Why am I getting this error the code works on the live demo the developer shows and its the same code? Any help would be most appreciated.
$method = $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] ?: $_SERVER['REQUEST_METHOD'];
The problem is not with the fact that the ternary operator is missing an argument as other stated. The problem is probably the PHP version of the server.
Straight from the PHP doc :
Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.
The way it is written is valid for any server with PHP version equal or above to 5.3.
Else it should be re-written in its equivalent expression :
$method = $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] ? $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] : $_SERVER['REQUEST_METHOD'];
change this
$method = $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] ?: $_SERVER['REQUEST_METHOD'];
to
$method = $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] ? "" : $_SERVER['REQUEST_METHOD'];
OR
$method = $_SERVER['HTTP_X_HTTP_METHOD_OVERRIDE'] ? NULL : $_SERVER['REQUEST_METHOD'];
Related
This question already has answers here:
Stacking Multiple Ternary Operators in PHP
(11 answers)
Closed 4 years ago.
I have a method that I'm checking if param is null, but if I use a ternary operator to make sure the false result isn't a string, I don't get the same expected result... I am a full stack .NET dev by day, but do some PHP free lance and this just stumped me...
$param = null;
// $active evaluates to true
$active = is_null($param) ? true : false;
// $active evaluates to false
$active = is_null($param) ? true : is_string($param)
? (strtolower($param) === 'true')
: true;
I have used nested ternary operators in C# and JavaScript what feels like countless times, but I don't know if I have ever tried in PHP... does PHP attempt to evaluate all nested ternary operations prior to expressing a result or is there something I'm missing here since from my understanding in this case, the ternary operator should be short circuited and evaluated to true in both circumstances.
The ternary operator is left associative unlike most other languages such as C#. The code:
$active = is_null($param)
? true
: is_string($param)
? (strtolower($param) === 'true')
: true;
is evaluated as follows:
$active = ((is_null($param) ? true : is_string($param))
? (strtolower($param) === 'true') : true);
You must explicitly add parenthesis to make sure ?: works the way it does in familiar languages:
$active = is_null($param)
? true
: (is_string($param)
? (strtolower($param) === 'true')
: true);
You need to wrap your second ternary condition with parenthesis (),
<?php
$param = null;
// $active evaluates to true
$active = is_null($param) ? true : false;
echo "Simple ternary result = $active".PHP_EOL;
// $active evaluates to true
$active = is_null($param) ? true : (is_string($param)? (strtolower($param) === 'true'): true);
echo "Nested ternary result = $active";
?>
Note:
It is recommended that you avoid "stacking" ternary expressions. PHP's
behaviour when using more than one ternary operator within a single
statement is non-obvious:
See Example #4 here at http://php.net/manual/en/language.operators.comparison.php
Example #4 Non-obvious Ternary Behaviour
<?php
// on first glance, the following appears to output 'true'
echo (true?'true':false?'t':'f');
// however, the actual output of the above is 't'
// this is because ternary expressions are evaluated from left to right
// the following is a more obvious version of the same code as above
echo ((true ? 'true' : false) ? 't' : 'f');
// here, you can see that the first expression is evaluated to 'true', which
// in turn evaluates to (bool)true, thus returning the true branch of the
// second ternary expression.
?>
DEMO: https://3v4l.org/gW8pk
This is a well-known problem with PHP. I doubt it will ever be fixed. Use parentheses, or if..else or switch statements, to get the behaviour you want.
(In technical terms, the ternary operator in PHP is "left associative", while that in every other language with this operator is "right associative". The latter is the more logical behaviour for this operator.)
In an online tutorial I have seen the following snippet of code:
$this->data = $data ?: \Input::all();
Is this a standard ternary operator? What would happen when $data evaluates to true?
Does the following code do the same thing as the original I posted?
$this->data = $data ? null : \Input::all();
It's a ternary operator, shortcut of
$this->data = $data? $data : \Input::all();
From http://php.net/manual/en/language.operators.comparison.php
Since PHP 5.3, it is possible to leave out the middle part of the ternary operator.
Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.
Given the following expression:
$att['menutext'] = isset($attrib_in['i_menu_text']) ? : $this->getID();
If it evaluates to true, will $att['menutext'] be set to true or $this->getID()?
According to this reference:
Since PHP 5.3, it is possible to leave out the middle part of the
ternary operator. Expression expr1 ?: expr3 returns expr1 if
expr1 evaluates to TRUE, and expr3 otherwise.
