HTML from dropdown lists third category - php

Yesterday i asked how i could generate a second dropdown list for a subcategory, so in the first dropdown i would select "Trucks" and a second dropdown would appear with the colors "Black" or "White" to pick or if in the first dropdown i select "Cars" the second generated dropdown would have "Red", "Green" or "Blue" options, that lead to this http://jsfiddle.net/7YeL6/5/ that i implemented in my code and works like a charm (i already put more results in the ".js" and is working 100%).
But now im facing a new problem because i need to generate a third category and i dont know anything about jquery.
Based on the previous code, i need a third dropdown to appear based on the second dropdown so for example:
If i select "Trucks", then "Black" a new dropdown will appear to select "New" or "Used" or if i select "Cars", then "Red" a new dropdown will appear to select "Buy" or "Rent".
HTML CODE
<select name="category" id="category">
<option selected value="Please Select">Please Select</option>
<option value="Cars">Cars</option>
<option value="Trucks">Trucks</option>
<option value="Motorcycles">Motorcycles</option>
<option value="Boats">Boats</option>
</select>
<div>
<select name="category2" id="truck" class="second">
<option value="white">white</option>
<option value="black">black</option>
</select>
<select name="category2" id="car" class="second">
<option value="red">red</option>
<option value="green">green</option>
<option value="blue">blue</option>
</select>
</div>
CSS CODE
#category2{
display: none;
}
.second{
display: none;
}
JS CODE
$(document).ready(function(){
$("#category").change(function () {
var str = "";
str = $("select#category option:selected").text();
if(str == "Trucks"){
$("select.second").not("#truck").hide();
$("#truck").show();
$("#truck").fadeIn(1000);
}
else if(str == "Cars"){
$("select.second").not("#car").hide();
$("#car").show();
$("#car").fadeIn(1000);
}
})
});
Thanks

It looks like you wanted to this instead
Demo: http://jsfiddle.net/7YeL6/7/
HTML CODE
<select id="category" class="first">
<option selected value="Please Select">Please Select</option>
<option value="car">Cars</option>
<option value="truck">Trucks</option>
<option value="motor">Motorcycles</option>
<option value="boat">Boats</option>
</select>
<select id="truck" class="second">
<option selected value="Please Select">Please Select</option>
<option value="white">white</option>
<option value="black">black</option>
</select>
<select id="car" class="second">
<option selected value="Please Select">Please Select</option>
<option value="red">red</option>
<option value="green">green</option>
<option value="blue">blue</option>
</select>
<select id="truck-white" class="third">
<option value="size1">truck-white1</option>
<option value="size2">truck-white2</option>
</select>
<select id="truck-black" class="third">
<option value="size1">truck-black1</option>
<option value="size2">truck-black2</option>
</select>
<select id="car-red" class="third">
<option value="1">car-red1</option>
<option value="2">car-red2</option>
<option value="3">car-red3</option>
</select>
<select id="car-green" class="third">
<option value="1">car-green1</option>
<option value="2">car-green2</option>
<option value="3">car-green3</option>
</select>
CSS CODE
.second{
display: none;
}
.third{
display: none;
}
JQuery CODE
$(".first").change(function () {
var str = "";
str = $(this).val();
$('.second').hide();
$('.third').hide();
$('#'+str).show();
});
$(".second").change(function () {
var str = "";
str = $(this).val();
var id = $(this).attr('id');
$('.third').hide();
$('#' + id + "-" + str).show();
})

