
If you know of some other way of triggering a shell script via the web that would be fine.
Thanks in advance.
well i got few weeks same problem, the solution is to check if the apace has the permission to execute your script. You could also try to run the script in php cli.
Since it is a shellscript, it needs to be invoked with the path prefix. My guess is you need to do this:
shell_exec('./my_shellscript');
First thing: make sure php isn't running in Safe Mode
Next thing: Try running it with the exec() function and using the full path (e.g. /var/www/htdocs/my_shellscript)
Try doing
echo shell_exec('my_shellscript 2>&1');
which will capture the script's stderr output and print it out. If something inside the script is failing, this output would otherwise be lost when not being run interactively.