Closest number in array, but on Monopoly table - php

Question

I have a monopoly game in progress and I need to retrieve the closest location from given value. I get available closest locations like this:
function Field_GetNearestByCategory($current,$category) {
$current = (int)$current;
$category = SQLEscape($category);
$s = "SELECT ID,Location FROM `card` WHERE Category='$category' AND Location <> $current";
$qr = SQLQuery($s);
$locs = array();
while($r = SQLGetArray($qr)) {
$locs[] = $r[1];
}
return $locs;
}
I have found solution for getting the closest value in array but problem occurs when $current == 40 and next closest field should be 6 (lets say we want to go to closest railroads).
function closest($search, $arr)
{
$closest = null;
foreach($arr as $item)
{
if($closest == null || abs($search - $closest) > abs($item - $search))
{
$closest = $item;
}
}
return $closest;
}
Please note that if $current == 40, anything below it is FAR away since Monopoly goes in one direction so 1 is closer to 40 than 39.
UPDATE:
I have found solution, thanks everyone
function closest($search, $arr) {
$c = null;
sort($arr);
foreach($arr as $k) {
if($k > $search) { return $k; }
else {
if(!$c) $c = $k;
}
}
return $c;
}

Answer 1

Here's a query that adds a "distance" field (the distance ahead the square is from $current) - mysql syntax for the CASE statement
SELECT ID, Location,
CASE WHEN Location < $current THEN Location + 40 - $current
ELSE Location - $current
END
AS Distance
FROM `card` WHERE Category='$category' AND Location <> $current