Getting "wrong parameter count..." error with prepared statement - php

Question

I have been trying to learn prepared statements so that we can start implementing them thoughout our PHP sites. This function takes values (or none) from text boxes on a search form using the $_POST transfer method then uses the names and values of those textboxes to add criteria to the WHERE clause. The function worked previously ut I can't seem to get the prepared statement to function.
Researching several scripts I started using the one below and worked out a few bugs. now when I run it I get the error Wrong parameter count for mysqli_stmt::bind_param()
After this query runs I want to export the values into a table and was working before attempting the prepared statement.
Here is the code I have so far:
<?php
$db = mysqli_connec("ip_address", "loginname", "password", "database");
$refs = array('sssss');
foreach ($_POST as $key => $value)
{
$refs[] =& $_POST[$key];
}
$query = "SELECT col1, col2, col3, col4, col5 FROM tbl_name WHERE 1=1";
foreach ($_POST as $k => $v)
{
if(!empty($v)) {
$query .= " AND $k = ?";
$params[$k] = $v;
}
}
$results = $db->prepare($query);
call_user_func_array(array($results, 'bind_param'), $refs);
$results->execute();
?>

Answer 1

Parameters passed to mysqli_stmt::bind_param must be passed by reference, and only variables can be passed by reference, so you cannot pass the result of a function directly into call_user_func_array in this case. Also, the first parameter passed to bind_param is a string list of the variable types. Instead, try this:
// Change to whatever types are relevant
$refs = array('sss');
foreach ($arr as $key => $value)
{
$refs[] =& $arr[$key];
}
call_user_func_array(array($results, 'bind_param'), $refs);
Edit
This line is wrong:
$results = $mysqli->prepare($query);
Should be
$results = $db->prepare($query);

Answer 2

Ok, the way I solved this was to scrap everything and start over, which is always fun...but the new script that works for what I need is here
<?php
$dbhost = "ip_address";
$dbname = "db_name";
$dbuser = "db_login";
$dbpass = "db_pass";
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$query = "SELECT * FROM tbl_name WHERE 1=1";
foreach ($_POST as $k => $v)
{
if(!empty($v)) {
$query .= " AND $k LIKE ?";
$params[] = $v;
}
}
$results = $conn->prepare($query);
$results->execute($params);
$results->bindColumn(1, $no);
$results->bindColumn(2, $date);
$results->bindColumn(3, $name);
$results->bindColumn(4, $id);
$results->bindColumn(5, $path);
?>