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I have created a dropdown list with links in the options, but while I'm submitting the form, the link goes into the database, instead of the value inside the option tags.
<select name="loc" id="location" onchange="setIframeSource()">
<li>TV</li>
<option value = "" disabled selected>Select Channel</option>
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<option name="ABC News" value="https://www.youtube.com/embed/w_Ma8oQLmSM">ABC News</option>
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<option name="Bloomberg Live" value="https://www.youtube.com/embed/dp8PhLsUcFE?rel=0&modestbranding=1">Bloomberg Live</option>
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My question here is, instead of passing the link to the database, I wanted the name of the channel, say ABC news inside the database?
I dont konw if you will need option value also.
but if you want only option name value then you can do this with jquery:
<script type="text/javascript">
$('#location').on('change', function() {
var selectedOption = $(this).find(':selected').attr('name');
setIframeSource();
});
</script>
<select name="loc" id="location">
<li>TV</li>
<option value = "" disabled selected>Select Channel</option>
<option name="News" Value="News"><p>News</p></option>
<option name="ABC News" value="https://www.youtube.com/embed/w_Ma8oQLmSM">ABC News</option>
<option name="RT" value="https://www.youtube.com/embed/NvCSr7qzAAM?rel=0&showinfo=0&modestbranding=1" frameborder="0" allowfullscreen="">RT</option>
<option name="Bloomberg Live" value="https://www.youtube.com/embed/dp8PhLsUcFE?rel=0&modestbranding=1">Bloomberg Live</option>
<option name="Skynews" value="https://www.youtube.com/embed/x5EZPXBuh7g">Sky News</option>
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and then sent selectedOption variable with ajax.

Creating dynamic button with Jquery

Hey guys I'm trying to create a dynamic button from a drop down list. for example, in the HTML code below...
function dropdownbutton(){
var make = document.getElementById("makelist");
var answer = make.options[make.selectedIndex].value;
alert("answer")
}
<div class="make">
<label>Make</label>
<select name="make" id="makelist" onchange="getId(this.value);">
<option value="">Select Make</option>
<option value="">1</option>
</select>
</div>
<div id="model">
<label>Model</label>
<select name="model" id="modellist" onchange="getId2(this.value);">
<option value="">Select Model</option>
<option value="">1</option>
<option value="">2</option>
</select>
</div>
<div id="year">
<label>Year</label>
<select name="year" id="yearlist" onchange="getId3(this.value);">
<option value="">Select Year</option>
<option value="">1</option>
<option value="">2</option>
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</div>
<button id="dropdownbutton" onclick="dropdownbutton()" class="vc_general vc_btn3 vc_btn3-size-md vc_btn3-shape-rounded vc_btn3-style-3d vc_btn3-color-success">Dropdown</button>
I'm open to trying it in different languages but I would prefer to do it in php, I simply don't know how to get the values from each dropdown.
I have taken help of Jquery here, inside the dropdownbutton() function i call all the select box element.
And using .each function extracted the value selected value of dropdowns.
i check those value if not empty then created a button inside element having Id #append_new_button
Please check the below code it might solve your issue
Thanks
function dropdownbutton() {
jQuery('#append_new_button').html('');
jQuery('select').each(function(){
var select_value = jQuery(this).val();
var select_label = jQuery("#"+jQuery(this).attr('id')+" option[value='"+select_value+"']"). text();
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jQuery('#append_new_button').append('<input type="button" id="'+select_value+'" value="'+select_label+'"></button>')
}
});
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
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<label>Make</label>
<select name="make" id="makelist">
<option value="">Select Make</option>
<option value="make_1">Make 1</option>
<option value="make_2">Make 2</option>
</select>
</div>
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<label>Model</label>
<select name="model" id="modellist" >
<option value="">Select Model</option>
<option value="model_1">Model 1</option>
<option value="model_2">Model 2</option>
</select>
</div>
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<label>Year</label>
<select name="year" id="yearlist" >
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<option value="year_1">year 1</option>
<option value="year_2">year 2</option>
</select>
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<div id="append_new_button">
</div>
I updated that code to find the values for each drop down
function dropdownbutton(val){
var make = document.getElementById("makelist");
var answer = make.options[make.selectedIndex].value;
var model = document.getElementById("modellist");
var answer2 = model.options[model.selectedIndex].value;
var year = document.getElementById("yearlist");
var answer3 = year.options[year.selectedIndex].value;
alert(answer2);
}
Now i need to figure out how to pass these variables to a link for example, mydomain.com/answer/answer2/answer3
i think that this code is more dynamic.
$("button").click(function() { // if button is clicked
var arr = $('select').map(function() { // run through all selects and get value
return this.value
}).get();
var url = "http://exp.com"; // base for the url
arr.forEach(function(item) {
url = url + '/' + item; // append all options to the base url
});
window.location.href(url); // redirect to base url + all options
});
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Please look at jsfiddle for a working example