Yes, in version 5.3+ the middle expression is optional and returns true.
$a = (true ? : 1); // $a evaluates to true.
$a = (false ? : 1); // $a evaluates to 1.
It's just the same as the following
$att['menutext'] = isset($attrib_in['i_menu_text']) ? true : $this->getID();
never tested before, but its quite easy to test:
<?php var_dump(TRUE ? : 'F'); ?>
and its says: bool(true)
This won't execute, it's invalid syntax for PHP < 5.3.
Parse error: syntax error, unexpected ':' on line X
If you want the value to be set to true, then use true:
$att['menutext'] = isset($attrib_in['i_menu_text']) ? true : $this->getID();
Or it may be more likely that you want:
$att['menutext'] = isset($attrib_in['i_menu_text']) ? $attrib_in['i_menu_text'] : $this->getID();
what does this structure mean:
$var = isset($var_1) ? $var_1 : $var_2;
I came across it and of course with other values, not $va, $var_1 and $var_2.
thanks.
This is the ternary operator, and means the same as:
if (isset($var_1)) {
$var = $var_1;
}
else {
$var = $var_2;
}
The ternary operator provides a short-hand method of creating simple if/else statements.
It has some syntax errors, correctly:
$var = isset($var_1) ? $var_1 : $var_2;
This means:
if (isset($var_1))
{
$var = $var_1;
}
else
{
$var = $var_2;
}
That means:
if(isset($var_1))
$var = $var_1;
else
$var = $var_2;
It is short syntax for that.
just for your information from the php manual i copy pasted good things to know about ternary comparision operators
The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1 evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.
Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.
Note: Please note that the ternary operator is a statement, and that it doesn't evaluate to a variable, but to the result of a statement. This is important to know if you want to return a variable by reference. The statement return $var == 42 ? $a : $b; in a return-by-reference function will therefore not work and a warning is issued in later PHP versions.
Note:
It is recommended that you avoid "stacking" ternary expressions. PHP's behaviour when using more than one ternary operator within a single statement is non-obvious:
Example #3 Non-obvious Ternary Behaviour
<?php
// on first glance, the following appears to output 'true'
echo (true?'true':false?'t':'f');
// however, the actual output of the above is 't'
// this is because ternary expressions are evaluated from left to right
// the following is a more obvious version of the same code as above
echo ((true ? 'true' : false) ? 't' : 'f');
// here, you can see that the first expression is evaluated to 'true', which
// in turn evaluates to (bool)true, thus returning the true branch of the
// second ternary expression.
?>
Simple question. Here is this code.
$r = rand(0,1);
$c = ($r==0)? rand(65,90) : rand(97,122);
$inputpass .= chr($c);
I understand what it does in the end result, but I'd like a better explanation on how it works, so I can use it myself. Sorry if this is a bad question.
If you're unsure of what I'm asking about, its the (function?) used here:
$c = ($r==0)? rand(65,90) : rand(97,122);
That's called a ternary operator. It's effectively the equivalent of
if ($r == 0) {
$c = rand(65, 90);
} else {
$c = rand(97, 122);
}
But it's obviously a bit more compact. Check out the docs for more info.
That simply means:
if($r==0){
$c = rand(65,90);
else{
$c = rand(97,122);
}
If the statement is true the first operation after that ? is executed, else the operation after : is executed.
Its called a ternary operator.
Its the Ternary Operator
<?php
// Example usage for: Ternary Operator
$action = (empty($_POST['action'])) ? 'default' : $_POST['action'];
// The above is identical to this if/else statement
if (empty($_POST['action'])) {
$action = 'default';
} else {
$action = $_POST['action'];
}
?>
The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1 evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.
Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.
It's called the ternary operator. It's similar to an if/else construct, but the difference is that an expression using the ternary operator yields a value.
That is, you can't set a variable to the result of an if/else construct:
// this doesn't work:
$c = if ($r == 0) {
rand(65, 90);
} else {
rand(97, 122);
}
You can read more about it here: http://php.net/ternary#language.operators.comparison.ternary
The ternary operator is frequently misused. There's little benefit to using it in the example you showed. Some programmers love to use compact syntactic sugar even when it's not needed. Or even when it's more clear to write out the full if/else construct.
The ternary operator can also obscure test coverage if you use a tool that measures lines of code covered by tests.