I have 2 links like this:
http://www.site.com/report/4fbb14
http://www.site.com/4fbb14
so $_SERVER['REQUEST_URI'] for them is like:
/report/4fbb14
/4fbb14
I just need to get 4fbb14
I have used
$r_url = str_replace("/","",$_SERVER['REQUEST_URI']);
But I need it to work for both links, is something like this acceptable?
$r_url = str_replace("(/ or report)","",$_SERVER['REQUEST_URI']);
Much simpler would be
$r_url = end(explode('/', $_SERVER['REQUEST_URI']));
That gives you whatever was after the last forward slash
Using regular expressions
Looking for the value at the end of the string, coming just after a /.
if ( preg_match("/\/(\d+)$/", "http://www.site.com/report/4fbb14", $result) )
{
$value = $result[1];
}
Using parse_url and a simple explode
$values = parse_url("http://www.site.com/report/4fbb14");
$parts_of_the_url = explode("/", $values['path']);
$result = end($parts_of_the_url);
All the previous answers will work, except for php NoOb's, but if all the links will have the same format you can just do this:
$r_url = $_SERVER['REQUEST_URI'];
$r_url = str_replace("report","",$r_url);
$r_url = str_replace("/","",$r_url);
echo $r_url;
if you want to get the 4fbb14
<?php
$ex = explode('/', 'http://www.site.com/4fbb14');
echo $ex['3'];
Related
$url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of a URL.Its working.But I want to remove the last part from the URL and display the remaining part.Please help me.Here I am mentioning the example URL.
http://www.brightknowledge.org/knowledge-bank/media/studying-media/student-media/image_rhcol_thin
Try this:
$url = explode('/', 'http://www.brightknowledge.org/knowledge-bank/media/studying-media/student-media/image_rhcol_thin');
array_pop($url);
echo implode('/', $url);
There is no need to use explode, implode, and array_pop.
Just use dirname($path). It's a lot more efficient and cleaner code.
Use the following string manipulation from PHP
$url_without_last_part = substr($articleimage, 0, strrpos($articleimage, "/"));
For Laravel
dirname(url()->current())
In url()->current() -> you will get current URL.
In dirname -> You will get parent directory.
In Core PHP:
dirname($currentURL)
after the array_pop you can do
$url2=implode("/",$url)
to get the url in a string
Change this:
$articleurl = array_pop($url);
Into this:
$articleurl = end($url);
$articleurl will then hold the last array key.
Missed the part where you want to remove the value, you can use the function key() to get the key and then remove the value using that key
$array_key = key($articleurl);
unset(url[$array_key])
Pretty simple solution add in the end of your code
$url = implode('/', $url);
echo $url;
Notice that array_pop use reference argument passing so array will be modifed implode() function does the opposite to explode function and connects array elements by first argument(glue) and returns the string.
It looks like this may be what you are looking for. Instead of exploding and imploding, you can use the parsing functions which are designed to handle exactly this kind of URL manipulation.
$url = parse_url( $url_string );
$result =
$url['scheme']
. "://"
. $url['host']
. pathinfo($url['path'], PATHINFO_DIRNAME );
Here's the simple way to achieve
str_replace(basename($articleimage), '', $articleimage);
For the one-liners:
$url = implode('/', array_splice( explode('/', $articleimage), 0, -1 ) );
$url[''] and enter the appropriate number
I have looked around for this but can only find links and references to this been done after an anchor hashtag but I need to get the value of the URL after the last / sign.
I have seen this used like this:
www.somesite.com/archive/some-post-or-article/53272
the last bit 53272 is a reference to an affiliate ID..
Thanks in advance folks.
PHPs parse_url (which extracts the path from the URL) combined with basename (which returns the last part) will solve this:
var_dump(basename(parse_url('http://www.somesite.com/archive/some-post-or-article/53272', PHP_URL_PATH)));
string(5) "53272"
You can do this :
$url = 'www.somesite.com/archive/some-post-or-article/53272';
$id = substr(url, strrpos(url, '/') + 1);
You can do it in one line with explode() and array_pop() :
$url = 'www.somesite.com/archive/some-post-or-article/53272';
echo array_pop(explode('/',$url)); //echoes 53272
<?php
$url = "www.somesite.com/archive/some-post-or-article/53272";
$last = end(explode("/",$url));
echo $last;
?>
Use this.
I'm not an expert in PHP, but I would go for using the split function: http://php.net/manual/en/function.split.php
Use it to split a String representation of your URL with the '/' pattern, and it will return you an array of strings. You will be looking for the last element in the array.
This will work!
