I need to create something to display an image based on the current date and time. I have an SQL table set up that looks like this:
eventid | startdate | enddate | imgfile | status
6 | 2013-04-29 | 2013-05-03 | finals.jpg | active
What I need to do is compare the start date and end date to the current date, and if the current date falls within the startdate and enddate, then display the imgfile.
I'm not sure how to go about this, but this is what I tried.
//get current date and time
$currentdatetime = strtotime(now);
$formatteddatetime = date("y-m-d", $currentdatetime);
while($row=mysql_fetch_array($getimage))
{
//get variable for startdate
$formattedstartdate = date("y-m-d", $row[startdate]);
$formattedenddate = date("y-m-d", $row[enddate]);
if($formatteddatetime >= $formattedstartdate AND $formatteddatetime <= $formattedenddate AND $row[status] == 'active')
{
echo $row[imgfile];
}
}
?>
Right now, it doesn't show anything inside of the entire while statement. Am I at least on the right track?
the CURRENT_DATE returns the current date in ‘YYYY-MM-DD’ format or YYYYMMDD format depending on whether numeric or string is used in the function. CURDATE() and CURRENT_DATE() are the synonym of CURRENT_DATE.
You should do it in your SQL query instead of PHP. For example:
SELECT * FROM table WHERE CURRENT_DATE BETWEEN startdate AND enddate;
CURRENT_DATE() is a MySQL function that returns the current date, as the name suggests. It is one of a few special functions that have an alias without the parentheses.
Related
I have a table (Hire Rates) which contains multiple records. I'm trying to find records based on a date query but cannot get it to work correctly.
Essentially I am looking for records that contain a date between two dates. If my query date is "2021-08-15", it should return the third row (3000) as the query date falls between the two dates.
It is mostly working for me, except if the query date is equal to the start date or end date - in that case it doesn't return any result.
Table
startDate
endDate
hireRate
2021-01-01
2021-03-05
2350
2021-03-06
2021-04-08
2890
2021-04-09
2021-09-15
3000
Query
$sql = "SELECT rate, currencyID FROM hire_rates WHERE status = '1' AND NOT (startDate >= '$queryDate' OR endDate <= '$queryDate')
Try adding 'between' condition.
Like
select rate, currencyId from hire_rates where states =1 and not (cast($queryDate as DATE) between cast(startDate As DATE) and cast(endDate AS DATE) )
You would pass in the date you care about as a parameter. Then you can use between (based on your description of the logic):
SELECT rate, currencyID
FROM hire_rates
WHERE status = 1 AND
? BETWEEN startDate AND endDate;
Where ? is a parameter for the date you are passing in.
For 2021-08-15, you can write:
WHERE status = 1 AND
'2021-08-15' BETWEEN startDate AND endDate;
If you want the current date, you can actually get that from the database:
SELECT rate, currencyID
FROM hire_rates
WHERE status = 1 AND
curdate() BETWEEN startDate AND endDate;
Just try this then, `$sql = SELECT hireRate FROM hire_rate WHERE startDate<= '$queryDate' and endDate >= '$queryDate'
I want to make monthly sales from the sales table but i store date data using time() format
Example :
UserID | Product | Date
1 | Hot Dog | 1504363230
4 | Chicken | 1504695631
1 | Potato | 1504761716
3 | Spinach | 1505003789
So, how can i create monthly sales from there without replace Date into date() ? Because it will take a long time if i have to change 300K row
What should i do ?
Select * FROM Sales WHERE UserID = UserID AND Date = ?
the output must be like this
UserID 1 do 2 transaction in the last month or UserID 1 do 3 transaction in this
month
A PHP solution would be to use the second parameter in the date function:
string date ( string $format [, int $timestamp = time() ] )
The optional timestamp parameter is an integer Unix timestamp that defaults to the current local time if a timestamp is not given. In other words, it defaults to the value of time().
You can convert a unix timestamp to a datetime string in MySQL with FROM_UNIXTIME.
