determine which dynamically generated checkboxes are checked - php

Question

I'm trying to make a form with checkboxes which should subscribe a user to a forum in the database eventually.
I use this code to dynamically create a list of subscribed/unsubscribed forums for the current user:
//$checkboxes = array();
echo' <form action="" method="post">';
while($unsubscrlist = mysql_fetch_assoc($sublist))
{
//$checkboxes[] = $unsubscrlist['Name'];
echo '<input type="checkbox" checked="checked" name="subscrform[]"
value="' .$unsubscrlist['Name']. ' "/>' .$unsubscrlist['Name']. ' <br />';
}
while($subscrlist = mysql_fetch_assoc($notsublist))
{
// $checkboxes[] = $subscrlist['Name'];
echo '<input type="checkbox" name"subscrform[]"
value="' .$subscrlist['Name']. '"/>' .$subscrlist['Name']. '<br />';
}
echo '<br />
<input type="submit" value="Submit" />
</form>';
Then, to determine which checkboxes are checked I use this code:
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if(isset($_POST['subscrform']))
{
//echo 'getshereeee';
foreach($_POST['subscrform'] as $value)
{
//echo 'getshereeee';
echo $value;
}
}
Now the first checkboxes - to which the user is already subscribed -are output as value by this code, while the second list of checked checkboxes is never output as value somehow..
I thought this might had to do with using the same name twice. So I changed the first list to unsubscrform and did the check loop loop for both but still only get the first list as output values.
I feel like I'm missing something simple but can't really find out what. I would very much appreciate your help!

Answer 1

I just found a solution to my problem!
by changing
echo' <form action="" method="post">';
to
echo' <form name="subscrform" action="" method="post">';