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Below is my html code
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<option value="2015">2015</option>
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<label>To</label>
<select id="to_data_year" name="to_data_year" class="graph-select">
<option selected="" value="2016">2016</option>
<option value="2015">2015</option>
<option value="2014">2014</option>
<option value="2013">2013</option>
</select>
<input type="submit" value="Submit">
Try like this
function change_data_year(){
$('#to_data_year option').prop('disabled',false);
var from_data_year=$('#from_data_year').val();
var to_data_year=$('#to_data_year').val();
$('#to_data_year option').filter(function() {
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I hope that is like you need it.

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<form action="" method="get">
<select multiple="multiple" name="category">
<optgroup label="Category1">
<option value="1">A</option>
<option value="2">B</option>
<option value="3">C</option>
</optgroup>
<optgroup label="Category2">
<option value="4">D</option>
<option value="5">E</option>
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</optgroup>
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EDIT:
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how can I show "2 Selected" instead of "Select..." when selections are made?
See code below, construct the url yourself and it will work. In case the form contains more values you can better add the category to the value of the option.
<form method="get">
<select multiple="multiple" name="category">
<optgroup label="Category1">
<option value="1">A</option>
<option value="2">B</option>
<option value="3">C</option>
</optgroup>
<optgroup label="Category2">
<option value="4">D</option>
<option value="5">E</option>
<option value="6">F</option>
</optgroup>
</select>
<br><input type="button" value="go" onclick="clicked();">
</form>
<script type="text/javascript">
function clicked(){
var v = "";
$('select').find(":selected").each(
function(){
if (v != ""){
v += "&";
}
v += $(this).parent()[0].label + '=' + $(this).context.value;
}
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window.location.href = "index.php?" + v;
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</script>

Dynamically generate a single new drop down menu in a html form

I have a html form defined . I have a button for the user to select his occupation . If his occupation happens to be a student then i need to generate another new button dynamically . If the user selects anything other than a student then i dont want any new button . I am unsure how to do . Do i use jquery ? I have no idea to use jquery . Can some one help ? Any pointers
Thanks.
<?php
?>
<script language="javascript" type="text/javascript">
$(document).ready(function()
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$('#occupation').change(function()
{
if($(this).val() == 'Student')
{
$('#school').show();
} else {
$('#school').hide();
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});
});
</script>
<html>
<body>
<h1>My First Heading</h1>
<p>My first paragraph.</p>
<form>
<select name="occupation" id="occupation">
<option value="">- Select Occupation -</option>
<option value="Worker">Worker</option>
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</select>
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<option value="">Select School Type</option>
<option value="4 Year">4 Year</option>
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</form>
</body>
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Personally I accomplish this by placing the additional form element in the HTML, simply hidden like so:
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<option value="">- Select Occupation -</option>
<option value="Worker">Worker</option>
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</select>
<select name="school" id="school" style="display: none;">
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<option value="4 Year">4 Year</option>
<option value="2 Year">2 Year</option>
</select>
Then you can use JS, as I prefer jQuery, to show the div or hide the div when applicable:
$(document).ready(function()
{
$('#occupation').change(function()
{
if($(this).val() == 'Student')
{
$('#school').show();
} else {
$('#school').hide();
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Using jQuery would simplify this:
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<form>
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