SELECT FROM_UNIXTIME(`Date`) as `Datetime` FROM sales
You can then expand on this with other date functions like MONTH or YEAR
SELECT MONTH(FROM_UNIXTIME(`Date`)) as `Month` FROM sales
EDIT:
I think this should work for you. I guess you want to avoid PHP's date() but MySQL's DATE() is okay.
SELECT
COUNT(*) AS nb_transaction,
UserID
FROM
sales
WHERE
DATE(`Date`) LIKE '2018-06-%'
Of course replace the month with the one you are looking for.
SQL (will be faster than PHP):
You can convert any UNIX Timestamp using FROM_UNIXTIME() to any format:
FROM_UNIXTIME(`Date`, '%Y %D %M %h:%i:%s')
PHP:
The time() function returns a UNIX Timestamp.
If you want to display a date using one, you can use DateTime::setTimestamp:
$date = new DateTime();
$date->setTimestamp($row['Date']);
echo $date->format('Y-m-d H:i:s'); // Hot Dog = 2017-09-02 14:40:30
Or shortly:
echo (new DateTime())->setTimestamp($row['Date'])->format('Y-m-d H:i:s');
$timestamp = 1517317337107; $date=date('Y-m-d H:i:s',
$timestamp/1000);
echo "date and time : ". $date."<br>";
$month=date('Y-m-d',$timestamp/1000);
echo "only date : ".$month."<br>";
#output
date and time : 2018-01-30 13:02:17
only date : 2018-01-30
hope this will help
I have my date in format March 2014. How do I get month and year in number format to compare it in Oracle 10g query.
<?php
$date = "March 2014";
?>
My query that I am trying to get is
select EMP_NAME where month = "03" and year = "2014".
Here is my table structure
EMP_ID | EMP_NAME | C_DATE
1 | ABC | 01-FEB-14
2 | XYZ | 03-MAR-14
Note: I am writing the coding in php
For a sargable predicate you should avoid altering every row of data to suit the single parameter.
Instead: Adjust the parameter to suit the data
select
*
from your_table
where C_DATE>= to_date('March 2014','MON YYYY', 'NLS_DATE_LANGUAGE = American')
and C_DATE< add_months(to_date('March 2014','MON YYYY', 'NLS_DATE_LANGUAGE = American'),1)
Note the data - C_DATE - is not affected by any function, yet you get the desired outcome (all records of March 2014); this method permits use of indexes on the field C_DATE for query efficiency.
You can try with TO_CHAR(date, 'MON') for the months and TO_CHAR(date, 'YYYY') for the year.
The query will be
select EMP_NAME where TO_CHAR(C_DATE, 'MON') = month and TO_CHAR(C_DATE, 'YYYY') = year
And in php you'll have to manage the date to get year and month and pass them to the query
$dt = new DateTime("March 2014");
$month = $dt->format("m"); //03
$year = $dt->format("Y"); //2014
//Here connect to the db..
$db->query("SELECT EMP_NAME FROM yourTable WHERE TO_CHAR(C_DATE, 'MON') = :month AND TO_CHAR(C_DATE, 'YYYY') = :year");
$db->bindParam(":month", $month);
$db->bindParam(":year", $month);
I have a table that stores dates in the format of MM/DD/YY (field name is date). I need to have a count that totals just the records for the current month. From searching, this is what I currently have but something is not right. Do I need to do a convertToDate, is it that my field is called "date", or am I missing something entirely?
$totalcount = mysql_query("select count(*) as 'total'
FROM state_to_state
WHERE status = 99 AND type = 1
AND MONTH(`date`) = MONTH(CURDATE())
AND YEAR(`date`) = YEAR(CURDATE())");
$totalnum = mysql_fetch_array($totalcount);
if($totalnum['total'] > 0) { $month_status = $totalnum['total']." this Month. "; }
Your dates are NOT native mysql dates (varchar, probably?), so you cannot use the mysql date functions on them directly. date('MM/DD/YY') will not work reliably:
mysql> select month('03/03/14'), month('03/18/14');
+-------------------+-------------------+
| month('03/03/14') | month('03/18/14') |
+-------------------+-------------------+
| 3 | NULL |
+-------------------+-------------------+
Convert your date fields to native mysql date types, or take a huge hit on performance and convert them to native date values onthefly via str_to_date().