$url = 'www.somesite.com/archive/some-post-or-article/53272';
$pieces = explode("/", $url);
$id = $pieces[count($pieces)]; //or $id = $pieces[count($pieces) - 1];
If you always have the id on the same place, and the actual link looks something like
http://www.somesite.com/archive/article-post-id/74355
$link = "http://www.somesite.com/archive/article-post-id/74355";
$string = explode('article-post-id/', $link);
$string[1]; // This is your id of the article :)
Hope it helped :)
$info = parse_url($yourUrl);
$result = '';
if( !empty($info['path']) )
{
$result = end(explode('/', $info['path']));
}
return $result;
$url = 'www.somesite.com/archive/some-post-or-article/53272';
$parse = explode('/',$url);
$count = count($parse);
$yourValue = $parse[$count-1];
That's all.
I have the following URI:
/belt/belts/fk/product/40P35871
And I want to retrieve the last content after the last /.
In this case is 40P35871.
How can I do this?
How about explode?
$elements = explode('/', $input);
$productId = end($elements);
Here's a different solution entirely. (and the simplest!)
Using basename
$var = "/belt/belts/fk/product/40P35871";
echo basename($var);
Output:
40P35871
You don't need regex for something simple like that. Consider using strrchr, documentation here
$lastcontent = substr(strrchr($uri, "/"), 1);
Considering this special case of $uri being a path, the best answer would be the one provided by Chtulhu.
basename will return the last part of a path, documentation here
$lastcontent = basename($uri);
Just like this
$str = '/belt/belts/fk/product/40P35871';
$arr = explode('/', $str);
$var = array_pop($arr);
var_dump($var);
or
$var = substr($str, strrpos($str,'/') + 1);
Try this
$result = preg_replace('%(/(?:[^/]+?/)+)([^/]+)\b%', '$2', $subject);
use this:
echo preg_replace('/[a-z0-9]$/i', '$1', $url);
this will give you the last position
note: but on this url only, query strings make this useless and use need to parse the url for the same first for this to work
Don't use regex. In this case you can act as the follow
myUrl = $_SERVER[REQUEST_URL];
$number = substr(strrpos(myUri,'/')+1);
You don't need regex.
Find the last content and get it using substr():
$lastcontent = substr(strrchr($uri, "/"), 1);
Hi all i know preg_replace can be used for formatting string but i need help in that concerned area my url will be like this
http://www.example.com/index.php/
also remove the http,https,ftp....sites also
what i want is to get
result as
example.com/index.php
echo preg_replace("~(([a-z]*[:](//))|(www.))~", '', "ftp://www.example.com");
$url = 'http://www.example.com/index.php/';
$strpos = strpos($url,'.');
$output = substr($url,$strpos+1);
$parts=parse_url($url);
unset($parts['scheme']);
//echo http_build_url($parts);
echo implode("",$parts);
EDIT
To use http_build_url you needs pecl_http you can use implode as alternate
Something like this
$url = "http://www.example.com/index.php";
$parts = parse_url($url);
unset($parts['scheme']);
echo preg_replace('/^((ww)[a-z\d][\x2E])/i', '', join('', $parts));
Output
example.com/index.php
Example #2
$url = "http://ww3.nysif.com/Workers_Compensation.aspx";
Output
nysif.com/Workers_Compensation.aspx
Having a brain freeze...
Have a URL which may be in any of the formats :
http://url.com/stuff
url.com/somestuff
www.url.com/otherstuff
https://www.url.com/morestuff
You get the picture.
How do I remove the .com part to leave just the various 'stuff' parts ? For example, the above would end up :
stuff
somestuff
otherstuff
morestuff
You could achieve that using the following code:
$com_pos = strpos($url, '.com/');
$stuff_part = substr($url, $com_pos + 5);
Click here to see the working code.
This should do the trick for you!
<?php
$url = "http://url.com/stuff";
$querystring = preg_replace('#^(https|http)?(://)?(www.)?([a-zA-Z0-9-]+)\.[a-zA-Z]{2,6}/#', "", $url);
echo $querystring;
I submitted this answer because I'm not very fond of solutions using explode() to handle this. Maybe your query string contains more slashes so, you'd have to write exceptions for those cases.
You can use explode to make an array, then get the last element from the array.
$str = 'http://url.com/stuff';
$arr = explode('/', $str);
echo end($arr); // 'stuff'
$path = parse_url('http://url.com/stuff', PHP_URL_PATH);
If you leave the second parameter unspecified you can return an array including the domain etc.
Use explode function to divide the string.
<?php
$url = "http://url.com/stuff";
$stuff = explode("/", $url);
echo $stuff[sizeof($stuff) - 1];
?>
I used sizeof to access to last element.
preg_replace("/^(https?:\/\/)?[^\/]+/" ,"", $url);