Replacing Placeholder Variables in a String - php

Question

Just finished making this function. Basically it is suppose to look through a string and try to find any placeholder variables, which would be place between two curly brackets {}. It grabs the value between the curly brackets and uses it to look through an array where it should match the key. Then it replaces the curly bracket variable in the string with the value in the array of the matching key.
It has a few problems though. First is when I var_dump($matches) it puts puts the results in an array, inside an array. So I have to use two foreach() just the reach the correct data.
I also feel like its heavy and I've been looking over it trying to make it better but I'm somewhat stumped. Any optimizations I missed?
function dynStr($str,$vars) {
preg_match_all("/\{[A-Z0-9_]+\}+/", $str, $matches);
foreach($matches as $match_group) {
foreach($match_group as $match) {
$match = str_replace("}", "", $match);
$match = str_replace("{", "", $match);
$match = strtolower($match);
$allowed = array_keys($vars);
$match_up = strtoupper($match);
$str = (in_array($match, $allowed)) ? str_replace("{".$match_up."}", $vars[$match], $str) : str_replace("{".$match_up."}", '', $str);
}
}
return $str;
}
$variables = array("first_name"=>"John","last_name"=>"Smith","status"=>"won");
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you {STATUS} the competition.';
echo dynStr($string,$variables);
//Would output: 'Dear John Smith, we wanted to tell you that you won the competition.'

Answer 1

I think for such a simple task you don't need to use RegEx:
$variables = array("first_name"=>"John","last_name"=>"Smith","status"=>"won");
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you {STATUS} the competition.';
foreach($variables as $key => $value){
$string = str_replace('{'.strtoupper($key).'}', $value, $string);
}
echo $string; // Dear John Smith, we wanted to tell you that you won the competition.

Answer 2

I hope I'm not too late to join the party — here is how I would do it:
function template_substitution($template, $data)
{
$placeholders = array_map(function ($placeholder) {
return strtoupper("{{$placeholder}}");
}, array_keys($data));
return strtr($template, array_combine($placeholders, $data));
}
$variables = array(
'first_name' => 'John',
'last_name' => 'Smith',
'status' => 'won',
);
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you have {STATUS} the competition.';
echo template_substitution($string, $variables);
And, if by any chance you could make your $variables keys to match your placeholders exactly, the solution becomes ridiculously simple:
$variables = array(
'{FIRST_NAME}' => 'John',
'{LAST_NAME}' => 'Smith',
'{STATUS}' => 'won',
);
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you have {STATUS} the competition.';
echo strtr($string, $variables);
(See strtr() in PHP manual.)
Taking in account the nature of the PHP language, I believe that this approach should yield the best performance from all listed in this thread.
EDIT: After revisiting this answer 7 years later, I noticed a potentially dangerous oversight on my side, which was also pointed out by another user. Be sure to give them a pat on the back in the form of an upvote!
If you are interested in what this answer looked like before this edit, check out the revision history

Answer 3

I think you can greatly simplify your code, with this (unless I'm misinterpreting some of the requirements):
$allowed = array("first_name"=>"John","last_name"=>"Smith","status"=>"won");
$resultString = preg_replace_callback(
// the pattern, no need to escape curly brackets
// uses a group (the parentheses) that will be captured in $matches[ 1 ]
'/{([A-Z0-9_]+)}/',
// the callback, uses $allowed array of possible variables
function( $matches ) use ( $allowed )
{
$key = strtolower( $matches[ 1 ] );
// return the complete match (captures in $matches[ 0 ]) if no allowed value is found
return array_key_exists( $key, $allowed ) ? $allowed[ $key ] : $matches[ 0 ];
},
// the input string
$yourString
);
PS.: if you want to remove placeholders that are not allowed from the input string, replace
return array_key_exists( $key, $allowed ) ? $allowed[ $key ] : $matches[ 0 ];
with
return array_key_exists( $key, $allowed ) ? $allowed[ $key ] : '';

Answer 4

Just a heads up for future people who land on this page: All the answers (including the accepted answer) using foreach loops and/or the str_replace method are susceptible to replacing good ol' Johnny {STATUS}'s name with Johnny won.
Decent Dabbler's preg_replace_callback approach and U-D13's second option (but not the first) are the only ones currently posted I see that aren't vulnerable to this, but since I don't have enough reputation to add a comment I'll just write up a whole different answer I guess.
If your replacement values contain user-input, a safer solution is to use the strtr function instead of str_replace to avoid re-replacing any placeholders that may show up in your values.
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you {STATUS} the competition.';
$variables = array(
"first_name"=>"John",
// Note the value here
"last_name"=>"{STATUS}",
"status"=>"won"
);
// bonus one-liner for transforming the placeholders
// but it's ugly enough I broke it up into multiple lines anyway :)
$replacement = array_combine(
array_map(function($k) { return '{'.strtoupper($k).'}'; }, array_keys($variables)),
array_values($variables)
);
echo strtr($string, $replacement);
Outputs: Dear John {STATUS}, we wanted to tell you that you won the competition.
Whereas str_replace outputs: Dear John won, we wanted to tell you that you won the competition.

Answer 5

This is the function that I use:
function searchAndReplace($search, $replace){
preg_match_all("/\{(.+?)\}/", $search, $matches);
if (isset($matches[1]) && count($matches[1]) > 0){
foreach ($matches[1] as $key => $value) {
if (array_key_exists($value, $replace)){
$search = preg_replace("/\{$value\}/", $replace[$value], $search);
}
}
}
return $search;
}
$array = array(
'FIRST_NAME' => 'John',
'LAST_NAME' => 'Smith',
'STATUS' => 'won'
);
$paragraph = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you {STATUS} the competition.';
// outputs: Dear John Smith, we wanted to tell you that you won the competition.
Just pass it some text to search for, and an array with the replacements in.

Answer 6

/**
replace placeholders with object
**/
$user = new stdClass();
$user->first_name = 'Nick';
$user->last_name = 'Trom';
$message = 'This is a {{first_name}} of a user. The user\'s {{first_name}} is replaced as well as the user\'s {{last_name}}.';
preg_match_all('/{{([0-9A-Za-z_]+)}}/', $message, $matches);
foreach($matches[1] as $match)
{
if(isset($user->$match))
$rep = $user->$match;
else
$rep = '';
$message = str_replace('{{'.$match.'}}', $rep, $message);
}
echo $message;