I have a database holding two bits of information. from date to date. I need this entry to appear in my calender on every day, but I can only manage to get to appear on the first and last date.
example of DB:
job_no | date1(from)| date2(to)
________________________________
1 |2013-01-28 | 2013-02-03
2 |2013-01-14 | 2013-01-18
Edit for question. the search bar I have allows for ONE date input and the the calender finds entries through date1 and the next 6 days.
I cannot have a search which contains two date inputs because my users are so used to this way and i do not want to increase searching time. I started to think that I had to find the dates between the dates, add that to an array then use an if statement to find matches...but even saying this makes no sense to me.
regarding job 1, I need my calender to show this job up on all dates 28/29/30/31/01/02/03.
My current search SELECT * FROM jobs WHERE date1='$searchinput' PER day and calender this search. I use strtotime to increase the input date by +1 to add to the search for each day.
Calender page.
What I want with my results. User searched Date 28th.
Mon 28 | Tues 29 | Wed 30 ...... | Fri 03 |
_________________________________________________________________________
Job no 1 | job no 1 | job no 1 ...... | job no 1
What I have now.
Mon 28 | Tues 29 | Wed 30 ...... | Fri 03 |
_________________________________________________________________________
Job no 1 | blank | blank | job no 1
each day has a new select query right now. It matches days with date 1 and date 2. I dont need this as before I only had jobs out on one day now they go out for more than one day and need the job to be noted on all days it is out by only using a job from date and job to date.
EDIT 2:
SELECT * FROM calender_db NATURAL JOIN job_db
WHERE section='two'
AND date1 < '$day' AND date2 > '$day'
OR date1 = '$day' OR date2 = '$day'
This query selects what I need, but as I am using OR the first WHERE CLAUSE can be null. I need that to always be in the clause. I have been looking at using IIF or CASE to rectify but do not how to implement 100%...?
why not use BETWEEN
SELECT * FROM tableName WHERE date BETWEEN 'date1' AND 'date2'
SQLFiddle Demo
UPDATE 1
SELECT *
FROM tableName
WHERE date BETWEEN '2013-01-28' AND '2013-01-28' + INTERVAL 6 DAY
SQLFiddle Demo
To generate a list of days between two dates:
$days = array();
$stop = strtotime($date2);
for ($current = strtotime($date1); $current <= $stop; $current = strtotime('+1 days', $current)) {
$days[] = date('d', $current);
}
echo join('/', $days);
Demo
Update
Misunderstood the question it seems, if both dates are stored as columns and you're querying with a single date:
SELECT *
FROM jobs
WHERE 'date_from_input' BETWEEN date1 AND date2
Update 2
Your latest query can be written as:
SELECT *
FROM calender_db NATURAL JOIN job_db
WHERE section='two' AND '$day' BETWEEN date1 AND date2
Try like this
SELECT * FROM Mytimetable WHERE date BETWEEN 'date1' AND 'date2'
Query between date1 - date2
SELECT *
FROM `objects`
WHERE (date_field BETWEEN '2013-01-30 14:15:55' AND '2013-02-19 10:15:55')
OR
SELECT *
FROM `objects`
WHERE (date_field BETWEEN date1 AND date2)
query to select dates between two dates with PHP variables.
i will explain with exapmle :
$date1 = "2013-02-19";
$date2 = "2013-02-25";
then sql query will be :
$query = " SELECT * FROM table_xyz where (date_item BETWEEN date('".$date1."') AND date('".$date2."')";
hope it solves your problem
SELECT
*
FROM
tablename
WHERE
date between '$date1' and '$date2'
order by
date